PHP: show only last data from same data on loop - php

Question

i have data from php loop foreach like this
foreach ($query->result() as $row) {
echo $row->name;
}
how to make the result show only the end data without remove others if data has same (if data have same value, hide all except the last one) like this:
*sorry bad english, this is the first time i ask here. thank you

Answer 1

Online Check, This is just a demo example.
See below the real example:
At first you need to use array_search for get the position of the same data, if exist then just remove it using $arr[$pos] = '';, and each and every time you need to import data into the new array called $arr and after completing fetching data you need to use a foreach loop to print them.
$arr = array();
foreach($query->result() as $row){
$pos = array_search($row->name, $arr);
if($pos !== false)
$arr[$pos] = '';
$arr[] = $row->name;
}
foreach($arr as $val){
echo $val.'<br/>';
}
Check this and let me know.

Answer 2

The data_seek method might help. This assumes your array is reasonable ordered to begin with.
$rowCount = 0;
$res = $query->result();
foreach($res as $row) {
if ($rowCount < $res->num_rows - 1) {
// set internal pointer to next row
$res->data_seek($rowCount + 1);
// if the row names match, print an empty string
// otherwise print the current name
$nextRow = $res->fetch_row();
if ($row->name == $nextRow->name) {
echo "";
// reset the internal pointer
$res->data_seek($rowCount);
} else {
echo $row->name;
}
} else {
echo $row->name;
}
// update the row count
$rowCount += 1;
}