if statement is equal to a value - php

I have a result(string) of 1,1,0,0 - These come from $sub_array['state']
Currently all of my check boxes are checked. How can I code the code below so that if its 1 its checked else its not? as the current code gives them all 'checked'
<?php
foreach($assoc_categories as $sub_array)
{
if($sub_array['state'] == 1)
{
$checked_state = " checked='checked'";
}
?>
<div>
<input
class="checkbox"
type="checkbox"
name="product_category"
class="product_category_selector"
id="product_category_<?php echo $sub_array['cat_id']; ?>"
data-id="<?php echo $sub_array['cat_id']; ?>"
<?php echo $checked_state; ?>
/>
<?php echo $sub_array['name']; ?>
</div>
<input
class="order"
type="input"
value="<?php echo $sub_array['sorder']; ?>"
/>
<?php
}
?>

Change:
if($sub_array['state'] == 1)
{
$checked_state = " checked='checked'";
}
To:
if($sub_array['state'] == 1)
{
$checked_state = " checked='checked'";
} else
{
$checked_state = "";
}
Basically, you are not clearing the previous value as the loop continues.
Alternatively, you could use:
$checked_state = ($sub_array['state'] == 1) ? " checked='checked'" : "" ;

You forget to reset checked_state or reset it to '' if $sub_array['state'] is equal to 0.
<?php
$assoc_categories = array(
array('state'=>1, 'cat_id'=>1, 'name'=>'one', 'sorder'=>1),
array('state'=>1, 'cat_id'=>2, 'name'=>'three', 'sorder'=>2),
array('state'=>0, 'cat_id'=>3, 'name'=>'four', 'sorder'=>3),
array('state'=>0, 'cat_id'=>4, 'name'=>'five', 'sorder'=>4),
);
foreach($assoc_categories as $sub_array)
{
$checked_state = $sub_array['state'] == 1 ? " checked='checked'" : '';
?>
<div>
<input
class="checkbox"
type="checkbox"
name="product_category"
class="product_category_selector"
id="product_category_<?php echo $sub_array['cat_id']; ?>"
data-id="<?php echo $sub_array['cat_id']; ?>"
<?php echo $checked_state; ?>
/>
<?php echo $sub_array['name']; ?>
</div>
<input
class="order"
type="input"
value="<?php echo $sub_array['sorder']; ?>"
/>
<?php
}

Related

For loop display radio buttons with first one checked

I have a for loop that displays radio buttons and I want the first one to display as checked. But when I put a if statement inside the for loop for this the page nevers loads. Any ideas?
$mains = array(0=>'Beef Steak', 1=>'Chicken Breast', 2=>'Pork Chops');
$mainscount = count($mains);
<?php for ($mainNO = 0; $mainNO < $mainscount; $mainNO++) { ?>
<label for="mains<?php echo $mainNO ?>" class="radiobutton"><?php echo $mains[$mainNO]; ?></label>
<input type="radio" name="mains" id="mains<?php echo $mainNO; ?>" value="<?php echo $mainNO; ?>"
<?php if($mainNO = 0){ echo 'checked="checked"'; } ?>/>
<?php } ?>
<?php for ($mainNO = 0; $mainNO < $mainscount; $mainNO++) { ?>
<label for="mains<?php echo $mainNO ?>" class="radiobutton"><?php echo $mains[$mainNO]; ?></label>
<input type="radio" name="mains" id="mains<?php echo $mainNO; ?>" value="<?php echo $mainNO; ?>"
<?php if ($mainNO == 0) {
echo ' checked="checked" ';
} ?>/>
<?php } ?>
you use = where you should use ==
u are using assingment operator in comparision statement
<?php for ($mainNO = 0; $mainNO < $mainscount; $mainNO++) { ?>
<label for="mains<?php echo $mainNO ?>" class="radiobutton"><?php echo $mains[$mainNO]; ?></label>
<input type="radio" name="mains" id="mains<?php echo $mainNO; ?>" value="<?php echo $mainNO; ?>"
<?php if ($mainNO == 0) {
echo " checked";
} ?>/>
and in HTML5 you can use checked only
<input type="checkbox" checked>
// Note: You used single = in if condition that is wrong, it will create indefinite loop . Tested code.
$mains = array(0=>'Beef Steak', 1=>'Chicken Breast', 2=>'Pork Chops');
$mainscount = count($mains);
for ($mainNO = 0; $mainNO < $mainscount; $mainNO++) {
// Checked if value is 0
if($mainNO == 0){ $checked = 'checked="checked"'; }else { $checked =''; };
echo "<label for='mains".$mainNO."' class='radiobutton'>".$mains[$mainNO]."</label>";
echo "<input type='radio' name='mains' id='mains".$mainNO."' value='".$mainNO."' $checked />";
}

