I am trying to create a quiz with PHP/Mysql...
I have created a form with radio buttons for answers which displays data pulled from the database as values for the radio buttons. I tried to submit the form but the result page does not show anything.
My quiz code goes as follows:
<form method="post" action="insertscore.php" name="cssCheckbox" id = "cssCheckbox">
<?php $query = "SELECT * FROM questions WHERE (`topics` = '.NET' OR `topics` = 'PHP') ORDER BY Rand() LIMIT 5"; $result = mysql_query($query);
if ($result && mysql_num_rows($result)) {
$numrows = mysql_num_rows($result);
$count =1;
while ($row = mysql_fetch_array($result))
{
?>
<div class="group">
<input type="hidden" name="<?php echo $row['key_id']; ?>"><?php $row['key_id']; ?></input>
<span class="test_question"><strong><?php echo $count;?>) <?php echo $row['question']; ?>
</strong><br />
<?php if($row['answer1'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer1']; ?>" id="chkLimit_1" ></input>
<label for="chkLimit_1" ><?php echo $row['answer1']; echo "<br />"; } else {} ?></label>
<?php if($row['answer2'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer2']; ?>" id="chkLimit_2" ></input>
<label for="chkLimit_2" ><?php echo $row['answer2']; echo "<br />"; } else {} ?></label>
<?php if($row['answer3'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer3']; ?>" id="chkLimit_3" ></input>
<label for="chkLimit_3" ><?php echo $row['answer3']; echo "<br />"; } else {} ?></label>
<?php if($row['answer4'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer4']; ?>" id="chkLimit_4" ></input>
<label for="chkLimit_4" ><?php echo $row['answer4']; echo "<br />"; } else {} ?></label>
<?php if($row['answer5'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer5']; ?>" id="chkLimit_5" ></input>
<label for="chkLimit_5" ><?php echo $row['answer5']; echo "<br />"; } else {} ? ></label>
<?php if($row['answer6'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer6']; ?>" id="chkLimit_6" ></input>
<label for="chkLimit_6" ><?php echo $row['answer6']; echo "<br />"; } else {} ?></label>
<?php if($row['answer7'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer7']; ?>" id="chkLimit_7" ></input>
<label for="chkLimit_7" ><?php echo $row['answer7']; echo "<br />"; } else {} ?></label>
<?php if($row['answer8'] != NULL){ ?>
<input type = "radio" name="answers" value="<?php echo $row['answer8']; ?>" id="chkLimit_8" ></input>
<label for="chkLimit_8" ><?php echo $row['answer8']; echo "<br />"; } else {} ?></label>
<input type="hidden" name="<?php echo $row['right_answer']; ?>"><?php $row['right_answer']; ?></input>
</div>
<input name="Submit" type="submit" value="Submit Your Answers" class="submit">
</form>
Code on submitted Page looks like:
<?php
if(isset($_POST['Submit'])){
$key_id=$_POST['key_id']; echo $key_id;
$question=$_POST['question']; echo $question;
$answers=$_POST['answers']; echo $answers;
$correctanswer=$_POST['correctanswer']; echo $correctanswer;
}
foreach($_POST as $key => $val)
{
echo "$key --> $val<br />";
}
//var_dump($_POST);
?>
Please let me know if anything is not clear or if I am missing anything....
Thanks,
Shank
I would:
remove comments to //var_dump($_POST); and move this line at the top of the code on submitted Page.
if you still don't see anything, I think the code on submitted page is not in a file called insertscore.php or such file is not in same folder of your form page.
Related
I have a for loop that displays radio buttons and I want the first one to display as checked. But when I put a if statement inside the for loop for this the page nevers loads. Any ideas?
