Best Solution for this array - php

I am using checkboxes to query the database and I am struggling with this one, I am new to MySQL and PHP so sorry if this is simple!
Here is my code that I have...
<input type="checkbox" name="season2005" value="2005" <?php if(isset($_POST['season2005'])) echo "checked='checked'"; ?> > 2005-06
<input type="checkbox" name="season2006" value="2006" <?php if(isset($_POST['season2006'])) echo "checked='checked'"; ?> > 2006-07
<input type="checkbox" name="season2007" value="2007" <?php if(isset($_POST['season2007'])) echo "checked='checked'"; ?> > 2007-08
<input type="checkbox" name="season2008" value="2008" <?php if(isset($_POST['season2008'])) echo "checked='checked'"; ?> > 2008-09
<input type="checkbox" name="season2009" value="2009" <?php if(isset($_POST['season2009'])) echo "checked='checked'"; ?> > 2009-10
<input type="checkbox" name="season2010" value="2010" <?php if(isset($_POST['season2010'])) echo "checked='checked'"; ?> > 2010-11
<input type="checkbox" name="season2011" value="2011" <?php if(isset($_POST['season2011'])) echo "checked='checked'"; ?> > 2011-12
<input type="checkbox" name="season2012" value="2012" <?php if(isset($_POST['season2012'])) echo "checked='checked'"; ?> > 2012-13
<input type="checkbox" name="season2013" value="2013" <?php if(isset($_POST['season2013'])) echo "checked='checked'"; ?> > 2013-14
if (#$_POST['season2005'] == ""){ $season2005 = "0000"; } else { $season2005 = "2005"; }
if (#$_POST['season2006'] == ""){ $season2006 = "0000"; } else { $season2006 = "2006"; }
if (#$_POST['season2007'] == ""){ $season2007 = "0000"; } else { $season2007 = "2007"; }
if (#$_POST['season2008'] == ""){ $season2008 = "0000"; } else { $season2008 = "2008"; }
if (#$_POST['season2009'] == ""){ $season2009 = "0000"; } else { $season2009 = "2009"; }
if (#$_POST['season2010'] == ""){ $season2010 = "0000"; } else { $season2010 = "2010"; }
if (#$_POST['season2011'] == ""){ $season2011 = "0000"; } else { $season2011 = "2011"; }
if (#$_POST['season2012'] == ""){ $season2012 = "0000"; } else { $season2012 = "2012"; }
if (#$_POST['season2013'] == ""){ $season2013 = "0000"; } else { $season2013 = "2013"; }
$seasons = array($season2005,$season2006,$season2007,$season2008,$season2009,$season2010,$season2011,$season2012,$season2013);
$seasonpick = implode(",",$seasons);;
$matcharrays = array("AND season in ($seasonpick)");
At the moment all of the data is being queried to the database, so if nothing is selected them then part of query from this is "AND season in (0000,0000,0000,0000) etc
How would I go about only getting those selected into the array and if none are selected then the array would be blank.
Hope you understand what I mean!

