Displaying an associative array in PHP - php

I am trying to build a function that extracts information from a database and inserts it into an associative array in PHP using mysql_fetch_assoc, and return the array so another function can display it. I need a way to display the returned assoc array. This should be a different function from the first one

print_r($array) will give nicely formatted (textually, not html) output.

If you just want information about what is in the array (for debugging purposes), you can use print_r($array) or var_dump($array), or var_export($array) to print it in PHP's array format.
If you want nicely formatted output, you might want to do something like:
<table border="1">
<?php
foreach($array as $name => $value) {
echo "<tr><th>".htmlspecialchars($name).
"</th><td>".htmlspecialchars($value)."</th></tr>";
}
?>
</table>
This will, as you might already see, print a nicely formatted table with the names in the left column and the values in the right column.

while ($row = mysql_fetch_assoc($result)) {
foreach ($row as $column => $value) {
//Column name is in $column, value in $value
//do displaying here
}
}
If this is a new program, consider using the mysqli extension instead.

Assuming you've made the call, and got $result back:
$array = new array();
while($row = mysql_fetch_assoc($result)){
$array[] = $row;
}
return $array;

This should get you going:
$rows = mysql_query("select * from whatever");
if ($rows) {
while ($record = mysql_fetch_array($rows)) {
echo $record["column1"];
echo $record["column2"];
// or you could just var_dump($record); to see what came back...
}
}

The following should work:
$rows = mysql_query("select * from whatever");
if ($rows) {
$header = true;
while ($record = mysql_fetch_assoc($rows)) {
if ($header) {
echo '<tr>';
foreach (array_keys($record) AS $col) {
echo '<td>'.htmlspecialchars($col).'</td>';
}
echo '</tr>';
$header = false;
}
echo '<tr>';
foreach (array_values($record) AS $col) {
echo '<td>'.htmlspecialchars($col).'</td>';
}
echo '</tr>';
}
}
(Yes, blatant mod of Fosco's code)
This should print the column headers once, then the contents after that. This would print just whatever columns were retrieved from the DB, regardless of the query.

Related

PHP show associative array content into JSON format

i'm new in PHP language. I'm writing a PHP script to get information from my online database(created on my altervista personal webpage) and convert in JSON format.
The problem is about when i get elements from my database i can show them correctly using "echo" command, but when i parse associative array to "json_encode" function i can't see correctly elements.
Here is the code:
$sql = "SELECT * FROM People";
$result = $conn->query($sql);
$json_array = array();
if ($result->num_rows > 0) {
// output data of each row
$row = $result->fetch_assoc();
foreach($row as $key => $value) {
echo "" . $key . ": " . $value;
echo "<br>";
$json_array[] = array(''=>$key, ''=>$value);
}
} else {
echo "0 results";
}
echo json_encode($json_array);
$conn->close();
?>
The $result->fetch_assoc(); returns an associative array.
As i said before i can see correct information using echo commands.
The problem is when i use this:
$json_array[] = array(''=>$key, ''=>$value);
The output is as follow:
[{"":"Mark"},{"":"ABC"},{"":"25"}]
Basically it's showing me only the second parameter "=>$value", while the first parameter "=>$key" is ignored.
Can you tell me please what should i change in order to see also the first parameter in my output?
Thanks
The correct way would be to do that
$json_array[] = array( $key => $value );
instead of
$json_array[] = array(''=>$key, ''=>$value);
You are essentially adding an EMPTY string as key and the $key as value at first, and then you replace it with the $value as they share the EMPTY string key in the array.
Read more at: http://php.net/manual/en/language.types.array.php#language.types.array.syntax.array-func
First param is ignored because it has the same key as the second (the key is ''), you should write:
$json_array[] = array($key, $value); // Indexed array
Output will be:
[["key1", "value1"],["key2", "value2"],["key3", "value3"]]
OR
$json_array[] = array($key => $value); // Associative array
Output will be:
[{"key1": "value1"},{"key2": "value2"},{"key3": "value3"}]
Try:
sql = "SELECT * FROM People";
$result = $conn->query($sql);
$json_array = array();
if ($result->num_rows > 0) {
// output data of each row
while ($row = $result->fetch_assoc()) {
$json_array[] = $row;
}
} else {
echo "0 results";
}
echo json_encode($json_array);
$conn->close();
In your code you are parsing only the first db result