How to retrieve checkbox value from database in php?

this is my code
<tr><td valign="top">Sebab Kekosongan</td>
<?php
$QQQ = "SELECT sbbKekosongan FROM infojawatan WHERE ID = '$ID'";
$rs_QQQ = mysql_query($QQQ);
while($row_QQQ = mysql_fetch_array($rs_QQQ))
{
$kerana = explode(",", $row_QQQ['kerana']); ?>
<td>
<input type="checkbox" name="kerana[]" value="retire" <?php if(in_array("retire",$kerana)) echo 'checked="checked"' ?>> Bersara
> Meninggal Dunia
## continue coding ##
> Bertukar
<input type="checkbox" name="kerana[]" value="promote" <?php if(in_array("promote",$kerana)) echo 'checked="checked"' ?>> Naik Pangkat
<input type="checkbox" name="kerana[]" value="others" <?php if(in_array("others",$kerana)) echo 'checked="checked"' ?>> Lain -lain
</td> <?php } ?> </tr>
my second test code
<tr><td valign="top">Sebab Kekosongan</td><td>
<?php
$keranaS = array('retire', 'death', 'change', 'promote', 'others');
if(! empty($keranaS))
{
foreach ($keranaS as $myKerana)
{
$checked = (in_array($myKerana, $kerana)) ? 'checked="checked"' : ''; ?>
<input type="checkbox" name="kerana[]" value="<?php echo $myKerana; ?>" <?php echo $checked; ?>> <?php echo $myKerana;?>
<?php } ?>
</td>
<?php } ?>
</tr>
i have tried both., but its not working
# Please Try again below code.. #
<tr><td valign="top">Sebab Kekosongan</td><td>
<?php
$keranaS = array('retire', 'death', 'change', 'promote', 'others');
//echo '<pre>'; print_r($keranaS); exit;
if(!empty($keranaS))
{
foreach ($keranaS as $myKerana)
{
$checked = (in_array($myKerana, $keranaS)) ? 'checked="checked"' : ''; ?>
<input type="checkbox" name="kerana[]" value="<?php echo $myKerana; ?>" <?php echo $checked; ?>> <?php echo $myKerana;?>
<?php } ?>
</td>
<?php } ?>
</tr>
# Please try again below dynamic through checkbox checked.
<tr><td valign="top">Sebab Kekosongan</td><td>
<?php
$keranaS = array('retire', 'death', 'change', 'promote', 'others');
//$kerana_data data databse though fetch
$kerana_data = array('retire', 'change', 'others');
if(!empty($keranaS))
{
$i = 0;
foreach ($keranaS as $myKerana)
{
if(in_array($myKerana, $kerana_data)){
$checked = (in_array($myKerana, $kerana_data)) ? 'checked="checked"' : ''; ?>
<input type="checkbox" name="kerana[]" value="<?php echo $myKerana; ?>" <?php echo $checked; ?>> <?php echo $myKerana;?>
<?php }else{?>
<input type="checkbox" name="kerana[]" value="<?php echo $myKerana; ?>"> <?php echo $myKerana;?>
<?php }?>
<?php $i++;
} ?>
</td>
<?php } ?>
</tr>