Here is a working form with some checkboxes that will allow you to test and get the sql you intended.
<?php
$dateArr=array();
if(isset($_POST['season']))
{
$dateArr=array_unique($_POST['season']);
$dateSearch=implode(",", $dateArr);
$sql=".... and season in (".$dateSearch.")";
echo $sql;
}
?>
<html>
<form action="?" method="post">
<?php
for($i=0;$i<10;$i++)
{
echo "<input type=\"checkbox\" name=\"season[]\" value=\"".($i+2005)."\"> ".($i+2005);
}
?>
<input type="submit">
</form>
Output when 2009, 2010 and 2011 selected:
.... and season in (2009,2010,2011)
Okay, so how it works:
Checkboxes are best used when they all have the same name ending in a []. This makes it a nice array on it's own.
If post data is set, we then quickly throw an array unique over it (good habit for the most part in these types of queries) so that there are no duplicate values.
Then simply implode it into a string and pop it into the SQL query.
Edit: Added functionality to re-check checkboxes when submitted.
<?php
$dateArr=array();
if(isset($_POST['season']))
{
$dateArr=array_unique($_POST['season']);
$dateSearch=implode(",", $dateArr);
$sql=".... and season in (".$dateSearch.")";
echo $sql;
}
?>
<html>
<form action="?" method="post">
<?php
for($i=0;$i<10;$i++)
{
$chk="";
if(!empty($_POST['season']))
{
if(in_array($i+2005, $_POST['season']))
{
$chk=" checked=\"checked\" ";
}
}
echo "<input type=\"checkbox\" name=\"season[]\" ".$chk." value=\"".($i+2005)."\"> ".($i+2005);
}
?>
<input type="submit">
</form>
Edit 2: Just add quotes in the right places :)
<?php
$dateArr=array();
if(isset($_POST['season']))
{
$dateArr=array_unique($_POST['season']);
$dateSearch=implode("', '", $dateArr);
$sql=".... and season in ('".$dateSearch."')";
echo $sql;
}
?>
<html>
<form action="?" method="post">
<?php
for($i=0;$i<10;$i++)
{
$chk="";
if(!empty($_POST['season']))
{
if(in_array(($i+2005)."i", $_POST['season']))
{
$chk=" checked=\"checked\" ";
}
}
echo "<input type=\"checkbox\" name=\"season[]\" ".$chk." value=\"".(($i+2005)."i")."\"> ".($i+2005)."i";
}
?>
<input type="submit">
</form>
Edit 3: I feel like this is starting to really answer much more than one question :)
You can simply check the textbox to make sure it isn't empty and then append to a SQL string:
$sql="";
if(!empty($_POST['text1']))
{
$sql.=" and ftgf>= ".$_POST['text1']." ";
}
Having said that, I would strongly suggest that you NEVER allow the user to enter in parts of the actual SQL you will run - unless it is a closed/secure environment, which means NOT an ope website.

Insert the below code
$seasons = array($season2005,$season2006,$season2007,$season2008,$season2009,$season2010,$season2011,$season2012,$season2013);
//start
$seasons2 = array();
foreach ($seasons as $season)
{
if($season!=="0000")
{
array_push($seasons2,$season);
}
}
$seasonpick = implode(",",$seasons2);
//end

Related

edit_subject.php is not working, the error is saying about database query failed

This is kind of the error I'm getting:
Database query failed.
I've uploaded this webpage: http://widgetcorp.bugs3.com/public/edit_subject.php?subject=1
Here's my file:
<?php require_once("../includes/session.php"); ?>
<?php require_once("../includes/db_connection.php"); ?>
<?php require_once("../includes/functions.php"); ?>
<?php require_once("../includes/validation_functions.php"); ?>
<?php find_selected_page(); ?>
<?php
if (!$current_subject)
{
// subject ID was missing or invalid or
// subject couldn't be found in database
redirect_to("manage_content.php");
}
?>
