Populating checkboxes from database using PHP - only last option is getting checked - php

I am trying to populate checkboxes with the data from my mysql database but for some reason only the last checkbox is being checked (for example if automotive, carpentry and hand tools should be checked, only hand tools is being checked) and I can't figure out why. The mysql statement is running correctly and giving me the correct information. Here is the relevant code.
<?php
require_once('../../private/initialize.php');
require_login();
if(!isset($_GET['id'])) {
redirect_to(url_for('/members/show_member_tools.php'));
}
$id = $_GET['id'];
if(is_post_request()) {
// Handle form values sent by new.php
$tool = [];
$tool['tool_ID'] = $id;
$tool['serial_number'] = $_POST['serial_number'] ?? '';
$tool['tool_name'] = $_POST['tool_name'] ?? '';
$tool['tool_description'] = $_POST['tool_description'] ?? '';
$tool['tool_picture'] = $_POST['tool_picture'] ?? '';
$category =[];
$category = $_POST['category_ID'];
$result = update_tool($tool, $category);
//get info for checkboxes
global $db;
if($result === true) {
$_SESSION['message'] = "The tool has been updated sucessfully";
redirect_to(url_for('/members/show_tool.php?id=' . $id));
} else {
$errors = $result;
}
} else {
$tool = find_tool_by_id($id);
if(isset($_GET['id'])){
$id=$_GET['id'];
$sql = "select category_name from category INNER JOIN tool_category ON category.category_ID = tool_category.category_ID where tool_category.tool_id=$id";
$query = mysqli_query($db, $sql);
while($row=mysqli_fetch_array($query)) {
// $str = "";
$str = $row['category_name'];
echo $str;
if (strpos($str , "automotive")!== false){
$checked1 ="checked";
echo "made it to automotive";
} else {
$checked1 ="";
}
if (strpos($str , "carpentry")!== false){
$checked2 ="checked";
echo "made it to carpentry";
} else {
$checked2 ="";
}
if (strpos($str , "home maintenance")!== false){
$checked3 ="checked";
echo "made it to home maintenance";
} else {
$checked3 ="";
}
if (strpos($str , "plumbing")!== false){
$checked4 ="checked";
} else {
$checked4 ="";
}
if (strpos($str , "yard and garden")!== false){
$checked5 ="checked";
} else {
$checked5 ="";
}
if (strpos($str , "hand tools")!== false){
$checked6 ="checked";
} else {
$checked6 ="";
}
}//end while loop
} //end if
} //end else
$tool_set = find_all_tools();
$tool_count = mysqli_num_rows($tool_set);
mysqli_free_result($tool_set);
?>
<?php $page_title = 'Edit Tool'; ?>
<?php include(SHARED_PATH . '/header.php'); ?>
<div id="content">
<div class="center">
« Back to My Tools
<h2>Edit Tool</h2>
</div>
<?php echo display_errors($errors); ?>
<form action="<?php echo url_for('/members/edit_tool.php?id=' . h(u($id))); ?>" method="post">
<fieldset class="form">
<img src ="<?php echo h($tool['tool_picture']); ?>" alt="<?php echo h($tool['tool_picture']); ?>"width="150"><br>
<label for="serial_number">Serial Number</label><br>
<input type="text" name="serial_number" value="<?php echo h($tool['serial_number']); ?>" ><br>
<label for="tool_name">Tool Name</label><br>
<input type="text" name="tool_name" value="<?php echo h($tool['tool_name']); ?>" ><br>
<label for="tool_description">Tool Description</label><br>
<input type="text" name="tool_description" value="<?php echo h($tool['tool_description']); ?>" ><br>
<label for="category_ID">Tool Category: </label><br>
<input type="checkbox" name="category_ID[]" value="1" <?php echo $checked1; ?>> <label for="1">Automotive</label> <br>
<input type="checkbox" name="category_ID[]" value="2" <?php echo $checked2; ?>> <label for="2">Carpentry</label> <br>
<input type="checkbox" name="category_ID[]" value="3" <?php echo $checked3; ?>> <label for="3">Home Maintenance</label> <br>
<input type="checkbox" name="category_ID[]" value="4" <?php echo $checked4; ?>> <label for="4">Plumbing </label><br>
<input type="checkbox" name="category_ID[]" value="5" <?php echo $checked5; ?>> <label for="5">Yard and Garden</label> <br>
<input type="checkbox" name="category_ID[]" value="6" <?php echo $checked6; ?>> <label for="6">Hand Tools</label> <br>
<input type="submit" value="Edit Tool" >
<a class="block" href="<?php echo url_for('/members/delete_tool.php?id=' . $id); ?>">Delete Tool</a>
</fieldset>
</form>
<div class="push"></div>
</div>
<?php include(SHARED_PATH . '/footer.php'); ?>

