I created associative array as below
$query = "SELECT word,meaning1,meaning2 FROM dictionary";
$results = $db->exeQuery($query);
$arrDictionary = array();
while($line = mysql_fetch_array($results, MYSQL_ASSOC))
{
$arrDictionary[] = $results;
}
Then i am iterative through another list of word array
foreach ($file_array as $value)
{
}
within this loop, for each word, i need to find meaning1 and meaning2. Tried many ways, but no success.
Could somebody help me?
I think
while($line = mysql_fetch_array($results, MYSQL_ASSOC))
{
$arrDictionary[] = $results;
}
should be replaced with
while($line = mysql_fetch_assoc($results))
{
$arrDictionary[] = $line;
}
and
foreach ($arrDictionary as $value)
{
echo $value['field_name'];
}
Related
One of my PDO statements returns an array. For JSON encoding I want to cast this array to an Object and append it to another array.
while($row = $sth->fetch()){
foreach($row as $key=>$value){
$r = (object) $row;
$recordArray[] = $r;
}
}
$json->record = $recordArray;
echo json_encode($json);
$recordArray seems to stay empty but it doesn't if I write $recordArray[] = "test" in the loop. So there must be something wrong with my Object $r but I can't spot the mistake. Any help is appreciated.
Here is an easier way
echo json_encode(array('record'=>$sth->fetchAll(PDO::FETCH_OBJ)));
Your foreach is wrong: in body you use object on which you iterate.
May be you mean this?
$records = [];
while($row = $sth->fetch()) {
$current = [];
foreach($row as $key => $value) {
$current[$key] = $value;
}
$records[] = $current;
}
If I understood, you want to loop over $row and add every object within $row to $recordArray.
Then you should do this:
while($row = $sth->fetch()){
foreach($row as $value){
$recordArray[] = $value;
}
}
I have been trying to convert the fields from a mysql_fetch_array (that are urlencoded) to urldecode before converting to JSON (json_encode)
Here's what I'm working with that doesn't work:The output is still urlencoded
$query = "SELECT * FROM table WHERE tableId=$tableId";
$result = mysql_fetch_array(mysql_query($query));
foreach($result as $value) {
$value = urldecode($value);
}
$jsonOut = array();
$jsonOut[] = $result;
echo (json_encode($jsonOut));
Any ideas?
yeah....! you're not updating $result with the value returned by the function. $value needs to be passed by reference.
foreach($result as &$value) {
$value = urldecode($value);
}
or
foreach($result as $i => $value) {
$result[$i] = urldecode($value);
}
when you do this...
foreach($result as $value) {
$value = urldecode($value);
}
The result of the function is lost at at iteration of the foreach. You're trying to update each value stored in $result but that's not happening.
Also take note that the code only fetches one row from your query. I'm not sure if that's by design or not.
Try:
$query = "SELECT * FROM table WHERE tableId=$tableId";
$result = mysql_query($query);
$value = array();
while($row = mysql_fetch_array($result))
$value[] = urldecode($row);
}
$jsonOut = array();
$jsonOut[] = $result;
echo (json_encode($jsonOut));
I want to echo the values of all arrays that has been returned from a search function. Each array contains one $category, that have been gathered from my DB. The code that I've written so far to echo these as their original value (e.g. in the same form they lay in my DB.) is:
$rows = search($rows);
if (count($rows) > 0) {
foreach($rows as $row => $texts) {
foreach ($texts as $idea) {
echo $idea;
}
}
}
However, the only thing this code echoes is a long string of all the info that exists in my DB.
The function, which result I'm calling looks like this:
function search($query) {
$query = mysql_real_escape_string(preg_replace("[^A-Za-zÅÄÖåäö0-9 -_.]", "", $query));
$sql = "SELECT * FROM `text` WHERE categories LIKE '%$query%'";
$result = mysql_query($sql);
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows['text'] = $row;
}
mysql_free_result($result);
return $rows;
}
How can I make it echo the actual text that should be the value of the array?
This line: echo $rows['categories'] = $row; in your search function is problematic. For every pass in your while loop, you are storing all rows with the same key. The effect is only successfully storing the last row from your returned query.
You should change this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
echo $rows['categories'] = $row;
}
mysql_free_result($result);
return $rows;
to this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows[] = $row;
}
return $rows;
Then when you are accessing the returned value, you could handle it like the following...
foreach ($rows as $key => $array) {
echo $array['columnName'];
// or
foreach ($array as $column => $value) {
echo $column; // column name
echo $value; // stored value
}
}
The problem is that you have a multi-dimensional array, that is each element of your array is another array.
Instead of
echo $row['categories'];
try print_r:
print_r($row['categories']);
This will technically do what you ask, but more importantly, it will help you understand the structure of your sub-arrays, so you can print the specific indices you want instead of dumping the entire array to the screen.