Checkboxes Do Not Get Processed Even Without Pagination

I'm aware that with pagination, if a checkbox is clicked and you move onto another page, that checked checkbox is no longer recognized, so I made my php pull depending on a category chosen by the user, and each row spits out in a w3css w3-third div:
while($rowtbl = mysqli_fetch_array($resulttbl)) {
?>
<div id="parent">
<div class="<?php echo $rowtbl['brand']?>">
<section class="allitems">
<div class="w3-third w3-margin-bottom" id="itemsToFilter" data-type="<?php echo $rowtbl['brand']?>">
<ul class="w3-ul w3-border w3-center w3-hover-shadow" >
<li class="w3-padding-16 w3-green">Desc: <b><?php echo htmlspecialchars($rowtbl['description']) ?></b>
<input type="hidden" name="descriptionid<?php echo $i; ?>" value="<?php echo $rowtbl['description']; ?>" /></li>
<li class="w3-padding-4">Brand: <b><?php echo htmlspecialchars($rowtbl['brand']) ?></b>
<input type="hidden" name="brandid<?php echo $i; ?>" value="<?php echo $rowtbl['brand']; ?>" /></li>
<li class="w3-padding-4">Category: <b><?php echo htmlspecialchars($rowtbl['category']) ?></b>
<input type="hidden" name="categoryid<?php echo $i; ?>" value="<?php echo $rowtbl['category']; ?>" /></li>
<li class="w3-padding-4">Item#: <b><?php echo htmlspecialchars($rowtbl['itemNu']) ?></b>
<input type="hidden" name="itemid<?php echo $i; ?>" value="<?php echo $rowtbl['itemNu']; ?>" /></li>
<li class="w3-padding-2">Pack Size: <b><?php echo htmlspecialchars($rowtbl['packsz']) ?></b>
<input type="hidden" name="packszid<?php echo $i; ?>" value="<?php echo $rowtbl['packsz']; ?>" /></li>
<?php if ($rowtbl['bc'] == "Y") { ?>
<li class="w3-padding-10">Broken Cs: <b><input type="checkbox" value="checkedup" name="bcase<?php echo $i; ?>" /></b></li>
<?php }
else { ?>
<li class="w3-padding-10">Broken Cs: <b><input type="checkbox" value="notcheckedup" name="bcase<?php echo $i; ?>" disabled /></b></li>
<?
}
?>
<li><input type="checkbox" name="checkbox<?php echo $i; ?>" /></li>
<input type="hidden" name="roses" id="roses" value="<?php echo $i; ?>" />
<input type="hidden" name="filler<?php echo $i; ?>" id="filler" />
</ul>
</div>
</section>
</div>
</div>
<?php $i++; //increment counter variable
} ?>
Everything is fine in regards to adding any item(s) to the db, until I get to any div passed 142. After that, when i click add, the page refreshes as if it was processed, but nothing gets added to the db.
What am I doing wrong?
Thanks in advance!
Edit: showing the php that adds items to the db:
<?php
if(isset($_POST['submitnew'])){
for ($i=1;$i<=$_POST['roses'];$i++)
{
if(isset($_POST['checkbox'.$i]))
{
$custnum = $_SESSION['customerNumber'];
$category = $_POST['categoryid'.$i];
$brand = $_POST['brandid'.$i];
$description = $_POST['descriptionid'.$i];
$pksz = $_POST['packszid'.$i];
$itemnum = $_POST['itemid'.$i];
if($_POST['bcase'.$i] == "notcheckedup")
{
$bcc = "n";
$eaa = 0;
} elseif ($_POST['bcase'.$i] == "checkedup" && isset($_POST['bcase'.$i]))
{ $bcc = "y";
$eaa = 1;
} else
{
$bcc = "y";
$eaa = 0;
};
$ordNew = "INSERT INTO `abc123` (`CustNo`,`category`, `brand`, `description`, `pksz`, `ea`, `itemNu`, `bc`) values('$custnum', '$category', '$brand', '$description', '$pksz', '$eaa', '$itemnum', '$bcc')";
mysqli_query($link, $ordNew);
}
header("Location: index.php");
}
}
?>

Passing checkbox values into an array?