You're looping over your results. This means with every loop you're setting one variable to "checked" and the rest to an empty string. So only the last one will be checked. The band-aid fix is to set unchecked as the default outside of the loop, and then change to checked only when it's needed.
But the real fix is to be pulling this info from the database and working with it instead of manually mapping database IDs to labels. By moving your condition into the join, you pull all the categories. The rows that have a tool ID are checked, and the others are not. You're also pulling the category names and IDs so you can programmatically build your checkboxes.
See here for DB sample: http://sqlfiddle.com/#!9/20b223/14/0
$tool = find_tool_by_id($id);
$tool["categories"] = [];
$sql = "SELECT c.category_name, c.category_ID, tc.tool_id
FROM category c
LEFT JOIN tool_category tc ON c.category_ID = tc.category_id
AND tc.tool_id = ?";
$stmt = $db->prepare($sql);
$stmt->bind_param("i", $_GET["id"]);
$result = $stmt->execute();
while($row = $stmt->fetch_assoc()) {
$id = $row["category_ID"];
$name = $row["category_name"];
$checked = $row["tool_id"] ? "checked" : "";
$tool["categories"][$id] = ["name" => $name, "checked" => $checked];
}
Now later on you can do this to automatically build all your checkbox inputs:
<?php foreach ($tool["categories"] as $id=>$category): ?>
<input type="checkbox" name="category_ID[]" id="category_<?=$id?>" value="<?=$id?>" <?=$category["checked"]?>>
<label for="category_<?=$id?>">
<?=htmlspecialchars($category["name"])?>
</label><br/>
<?php endforeach ?>

Related

multiple checkbox check if value in database?