$mains = array(0=>'Beef Steak', 1=>'Chicken Breast', 2=>'Pork Chops');
$mainscount = count($mains);
<?php for ($mainNO = 0; $mainNO < $mainscount; $mainNO++) { ?>
<label for="mains<?php echo $mainNO ?>" class="radiobutton"><?php echo $mains[$mainNO]; ?></label>
<input type="radio" name="mains" id="mains<?php echo $mainNO; ?>" value="<?php echo $mainNO; ?>"
<?php if($mainNO = 0){ echo 'checked="checked"'; } ?>/>
<?php } ?>
<?php for ($mainNO = 0; $mainNO < $mainscount; $mainNO++) { ?>
<label for="mains<?php echo $mainNO ?>" class="radiobutton"><?php echo $mains[$mainNO]; ?></label>
<input type="radio" name="mains" id="mains<?php echo $mainNO; ?>" value="<?php echo $mainNO; ?>"
<?php if ($mainNO == 0) {
echo ' checked="checked" ';
} ?>/>
<?php } ?>
you use = where you should use ==
u are using assingment operator in comparision statement
<?php for ($mainNO = 0; $mainNO < $mainscount; $mainNO++) { ?>
<label for="mains<?php echo $mainNO ?>" class="radiobutton"><?php echo $mains[$mainNO]; ?></label>
<input type="radio" name="mains" id="mains<?php echo $mainNO; ?>" value="<?php echo $mainNO; ?>"
<?php if ($mainNO == 0) {
echo " checked";
} ?>/>
and in HTML5 you can use checked only
<input type="checkbox" checked>
// Note: You used single = in if condition that is wrong, it will create indefinite loop . Tested code.
$mains = array(0=>'Beef Steak', 1=>'Chicken Breast', 2=>'Pork Chops');
$mainscount = count($mains);
for ($mainNO = 0; $mainNO < $mainscount; $mainNO++) {
// Checked if value is 0
if($mainNO == 0){ $checked = 'checked="checked"'; }else { $checked =''; };
echo "<label for='mains".$mainNO."' class='radiobutton'>".$mains[$mainNO]."</label>";
echo "<input type='radio' name='mains' id='mains".$mainNO."' value='".$mainNO."' $checked />";
}
function chkQuestions($info)
{
$query = $this->handle->prepare("SELECT * FROM tbltest");
$query->execute();
$rows = $query->fetchAll();
$getPost = $query->rowCount();
foreach($rows as $row) {
for($i = 1; $i <= $getPost; $i++) {
$answerID[$i] = array($info['answer'.$i]);
$lo = array($answerID);
}
foreach($answerID as $question) {
if(array_key_exists($row['answer'],$question)) {
$test = "found";
return $test;
} else {
return $question;
}
}
}
}//chkQuestions
Above is my function, all works, but when I compare the row in my database called answer with the array it doesn't work?
I tried hard coding in the value and it works correctly but not with the array.
I checked to see the values of array and the value is indeed there.
In logic $answerID[$i] = array($info['answer'.$i]); = option1 and if the array value option1 = the database row answer which is set to option1 than return found, but it tells me it cannot find it.
array(1)
{
[0]=> string(7) "option1"
}
Above is the dum_var of the array $question. Any help?
foreach($questions as $question)
{
?>
<h3><?php echo $question['question'] ?></h3>
<div class = "col-xs-12">
<input type="radio" name="answer<?php echo $question['testID'] ?>" id="answer<?php echo $question['testID'] ?>" value="<?php echo $question['option1']?>" />
<label for="question-1-answers-A">A)<?php echo $question['option1'] ?> </label>
</div>
<div class = "col-xs-12">
<input type="radio" name="answer<?php echo $question['testID'] ?>" id="answer<?php echo $question['testID'] ?>" value="<?php echo $question['option2']?>" />
<label for="question-1-answers-B">B)<?php echo $question['option2'] ?></label>
</div>
<div class = "col-xs-12">
<input type="radio" name="answer<?php echo $question['testID'] ?>" id="answer<?php echo $question['testID'] ?>" value="<?php echo $question['option3']?>" />
<label for="question-1-answers-C">C)<?php echo $question['option3'] ?></label>
</div>
<div class = "col-xs-12">
<input type="radio" name="answer<?php echo $question['testID'] ?>" id="answer<?php echo $question['testID'] ?>" value="<?php echo $question['option4']?>" />
<label for="question-1-answers-D">D)<?php echo $question['option4'] ?></label>
<br>
<br>
</div>
<?php
}
echo "<input type='hidden' name='subaction' id='subaction' value='chkQuestion'> <button class='btn btn-primary' name='submit' type='submit'>Submit</button> </form>";
