I am trying to get numbers from a string but i keep getting the complete string with numbers and not numbers alone
$string = "stuff here with id=485&other=123";
preg_match('(id=\d+)',$string,$match);
the above results like id=485 but i just want 485
Any help would be appreciated guys.
The parentheses say what to collect. You also need to use a delimiter at either end
preg_match('/id\=(\d+)/',$string,$match);
print_r($match);
/* should be
0=>"id=485",
1=>"485"
*/
echo $match[1];
Edit: See cryptic's answer, parse_str is most likely faster than preg_match. Most things are.
$string = "stuff here with id=485&other=123";
parse_str(strstr($string, 'id='), $output);
echo $output['id']; // 485
Without using a regex.
Related
I'm trying to read a number in a link in php. But I'm not sure how to do it.
http://example.com/Productdetail.asp?SID=72&ProductID=8640
How can I read the number 8640 without reading 72 at the same time.
ProductID= <- it will always be there.
SID=X <- this one will be there sometimes and left out on other pages. and the number can change between 1-999,
Is there a way to say ProductID= "read the next 4 numbers and save in string"
Thanks
you can get this output by using explode()
$link='http://example.com/Productdetail.asp?SID=72&ProductID=8640';
$links=explode('ProductID=',$link);
echo $link[1]; //this is your number
Simple use
echo $_GET['ProductID'];//8640
You can use preg_match as
$str = "http://example.com/Productdetail.asp?SID=72&ProductID=8640";
preg_match('/&ProductID=(\d+)?/',$str,$match);
echo $match[1];
Or you can simply use parse_str as
$str = "http://example.com/Productdetail.asp?SID=72&ProductID=8640";
parse_str($str,$res);
echo $res['ProductID'];
You can use:
strpos to get the ProductID=
's index
substr to get the string from ProductID= until the end of the string
str_replace to replace the ProductID= part
<?php
$str = "http://example.com/Productdetail.asp?SID=72&ProductID=8640";
echo str_replace("ProductID=", "", substr($str, strpos($str, "ProductID=")));
?>
i've a little problem.
I want to check the numer of post like this:
http://xxx.xxxxxx.net/episodio/168
this is part of my code, only need the number check:
[...]
if(preg_match('#^http://horadeaventura.enlatino.net/episodio/[0-9]',trim($url))){
[...]
Can help me?
Thanks!
If you want to do it with preg_match:
$url = 'http://horadeaventura.enlatino.net/episodio/168';
if(preg_match('#^http://horadeaventura.enlatino.net/episodio/([0-9]+)#',trim($url), $matches)){
$post = $matches[1];
echo $post;
}
So, basically: I added an end delimiter (#), changed "[0-9]" to "([0-9])+", added ", $matches" to capture the matches. Of course it can be done better and using other options than preg_match. But I wanted to make your snippet work - not rewrite it.
If you don't have your heart set on using preg_match(), you could do
$string = "http://xxx.xxxxxx.net/episodio/168";
$array = explode("/", $string);
echo end($array);
which will output
168
this is assuming the number you are looking for will always be the last section of the url string
Or, you can just check for number, on last position:
if(preg_match('#[0-9]+$#',trim($url),$match)){
print_r($match);
}
I'm trying to find the best way to grab the dynamic substring, but replace all of the content after.
This is what I'm trying to achieve:
{table_telecommunications}
The substring {table_ is always the same, the only that varies is telecommunications}.
I want to grab the word telecommunications so I can do a search on a MySQL table and then replace {table_telecommunications} with the content returned.
I thought of making a strpos and then explode and so on.
But I guess it would be easier with regex, but I have no skills on creating regex.
Could you possibly give me the best way to do this?
Edit: I'm saying possibly regex is the best way because I need to find strings that are in this format, but the second part is variable, just like {table_*}
Use Regex.
<?php
$string = "{table_telecommunications} blabla blabla {table_block}";
preg_match_all("/\{table_(.+?)\}/is", $string, $matches);
$substrings = $matches[1];
print_r($substrings);
?>
if (preg_match('#table_([^}]+)}#', '{table_telecommunications}', $matches)){
echo $matches[1];
}
That's a regex solution. You can do the same with explode:
$parts = explode('table_', '{table_telecommunications}');
echo substr($parts[1], 0, -1);
$input = '{table_telecommunications}';
$table_name = trim(implode('_', array_shift(explode($input, '_'))), '}');
Should be fast, no regex required.
I have the following string
"This is very nice. Thanks for your support."
Now I want to remove the line that contains Thanks word
you need to explode the paragraph by fullstop.
lets say your full paragraph is store in $str
$lines_arr = explode(".",$str);
now $lines_arr is an array contains numbers of lines.
now under loop you can check which lines contains "thanks" , if it is then skip it.
$string = '';
for($i=0; $i<(count($lines_arr)-1); $i++){
//with the help of strpos
if(strpos($lines_arr[$i],"Thanks") == false){
$string .= $lines_arr[$i].". ";
}
}
you can use str_replace
echo str_replace("Thanks", "", "This is very nice. Thanks for your support.");
# Output: This is very nice. for your support.
If you expect proper punctuation, you could explode() the string into an array on the full stops and delete the elements with your particular word, then merge all the elements back into a string.
I know there are lots of tutorials and question on replacing something in a string.
But I can't find a single one on what I want to do!
Lets say I have a string like this
$string="Hi! [num:0]";
And an example array like this
$array=array();
$array[0]=array('name'=>"na");
$array[1]=array('name'=>"nam");
Now what I want is that PHP should first search for the pattern like [num:x] where x is a valid key from the array.
And then replace it with the matching key of the array. For example, the string given above should become: Hi! na
I was thinking of doing this way:
Search for the pattern.
If found, call a function which checks if the number is valid or not.
If valid, returns the name from the array of that key like 0 or 1 etc.
PHP replaces the value returned from the function in the string in place of the pattern.
But I can't find a way to execute the idea. How do I match that pattern and call the function for every match?
This is just the way that I am thinking to do. Any other method will also work.
If you have any doubts about my question, please ask in comments.
Try this
$string="Hi! [num:0]";
$array=array();
$array[0]=array('name'=>"na");
$array[1]=array('name'=>"nam");
echo preg_replace('#(\!)?\s+\[num:(\d+)\]#ie','isset($array[\2]) ? "\1 ".$array[\2]["name"] : " "',$string);
If you don't want the overhead of Regex, and your string format remains same; you could use:
<?php
$string="Hi! [num:0]";
echo_name($string); // Hi John
echo "<br />";
$string="Hello! [num:10]";
echo_name($string); // No names, only Hello
// Will echo Hi + Name
function echo_name($string){
$array=array();
$array[0]=array('name'=>"John");
$array[1]=array('name'=>"Doe");
$string = explode(" ", $string);
$string[1] = str_replace("[num:", "", $string[1]);
$string[1] = str_replace("]", "", $string[1]);
if(array_key_exists($string[1], $array)){
echo $string[0]." ".$array[$string[1]]["name"];
} else {
echo $string[0]." ";
}
}// function echo_sal ENDs
?>
Live: http://codepad.viper-7.com/qy2uwW
Assumptions:
$string always will have only one space, exactly before [num:X].
[num:X] is always in the same format.
Of course you could skip the str_replace lines if you could make your input to simple
Hi! 0 or Hello! 10