<?php
if (isset($_POST['submit']))
{
// validations
$required_fields = array("menu_name", "position", "visible");
validate_presences($required_fields);
$fields_with_max_lengths = array("menu_name" => 30);
validate_max_lengths($fields_with_max_lengths);
if (empty($errors))
{
// Perform Update
$id = $current_subject["id"];
$menu_name = mysql_prep($_POST["menu_name"]);
$position = (int) $_POST["position"];
$visible = (int) $_POST["visible"];
$query = "UPDATE subjects SET ";
$query .= "menu_name='{$menu_name}', ";
$query .= "position={$position}, ";
$query .= "visible={$visible} ";
$query .= "WHERE id={$id} ";
$query .= "LIMIT 1";
$result = mysqli_query($connection, $query);
if ($result && mysqli_affected_rows($connection) >= 0)
{
// Success
$_SESSION["message"] = "Subject updated.";
redirect_to("manage_content.php");
}
else
{
// Failure
$message = "Subject update failed.";
}
}
}
// else
// {
// // This is probably a GET request
// }
?>
<?php include("../includes/layouts/header.php"); ?>
<div id="main">
<div id="navigation">
<?php
echo navigation($current_subject, $current_page);
?>
</div>
<div id="page">
<?php
// echo message();
// $message is just a variable, doesn't use the SESSION
if(!empty($message))
{
echo "<div class=\"message\">" . htmlentities($message) . "</div>";
}
?>
<?php echo form_errors($errors); ?>
<h2>Edit Subject: <?php echo htmlentities($current_subject["menu_name"]); ?></h2>
<form action="edit_subject.php?subject=<?php echo htmlentities($current_subject["menu_name"]); ?>" method="post">
<p>Menu name:
<input type="text" name="menu_name" value="<?php echo htmlentities($current_subject["menu_name"]); ?>" />
</p>
<p>Position:
<select name="position">
<?php
$subject_set = find_all_subjects();
$subject_count = mysqli_num_rows($subject_set);
for ($count=1; $count <= $subject_count; $count++)
{
echo "<option value=\"{$count}\"";
if ($current_subject["position"] == $count)
{
echo " selected";
}
echo ">{$count}</option>";
}
?>
</select>
</p>
<p>Visible:
<input type="radio" name="visible" value="0" <?php if ($current_subject["visible"] == 0) { echo "checked"; } ?> /> No
<input type="radio" name="visible" value="1" <?php if ($current_subject["visible"] == 1) { echo "checked"; } ?> /> Yes
</p>
<input type="submit" name="submit" value="Edit Subject" />
</form>
<br />
Cancel
Delete Subject
</div>
The problem is somewhere else and not with your UPDATE query actually. If you see the link you posted, you are passing subject parameter with url, whose value is 1 which is integer.
Now when you click submit it's changing the url to http://widgetcorp.bugs3.com/public/edit_subject.php?subject=About%20Widget%20Corp .
Here as you see the subject parameter is not integer but string value name of subject. And that is causing the problem.
You are getting error as it's not retrieving the subject data from database correctly because of wrong id type. You just need to make sure the form is being posted to right url, which would be http://widgetcorp.bugs3.com/public/edit_subject.php?subject=1.
You need to correct the action parameter on the <form> tag for that.
Look for the line below in your code:
<form action="edit_subject.php?subject=<?php echo htmlentities($current_subject["menu_name"]); ?>" method="post">
And change it to
<form action="edit_subject.php?subject=<?php echo htmlentities($current_subject["id"]); ?>" method="post">
If you see, now the form will be submitted to http://widgetcorp.bugs3.com/public/edit_subject.php?subject=1, which is the correct url.

