I want to echo the values of all arrays that has been returned from a search function. Each array contains one $category, that have been gathered from my DB. The code that I've written so far to echo these as their original value (e.g. in the same form they lay in my DB.) is:
$rows = search($rows);
if (count($rows) > 0) {
foreach($rows as $row => $texts) {
foreach ($texts as $idea) {
echo $idea;
}
}
}
However, the only thing this code echoes is a long string of all the info that exists in my DB.
The function, which result I'm calling looks like this:
function search($query) {
$query = mysql_real_escape_string(preg_replace("[^A-Za-zÅÄÖåäö0-9 -_.]", "", $query));
$sql = "SELECT * FROM `text` WHERE categories LIKE '%$query%'";
$result = mysql_query($sql);
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows['text'] = $row;
}
mysql_free_result($result);
return $rows;
}
How can I make it echo the actual text that should be the value of the array?
This line: echo $rows['categories'] = $row; in your search function is problematic. For every pass in your while loop, you are storing all rows with the same key. The effect is only successfully storing the last row from your returned query.
You should change this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
echo $rows['categories'] = $row;
}
mysql_free_result($result);
return $rows;
to this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows[] = $row;
}
return $rows;
Then when you are accessing the returned value, you could handle it like the following...
foreach ($rows as $key => $array) {
echo $array['columnName'];
// or
foreach ($array as $column => $value) {
echo $column; // column name
echo $value; // stored value
}
}
The problem is that you have a multi-dimensional array, that is each element of your array is another array.
Instead of
echo $row['categories'];
try print_r:
print_r($row['categories']);
This will technically do what you ask, but more importantly, it will help you understand the structure of your sub-arrays, so you can print the specific indices you want instead of dumping the entire array to the screen.
What does a var_dump($rows) look like? Sounds like it's a multidimensional array. You may need to have two (or more) loops:
foreach($rows as $row => $categories) {
foreach($categories as $category) {
echo $category;
}
}
I think this should work:
foreach ($rows as $row => $categories) {
echo $categories;
}
If this will output a sequence of Array's again, try to see what in it:
foreach ($rows as $row => $categories) {
print_r($categories);
}
Related
One of my PDO statements returns an array. For JSON encoding I want to cast this array to an Object and append it to another array.
while($row = $sth->fetch()){
foreach($row as $key=>$value){
$r = (object) $row;
$recordArray[] = $r;
}
}
$json->record = $recordArray;
echo json_encode($json);
$recordArray seems to stay empty but it doesn't if I write $recordArray[] = "test" in the loop. So there must be something wrong with my Object $r but I can't spot the mistake. Any help is appreciated.
Here is an easier way
echo json_encode(array('record'=>$sth->fetchAll(PDO::FETCH_OBJ)));
Your foreach is wrong: in body you use object on which you iterate.
May be you mean this?
$records = [];
while($row = $sth->fetch()) {
$current = [];
foreach($row as $key => $value) {
$current[$key] = $value;
}
$records[] = $current;
}
If I understood, you want to loop over $row and add every object within $row to $recordArray.
Then you should do this:
while($row = $sth->fetch()){
foreach($row as $value){
$recordArray[] = $value;
}
}
Is there any reason why this code would avoid the first value in an array?
$rappels = array();
$i = 0;
while($row = $result->fetch_assoc()) {
foreach($row as $key=>$val) {
$rappels[$i][$key] = $val;
}
$i++;
}
return $rappels;
When I return the rappels, it always seems to avoid returning the very first item, which should be [0] in the array.
You have a number of redundancies in your code. You don't need $i nor do you need the foreach loop.
$rappels = array();
while($row = $result->fetch_assoc()) {
$rappels[] = $row;
}
return $rappels;
Your code as you posted it shouldn't remove any rows. You may need to look at the code you haven't posted to see if there's something there that's skipping the first row.
I created associative array as below
$query = "SELECT word,meaning1,meaning2 FROM dictionary";
$results = $db->exeQuery($query);
$arrDictionary = array();
while($line = mysql_fetch_array($results, MYSQL_ASSOC))
{
$arrDictionary[] = $results;
}
Then i am iterative through another list of word array
foreach ($file_array as $value)
{
}
within this loop, for each word, i need to find meaning1 and meaning2. Tried many ways, but no success.
Could somebody help me?