I have set up a group of checkboxes. They are dynamic, so the number of checkboxes will be different dependent on the person using the site. The structure of how the checkboxes are created is:
<label for="plabackformat-holder-label">Format</label>
<div class=" playbackformat-holder-<?php echo $num; ?> playbackformat-holder">
<div class="playback-format-radio-buttons">
<label for="notset-<?php echo $num; ?>">
<input type="checkbox" class="playbackformat-holder-radiobutton" value="notset" name="playback_format[<?php echo $second_num; ?>]" id="notset-<?php echo $num; ?>" <?php if($field['playback_format'] == 'notset') { echo 'checked'; } ?>>None
</label>
<label for="dvd-<?php echo $num; ?>">
<input type="checkbox" class="playbackformat-holder-radiobutton" value="dvd" name="playback_format[<?php echo $second_num; ?>]" id="dvd-<?php echo $num; ?>" <?php if($field['playback_format'] == 'dvd') { echo 'checked'; } ?>>DVD
</label>
<label for="bluray-<?php echo $num; ?>">
<input type="checkbox" class="playbackformat-holder-radiobutton" value="bluray" name="playback_format[<?php echo $second_num; ?>]" id="bluray-<?php echo $num; ?>" <?php if($field['playback_format'] == 'bluray') { echo 'checked'; } ?>>Bluray
</label>
<label for="3d-<?php echo $num; ?>">
<input type="checkbox" class="playbackformat-holder-radiobutton" value="3d" name="playback_format[<?php echo $second_num; ?>]" id="3d-<?php echo $num; ?>" <?php if($field['playback_format'] == '3d') { echo 'checked'; } ?>>3d
</label><br />
</div>
</div>
My save function is:
$new = array();
for ( $i = 0; $i < $count; $i++ ) {
$new[$i]['playback_format'] = $playbackFormats[$i];
}
I've been reading up on this issue and it seems its because my input fields do not contain unique names. I'm trying to store the data into an array, so it would be ['playback_format'] => dvd,3d,bluray or something similar.
Right now its only storing the last checked value. Is there a way I can use a forloop or something to iterate over the checked values and push them into my array??
You can just get rid of the "$second_num" in each <input name="playback_format[]"/> html tag. This will put everything into an array for you once you submit the form. You can check this by adding this line to the page as a test.
<?php print_r($_REQUEST['playback_format']); ?>
Generally, You want to avoid any loop if they aren't required.
Hope that helps with what you are doing.
What is $second_num? Does it need to be a part of the input name?
You can get PHP to recognise the submitted values as an array if you do it this way:
<input name="playback_format[<?php echo $second_num; ?>][]">
Or if you don't need $second_num as part of the name, just:
<input name="playback_format[]">
$_POST['playback_format'] will then be an array containing all the selected options.
There is a section in the PHP docs specifically about this behaviour.
Checkboxes have all the same name in your example. Name it differently like :
<label for="plabackformat-holder-label">Format</label>
<div class=" playbackformat-holder-<?php echo $num; ?> playbackformat-holder">
<div class="playback-format-radio-buttons">
<label for="notset-<?php echo $num; ?>">
<input type="checkbox" class="playbackformat-holder-radiobutton" value="notset" name="playback_format_notset" id="notset-<?php echo $num; ?>" <?php if($field['playback_format_notset'] == 'notset') { echo 'checked'; } ?>>None
</label>
<label for="dvd-<?php echo $num; ?>">
<input type="checkbox" class="playbackformat-holder-radiobutton" value="dvd" name="playback_format_dvd" id="dvd-<?php echo $num; ?>" <?php if($field['playback_format_dvd'] == 'dvd') { echo 'checked'; } ?>>DVD
</label>
<label for="bluray-<?php echo $num; ?>">
<input type="checkbox" class="playbackformat-holder-radiobutton" value="bluray" name="playback_format_bluray" id="bluray-<?php echo $num; ?>" <?php if($field['playback_format_bluray'] == 'bluray') { echo 'checked'; } ?>>Bluray
</label>
<label for="3d-<?php echo $num; ?>">
<input type="checkbox" class="playbackformat-holder-radiobutton" value="3d" name="playback_format_3d" id="3d-<?php echo $num; ?>" <?php if($field['playback_format_3d'] == '3d') { echo 'checked'; } ?>>3d
</label><br />
</div>
</div>
And Try this in PHP :
//WHen you want to see what is send in Post :
var_dump($_POST);
//So, for get result :
$tab = array();
foreach($_POST as $key =>$value){
$tab[$key] = $value;
//Display it
echo $key . "=" . $value;
}