PHP not getting values inside if statement using GET

In my code, I am trying to get values of variables from one php to another. In this php file I am getting values from some other php file through url.
I got all the values inside else part but not inside if, the variable meeting_id and pemail are not storing any thing in the database and all the other fields are storing values perfectly. Where am I wrong?
<?php
if (isset($_POST['send'])) {
$pemail = $_POST['e'];
$meeting_id = $_POST['mid'];
$date = $_POST["dat"];
if ($date=="val1") {
$d1 = 'Yes';
}
else {
$d1='No';
}
if ($date=="val2") {
$d2 = 'Yes';
}
else {
$d2='No';
}
$location = $_POST["location"];
if ($location=="val1") {
$l1 = 'Yes';
}
else {
$l1='No';
}
if ($location=="val2") {
$l2 = 'Yes';
}
else {
$l2='No';
}
$check_list1 = $_POST['check_list1'];
if ($check_list1 != 'yes') {
$check_list1 = 'No';
}
$check_list2 = $_POST['check_list2'];
if ($check_list2 != 'yes') {
$check_list2 = 'No';
}
$host='mysql5.000webhost.com';
$uname='admin';
$pwd='*****';
$db="meeting";
$con = mysql_connect($host,$uname,$pwd) or die("connection failed");
mysql_select_db($db,$con) or die("db selection failed");
$flag['code']=0;
if($r=mysql_query("insert into meeting.response (meeting_id, Email,
DAT1, DAT2, Location1, Location2, Travel, Hotel)
values('$meeting_id','$pemail','$d1','$d2','$l1','$l2','$check_list1',
'$check_list2') ",$con))
{
$flag['code']=1;
echo"hi";
}
print(json_encode($flag));
mysql_close($con);
?>
Your response was sent
<?php
} else {
$top=$_GET['t'];
$dat1=$_GET['d1'];
$tim1=$_GET['t1'];
$dat2=$_GET['d2'];
$tim2=$_GET['t2'];
$loc1=$_GET['l1'];
$loc2=$_GET['l2'];
$mid=$_GET['id'];
$e=$_GET['pemail'];
?>
<h1><center>Meeting Invitation</center></h1>
<form action="my.php" method="post">
You are invited for the meeting on <?php echo $top; ?>
proposed dates are :<br><br>
Date
Time<br>
<?php echo $dat1; ?> <?php echo $tim1; ?><input
type = "radio" name = "dat" <?php if (isset($dat) && $dat=="val1") echo
"checked";?> value = "val1" checked="true" ><br>
<?php echo $dat2; ?> <?php echo $tim2; ?><input
type = "radio" name = "dat" <?php if (isset($dat) && $dat=="val2") echo
"checked";?> value = "val2" ><br><br>
Proposed locations are :<br>
Location 1 : <?php echo $loc1; ?> <input type =
"radio" name = "location" <?php if (isset($location) &&
$location=="val1") echo
"checked";?> value = "val1" checked="true" ><br>
Location 2 : <?php echo $loc2; ?> <input type =
"radio" name = "location" <?php if (isset($location) && $location=="val2")
echo
"checked";?> value = "val2" ><br><br>
Do you want travel facility ?
<input type="checkbox" name="check_list1" value="yes"> <br><br>
Do you want hotel facility ?
<input type="checkbox" name="check_list2" value="yes"> <br><br><br>
<input type="submit" name="send" value="Send Response">
<input type="reset" >
</form>
<?php
};
?>
You are passing variables with POST not GET. For bonus I cleaned up your code for readability.
In your code change this:
Your response was sent
<?php
} else {
$top=$_GET['t'];
$dat1=$_GET['d1'];
$tim1=$_GET['t1'];
$dat2=$_GET['d2'];
$tim2=$_GET['t2'];
$loc1=$_GET['l1'];
$loc2=$_GET['l2'];
$mid=$_GET['id'];
$e=$_GET['pemail'];
?>
TO THIS:
Your response was sent
<?php
} else {
$top=$_POST['t'].'<br>';
$dat1=$_POST['d1'].'<br>';
$tim1=$_POST['t1'].'<br>';
$dat2=$_POST['d2'].'<br>';
$tim2=$_POST['t2'].'<br>';
$loc1=$_POST['l1'].'<br>';
$loc2=$_POST['l2'].'<br>';
$mid=$_POST['id'].'<br>';
$e=$_POST['pemail'];
?>
You say you sent your values via url, not via a post action. So $_POST is empty, use $_GET for url values.
Check what you send by displaying the values like: print_r($_GET) and print_r($_POST).