What does a var_dump($rows) look like? Sounds like it's a multidimensional array. You may need to have two (or more) loops:
foreach($rows as $row => $categories) {
foreach($categories as $category) {
echo $category;
}
}
I think this should work:
foreach ($rows as $row => $categories) {
echo $categories;
}
If this will output a sequence of Array's again, try to see what in it:
foreach ($rows as $row => $categories) {
print_r($categories);
}
If I need to select and use information of every element of a table in a database the procedure would be this:
$query = "...mySql query...";
$query_result = mysql_query($query) or die (mysql_error());
Then if I wished to access the fields of the result I would use the function mysql_fetch_array() and access them like this:
$query_result_array = mysql_fetch_array($query_result);
echo $query_result_array['field_1'];
....
echo $query_result_array['field_i'];
....
But since more elements could be returned by the query I would like to access every single of them with an array indexed from 0 to mysql_num_rows($query_result).
As an example:
echo $query_result_array['field_i'][0];
....
echo $query_result_array['field_i'][mysql_num_rows($query_result)];
should print for every selected element of the table the value of field i.
Is there a function that will do the job for me?
If not, any suggestions on how to do it?
Thanks in advance for help.
This may be an alternative
$res = mysql_query("..SQL...");
$arr = array();
while ($row = mysql_fetch_assoc($res)) {
$arr[] = $row;
}
var_dump($arr);
Or
$res = mysql_query("..SQL...");
for
(
$arr = array();
$row = mysql_fetch_assoc($res);
$arr[] = $row
);
var_dump($arr);
I don't think there is such a method; you have to do it yourself.
try with something like:
$res = mysql_query("..mySql query...");
$arr = array();
while ($row = mysql_fetch_assoc($res)) {
$query_result_array[] = $row;
}
then you access your data like:
echo $query_result_array[0]['field_i'];
based on 2 previous answers, those authors assuming that usual SO author is familiar with such a thing as creating a function
function sqlArr($sql) { return an array consists of
$ret = array();
$res = mysql_query($sql) or trigger_error(mysql_error()." in ".$sql);
if ($res) {
while ($row = mysql_fetch_assoc($res)) {
$ret[] = $row;
}
}
return $ret;
}
$array = sqlArr("SELECT * FROM table");
foreach ($array as $row) {
echo $row['name'],$row['sex'];
}
this resulting array have different structure from what you asked, but it is way more convenient too.
if you still need yours unusual one, you have to tell how you gonna use it
why doesnt this array work? What do I do wrong? The result of my foreach loop is always either empty or just some weird numbers and signs. So what is wrong with my foreach loop?
$array = array();
while($row = mysqli_fetch_array($result)) {
if(!empty($row["some"])) {
$array["some"] = $row["some"];
$array["some2"] = $row["some2"];
}
}
foreach($array as $property=>$value) {
echo '<p>'.$value["some"].' - '.$value["some2"].'</p>'; }
$array will have only two properties, some and some2. Therefore your foreach loop doesn't make any sense. The foreach will loop two times, the first time with this:
$property = 'some';
$value = $row["some"];
and the second with this:
$property = 'some2';
$value = $row["some2"];
You will have to make $array multidimensional in your first loop by doing this:
while($row = mysqli_fetch_array($result)) {
$new = array();
if(!empty($row["some"])) {
$new["some"] = $row["some"];
$new["some2"] = $row["some2"];
$array[] = $new;
}
}
or shorter:
while($row = mysqli_fetch_array($result)) {
if(!empty($row["some"])) {
$array[] = array('some' => $row["some"],
'some2' => $row["some2"]);
}
}
$array["some"] and $array["some2"] are specific array elements. You are overwriting them every iteration of your while loop.
Not sure what you're trying to actually accomplish but I think possibly this is what you want:
$array = array();
while($row = mysqli_fetch_array($result)) {
if(!empty($row["some"])) {
$array["some"][] = $row["some"];
$array["some2"][] = $row["some2"];
}
}
foreach($array["some"] as $property=>$value) {
echo '<p>'.$value.' - '.$array["some2"][$property].'</p>';
}
or
$array = array();
while($row = mysqli_fetch_array($result)) {
if(!empty($row["some"])) {
$array[] = array('some' => $row["some"],
'some2' => $row["some2"]);
}
}
foreach($array as $property=>$value) {
echo '<p>'.$value['some'].' - '.$value['some2'].'</p>';
}
or similar...kinda depends on what you're ultimately trying to accomplish...
This doesn't explain the weird numbers and signs, but you are overwriting $array['some'] and $array['some2'] on each loop iteration.
Instead, try this:
while($row = mysqli_fetch_array($result)) {
if(!empty($row["some"])) {
$array[] = array("some"=>$row['some'], "some2"=>$row['some2']);
}
}
$array[] = array('some' => $row["some"], 'some2' => $row["some2"]);
But it would be better to retrieve only these columns.
Emil has the right answer :D. I love how people post so fast on here lol.