I think
while($line = mysql_fetch_array($results, MYSQL_ASSOC))
{
$arrDictionary[] = $results;
}
should be replaced with
while($line = mysql_fetch_assoc($results))
{
$arrDictionary[] = $line;
}
and
foreach ($arrDictionary as $value)
{
echo $value['field_name'];
}
If I need to select and use information of every element of a table in a database the procedure would be this:
$query = "...mySql query...";
$query_result = mysql_query($query) or die (mysql_error());
Then if I wished to access the fields of the result I would use the function mysql_fetch_array() and access them like this:
$query_result_array = mysql_fetch_array($query_result);
echo $query_result_array['field_1'];
....
echo $query_result_array['field_i'];
....
But since more elements could be returned by the query I would like to access every single of them with an array indexed from 0 to mysql_num_rows($query_result).
As an example:
echo $query_result_array['field_i'][0];
....
echo $query_result_array['field_i'][mysql_num_rows($query_result)];
should print for every selected element of the table the value of field i.
Is there a function that will do the job for me?
If not, any suggestions on how to do it?
Thanks in advance for help.
This may be an alternative
$res = mysql_query("..SQL...");
$arr = array();
while ($row = mysql_fetch_assoc($res)) {
$arr[] = $row;
}
var_dump($arr);
Or
$res = mysql_query("..SQL...");
for
(
$arr = array();
$row = mysql_fetch_assoc($res);
$arr[] = $row
);
var_dump($arr);
I don't think there is such a method; you have to do it yourself.
try with something like:
$res = mysql_query("..mySql query...");
$arr = array();
while ($row = mysql_fetch_assoc($res)) {
$query_result_array[] = $row;
}
then you access your data like:
echo $query_result_array[0]['field_i'];
based on 2 previous answers, those authors assuming that usual SO author is familiar with such a thing as creating a function
function sqlArr($sql) { return an array consists of
$ret = array();
$res = mysql_query($sql) or trigger_error(mysql_error()." in ".$sql);
if ($res) {
while ($row = mysql_fetch_assoc($res)) {
$ret[] = $row;
}
}
return $ret;
}
$array = sqlArr("SELECT * FROM table");
foreach ($array as $row) {
echo $row['name'],$row['sex'];
}
this resulting array have different structure from what you asked, but it is way more convenient too.
if you still need yours unusual one, you have to tell how you gonna use it
I am trying to build a function that extracts information from a database and inserts it into an associative array in PHP using mysql_fetch_assoc, and return the array so another function can display it. I need a way to display the returned assoc array. This should be a different function from the first one
print_r($array) will give nicely formatted (textually, not html) output.
If you just want information about what is in the array (for debugging purposes), you can use print_r($array) or var_dump($array), or var_export($array) to print it in PHP's array format.
If you want nicely formatted output, you might want to do something like:
<table border="1">
<?php
foreach($array as $name => $value) {
echo "<tr><th>".htmlspecialchars($name).
"</th><td>".htmlspecialchars($value)."</th></tr>";
}
?>
</table>
This will, as you might already see, print a nicely formatted table with the names in the left column and the values in the right column.
while ($row = mysql_fetch_assoc($result)) {
foreach ($row as $column => $value) {
//Column name is in $column, value in $value
//do displaying here
}
}
If this is a new program, consider using the mysqli extension instead.
Assuming you've made the call, and got $result back:
$array = new array();
while($row = mysql_fetch_assoc($result)){
$array[] = $row;
}
return $array;
This should get you going:
$rows = mysql_query("select * from whatever");
if ($rows) {
while ($record = mysql_fetch_array($rows)) {
echo $record["column1"];
echo $record["column2"];
// or you could just var_dump($record); to see what came back...
}
}
The following should work:
$rows = mysql_query("select * from whatever");
if ($rows) {
$header = true;
while ($record = mysql_fetch_assoc($rows)) {
if ($header) {
echo '<tr>';
foreach (array_keys($record) AS $col) {
echo '<td>'.htmlspecialchars($col).'</td>';
}
echo '</tr>';
$header = false;
}
echo '<tr>';
foreach (array_values($record) AS $col) {
echo '<td>'.htmlspecialchars($col).'</td>';
}
echo '</tr>';
}
}
(Yes, blatant mod of Fosco's code)
This should print the column headers once, then the contents after that. This would print just whatever columns were retrieved from the DB, regardless of the query.