Only 1 checkbox can be checked? PHP - php

Question

I'm having an issue with checkboxes. I can check both checkboxes, but after submitting, only 1 checkbox is checked. I want them to both be checked after submitting.
Why are they not both checked after submit? What's going wrong in the process?
<?php
$id = $_GET["id"];
$stmt = $dbConnection->prepare('SELECT * FROM paginas WHERE id = ?');
$stmt->bind_param('s', $id);
$stmt->execute();
$result = $stmt->get_result();
if(mysqli_num_rows($result) > 0) {
while ($row = $result->fetch_assoc()) {
?>
Terugkeren naar mijn pagina's
<h1>Wijzig pagina: <?php echo $row["name"]; ?></h1>
<?php
if(isset($_POST["opslaan"])) {
if(empty($_POST["heading"])) {
echo '<p class="error">Titel kan niet leeg zijn</p>';
} elseif(empty($_POST["content"])) {
echo '<p class="error">Content kan niet leeg zijn</p>';
} else {
$heading = $_POST["heading"];
$content = $_POST["content"];
$updated = date("d-m-Y H:i:s");
$id = $row["id"];
$public = $_POST["public"];
$menu = $_POST["menu"];
$stmt = $dbConnection->prepare('UPDATE paginas SET heading = ?, content = ?, updated = ?, public = ?, menu = ? WHERE id = ?');
$stmt->bind_param('ssssss', $heading, $content, $updated, $public, $menu, $id);
$stmt->execute();
echo '<p class="success">Wijzigingen zijn succesvol opgeslagen. Bekijken</p>';
}
} else {
?>
<form method="POST" action="">
<input type="text" name="heading" id="fulltext" placeholder="Titel" value="<?php echo $row["heading"]; ?>">
<textarea id="fullbox" class="editor" name="content"><?php echo $row["content"]; ?></textarea>
<div class="pad"><input type="checkbox" name="public" id="public" value="<?php
if($row["public"] == "1") {
echo '0';
} else {
echo '1';
}
?>" <?php
if($row["public"] == "1") {
echo ' checked';
} else {
echo '';
}
?>><label for="public" class="checker">Gepubliceerd</label><input type="checkbox" name="menu" id="menu" value="<?php
if($row["menu"] == "1") {
echo '0';
} else {
echo '1';
}
?>" <?php
if($row["menu"] == "1") {
echo ' checked';
} else {
echo '';
}
?>><label for="menu" class="checker">Menu</label></div>
<div class="clear"></div>
<p id="left">Laatst gewijzigd: <?php echo $row["updated"]; ?></p><input type="submit" value="Bewaar wijzigingen" name="opslaan" class="nomp">
<div class="clear"></div>
</form>
<?php
}
}
} else {
echo '<p>Deze pagina bestaat niet.</p>';
}
?>

Answer 1

The value of the checkbox should always be 1 instead of the condition you have there, and when preparing to put it in the database you should do:
$public = isset($_POST['public']) ? 1 : 0;
Otherwise, you will be submitting the value 0 every other time, which will turn the value off even if you checked the box.

Answer 2

In addition to Niet the Dark Absol's answer above you should create dynamic names for each element or use name="public[] to capture all selected values.

Answer 3

You must set your input name with [] after the name. like check_list[].
For example:
<form action="test.php" method="post">
<input type="checkbox" name="check_list[]" value="value 1">
<input type="checkbox" name="check_list[]" value="value 2">
<input type="checkbox" name="check_list[]" value="value 3">
<input type="checkbox" name="check_list[]" value="value 4">
<input type="checkbox" name="check_list[]" value="value 5">
<input type="submit" />
</form>
<?php
if(!empty($_POST['check_list'])) {
foreach($_POST['check_list'] as $check) {
echo $check; //echoes the value set in the HTML form for each checked checkbox.
//so, if I were to check 1, 3, and 5 it would echo value 1, value 3, value 5.
//in your case, it would echo whatever $row['Report ID'] is equivalent to.
}
}
?>