Dynamically Generated Radio button form when submitted does not display data

I am trying to create a quiz with PHP/Mysql...
I have created a form with radio buttons for answers which displays data pulled from the database as values for the radio buttons. I tried to submit the form but the result page does not show anything.
My quiz code goes as follows:
<form method="post" action="insertscore.php" name="cssCheckbox" id = "cssCheckbox">
<?php $query = "SELECT * FROM questions WHERE (`topics` = '.NET' OR `topics` = 'PHP') ORDER BY Rand() LIMIT 5"; $result = mysql_query($query);
if ($result && mysql_num_rows($result)) {
$numrows = mysql_num_rows($result);
$count =1;
while ($row = mysql_fetch_array($result))
{
?>
<div class="group">
<input type="hidden" name="<?php echo $row['key_id']; ?>"><?php $row['key_id']; ?></input>
<span class="test_question"><strong><?php echo $count;?>) <?php echo $row['question']; ?>
</strong><br />
<?php if($row['answer1'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer1']; ?>" id="chkLimit_1" ></input>
<label for="chkLimit_1" ><?php echo $row['answer1']; echo "<br />"; } else {} ?></label>
<?php if($row['answer2'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer2']; ?>" id="chkLimit_2" ></input>
<label for="chkLimit_2" ><?php echo $row['answer2']; echo "<br />"; } else {} ?></label>
<?php if($row['answer3'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer3']; ?>" id="chkLimit_3" ></input>
<label for="chkLimit_3" ><?php echo $row['answer3']; echo "<br />"; } else {} ?></label>
<?php if($row['answer4'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer4']; ?>" id="chkLimit_4" ></input>
<label for="chkLimit_4" ><?php echo $row['answer4']; echo "<br />"; } else {} ?></label>
<?php if($row['answer5'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer5']; ?>" id="chkLimit_5" ></input>
<label for="chkLimit_5" ><?php echo $row['answer5']; echo "<br />"; } else {} ? ></label>
<?php if($row['answer6'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer6']; ?>" id="chkLimit_6" ></input>
<label for="chkLimit_6" ><?php echo $row['answer6']; echo "<br />"; } else {} ?></label>
<?php if($row['answer7'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer7']; ?>" id="chkLimit_7" ></input>
<label for="chkLimit_7" ><?php echo $row['answer7']; echo "<br />"; } else {} ?></label>
<?php if($row['answer8'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer8']; ?>" id="chkLimit_8" ></input>
<label for="chkLimit_8" ><?php echo $row['answer8']; echo "<br />"; } else {} ?></label>
<input type="hidden" name="<?php echo $row['right_answer']; ?>"><?php $row['right_answer']; ?></input>
</div>
<input name="Submit" type="submit" value="Submit Your Answers" class="submit">
</form>
Code on submitted Page looks like:
<?php
if(isset($_POST['Submit'])){
$key_id=$_POST['key_id']; echo $key_id;
$question=$_POST['question']; echo $question;
$answers=$_POST['answers']; echo $answers;
$correctanswer=$_POST['correctanswer']; echo $correctanswer;
}
foreach($_POST as $key => $val)
{
echo "$key --> $val<br />";
}
//var_dump($_POST);
?>
Please let me know if anything is not clear or if I am missing anything....
Thanks,
Shank
I would:
remove comments to //var_dump($_POST); and move this line at the top of the code on submitted Page.
if you still don't see anything, I think the code on submitted page is not in a file called insertscore.php or such file is not in same folder of your form page.

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