}
else
echo "No Quiz Found </form>";
?>
</div>
I don't have a lot of confidence in my answer because your coding method does a good job of confusing me. However, I feel like I need to get something on the page so we have some sort of solid base to work from:
function chkQuestions($info){
$check=array(); // this will hold the results to return
$stmt=$this->handle->prepare("SELECT `testID`,`answer` FROM tbltest");
$stmt->execute();
while($row=$stmt->fetch(PDO::FETCH_ASSOC)){
if($info['answer'][$row['testID']]==$row['answer']){
$check[$row['testID']]="correct";
}else{
$check[$row['testID']]="incorrect";
}
}
return $check; // handle this however you like on your main page
}
this is radio button code
now what if radio button does not have a constant name how would i store the data in database because to store the data in database we will need a name of form attribute
$sql1="select * from questions where email='". $_SESSION['email'] ."'";
$row=mysqli_query($conn,$sql1);
while ($result = mysqli_fetch_array($row))
{
?>
<h2 id="question_<?php echo $result['qid'];?>"><?php echo $result['qid'].".".$result['question'];?></h2>
<input type="radio" value="<?php echo $result['answer1'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer1'];?>
<input type="radio" value="<?php echo $result['answer2'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer2'];?>
<input type="radio" value="<?php echo $result['answer3'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer3'];?>
<input type="radio" value="<?php echo $result['answer4'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer4'];?>
if we know the name of radio button we can access it using
<input type="radio" value="<?php echo $result['answer4'];?>" name="name"><?php echo $result['answer4'];?>
$name=$_POST['name'];
but in the above code name of radio button is not fixed.questions is the table which consists of qid and questions with multiple options that is answer1,answer2 etc
i want to store the option select by user into database.for which i need to know the name of radio button
how should i use post in this case
$name=$_POST['what should go in here'];
You can get the radio button value along with question ID as:
Basic Example:
<?php
$array = array(1,2); // your Question ID array
?>
Your Form:
<form method="post" action="">
<?php
foreach ($array as $key => $qid) {
?>
<input type="radio" value="1" name="radio[<?=$qid?>]">
Answer 1
<input type="radio" value="2" name="radio[<?=$qid?>]">
Answer 2
<input type="radio" value="3" name="radio[<?=$qid?>]">
Answer 3
<input type="radio" value="4" name="radio[<?=$qid?>]">
Answer 4
<?php
echo "<br/>";
}
?>
<input type="submit" name="submit">
</form>
In PHP:
<?php
if(isset($_POST['submit'])) {
$query = array();
foreach ($_POST['radio'] as $key => $value) {
$query[] = "('$value','$key')";
}
$sql = "INSERT INTO table (answer,questionID) VALUES ";
$sql .= implode(",", $query);
echo $sql;
}
?>
In this example query look like:
INSERT INTO table (answer,questionID) VALUES ('2','1'),('3','2')
Few Suggestions:
- Your code is open for SQL Injection, you must need to prevent your code with SQL Attack and this reference will help you to understand: How can I prevent SQL injection in PHP?
- Make sure your column name and table name not having any conflict, currently, you are using same name for both.
Update with Your Code:
<?php
while ($result = mysqli_fetch_array($row))
{
?>
<h2 id="question_<?php echo $result['qid'];?>"><?php echo $result['qid'].".".$result['question'];?></h2>
<input type="radio" value="<?php echo $result['answer1'];?>" name="radio[<?php echo $result['qid'];?>]">
<?php echo $result['answer1'];?>
<input type="radio" value="<?php echo $result['answer2'];?>" name="radio[<?php echo $result['qid'];?>]">
<?php echo $result['answer2'];?>
<input type="radio" value="<?php echo $result['answer3'];?>" name="radio[<?php echo $result['qid'];?>]">
<?php echo $result['answer3'];?>
<input type="radio" value="<?php echo $result['answer4'];?>" name="radio[<?php echo $result['qid'];?>]">
<?php echo $result['answer4'];?>
<?