code:
<?php
$id = $_GET['id'];
$sql = "select * from admin_menu where id = '$id'";
$result = mysqli_query($link,$sql);
while ($row = mysqli_fetch_array($result))
{
$menu_name = $row['menu_name'];
$menu_link = $row['menu_link'];
$priority = $row['priority'];
$admin_id = explode(",", $row['admin_id']);
}
if(isset($_POST['update']))
{
$admin_id = $_POST['admin_id'];
$chk="";
foreach($admin_id as $chk1)
{
$chk .= $chk1.",";
}
$menu_name = $_POST['menu_name'];
$menu_link = $_POST['menu_link'];
$priority = $_POST['priority'];
$sql = "update admin_menu set menu_name = '$menu_name', menu_link = '$menu_link', priority = '$priority', admin_id = '$chk' where id = '$id'";
$result = mysqli_query($link,$sql);
if($result == true)
{
$msg .= "<h3 style='color:green;'>update</h3>";
}
else
{
$msg .= "<h3 style='color:red;'>Error!</h3>";
}
}
?>
<form name="myform" method="post" >
<div class="row">
<label for="Producer_firstname">Admin Name</label>
<?php
foreach ($admin_id as $admin_id)
{
$chk = "";
if (in_array($chk, $admin_id))
{
$chk = 'checked="checked" ';
}
echo '<input type="checkbox" name="admin_id[]" value="'.$admin_id.'" '.$chk.'/><br/>';
}
?>
</div>
<div class="row">
<label for="Producer_firstname">Menu Name </label>
<input size="60" maxlength="255" name="menu_name" id="menu_name" value="<?php echo $menu_name; ?>" type="text" />
</div>
<div class="row">
<label for="Producer_lastname" >Menu Link </label>
<input size="60" maxlength="255" name="menu_link" id="menu_link" type="text" value="<?php echo $menu_link; ?>" />
</div>
<div class="row">
<label for="Producer_lastname" >Priority</label>
<select name="priority" id="priority">
<option value="<?php echo $priority; ?>"><?php echo $priority; ?></option>
<option value="">choose any one</option>
<option value="1">1</option>
<option value="0">0</option>
</select>
</div>
<div class="row buttons">
<button type="submit" name='update' id='update'>update Menu</button>
</div>
</form>
In this code I am fetching multiple checkbox value from table admin2 and I want when I update form value checkbox check if the value of checkbox is exist into database. How can I fix it ?
Thank You
Your code has few issues,
1. Update should be done before select query
2. List of admin not managed separately
3. Priority radio buttons not managed properly
Additional Suggestions,
1. Use prepare query statements
2. use implode for appending multiple values instead of foreach
3. print admin names before checkboxes
<?php
$id = $_GET['id'];
if(isset($_POST['update']))
{
$chk = implode(',', $_POST['admin_id']);
$menu_name = $_POST['menu_name'];
$menu_link = $_POST['menu_link'];
$priority = $_POST['priority'];
$sql = "update admin_menu set menu_name = '$menu_name', menu_link = '$menu_link', priority = '$priority', admin_id = '$chk' where id = '$id'";
$result = mysqli_query($link,$sql);
$msg = "";
if($result == true)
{
$msg .= "<h3 style='color:green;'>update</h3>";
}
else
{
$msg .= "<h3 style='color:red;'>Error!</h3>";
}
echo $msg;
}
$sql = "select * from admin_menu where id = '$id'";
$result = mysqli_query($link,$sql);
$row = mysqli_fetch_array($result);
$menu_name = $row['menu_name'];
$menu_link = $row['menu_link'];
$priority = $row['priority'];
$admin_id = explode(",", $row['admin_id']);
$admins = array('admin1', 'admin2', 'admin3', 'admin4', 'admin5', 'admin6', 'admin7', 'admin8');
?>
<form name="myform" method="post" >
<div class="row">
<label for="Producer_firstname">Admin Name</label>
<?php
foreach ($admins as $admin)
{
$chk = "";
if (in_array($admin, $admin_id))
{
$chk = 'checked="checked" ';
}
echo $admin.' <input type="checkbox" name="admin_id[]" value="'.$admin.'" '.$chk.'/><br/>';
}
?>
</div>
<div class="row">
<label for="Producer_firstname">Menu Name </label>
<input size="60" maxlength="255" name="menu_name" id="menu_name" value="<?php echo $menu_name; ?>" type="text" />
</div>
<div class="row">
<label for="Producer_lastname" >Menu Link </label>
<input size="60" maxlength="255" name="menu_link" id="menu_link" type="text" value="<?php echo $menu_link; ?>" />
</div>
<div class="row">
<label for="Producer_lastname" >Priority</label>
<select name="priority" id="priority">
<option value="1" <?php if($priority == 1) echo "selected='selected'"; ?>>1</option>
<option value="0" <?php if($priority == 0) echo "selected='selected'"; ?>>0</option>
</select>
</div>
<div class="row buttons">
<button type="submit" name='update' id='update'>update Menu</button>
</div>
</form>