Making an Array from Database MySQL

I have database connection. I want to make an array but something is problem i think. Here is my array code:
$var = "SELECT SUBSTRING(KayitTarihi,1,4) AS year,SUBSTRING(KayitTarihi,6,2) AS month,SUBSTRING(KayitTarihi,9,2) AS day,SUBSTRING(KayitTarihi,12,2) AS saat,SUBSTRING(KayitTarihi,15,2) AS dakika,Guc FROM Urun WHERE Date(KayitTarihi)=\"".$link_m."\"";
$result = $mysqli->query($var);
$data = array();
foreach ($result as $row) {$data[] = $row;}
print_r($data);
$no=1;$total_deger=count($data);
echo $total_deger;
for($i=0;$i<$total_deger);$i++){
$xxx[i]="[Date.UTC(".$data[i]['year'].",".$data[i]['month'].",".$data[i]['day'].",".$data[i]['saat'].",".$data[i]['dakika'].",00),".$data[i]['Guc']."]";if($no < $total_deger){echo ",";}
echo $xxx[i];
}
When I run this code, nothing happens in page. When I write to for example 0 for i. I can see my array value. Where do I mistake?
Code with correction and suggestion (both are commented):-
<?php
error_reporting(E_ALL); // check all errors
ini_set('display_errors',1);// display those errors
$var = "SELECT SUBSTRING(KayitTarihi,1,4) AS year,SUBSTRING(KayitTarihi,6,2) AS month,SUBSTRING(KayitTarihi,9,2) AS day,SUBSTRING(KayitTarihi,12,2) AS saat,SUBSTRING(KayitTarihi,15,2) AS dakika,Guc FROM Urun WHERE Date(KayitTarihi)=\"".$link_m."\"";
$result = $mysqli->query($var);
$data = array();
if ($result->num_rows > 0) { // check you got results or not
while($row = $result->fetch_assoc()) {
$data[] = $row; // assign them
}
}
//foreach ($result as $row) {$data[] = $row;} // not needed
print_r($data);
$no=1;
$total_deger= count($data);
echo $total_deger;
for($i=0;$i<$total_deger;$i++){ // remove )
$xxx[$i]="[Date.UTC(".$data[$i]['year'].",".$data[$i]['month'].",".$data[$i]['day'].",".$data[$i]['saat'].",".$data[$i]['dakika'].",00),".$data[$i]['Guc']."]"; // use $i instead of i
if($no < $total_deger)
{
echo ",";
}
echo $xxx[$i];
}
Note:- Always add some error reporting code. So that all errors will populated and you can rectify those
Also better would be to use foreach() instead of for loop (as it will take care of indexes itself):-
//use foreach
foreach ($data as $dat){
echo "[Date.UTC(".$data['year'].",".$data['month'].",".$data['day'].",".$data['saat'].",".$data['dakika'].",00),".$data['Guc']."]";
}
Firstly you want to check your SQL query returns rows. Then I think you need to modify your foreach to a while as below. Also checking that rows are returned before looping.
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$data[] = $row;
}
}
As per example given here: http://www.w3schools.com/php/php_mysql_select.asp

