Update database with checkbox php mysql - php

Question

I want to update the database with a checkbox in checked state.
If it is checked then update the database with 1.
Else if it is unchecked then update it with 0.
It works fine but it doesn't work if unchecked.
<?php
include('lib/db.php');
$facebook_id ="10001088";
$query1 = "SELECT `video`,`quran`,`medical`,`groups` FROM `man_facebook`.`users` WHERE `facebook_id`='$facebook_id'";
$result1 = mysql_query($query1);
while($result = mysql_fetch_array($result1))
{
$video = $result['video'];
$quran = $result['quran'];
$medical = $result['medical'];
$groups = $result['groups'];
echo $video;
// echo $quran;
?>
<form method="post" action="<? echo $_SERVER['REQUEST_URI']; ?>" >
<input type="checkbox" name="video" id="video" value="<?echo $video;?>" <?php
if($video == '1'){
echo "checked='checked'";
}
else {}
echo "/>"
?>
<input type="submit" name="submit" value="Submit">
</form>
<?php
}
if (isset($_POST['submit']))
{
if (is_numeric($_POST['video']) && $_POST['video'] <2 )
{
$video1 = isset($_POST['video']) ? '1' : '0';
echo $video1;
$query = mysql_query("UPDATE `man_facebook`.`users`
SET `video` ='$video1'
WHERE `facebook_id`='$facebook_id'");
$video = $video1;
echo '<meta http-equiv="refresh" content="0" />';
}
}
//echo $query;
//header("Location: updatesql.php");
?>
Can I also use jquery to update it smoothly?

Answer 1

I find this part a bit weird:
if (is_numeric($_POST['video']) && $_POST['video'] <2 )
{
$video1 = isset($_POST['video']) ? '1' : '0';
You first check if it is numeric and then check if it is set. If it wasn't set, that if would become false automatically. In other words, $video is always 1. Assuming $video can be only true/false (or maybe it comes as "checked"/"unchecked", not really sure), use it like this:
$video1 = ($video ? '1' : '0');
Hopefully I spotted the issue successfully :)
UPDATE
<input type="checkbox" name="video" id="video" value="video" <?php
if($video == '1'){
echo "checked='checked'";
}
echo "/>";
...
if (isset($_POST['submit']))
{
echo $_POST['video']; // again, please tell what it outputs here!!!
$video1 = (($_POST['video'] == "video") ? '1' : '0');

Answer 2

checkbox update
if (isset($_POST["send"]) && $_POST["send"] == "ok") {
foreach ($_POST['membre'] as $id => $data) {
mysql_query("UPDATE tablename SET param1='" . $data['param'] . "' WHERE id='" . $id . "'");
}
}
<form>
<input type="hidden" name="send" value="ok" />
<td class="cel2" style=" width: 100px;">
<input name="membre[<?php print $val['id']; ?>][param]" type="checkbox" style="margin-top: 7px; width: 30px;" value="1" id="param" <?php if ($val['p'] == '1') print 'checked'; ?> />
</td>
</form>