i've a little problem.
I want to check the numer of post like this:
http://xxx.xxxxxx.net/episodio/168
this is part of my code, only need the number check:
[...]
if(preg_match('#^http://horadeaventura.enlatino.net/episodio/[0-9]',trim($url))){
[...]
Can help me?
Thanks!
If you want to do it with preg_match:
$url = 'http://horadeaventura.enlatino.net/episodio/168';
if(preg_match('#^http://horadeaventura.enlatino.net/episodio/([0-9]+)#',trim($url), $matches)){
$post = $matches[1];
echo $post;
}
So, basically: I added an end delimiter (#), changed "[0-9]" to "([0-9])+", added ", $matches" to capture the matches. Of course it can be done better and using other options than preg_match. But I wanted to make your snippet work - not rewrite it.
If you don't have your heart set on using preg_match(), you could do
$string = "http://xxx.xxxxxx.net/episodio/168";
$array = explode("/", $string);
echo end($array);
which will output
168
this is assuming the number you are looking for will always be the last section of the url string
Or, you can just check for number, on last position:
if(preg_match('#[0-9]+$#',trim($url),$match)){
print_r($match);
}
Related
i want to make regex to detect this format image(numeric, string). ex: image(100, 'test').
i have tried this one, but just detect the image(numeric)
/image\((\d+)\)/
Any help with second parameter and the ,?
Also how i can get the second parameter?
You can try the following pattern:
/image\(\d+,\s*'.+?'\)/
I removed the capture group since it would be not needed if using the regex for validation only.
Demo
If you want to capture the number and text, then use capture groups:
$input = "code image(123, 'meh') more code";
if (preg_match("/image\((\d+),\s*'(.+?)'\)/", $input, $m)) {
echo "match";
}
$number = $m[1];
$text = $m[2];
Try this:
image\((\d+), '(.+?)'\)
The . matches anything and the rest is pretty much self-explanatory. Group 1 is your number, group 2 is the string.
You can try this one:
image\(\s*\d+\s*\,\s*'.*'\s*\)
I'm trying to find the best way to grab the dynamic substring, but replace all of the content after.
This is what I'm trying to achieve:
{table_telecommunications}
The substring {table_ is always the same, the only that varies is telecommunications}.
I want to grab the word telecommunications so I can do a search on a MySQL table and then replace {table_telecommunications} with the content returned.
I thought of making a strpos and then explode and so on.
But I guess it would be easier with regex, but I have no skills on creating regex.
Could you possibly give me the best way to do this?
Edit: I'm saying possibly regex is the best way because I need to find strings that are in this format, but the second part is variable, just like {table_*}
Use Regex.
<?php
$string = "{table_telecommunications} blabla blabla {table_block}";
preg_match_all("/\{table_(.+?)\}/is", $string, $matches);
$substrings = $matches[1];
print_r($substrings);
?>
if (preg_match('#table_([^}]+)}#', '{table_telecommunications}', $matches)){
echo $matches[1];
}
That's a regex solution. You can do the same with explode:
$parts = explode('table_', '{table_telecommunications}');
echo substr($parts[1], 0, -1);
$input = '{table_telecommunications}';
$table_name = trim(implode('_', array_shift(explode($input, '_'))), '}');
Should be fast, no regex required.
I know it may sound as a common question but I have difficulty understanding this process.
So I have this string:
http://domain.com/campaign/tgadv?redirect
And I need to get only the word "tgadv". But I don't know that the word is "tgadv", it could be whatever.
Also the url itself may change and become:
http://domain.com/campaign/tgadv
or
http://domain.com/campaign/tgadv/
So what I need is to create a function that will get whatever word is after campaign and before any other particular character. That's the logic..
The only certain thing is that the word will come after the word campaign/ and that any other character that will be after the word we are searching is a special one ( i.e. / or ? )
I tried understanding preg_match but really cannot get any good result from it..
Any help would be highly appreciated!