Use PHP to Display MySQL Results in HTML Table

Update for CodingBiz:
I'm putting this in my code:
for($i=1;$i<=$numRows;$i++) {
$output .= '<tr>';
$row = $this->fetchAssoc($result);
$colRow = $this->fetchAssoc($colResult);
foreach($colRow as $colName) {
$output .= "<td>".$row[$colName]."</td>";
}
$output .= '</tr>';
}
in place of
for($i=1;$i<=$numRows;$i++) {
$output .= '<tr>';
$row = $this->fetchAssoc($result);
for($j=1;$j<=$colNumRows;$j++) {
$colRow = $this->fetchAssoc($colResult);
$output .= "<td>".$row[$colRow["COLUMN_NAME"]]."</td>";
}
$output .= '</tr>';
}
Is there anything wrong with this?
Original Post:
I'm writing a function in a PHP class to display the results of a query in a table. I'm not structuring any of the table myself, I want it everything to be done using PHP. Here is my code so far:
function allResults($table,$cols) {
if(isset($cols)) {
$query = "SELECT $cols FROM $table";
}
else {
$query = "SELECT * FROM $table";
}
$result = $this->query($query);
$numRows = $this->numRows($result);
$colQuery ="SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA='shareride' AND TABLE_NAME='$table'";
$colResult = $this->query($colQuery);
$colNumRows = $this->numRows($colResult);
$output = '<table class="allResults">';
$output .= '<tr>';
for($i=1;$i<=$colNumRows;$i++) {
$colRow = $this->fetchAssoc($colResult);
$output .= "<td>".$colRow["COLUMN_NAME"]."</td>";
}
$output .= '</tr>';
for($i=1;$i<=$numRows;$i++) {
$output .= '<tr>';
$row = $this->fetchAssoc($result);
for($j=1;$j<=$colNumRows;$j++) {
$colRow = $this->fetchAssoc($colResult);
$output .= "<td>".$row[$colRow["COLUMN_NAME"]]."</td>";
}
$output .= '</tr>';
}
$output .= '</table>';
return $output;
}
In case it is unclear, query refers to mysqli_query, numRows refers to mysqli_num_rows, and fetchAssoc refers to mysqli_fetch_assoc. The database name is "shareride."
I know I am missing something in this line:
$output .= "<td>".$row[$colRow["COLUMN_NAME"]]."</td>";
but I just don't know what it is. Right now, I get all the table column titles displayed correctly, and I get the correct number of content rows, but I just can't populate those rows with the actual data from the database.
What am I missing? Any help would be GREATLY appreciated!
Get the data and column names from the same result set
<?php
$i = 0;
$colNames = array();
$data = array();
while($row = ***_fetch_assoc($res)) //where $res is from the main query result not schema information
{
//get the column names into an array $colNames
if($i == 0) //make sure this is done once
{
foreach($row as $colname => $val)
$colNames[] = $colname;
}
//get the data into an array
$data[] = $row;
$i++;
}
?>
UPDATE: Suggested by #YourCommonSense to replace the above code and it worked, simple and shorter - A WAY TO GET THE COLUMN NAMES/ARRAY KEYS WITHOUT LOOPING THROUGH LIKE I DID
$data = array();
while($row = mysql_fetch_assoc($res))
{
$data[] = $row;
}
$colNames = array_keys(reset($data))
Continued as before: Print the table
<table border="1">
<tr>
<?php
//print the header
foreach($colNames as $colName)
{
echo "<th>$colName</th>";
}
?>
</tr>
<?php
//print the rows
foreach($data as $row)
{
echo "<tr>";
foreach($colNames as $colName)
{
echo "<td>".$row[$colName]."</td>";
}
echo "</tr>";
}
?>
</table>
Test Result
You can see how I separated the data retrieval from table generation. They are dependent of each other now and you can test your table generation without the database by populating the arrays with static data
You can also make them into separate functions.
Never mix your database handling code with HTML output code. These are 2 totally different matters. Make your allResults function only return array with data, and then you can make another function to print in fancy way (and not in the database handler class).
You don't need information schema to get column name - you already have it in the returned array keys.
You don't need numRows either - use while() and foreach()
NEVER insert anything into query directly like you do with $cols - eventually it will lead to errors and injections.
Such a function, without accepting some parameters for the query, makes absolutely no sense especially in the context of migrating from mysql to mysqli - you are going yo use it as an old school mysql query inserting variables, not placeholders. So, it makes migration totally useless.
To know "Is there anything wrong with code", one have to run it, not watch. Run and debug your code, outputting key variables and making sure you can see errors occurred.
i'd try replacing the data part with something like:
while($row = $this->fetchAssoc($colResult))
{
echo "<tr>";
foreach($row as $value)
{
echo sprintf("<td>%s</td>",$value)
}
echo "</tr>";
}
i know it's not a proper answer, but it's really hard to read that code imho