}
?>
In PHP:
<?php
if(isset($_POST['submit'])) {
$query = array();
foreach ($_POST['radio'] as $key => $value) {
$query[] = "('$value','$key')";
}
$sql = "INSERT INTO table (answer,questionID) VALUES ";
$sql .= implode(",", $query);
echo $sql; // run this query in mysqli_query()
}
?>
Few More Instructions:
- Change the table name as per your table name
- Change the column name according to your column.
- Use INSERT query at once, no need to use it inside the loop.
Create an array at the end of while loop like this :
while ($result = mysqli_fetch_array($row))
{
?>
<h2 id="question_<?php echo $result['qid'];?>"><?php echo $result['qid'].".".$result['question'];?></h2>
<input type="radio" value="<?php echo $result['answer1'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer1'];?>
<input type="radio" value="<?php echo $result['answer2'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer2'];?>
<input type="radio" value="<?php echo $result['answer3'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer3'];?>
<input type="radio" value="<?php echo $result['answer4'];?>" name="<?php echo $result['qid'];?>"><?php echo $result['answer4'];?>
<? $names[] = $result['qid'];
}
if(isset($_POST['submit'])) {
for ($i=0; $i<count($names); $i++) {
if(isset($_POST[$names[$i]]) {
$rate = $_POST[$names[$i]];
$sql ="INSERT INTO answer (answer, qid) VALUES (".$rate.", ".$names[$i] .")";
mysqli_query($con, $sql);
}
}
}
?>
i want to get the partcular text value as tittle in that field
How can i do..
<input type="text"
<?php if($name_one != '') { ?> value="<?php echo $name_one;?>" <?php echo set_value('name1'); ?>
<?php } else { ?> value="<?php echo set_value('name1'); ?>" <?php } ?>
name="act1" id="act1" title="<?php echo set_value('name1'); ?>">
You can try like this
<input type="text"
value="<?php echo (!empty($name_one)) ? $name_one : $name1 ; ?>"
Single line if condition
I'm making a site where the owner has to be able to update their events, but my update code isnt working even though im 99% sure I havent made any errors.
First the form where you press update:
<?php
$sql = "SELECT * FROM events ORDER BY id ASC";
$res = $objCon->query($sql) or die('fejl i query:'.mysqli_error($objCon));
while($row=$res->fetch_array()) {
$id = $row['id'];
echo "<div class='eventpost'>";
echo "<div class='dato'>";
echo $row['id'];
echo "</div>";
echo "<p class='overskrift'>";
echo "<a href='update.php?id=$id'>RET </a>";
echo "<a href='code_delete.php?id=$id'>SLET</a>";
echo $row['overskrift'];
echo "</p>";
echo "</div>";
}
?>
then the update form:
<form action="code_update.php" method="POST">
<label>Dato:<br>
<input type="text" name="dag" value="<?php echo $data['dag']; ?>"></label>
<label>Månede:<br>
<input type="text" name="month" value="<?php echo $data['month']; ?>"></label>
<label>Overskrift:<br>
<input type="text" name="overskrift" value="<?php echo $data['overskrift']; ?>"></label>
<label>Tekst:<br>
<input type="text" name="tekst" value="<?php echo $data['tekst']; ?>"></label>
<input type="hidden" name="id" value="<? echo $id; ?>">
<input type="submit" value="Opret">
</form>
and finally the update code
<?php
session_start();
if($_SESSION['auth'] == 2){
include('incl_db.php');
$id = $_POST['id'];
$overskrift = $_POST['overskrift'];
$dag = $_POST['dag'];
$month = $_POST['month'];
$tekst = $_POST['tekst'];
$sql = "UPDATE events SET overskrift='$overskrift', dag='$dag', month='$month', tekst='$tekst' WHERE id='$id'";
$res = $objCon->query($sql);
header('location:events.php');
}else{
header('location:index.php');
}
?>
Probably shorthand tags are disabled in your php version.So try changing this
<input type="hidden" name="id" value="<? echo $id; ?>">
to this
<input type="hidden" name="id" value="<?php echo $id; ?>">
You can check this answer for more.