PHP Update shows previous database entry's

I'm currently just coding around in my free time and follow up some random tutorials that other developers/coder's created in there spare time. Now I'm stuck with something very small. I have been trying to find a answer on the interwebz but I cant seem to find one, so here I'm hoping that someone is willing to read my PHP and HTML and see the error I created.
But before I share my code let me tell you what my problem is and what I try to achieve.
If you go to the following link "removed because problem is solved." and when you click on Home/About/Service/Random, you are able to edit one of these menu's. (title, posistion, visible). Now when I want to change the menu name "Home" to "Welcome" it correctly execute my SQL but for some reason, in the HTML Form it loads it's previous information. What I can do is copy the PHP and save it in a new php file and when clicking on submit it will change both menu/title/html form at the same time, but it wont show my succes and fail message anymore. I hope any of you understand what I'm trying to explain here and try to achieve. Now lets share the code.
PHP
<? find_selected_page(); ?>
<?
if (intval($_GET['info']) == 0){
redirect_to("content.php");
}
if(isset($_POST['submit'])){
$errors = array();
$required_fields = array('menu', 'position', 'visible');
foreach ($required_fields as $fieldname){
if (!isset($POST[$fieldname]) || (empty($_POST[$fieldname]) &&
!is_numeric($_POST[$fieldname]))) {
$errors [] = $fieldname;
}
}
$fields_with_lengths = array('menu' => 30);
foreach($fields_with_lengths as $fieldname => $maxlength) {
if(strlen(trim(mysql_prep($_POST[$fieldname]))) > $maxlength){
$errors[] = $fieldname;
}
}
$id = mysql_prep($_GET['info']);
$menu = mysql_prep($_POST['menu']); //use post array cuz we used post var to coll val in form
$position = mysql_prep($_POST['position']);
$visible = mysql_prep($_POST['visible']);
$query = "UPDATE information SET menu = '{$menu}', position = {$position}, visible = {$visible} WHERE id = {$id}";
$result = mysql_query($query, $connection);
if (mysql_affected_rows() == 1) {
$message = "The information was correctly updated.";
} else {
//failed
}
} else { //errors
}
?>
HTML
<? require_once ("includes/functions.php"); ?>
<? require_once ("includes/connect.php"); ?> //HERE IS MY CONNECTION TO MY DATABASE
///HERE IS MY PHP CODE
<? include ("includes/header.php"); ?>
<div id="content"> <!-- content here -->
<table id="table">
<tr>
<td id="nav">
<? echo navigation($sel_table1, $table2); ?>
</td>
<td id="main">
<h2>Edit Info <? echo $sel_table1['menu']; ?></h2>
<? if (!empty($message)) { echo "<p class=\"message\">" . $message . "</p>";} ?>
<form action="edit_info.php?info=<? echo urlencode($sel_table1['id']); ?>" method="post"/>
<p>Menu title
<input type="text" name="menu" value="<? echo ($sel_table1['menu']); ?>" id="menu">
</p>
<p>Position
<select name="position">
<?
$info_set = get_all_info();
$info_count = mysql_num_rows($info_set); //asks how many rows there are should be 3
for($count=1; $count <= $info_count+1; $count++){
echo "<option value='{$count}'";
if($sel_table1['position'] == $count){
echo "selected";
}
echo ">{$count}</option>";
}
?>
</select>
</p>
<p>Visible:
<input type="radio" name="visible" value="0"
<? if ($sel_table1['visible'] == 0){ echo "checked"; } ?>
/>No
<input type="radio" name="visible" value="1"
<? if ($sel_table1['visible'] == 1){ echo "checked"; } ?>
/>Yes
</p>
<input type="submit" name='submit' value="Edit information" />
</form> <br>
Cancel
</td>
</tr>
</table>
</div>
<? include ("includes/footer.php");?> //HERE I HAVE IF ISSET MYSQL CLOSE
And a more simple short version of the story is, I want to update the menu's with the success and failure message's without getting the old previous data in my HTML FORM
if needed for any reasons I have included the part of my functions.php where $sel_table and $table2 are staying.
function find_selected_page(){
global $sel_table1;
global $table2;
if (isset($_GET['info'])){
$sel_table1 = get_info_by_id($_GET['info']);
$sel_t2 = 0;
$table2 = NULL;
} else if (isset($_GET['page'])){
$table1 = 0;
$sel_table1 = NULL;
$table2 = get_pages_by_id($_GET['page']);
} else {
$table1 = NULL;
$sel_table1 = NULL;
$table2 = 0;
}
}
function navigation($sel_table1, $table2){
$output = "<ul class='info'>";
$info_set = get_all_info();
while ($info = mysql_fetch_array($info_set))
{
$output .= "<li"; if ($info["id"] == $sel_table1 ["id"]){
$output .= " class='selected'";
}
$output .= "><a href='edit_info.php?info=" . urlencode($info["id"]) . "'>{$info['menu']}</a></li>";
$page_set = get_pages_for_info($info["id"]);
$output .= "<ul class='pages'>";
while ($page = mysql_fetch_array($page_set))
{
$output .= "<li"; if ($page["id"] == $table2 ["id"]){
$output .= " class='selected'";
}
$output .= "><a href='content.php?page=" . urlencode($page["id"]) . "'>{$page['menu']}</a></li>"; }
$output .= "</ul>";
}
$output .= "</ul>";
return $output;
}

checkbox handling php multiple checkbox

Working on a simple php code. When it press on only PH it show hello, and only on chlorine it show yello. When both is pressed it show sello.
<?php
if(isset($_POST['submit'])){
foreach($_POST['verdi'] as $animal){
if(isset($_POST['verdi[]==PH']))
{
echo "hello";
}
}
}
?>
<form name="input" action="" method="POST">
<input type="checkbox" name="verdi[]" value="PH">PH<br>
<input type="checkbox" name="verdi[]" value="Chlorine">Chlorine<br>
<br><br>
<input type="submit" name="submit" value="Submit">
</form>
You can do a simple check in PHP:
if( in_array("PH", $_POST["verdi"]) ){
echo "in array!";
}
if(isset($_POST['submit']) && is_array($_POST['verdi'])) {
$checked = array();
foreach($_POST['verdi'] as $animal) {
// you can do extra validation here.
$checked[] = $animal;
}
if(in_array("PH", $checked) && in_array("Chlorine", $checked)) {
echo "sello";
} else {
if(in_array("PH", $checked)) {
echo "hello";
} else if(in_array("Chlorine", $checked)) {
echo "yello";
}
}
}