IMPLODE data by checkbox

i have this Interface where the user can add a flower
The user need to add a flower to the database and he can make them in different occasions a categories (the check boxes). Now to implode the data i made this code:
$occasions = implode( ';' , $_POST['reg_occassions'] );
$categories= implode( ';' , $_POST['reg_categories'] );
$query =
"INSERT INTO tbl_flower (flower_type, website_description,florist_description,name,image,enabled,florist_choice,categories,occasions)
VALUES ('$flowertype', '$websitedescription', '$floristdescription','$name', '$upfile', '$enabled','$floristchoice', '$categories','$occasions')";
In the database they save as follows :
id flower name occasions categories
1 Rose Birthday;Valentines Bouqet;flower arrangment
Now the user can edit a flower too.This is the interface
PROBLEM!:
i dont have an idea how can i make the checkboxes again and show him which one he checked and he can change the data. I need to know how can i show the checkboxes and which one he checked will be checked too .
Thank and I really appreaciate if someone can help me.
EDIT Answer: This is the interface of the checkboxes.
You can do something like:
$results = "Bouqet,flower arrangment"; //results from your database
$resultsArray = explode(",", $results); //split the comma
$checkValue = array("Bouqet", "flower arrangment", "other"); //your checkbox values
$html = "";
foreach($checkValue as $val)
{
if(in_array($val,$resultsArray ))
$html .= '<input type="checkbox" name="flower" value="'.$val.'" checked>'.$val.'<br>';
else
$html .= '<input type="checkbox" name="flower" value="'.$val.'">'.$val.'<br>';
}
echo $html;
Check Demo Here
EDIT: I am making this edit because of your comments, you need to do something like:(not tested)
<div class="table-responsive col-md-4">
<table>
<thead>Occasions</thead>
/**flower occassions **/
$flowerCategoriesQry "SELECT categories FROM tbl_flower where id = 1"; //you need to change the where clause to variable
$flowerResults = mysqli_query($conn, $flowerCategoriesQry)
$categoriesRow = $flowerResults->fetch_assoc();
$resultsArray = explode(",", $categoriesRow['categories']);
/**All Occassions **/
$query544="SELECT name FROM tbl_occasions";
$results544 = mysqli_query($conn, $query544);
while ($row = $results544->fetch_assoc()) { ?>
<div class="col-md-12">
<label class="checkbox" for="checkboxes">
<?php
if(in_array($row['name'],$resultsArray ))
{
?>
<input type="checkbox" name="flower" value="<?php echo $row['name'];?>" checked> <?php echo $row['name'];?> >
<?php }
else{
?>
<input type="checkbox" name="flower" value="<?php echo $row['name'];?>" ><?php echo $row['name'];?> >
<?php echo} $row['name']?> </label>
</div> <?php }?>
</table>
This is the answer. Thanks to the Flash!
session_start();
$conn = ConnectToSql();
?>
<div class="table-responsive col-md-6" style="border:1px solid blue">
<div class="col-md-6">Categories</div>
<div class="col-md-6">Occasions</div>
<hr>
<div class="col-md-6">
<?php
/**flower occassions **/
$flowerCategoriesQry= "SELECT categories FROM tbl_flower where id ='$_SESSION[flower]'";
$flowerResults = mysqli_query($conn, $flowerCategoriesQry) ;
$categoriesRow = $flowerResults->fetch_assoc();
$resultsArray = explode(";", $categoriesRow['categories']);
/**All Occassions **/
$query544="SELECT name FROM tbl_categories";
$results544 = mysqli_query($conn, $query544);
while ($row = $results544->fetch_assoc()) { ?>
<label class="checkbox" for="checkboxes">
<?php
if(in_array($row['name'],$resultsArray ))
{
?>
<input type="checkbox" name="edit_categories[]" value="<?php echo $row['name'];?>" checked> <?php echo $row['name'];?>
<?php
}
else{
?>
<input type="checkbox" name="edit_categories[]" value="<?php echo $row['name'];?>" ><?php echo $row['name']; } ?>
</label>
<?php
}
?>
</div>
click here for code