Printing an array in php

Now I understand that you cant just use echo to print the contents of an array and you have to use foreach but for some reason this is not working. Any ideas?
$rows = $stmt->fetchAll();
foreach ($rows as $key=>$row)
{
echo "My value at $key is $row";
}
}
Output:
My value at 0 is ArrayMy value at 1 is ArrayMy value at 2 is Array
It appears you've fetched something from PDO using fetchAll.
This method returns an array of arrays (rows). The inner arrays have column_name => value elements. So for example if you retrieved the column 'firstName' and 'lastName', these values for the first record will be $rows[0]['firstName'] and $rows[0]['lastName'] respectivelly.
The proper way to do this would be:
$rows = $stmt->fetchAll();
foreach ($rows as $key => $row) {
foreach ($row as $column => $value) {
echo "My $column value for row $key is $value\n";
}
}
Protip: Watch the parentheses alignment, this doesn't matter for correctness but makes the code more readable :)
Looks like a multi-dimensional array to me. Try var_dump or print_r
var_dump($rows);
print_r($rows);
$row is another array which can not be converted directly to string. You can use this function to check array content.
function d($data)
{
echo '<pre>';
print_r($data);
echo '</pre>';
}
d($stmt->fetchAll());
and better you do this (if you forgot to remove its calling doesn't harm your site)
define('ENVIRONMENT', 'development');
function d($data)
{
if(ENVIRONMENT == 'development')
{
echo '<pre>';
print_r($data);
echo '</pre>';
}
}
d($stmt->fetchAll());
Try this to debug the content of $row:
$rows = $stmt->fetchAll();
foreach ($rows as $key=>$row)
{
echo "First key: $key | ";
foreach($row as $subkey => $subrow)
{
echo "Subkey: $subkey | Value: $subrow <br />";
}
}
Addiotinally, it's important to use functions like var_dump(), print_r() and var_export(), they will prevent a lot of problems for you.
//<pre> tag will give you a well formatted version of var_dump
echo "<pre>";
var_dump($rows);
echo "</pre>";
//#parram $data-array,$d-if true then die by default it is false
//#author Your name
function p($data,$d = false){
echo "<pre>";
print_r($data);
echo "</pre>";
if($d == TRUE){
die();
}
} // END OF FUNCTION
Use this function every time whenver you need to string or array it will wroks just GREAT.
There are 2 Patameters
1.$data - It can be Array or String
2.$d - By Default it is FALSE but if you set to true then it will execute die() function
In your case you can write like this..
$rows = $stmt->fetchAll();
foreach ($rows as $key=>$row) {
p($rows); // to use p function use above code for p() in your code
}

Echo values of arrays?

I want to echo the values of all arrays that has been returned from a search function. Each array contains one $category, that have been gathered from my DB. The code that I've written so far to echo these as their original value (e.g. in the same form they lay in my DB.) is:
$rows = search($rows);
if (count($rows) > 0) {
foreach($rows as $row => $texts) {
foreach ($texts as $idea) {
echo $idea;
}
}
}
However, the only thing this code echoes is a long string of all the info that exists in my DB.
The function, which result I'm calling looks like this:
function search($query) {
$query = mysql_real_escape_string(preg_replace("[^A-Za-zÅÄÖåäö0-9 -_.]", "", $query));
$sql = "SELECT * FROM `text` WHERE categories LIKE '%$query%'";
$result = mysql_query($sql);
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows['text'] = $row;
}
mysql_free_result($result);
return $rows;
}
How can I make it echo the actual text that should be the value of the array?
This line: echo $rows['categories'] = $row; in your search function is problematic. For every pass in your while loop, you are storing all rows with the same key. The effect is only successfully storing the last row from your returned query.
You should change this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
echo $rows['categories'] = $row;
}
mysql_free_result($result);
return $rows;
to this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows[] = $row;
}
return $rows;
Then when you are accessing the returned value, you could handle it like the following...
foreach ($rows as $key => $array) {
echo $array['columnName'];
// or
foreach ($array as $column => $value) {
echo $column; // column name
echo $value; // stored value
}
}
The problem is that you have a multi-dimensional array, that is each element of your array is another array.
Instead of
echo $row['categories'];
try print_r:
print_r($row['categories']);
This will technically do what you ask, but more importantly, it will help you understand the structure of your sub-arrays, so you can print the specific indices you want instead of dumping the entire array to the screen.
What does a var_dump($rows) look like? Sounds like it's a multidimensional array. You may need to have two (or more) loops:
foreach($rows as $row => $categories) {
foreach($categories as $category) {
echo $category;
}
}
I think this should work:
foreach ($rows as $row => $categories) {
echo $categories;
}
If this will output a sequence of Array's again, try to see what in it:
foreach ($rows as $row => $categories) {
print_r($categories);
}

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