I would not use a regex for that. I would use parse_url and basename:
$bits = parse_url('http://domain.com/campaign/tgadv?redirect');
$filename = basename($bits['path']);
echo $filename;
However, if want a regex solution, use something like this:
$pattern = '~(.*)/(.*)(\?.*)~';
preg_match($pattern, 'http://domain.com/campaign/tgadv?redirect', $matches);
$filename = $matches[2];
echo $filename;
Actually, preg_match sounds like the perfect solution to this problem. I assume you are having problems with the regex?
Try something like this:
<?php
$url = "http://domain.com/campaign/tgadv/";
$pattern = "#campaign/([^/\?]+)#";
preg_match($pattern, $url, $matches);
// $matches[1] will contain tgadv.
$path = "http://domain.com/campaign/tgadv?redirect";
$url_parts = parse_url($path);
$tgadv = strrchr($url_parts['path'], '/');
You don't really need a regex to accomplish this. You can do it using stripos() and substr().
For example:
$str = '....Your string...';
$offset = stripos($str, 'campaign/');
if ( $offset === false ){
//error, end of h4 tag wasn't found
}
$offset += strlen('campaign/');
$newStr = substr($str, $offset);
At this point $newStr will have all the text after 'campaign/'.
You then just need to use a similar process to find the special character position and use substr() to strip the string you want out.
You can also just use the good old string functions in this case, no need to involve regexps.
First find the string /campaign/, then take the substring with everything after it (tgadv/asd/whatever/?redirect), then find the next / or ? after the start of the string, and everything in between will be what you need (tgadv).
I'm using the code at the bottom to grab parameters from a wordpress shortcode. The shortcode itself looks like this:
[FLOWPLAYER=http://www.tvovermind.com/wp-content/uploads/2013/01/pll-316-21.jpg|http://www.tvovermind.com/wp-content/uploads/2013/01/PLL316_fv2.h264HD-Clip2.flv,440,280]
Or
[FLOWPLAYER=http://www.tvovermind.com/wp-content/uploads/2013/01/pll-316-21.jpg|http://www.tvovermind.com/wp-content/uploads/2013/01/PLL316_fv2.h264HD-Clip2.flv,440,280,false]
What I would like to have happen is that if the extra parameter (false/true) is missing then that match becomes "false", however with the current code if the parameter is missing a match is never made. Any ideas?
function legacy_hook($content){
$regex = '/\[FLOWPLAYER=([a-z0-9\:\.\-\&\_\/\|]+)\,([0-9]+)\,([0-9]+)\,([a-z0-9\:\.\-\&\_\/\|]+)\]/i';
$matches = array();
preg_match_all($regex, $content, $matches);
if($matches[0][0] != '') {
foreach($matches[0] as $key => $data) {
$content = str_replace($matches[0][$key], flowplayer::build_player($matches[2][$key], $matches[3][$key], $matches[1][$key],$matches[4][$key]),$content);
}
}
return $content;
}
your regex is looking for the last comma to be there and one or more of the characters in the last set of brackets. Something like
/\[FLOWPLAYER=([a-z0-9\:\.\-\&\_\/\|]+)\,([0-9]+)\,([0-9]+)(\,[a-z]+)?\]/i
only issue is you'll get the comma in the match too.
might be what you're after, then you have to test for the last match being present. preg_match_all returns the number of matches so you might be able to use that, or you could do an inline if...
(count($matches) > 4 ? $matches[4][$key] : false)
You can add OR at the end of your expression
(,true|,false|$)
I didn't check does it work but you get the idea.
Basically I'll be having a string that looks like
#schedule take out trash #in 20
and I need to be able to pull out "take out trash" and "20" and put them in their own variables. Possible?
Use preg_match, for example
if (preg_match('/#schedule (.+?) #in (\d+)/', $string, $matches)) {
// found matches
$instruction = $matches[1];
$time = $matches[2];
}
list($task, $delay) = preg_split("/\s?#(\w+)\s?/")
should work for anything in that general format unless you need to worry about people putting # in the task name