Only 1 checkbox can be checked? PHP

I'm having an issue with checkboxes. I can check both checkboxes, but after submitting, only 1 checkbox is checked. I want them to both be checked after submitting.
Why are they not both checked after submit? What's going wrong in the process?
<?php
$id = $_GET["id"];
$stmt = $dbConnection->prepare('SELECT * FROM paginas WHERE id = ?');
$stmt->bind_param('s', $id);
$stmt->execute();
$result = $stmt->get_result();
if(mysqli_num_rows($result) > 0) {
while ($row = $result->fetch_assoc()) {
?>
Terugkeren naar mijn pagina's
<h1>Wijzig pagina: <?php echo $row["name"]; ?></h1>
<?php
if(isset($_POST["opslaan"])) {
if(empty($_POST["heading"])) {
echo '<p class="error">Titel kan niet leeg zijn</p>';
} elseif(empty($_POST["content"])) {
echo '<p class="error">Content kan niet leeg zijn</p>';
} else {
$heading = $_POST["heading"];
$content = $_POST["content"];
$updated = date("d-m-Y H:i:s");
$id = $row["id"];
$public = $_POST["public"];
$menu = $_POST["menu"];
$stmt = $dbConnection->prepare('UPDATE paginas SET heading = ?, content = ?, updated = ?, public = ?, menu = ? WHERE id = ?');
$stmt->bind_param('ssssss', $heading, $content, $updated, $public, $menu, $id);
$stmt->execute();
echo '<p class="success">Wijzigingen zijn succesvol opgeslagen. Bekijken</p>';
}
} else {
?>
<form method="POST" action="">
<input type="text" name="heading" id="fulltext" placeholder="Titel" value="<?php echo $row["heading"]; ?>">
<textarea id="fullbox" class="editor" name="content"><?php echo $row["content"]; ?></textarea>
<div class="pad"><input type="checkbox" name="public" id="public" value="<?php
if($row["public"] == "1") {
echo '0';
} else {
echo '1';
}
?>" <?php
if($row["public"] == "1") {
echo ' checked';
} else {
echo '';
}
?>><label for="public" class="checker">Gepubliceerd</label><input type="checkbox" name="menu" id="menu" value="<?php
if($row["menu"] == "1") {
echo '0';
} else {
echo '1';
}
?>" <?php
if($row["menu"] == "1") {
echo ' checked';
} else {
echo '';
}
?>><label for="menu" class="checker">Menu</label></div>
<div class="clear"></div>
<p id="left">Laatst gewijzigd: <?php echo $row["updated"]; ?></p><input type="submit" value="Bewaar wijzigingen" name="opslaan" class="nomp">
<div class="clear"></div>
</form>
<?php
}
}
} else {
echo '<p>Deze pagina bestaat niet.</p>';
}
?>
The value of the checkbox should always be 1 instead of the condition you have there, and when preparing to put it in the database you should do:
$public = isset($_POST['public']) ? 1 : 0;
Otherwise, you will be submitting the value 0 every other time, which will turn the value off even if you checked the box.
In addition to Niet the Dark Absol's answer above you should create dynamic names for each element or use name="public[] to capture all selected values.
You must set your input name with [] after the name. like check_list[].
For example:
<form action="test.php" method="post">
<input type="checkbox" name="check_list[]" value="value 1">
<input type="checkbox" name="check_list[]" value="value 2">
<input type="checkbox" name="check_list[]" value="value 3">
<input type="checkbox" name="check_list[]" value="value 4">
<input type="checkbox" name="check_list[]" value="value 5">
<input type="submit" />
</form>
<?php
if(!empty($_POST['check_list'])) {
foreach($_POST['check_list'] as $check) {
echo $check; //echoes the value set in the HTML form for each checked checkbox.
//so, if I were to check 1, 3, and 5 it would echo value 1, value 3, value 5.
//in your case, it would echo whatever $row['Report ID'] is equivalent to.
}
}
?>

