I know it may sound as a common question but I have difficulty understanding this process.
So I have this string:
http://domain.com/campaign/tgadv?redirect
And I need to get only the word "tgadv". But I don't know that the word is "tgadv", it could be whatever.
Also the url itself may change and become:
http://domain.com/campaign/tgadv
or
http://domain.com/campaign/tgadv/
So what I need is to create a function that will get whatever word is after campaign and before any other particular character. That's the logic..
The only certain thing is that the word will come after the word campaign/ and that any other character that will be after the word we are searching is a special one ( i.e. / or ? )
I tried understanding preg_match but really cannot get any good result from it..
Any help would be highly appreciated!
I would not use a regex for that. I would use parse_url and basename:
$bits = parse_url('http://domain.com/campaign/tgadv?redirect');
$filename = basename($bits['path']);
echo $filename;
However, if want a regex solution, use something like this:
$pattern = '~(.*)/(.*)(\?.*)~';
preg_match($pattern, 'http://domain.com/campaign/tgadv?redirect', $matches);
$filename = $matches[2];
echo $filename;
Actually, preg_match sounds like the perfect solution to this problem. I assume you are having problems with the regex?
Try something like this:
<?php
$url = "http://domain.com/campaign/tgadv/";
$pattern = "#campaign/([^/\?]+)#";
preg_match($pattern, $url, $matches);
// $matches[1] will contain tgadv.
$path = "http://domain.com/campaign/tgadv?redirect";
$url_parts = parse_url($path);
$tgadv = strrchr($url_parts['path'], '/');
You don't really need a regex to accomplish this. You can do it using stripos() and substr().
For example:
$str = '....Your string...';
$offset = stripos($str, 'campaign/');
if ( $offset === false ){
//error, end of h4 tag wasn't found
}
$offset += strlen('campaign/');
$newStr = substr($str, $offset);
At this point $newStr will have all the text after 'campaign/'.
You then just need to use a similar process to find the special character position and use substr() to strip the string you want out.
You can also just use the good old string functions in this case, no need to involve regexps.
First find the string /campaign/, then take the substring with everything after it (tgadv/asd/whatever/?redirect), then find the next / or ? after the start of the string, and everything in between will be what you need (tgadv).
Related
I have a server application which looks up where the stress is in Russian words. The end user writes a word жажда. The server downloads a page from another server which contains the stresses indicated with apostrophes for each case/declension like this жа'жда. I need to find that word in the downloaded page.
In Russian the stress is always written after a vowel. I've been using so far a regex that is a grouping of all possible combinations (жа'жда|жажда'). Is there a more elegant solution using just a regex pattern instead of making a PHP script which creates all these combinations?
EDIT:
I have a word жажда
The downloaded page contains the string жа'жда. (notice the
apostrophe, I do not before-hand know where the apostrophe in the
word is)
I want to match the word with apostrophe (жа'жда).
P.S.: So far I have a PHP script creating the string (жа'жда|жажда') used in regex (apostrophe is only after vowels) which matches it. My goal is to get rid of this script and use just regex in case it's possible.
If I understand your question,
have these options (d'isorder|di'sorder|dis'order|diso'rder|disor'der|disord'er|disorde'r|disorder') and one of these is in the downloaded page and I need to find out which one it is
this may suit your needs:
<pre>
<?php
$s = "d'isorder|di'sorder|dis'order|diso'rder|disor'der|disord'er|disorde'r|disorder'|disorde'";
$s = explode("|",$s);
print_r($s);
$matches = preg_grep("#[aeiou]'#", $s);
print_r($matches);
running example: https://eval.in/207282
Uhm... Is this ok with you?
<?php
function find_stresses($word, $haystack) {
$pattern = preg_replace('/[aeiou]/', '\0\'?', $word);
$pattern = "/\b$pattern\b/";
// word = 'disorder', pattern = "diso'?rde'?r"
preg_match_all($pattern, $haystack, $matches);
return $matches[0];
}
$hay = "something diso'rder somethingelse";
find_stresses('disorder', $hay);
// => array(diso'rder)
You didn't specify if there can be more than one match, but if not, you could use preg_match instead of preg_match_all (faster). For example, in Italian language we have àncora and ancòra :P
Obviously if you use preg_match, the result would be a string instead of an array.
Based, on your code, and the requirements that no function is called and disorder is excluded. I think this is what you want. I have added a test vector.
