I have database connection. I want to make an array but something is problem i think. Here is my array code:
$var = "SELECT SUBSTRING(KayitTarihi,1,4) AS year,SUBSTRING(KayitTarihi,6,2) AS month,SUBSTRING(KayitTarihi,9,2) AS day,SUBSTRING(KayitTarihi,12,2) AS saat,SUBSTRING(KayitTarihi,15,2) AS dakika,Guc FROM Urun WHERE Date(KayitTarihi)=\"".$link_m."\"";
$result = $mysqli->query($var);
$data = array();
foreach ($result as $row) {$data[] = $row;}
print_r($data);
$no=1;$total_deger=count($data);
echo $total_deger;
for($i=0;$i<$total_deger);$i++){
$xxx[i]="[Date.UTC(".$data[i]['year'].",".$data[i]['month'].",".$data[i]['day'].",".$data[i]['saat'].",".$data[i]['dakika'].",00),".$data[i]['Guc']."]";if($no < $total_deger){echo ",";}
echo $xxx[i];
}
When I run this code, nothing happens in page. When I write to for example 0 for i. I can see my array value. Where do I mistake?
Code with correction and suggestion (both are commented):-
<?php
error_reporting(E_ALL); // check all errors
ini_set('display_errors',1);// display those errors
$var = "SELECT SUBSTRING(KayitTarihi,1,4) AS year,SUBSTRING(KayitTarihi,6,2) AS month,SUBSTRING(KayitTarihi,9,2) AS day,SUBSTRING(KayitTarihi,12,2) AS saat,SUBSTRING(KayitTarihi,15,2) AS dakika,Guc FROM Urun WHERE Date(KayitTarihi)=\"".$link_m."\"";
$result = $mysqli->query($var);
$data = array();
if ($result->num_rows > 0) { // check you got results or not
while($row = $result->fetch_assoc()) {
$data[] = $row; // assign them
}
}
//foreach ($result as $row) {$data[] = $row;} // not needed
print_r($data);
$no=1;
$total_deger= count($data);
echo $total_deger;
for($i=0;$i<$total_deger;$i++){ // remove )
$xxx[$i]="[Date.UTC(".$data[$i]['year'].",".$data[$i]['month'].",".$data[$i]['day'].",".$data[$i]['saat'].",".$data[$i]['dakika'].",00),".$data[$i]['Guc']."]"; // use $i instead of i
if($no < $total_deger)
{
echo ",";
}
echo $xxx[$i];
}
Note:- Always add some error reporting code. So that all errors will populated and you can rectify those
Also better would be to use foreach() instead of for loop (as it will take care of indexes itself):-
//use foreach
foreach ($data as $dat){
echo "[Date.UTC(".$data['year'].",".$data['month'].",".$data['day'].",".$data['saat'].",".$data['dakika'].",00),".$data['Guc']."]";
}
Firstly you want to check your SQL query returns rows. Then I think you need to modify your foreach to a while as below. Also checking that rows are returned before looping.
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$data[] = $row;
}
}
As per example given here: http://www.w3schools.com/php/php_mysql_select.asp
Related
I'm trying to save into file a mysql SELECT query as follows:
$result = mysqli_query($db,$sql);
$out = fopen('tmp/csv.csv', 'w');
while ($row = $result -> fetch_row()) {
fputcsv($out,$row);
}
fclose($out);
after save I need to publish on a page as follows :
while ($row = mysqli_fetch_assoc($result)) {
//embed html code
}
The problem is that anytime I run $result->fetch_row(), a record of data is lost. I need to be able to run fetch_object at least 2 times within my code and preserve the data. I thought cloning would be a good solution for this, but it isn't.
Any hints, other that doing 2 query on the sql database ?
I believe another solution that could work is to use mysqli_data_seek.
The mysqli_result object is a pointer that moves through the data with each call of fetch_row(), but you can move the pointer back to the beginning by calling
mysqli_data_seek($result, 0);
And now the result is "reset", as it were, and you can use it again.