How to Edit a MySQL Data base from a PHP Site

I have built a database named "artStore" and a table within that database named "inventory". I've been able to figure out how to create a new entry to the database, but I'm trying to create a page that can edit those entries.
Here is "inventory" the table I created:
$sql = "CREATE TABLE inventory (
id INT(6) AUTO_INCREMENT PRIMARY KEY,
product VARCHAR(30),
category VARCHAR(30),
seller VARCHAR(30)
)";
Here is what I'm currently trying:
<?php
$resultProduct = "product";
$resultCategory = "category";
$resultSeller = "seller";
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$resultProduct = $row["product"];
$resultCategory = $row["category"];
$resultSeller = $row["seller"];
}
} else {
echo "No Results";
}
?>
<form action="update.php" method="POST">
<label for="product">Product</label>
<input id="product" type="text" name="product" value="<?php echo $resultProduct; ?>">
<br>
<label for="category">Category:</label>
<input id="category" type="text" name="category" value="<?php echo $resultCategory; ?>">
<br>
<label for="seller">Seller:</label>
<input id="seller" type="text" name="seller" value="<?php echo $resultSeller; ?>">
<br>
<input id="id" type="text" name="id" value="<?php echo $resultId; ?>" style="display:none;">
<input type="submit" value="Update My Record">
</form>
What I'm trying in update.php
$product = $_POST['product'];
$category = $_POST['category'];
$seller = $_POST['seller'];
$sql = "INSERT INTO inventory (product, category, seller) VALUES ('$product', '$category', '$seller')";
if ($connection->query($sql) === true) {
echo "Inserted Successfully";
} else {
echo "Error occured in the insert: " . $connection->error;
}
$connection->close();
Try the below code I added hidden field on form and changes on your sql query
<?php
$resultProduct = "product";
$resultCategory = "category";
$resultSeller = "seller";
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$resultProduct = $row["product"];
$resultCategory = $row["category"];
$resultSeller = $row["seller"];
$resultId = $row["id"];
}
} else {
echo "No Results";
}
?>
<form action="update.php" method="POST">
<input type="text" name="update_id" value="<?php echo $resultId; ?>">
<label for="product">Product</label>
<input id="product" type="text" name="product" value="<?php echo $resultProduct; ?>">
<br>
<label for="category">Category:</label>
<input id="category" type="text" name="category" value="<?php echo $resultCategory; ?>">
<br>
<label for="seller">Seller:</label>
<input id="seller" type="text" name="seller" value="<?php echo $resultSeller; ?>">
<br>
<input id="id" type="text" name="id" value="<?php echo $resultId; ?>" style="display:none;">
<input type="submit" value="Update My Record">
</form>
In update.php
$product = $_POST['product'];
$category = $_POST['category'];
$seller = $_POST['seller'];
$updateId = $_POST['update_id'];
$sql = "UPDATE inventory set product = '$product',category='$category',seller='$seller' WHERE id = '$updateId'";
<?php
$resultProduct = "product";
$resultCategory = "category";
$resultSeller = "seller";
$resultId = "product_id";
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
$resultProduct = $row["product"];
$resultCategory = $row["category"];
$resultSeller = $row["seller"];
$resultid = $row["id"];
}
} else {
echo "No Results";
}
?>
You were using $resultId in the form but you have not declared and assigned a value to it in the loop.
<form action="update.php" method="POST">
<input id="id" type="hidden" name="id" value="<?php echo $resultId; ?>">
<label for="product">Product</label>
<input id="product" type="text" name="product" value="<?php echo $resultProduct; ?>">
<br>
<label for="category">Category:</label>
<input id="category" type="text" name="category" value="<?php echo $resultCategory; ?>">
<br>
<label for="seller">Seller:</label>
<input id="seller" type="text" name="seller" value="<?php echo $resultSeller; ?>">
<br>
<input type="submit" value="Update My Record">
</form>
<!-- Instead of passing the ID in textbox with display: none you can pass it directly in hidden -->
<?php
$product = $_POST['product'];
$category = $_POST['category'];
$seller = $_POST['seller'];
$product_id = $_POST['id'];
if($product_id!='')//MEANS WE HAVE TO UPDATE THE RECORD
{
// UPDATE QUERY WILL UPDATE THE SAME RECORD ONLY MATCHING THE UNIQUE PRODUCT ID
$sql = "UPDATE inventory SET product = '$product', category = '$category', seller = '$seller' WHERE id = '$product_id' LIMIT 1";
if ($connection->query($sql) === true) {
echo "Updated Successfully";
} else {
echo "Error occured in the insert: " . $connection->error;
}
}
else// If id is blank it means you have a new record
{
$sql = "INSERT INTO inventory (product, category, seller) VALUES ('$product', '$category', '$seller')";
if ($connection->query($sql) === true) {
echo "Inserted Successfully";
} else {
echo "Error occured in the insert: " . $connection->error;
}
}
$connection->close();
?>

