I have the following string
"This is very nice. Thanks for your support."
Now I want to remove the line that contains Thanks word
you need to explode the paragraph by fullstop.
lets say your full paragraph is store in $str
$lines_arr = explode(".",$str);
now $lines_arr is an array contains numbers of lines.
now under loop you can check which lines contains "thanks" , if it is then skip it.
$string = '';
for($i=0; $i<(count($lines_arr)-1); $i++){
//with the help of strpos
if(strpos($lines_arr[$i],"Thanks") == false){
$string .= $lines_arr[$i].". ";
}
}
you can use str_replace
echo str_replace("Thanks", "", "This is very nice. Thanks for your support.");
# Output: This is very nice. for your support.
If you expect proper punctuation, you could explode() the string into an array on the full stops and delete the elements with your particular word, then merge all the elements back into a string.
Related
I have a string of words in an array, and I am using preg_replace to make each word into a link. Currently my code works, and each word is transformed into a link.
Here is my code:
$keywords = "shoes,hats,blue curtains,red curtains,tables,kitchen tables";
$template = '%1$s';
$newkeys = preg_replace("/(?!(?:[^<]+>|[^>]+<\/a>))\b([a-z]+)\b/is", sprintf($template, "\\1"), $keywords);
Now, the only problem is that when I want 2 or 3 words to be a single link. For example, I have a keyword "blue curtains". The script would create a link for the word "blue" and "curtains" separately. I have the keywords separated by commas, and I would like the preg_replace to only replace the text between the commas.
I've tried playing around with the pattern, but I just can't figure out what the pattern would be.
Just to clarify, currently the output looks as follows:
shoes,hats,blue curtains,red curtains,tables,kitchen tables
While I want to achieve the following output:
shoes,hats,blue curtains,red curtains,tables,kitchen tables
A little bit change in preg_replace code and your job will done :-
$keywords = "shoes,hats,blue curtains,red curtains,tables,kitchen tables";
$template = '%1$s';
$newkeys = preg_replace("/(?!(?:[^<]+>|[^>]+<\/a>))\b([a-z ' ']+)\b/is", sprintf($template, "\\1"), $keywords);
OR
$newkeys = preg_replace("/(?!(?:[^<]+>|[^>]+<\/a>))\b([a-z' ']+)\b/is", sprintf($template, "\\1"), $keywords);
echo $newkeys;
Output:- http://prntscr.com/77tkyb
Note:- I just added an white-space in your preg_replace. And you can easily get where it is. I hope i am clear.
Matching white-space along with words is missing there in preg_replace and i added that only.
I want to do something with PHP .
I have this list of names :
first
second
third
forth
Now i want to have this :
first,second,third,forth
How can this happen with a little PHP code ?
Assuming that you have those in array
$arr=array('first','second');
$str=implode(",",$arr);
EDIT(assuming each names are on the new line, i will replace \n with ,)
$str=file_get_contents("filename.txt");
$newstr=str_replace("\n",',',$str);
$newstr=trim($newstr, ",");//to remove the last comma
echo $newstr;
i think you text tag based on new line, so try this
first
second
third
forth
$arr = explode("\n", $txt);
echo implode(",",$arr);
every new line consider as a array value.
This is really basic PHP, I can't believe it isn't covered in most tutorials.
$array = file("filename", FILE_IGNORE_NEW_LINES);
$string = implode(',', $array);
I think you're looking for explode, like so http://us2.php.net/explode
array explode ( string $delimiter , string $string [, int $limit ] )
You want to set $delimiter to ' ', $string can be a copy -> paste of your text.txt content.
The best thing to do would be: take the text.txt content and use search-replace to remove new lines and add spaces (or commas), so you go from
ron
john
kahn
to ron, john, kahn, at which point you can import an array for use in php.
I am trying to use a License PHP System…
I will like to show the status of their license to the users.
The license Server gives me this:
name=Service_Name;nextduedate=2013-02-25;status=Active
I need to have separated the data like this:
$name = “Service_Name”;
$nextduedate = “2013-02-25”;
$status = “Active”;
I have 2 days tring to resolve this problem with preg_match_all but i cant :(
This is basically a query string if you replace ; with &. You can try parse_str() like this:
$string = 'name=Service_Name;nextduedate=2013-02-25;status=Active';
parse_str(str_replace(';', '&', $string));
echo $name; // Service_Name
echo $nextduedate; // 2013-02-25
echo $status; // Active
This can rather simply be solved without regex. The use of explode() will help you.
$str = "name=Service_Name;nextduedate=2013-02-25;status=Active";
$split = explode(";", $str);
$structure = array();
foreach ($split as $element) {
$element = explode("=", $element);
$$element[0] = $element[1];
}
var_dump($name);
Though I urge you to use an array instead. Far more readable than inventing variables that didn't exist and are not explicitly declared.