Learn more here:
https://www.php.net/manual/en/mysqli-result.data-seek.php
If you need to re-use the data, load it into an array - or do all the logic in the same loop.
So for example,
$data = []:
$result = $mysqli->query("...");
while ($row = mysqli_fetch_assoc($result)) {
$data[] = $row;
}
$out = fopen('tmp/csv.csv', 'w');
foreach ($data as $row) {
fputcsv($out, $row);
}
fclose($out);
// ...
foreach ($data as $row) {
//embed html code
}
Or do it all in the same loop (this may not always be possible, so if it isn't, go with the option above).
$result = mysqli_query($db, $sql);
$out = fopen('tmp/csv.csv', 'w');
while ($row = $result->fetch_row()) {
fputcsv($out,$row);
// embed HTML
}
fclose($out);
If you have mysqlind installed as part of your PHP MySQL infrastructure, Use a fetch_all() to get all the results into an array. You can then use that array as many times as you like.
$result = mysqli_query($db,$sql);
$all_results = $result->fetch_all();
$out = fopen('tmp/csv.csv', 'w');
foreach ( $all_results as $row){
fputcsv($out,$row);
}
fclose($out);
// now to reuse the array for your HTML output
foreach ($all_results as $row) {
//embed html code
}
Then you can reuse $all_results
If you dont have mysqlind then write a simple loop to load an array manually with all the results from the resultset
$result = mysqli_query($db,$sql);
$all_results = [];
while ($row = $result -> fetch_assoc()) {
$all_results[] = $row;
}
$out = fopen('tmp/csv.csv', 'w');
foreach ( $all_results as $row){
fputcsv($out,$row);
}
fclose($out);
// now to reuse the array for your HTML output
foreach ($all_results as $row) {
//embed html code
}
i have data from php loop foreach like this
foreach ($query->result() as $row) {
echo $row->name;
}
how to make the result show only the end data without remove others if data has same (if data have same value, hide all except the last one) like this:
*sorry bad english, this is the first time i ask here. thank you
Online Check, This is just a demo example.
See below the real example:
At first you need to use array_search for get the position of the same data, if exist then just remove it using $arr[$pos] = '';, and each and every time you need to import data into the new array called $arr and after completing fetching data you need to use a foreach loop to print them.
$arr = array();
foreach($query->result() as $row){
$pos = array_search($row->name, $arr);
if($pos !== false)
$arr[$pos] = '';
$arr[] = $row->name;
}
foreach($arr as $val){
echo $val.'<br/>';
}
Check this and let me know.
The data_seek method might help. This assumes your array is reasonable ordered to begin with.
$rowCount = 0;
$res = $query->result();
foreach($res as $row) {
if ($rowCount < $res->num_rows - 1) {
// set internal pointer to next row
$res->data_seek($rowCount + 1);
// if the row names match, print an empty string
// otherwise print the current name
$nextRow = $res->fetch_row();
if ($row->name == $nextRow->name) {
echo "";
// reset the internal pointer
$res->data_seek($rowCount);
} else {
echo $row->name;
}
} else {
echo $row->name;
}
// update the row count
$rowCount += 1;
}
Is there any reason why this code would avoid the first value in an array?
$rappels = array();
$i = 0;
while($row = $result->fetch_assoc()) {
foreach($row as $key=>$val) {
$rappels[$i][$key] = $val;
}
$i++;
}
return $rappels;
When I return the rappels, it always seems to avoid returning the very first item, which should be [0] in the array.
You have a number of redundancies in your code. You don't need $i nor do you need the foreach loop.
$rappels = array();
while($row = $result->fetch_assoc()) {
$rappels[] = $row;
}
return $rappels;
Your code as you posted it shouldn't remove any rows. You may need to look at the code you haven't posted to see if there's something there that's skipping the first row.