Checking checkboxes from database values

I post values from check boxes into a database for a user profile. When the user goes to edit his/her profile I want the checkboxes that they selected previously to be checked so they don't lose that info after updating their profile. I have tried many different solutions but with no luck.
The check box values get entered into table name members_teachers into a column called focus and are seperated by a comma for example art,mathematics,dance etc I am not sure how close or far I am away at accomplishing my goal but I greatly appreicate any help or suggestions you can provide. Thank you very much in advance
My code to try and check the values is
<?php
$focusQuery = mysql_query("SELECT focus FROM members_teachers WHERE id = $member_id") or die;
while ($new_row = mysql_fetch_assoc($focusQuery)){
$focusRow = $row['focus'];
$focusValue = explode(',', $focusRow);
foreach($focusValue as $newFocus){
//echo $newFocus;
//echo "<br/>";
$result = mysql_query("SELECT focus FROM members_teachers WHERE focus LIKE '%$focusRow%'") or die;
if(mysql_num_rows($result) > $newFocus){
$checked = 'checked="checked"';
}
else{
$checked = '';
}
}
}
?>
This is my html
<label for="art-focus">Art</label>
<input name="focus[]" type="checkbox" value="Art" <?php echo $checked ?>>
<label for="math-focus">Mathematics</label>
<input name="focus[]" type="checkbox" value="Mathematics" <?php echo $checked ?>>
<label for="dance-focus">Dance</label>
<input name="focus[]" type="checkbox" value="Dance" <?php echo $checked ?>>
<?php
// Create connection
$con=mysqli_connect("hostname","username","pass","dbname");
// Check connection
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT focus FROM members_teachers WHERE id = $member_id");
while($row = mysqli_fetch_array($result))
{
$focus=explode(",",$row['focus']);
?>
<input type="checkbox" name="focus[]" value="Art" <?php if(in_array("Art",$focus)) { ?> checked="checked" <?php } ?> >
<input type="checkbox" name="focus[]" value="Mathematics" <?php if(in_array("Mathematics",$focus)) { ?> checked="checked" <?php } ?> >
<input type="checkbox" name="focus[]" value="Dance" <?php if(in_array("Dance",$focus)) { ?> checked="checked" <?php } ?> >
<?php
}
?>
<?php
$focusedValues = array();
$focusQuery = mysql_query("SELECT focus FROM members_teachers WHERE id = $member_id") or die;
while ($row = mysql_fetch_assoc($focusQuery)){
$focusedValues = explode(',', $row['focus']);
}
?>
<label for="art-focus">Art</label>
<input name="focus[]" type="checkbox" value="Art" <?php echo in_array('Art', $checked) ?>>
<label for="math-focus">Mathematics</label>
<input name="focus[]" type="checkbox" value="Mathematics" <?php echo in_array('Mathematics', $checked) ?>
<label for="dance-focus">Dance</label>
<input name="focus[]" type="checkbox" value="Dance" <?php echo in_array('Dance', $checked) ?>
I don't know why you were SELECTing for the second time, that's pointless, you already know what's checked because it's in $focusedValues. Also, in your code, $checked would be empty if nothing was checked and checked="checked" otherwise. You obviously need a variable for each input, no?
<?php $hobby = $row['hobbies'];
$hobbies = explode (' ', $hobby);
?>
<input type="checkbox" name="hobbies[]" value="cricket" <?php echo in_array('cricket', $hobbies?'checked':'') ?> >cricket
<input type="checkbox" name="hobbies[]" value="singing" <?php echo in_array('singing' , $hobbies ?'checked': '') ; ?> >singing
<input type="checkbox" name="hobbies[]" value="football" <?php echo in_array('football', $hobbies ?'checked': '') ; ?> >footballl

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