It sounds like you just want to break the text down into separate lines along the semicolons, add a dollar sign at the front and then add spaces and quotes. I'm not sure you can do that in one step with a regular expression (or at least I don't want to think about what that regular expression would look like), but you can do it over multiple steps.
Use preg_split() to split the string into an array along the
semicolons.
Loop over the array.
Use str_replace to replace each '=' with ' = "'.
Use string concatenation to add a $ to the front and a "; to the end of each string.
That should work, assuming your data doesn't include quotes, equal signs, semicolons, etc. within the data. If it does, you'll have to figure out the parsing rules for that.
Hopefully, this is an easy one. I have an array with lines that contain output from a CSV file. What I need to do is simply remove any commas that appear between double-quotes.
I'm stumbling through regular expressions and having trouble. Here's my sad-looking code:
<?php
$csv_input = '"herp","derp","hey, get rid of these commas, man",1234';
$pattern = '(?<=\")/\,/(?=\")'; //this doesn't work
$revised_input = preg_replace ( $pattern , '' , $csv_input);
echo $revised_input;
//would like revised input to echo: "herp","derp,"hey get rid of these commas man",1234
?>
Thanks VERY much, everyone.
Original Answer
You can use str_getcsv() for this as it is purposely designed for process CSV strings:
$out = array();
$array = str_getcsv($csv_input);
foreach($array as $item) {
$out[] = str_replace(',', '', $item);
}
$out is now an array of elements without any commas in them, which you can then just implode as the quotes will no longer be required once the commas are removed:
$revised_input = implode(',', $out);
Update for comments
If the quotes are important to you then you can just add them back in like so:
$revised_input = '"' . implode('","', $out) . '"';
Another option is to use one of the str_putcsv() (not a standard PHP function) implementations floating about out there on the web such as this one.
This is a very naive approach that will work only if 'valid' commas are those that are between quotes with nothing else but maybe whitespace between.
<?php
$csv_input = '"herp","derp","hey, get rid of these commas, man",1234';
$pattern = '/([^"])\,([^"])/'; //this doesn't work
$revised_input = preg_replace ( $pattern , "$1$2" , $csv_input);
echo $revised_input;
//ouput for this is: "herp","derp","hey get rid of these commas man",1234
It should def be tested more but it works in this case.
Cases where it might not work is where you don't have quotes in the string.
one,two,three,four -> onetwothreefour
EDIT : Corrected the issues with deleting spaces and neighboring letters.
Well, I haven't been lazy and written a small function to do exactly what you need:
function clean_csv_commas($csv){
$len = strlen($csv);
$inside_block = FALSE;
$out='';
for($i=0;$i<$len;$i++){
if($csv[$i]=='"'){
if($inside_block){
$inside_block=FALSE;
}else{
$inside_block=TRUE;
}
}
if($csv[$i]==',' && $inside_block){
// do nothing
}else{
$out.=$csv[$i];
}
}
return $out;
}
You might be coming at this from the wrong angle.
Instead of removing the commas from the text (presumably so you can then split the string on the commas to get the separate elements), how about writing something that works on the quotes?
Once you've found an opening quote, you can check the rest of the string; anything before the next quote is part of this element. You can add some checking here to look for escaped quotes, too, so things like:
"this is a \"quote\""
will still be read properly.
Not exactly an answer you've been looking for - But I've used it for cleaning commas in numbers in CSV.
$csv = preg_replace('%\"([^\"]*)(,)([^\"]*)\"%i','$1$3',$csv);
"3,120", 123, 345, 567 ==> 3120, 123, 345, 567
When I've a string:
$string = 'word1="abc.3" word2="xyz.3"';
How can I replace the point with a comma after xyz in xyz.3 and keep him after abc in abc.3?
You've provided an example but not a description of when the content should be modified and when it should be kept the same. The solution might be simply:
str_replace("xyz.", "xyz", $input);
But if you explicitly want a more explicit match, say requiring a digit after the ful stop, then:
preg_replace("/xyz\.([0-9])+/", 'xyz\${1}', $input);
(not tested)
something like (sorry i did this with javascript and didn't see the PHP tag).
var stringWithPoint = 'word1="abc.3" word2="xyz.3"';
var nopoint = stringWithPoint.replace('xyz.3', 'xyz3');
in php
$str = 'word1="abc.3" word2="xyz.3"';
echo str_replace('xyz.3', 'xyz3', $str);
You can use PHP's string functions to remove the point (.).
str_replace(".", "", $word2);
It depends what are the criteria for replace or not.
You could split string into parts (use explode or preg_split), then replace dot in some parts (eg. str_replace), next join them together (implode).
how about:
$string = 'word1="abc.3" word2="xyz.3"';
echo preg_replace('/\.([^.]+)$/', ',$1', $string);
output:
word1="abc.3" word2="xyz,3"