I want to echo the values of all arrays that has been returned from a search function. Each array contains one $category, that have been gathered from my DB. The code that I've written so far to echo these as their original value (e.g. in the same form they lay in my DB.) is:
$rows = search($rows);
if (count($rows) > 0) {
foreach($rows as $row => $texts) {
foreach ($texts as $idea) {
echo $idea;
}
}
}
However, the only thing this code echoes is a long string of all the info that exists in my DB.
The function, which result I'm calling looks like this:
function search($query) {
$query = mysql_real_escape_string(preg_replace("[^A-Za-zÅÄÖåäö0-9 -_.]", "", $query));
$sql = "SELECT * FROM `text` WHERE categories LIKE '%$query%'";
$result = mysql_query($sql);
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows['text'] = $row;
}
mysql_free_result($result);
return $rows;
}
How can I make it echo the actual text that should be the value of the array?
This line: echo $rows['categories'] = $row; in your search function is problematic. For every pass in your while loop, you are storing all rows with the same key. The effect is only successfully storing the last row from your returned query.
You should change this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
echo $rows['categories'] = $row;
}
mysql_free_result($result);
return $rows;
to this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows[] = $row;
}
return $rows;
Then when you are accessing the returned value, you could handle it like the following...
foreach ($rows as $key => $array) {
echo $array['columnName'];
// or
foreach ($array as $column => $value) {
echo $column; // column name
echo $value; // stored value
}
}
The problem is that you have a multi-dimensional array, that is each element of your array is another array.
Instead of
echo $row['categories'];
try print_r:
print_r($row['categories']);
This will technically do what you ask, but more importantly, it will help you understand the structure of your sub-arrays, so you can print the specific indices you want instead of dumping the entire array to the screen.
What does a var_dump($rows) look like? Sounds like it's a multidimensional array. You may need to have two (or more) loops:
foreach($rows as $row => $categories) {
foreach($categories as $category) {
echo $category;
}
}
I think this should work:
foreach ($rows as $row => $categories) {
echo $categories;
}
If this will output a sequence of Array's again, try to see what in it:
foreach ($rows as $row => $categories) {
print_r($categories);
}
If I need to select and use information of every element of a table in a database the procedure would be this:
$query = "...mySql query...";
$query_result = mysql_query($query) or die (mysql_error());
Then if I wished to access the fields of the result I would use the function mysql_fetch_array() and access them like this:
$query_result_array = mysql_fetch_array($query_result);
echo $query_result_array['field_1'];
....
echo $query_result_array['field_i'];
....
But since more elements could be returned by the query I would like to access every single of them with an array indexed from 0 to mysql_num_rows($query_result).
As an example:
echo $query_result_array['field_i'][0];
....
echo $query_result_array['field_i'][mysql_num_rows($query_result)];
should print for every selected element of the table the value of field i.
Is there a function that will do the job for me?
If not, any suggestions on how to do it?
Thanks in advance for help.
This may be an alternative
$res = mysql_query("..SQL...");
$arr = array();
while ($row = mysql_fetch_assoc($res)) {
$arr[] = $row;
}
var_dump($arr);
Or
$res = mysql_query("..SQL...");
for
(
$arr = array();
$row = mysql_fetch_assoc($res);
$arr[] = $row
);
var_dump($arr);
I don't think there is such a method; you have to do it yourself.
try with something like:
$res = mysql_query("..mySql query...");
$arr = array();
while ($row = mysql_fetch_assoc($res)) {
$query_result_array[] = $row;
}
then you access your data like:
echo $query_result_array[0]['field_i'];
based on 2 previous answers, those authors assuming that usual SO author is familiar with such a thing as creating a function
function sqlArr($sql) { return an array consists of
$ret = array();
$res = mysql_query($sql) or trigger_error(mysql_error()." in ".$sql);
if ($res) {
while ($row = mysql_fetch_assoc($res)) {
$ret[] = $row;
}
}
return $ret;
}
$array = sqlArr("SELECT * FROM table");
foreach ($array as $row) {
echo $row['name'],$row['sex'];
}
this resulting array have different structure from what you asked, but it is way more convenient too.
if you still need yours unusual one, you have to tell how you gonna use it