change dropdown from array to check box

I would like a change from the drop down to the checkbox, I want to change it because I want firstly select the list in the array can be selected before store to database via the checkbox, so the dropdown script was as follows
<?php
session_start();
define('DEFAULT_SOURCE','Site_A');
define('DEFAULT_VALUE',100);
define('DEFAULT_STC','BGS');
include('class/stockconvert_class.php');
$st = new st_exchange_conv(DEFAULT_SOURCE);
if(isset($_GET['reset'])) {
unset($_SESSION['selected']);
header("Location: ".basename($_SERVER['PHP_SELF']));
exit();
}
?>
<form action="do.php" method="post">
<label for="amount">Amount:</label>
<input type="input" name="amount" id="amount" value="1">
<select name="from">
<?php
$stocks = $st->stocks();
asort($stocks);
foreach($stocks as $key=>$stock)
{
if((isset($_SESSION['selected']) && strcmp($_SESSION['selected'],$key) == 0) || (!isset($_SESSION['selected']) && strcmp(DEFAULT_STC,$key) == 0))
{
?>
<option value="<?php echo $key; ?>" selected="selected"><?php echo $stock; ?></option>
<?php
}
else
{
?>
<option value="<?php echo $key; ?>"><?php echo $stock; ?></option>
<?php
}
}
?>
</select>
<input type="submit" name="submit" value="Convert">
</form>
and i Changed it to the checkbox as follows
<?php
session_start();
define('DEFAULT_SOURCE','Site_A');
define('DEFAULT_VALUE',100);
define('DEFAULT_STC','BGS');
include('class/stockconvert_class.php');
$st = new st_exchange_conv(DEFAULT_SOURCE);
if(isset($_GET['reset'])) {
unset($_SESSION['selected']);
header("Location: ".basename($_SERVER['PHP_SELF']));
exit();
}
?>
<form action="do.php" method="post">
<label for="amount">Amount:</label>
<input type="input" name="amount" id="amount" value="1"><input type="submit" name="submit" value="Convert">
<?php
$stocks = $st->stocks();
asort($stocks);
foreach($stocks as $key=>$stock)
{
if((isset($_SESSION['selected']) && strcmp($_SESSION['selected'],$key) == 0) || (!isset($_SESSION['selected']) && strcmp(DEFAULT_STC,$key) == 0))
{
?>
<br><input type="checkbox" id="scb1" name="from[]" value="<?php echo $key; ?>" checked="checked"><?php echo $stock; ?>
<?php
}
else
{
?>
<br><input type="checkbox" id="scb1" name="from[]" value="<?php echo $key; ?>"><?php echo $stock; ?>
<?php
}
}
?>
</form>
but does not work, am I need to display Other codes related?
Thanks if some one help, and appreciated it
UPDATED:
ok post the first apparently less obvious, so I will add the problem of error
the error is
Fatal error: Call to undefined method st_exchange_conv::convert() in C:\xampp\htdocs\test\do.php on line 21
line 21 is $st->convert($from,$key,$date);
session_start();
if(isset($_POST['submit']))
{
include('class/stockconvert_class.php');
$st = new st_exchange_conv(DEFAULT_SOURCE);
$from = mysql_real_escape_string(stripslashes($_POST['from']));
$value = floatval($_POST['amount']);
$date = date('Y-m-d H:i:s');
$_SESSION['selected'] = $from;
$stocks = $st->stocks();
asort($stocks);
foreach($stocks as $key=>$stock)
{
$st->convert($from,$key,$date);
$stc_price = $st->price($value);
$stock = mysql_real_escape_string(stripslashes($stock));
$count = "SELECT * FROM oc_stock WHERE stock = '$key'";
$result = mysql_query($count) or die(mysql_error());
$sql = '';
if(mysql_num_rows($result) == 1)
{
$sql = "UPDATE oc_stock SET stock_title = '$stock', stc_val = '$stc_price', date_updated = '$date' WHERE stock = '$key'";
}
else
{
$sql = "INSERT INTO oc_stock(stock_id,stock_title,stock,decimal_place,stc_val,date_updated) VALUES ('','$stock','$key','2',$stc_price,'$date')";
}
$result = mysql_query($sql) or die(mysql_error().'<br />'.$sql);
}
header("Location: index.php");
exit();
}
Why I want to change it from dropdown to checkbox?
because with via checkbox list I will be able to choose which ones I checked it was the entrance to the database, then it seem not simple to me, I looking for some help< thanks So much For You mate.
You have not removed the opening <select> tag.
But you removed the <submit> button.
You changed the name from "from" to "from[]".
EDIT: After your additions:
Using the dropdown list you were only able to select one value for from. Now you changed it to checkboxes and thus are able to select multiple entries. This results in receiving an array from[] in your script in do.php. Your functions there are not able to handle arrays or multiple selections in any way.
You have to re-design do.php, change your form back to a dropdown list or use ratio buttons instead.

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