<pre>
<?php
// test code
$downloadedPage = "
there is some disorde'r
there is some disord'er in the example
there is some di'sorder in the example
there also' is some order in the example
there is some disorder in the example
there is some dso'rder in the example
";
$word = 'disorder';
preg_match_all("#".preg_replace("#[aeiou]#", "$0'?", $word)."#iu"
, $downloadedPage
, $result
);
print_r($result);
$result = preg_grep("#'#"
, $result[0]
);
print_r($result);
// the code you need
$word = 'also';
preg_match("#".preg_replace("#[aeiou]#", "$0'?", $word)."#iu"
, $downloadedPage
, $result
);
print_r($result);
$result = preg_grep("#'#"
, $result
);
print_r($result);
Working demo: https://eval.in/207312
I'm trying to find the best way to grab the dynamic substring, but replace all of the content after.
This is what I'm trying to achieve:
{table_telecommunications}
The substring {table_ is always the same, the only that varies is telecommunications}.
I want to grab the word telecommunications so I can do a search on a MySQL table and then replace {table_telecommunications} with the content returned.
I thought of making a strpos and then explode and so on.
But I guess it would be easier with regex, but I have no skills on creating regex.
Could you possibly give me the best way to do this?
Edit: I'm saying possibly regex is the best way because I need to find strings that are in this format, but the second part is variable, just like {table_*}
Use Regex.
<?php
$string = "{table_telecommunications} blabla blabla {table_block}";
preg_match_all("/\{table_(.+?)\}/is", $string, $matches);
$substrings = $matches[1];
print_r($substrings);
?>
if (preg_match('#table_([^}]+)}#', '{table_telecommunications}', $matches)){
echo $matches[1];
}
That's a regex solution. You can do the same with explode:
$parts = explode('table_', '{table_telecommunications}');
echo substr($parts[1], 0, -1);
$input = '{table_telecommunications}';
$table_name = trim(implode('_', array_shift(explode($input, '_'))), '}');
Should be fast, no regex required.
Basically from a database I am getting data that is formatted like this nameofproject101 Now this could continue to increase so eventually it could be nameofproject1001 my question is how can I trim off the number and just get the name of the project. I thought about using substr but since I dont know the length always I cant really do that. Since the numbers differ I dont think I can use str_replace is there any way to accomplish this?
It sounds like something is way off about your database scheme. You should probably try to do refactor/normalize your scheme.
But in the meantime, you can use rtrim() to trim all numbers off of the right side.
$val = rtrim($val, '0123456789');
Examples
Input Output
nameofproject1001 nameofproject
nameofproject nameofproject
n4me0fproj3ct1001 n4me0fproj3ct
for string like, project12V123, It is better to do this
$text = `project12V123`;
$text = preg_replace('/([\w]+)([^0-9])([0-9])+$/', '$1$2', $text);
Will return:
Project12V
or use rtrim:
$text = rtrim($text,'0123456789');
You should definitely use regular expressions:
$fullname = "nameofproject101";
preg_match("/([a-z]+)([0-9]+)/i", $fullname, $matches);
$name = $matches[1];
$number = $matches[2];
echo "'$fullname' is '$name' followed by '$number'";
preg_replace('/[^a-z]/i', '', $string);
$var="UseCountry=1
UseCountryDefault=1
UseState=1
UseStateDefault=1
UseLocality=1
UseLocalityDefault=1
cantidad_productos=5
expireDays=5
apikey=ABQIAAAAFHktBEXrHnX108wOdzd3aBTupK1kJuoJNBHuh0laPBvYXhjzZxR0qkeXcGC_0Dxf4UMhkR7ZNb04dQ
distancia=15
AutoCoord=1
user_add_locality=0
SaveContactForm=0
ShowVoteRating=0
Listlayout=0
WidthThumbs=100
HeightThumbs=75
WidthImage=640
HeightImage=480
ShowImagesSystem=1
ShowOrderBy=0
ShowOrderByDefault=0
ShowOrderDefault=DESC
SimbolPrice=$
PositionPrice=0
FormatPrice=0
ShowLogoAgent=1
ShowReferenceInList=1
ShowCategoryInList=1
ShowTypeInList=1
ShowAddressInList=1
ShowContactLink=1
ShowMapLink=1
ShowAddShortListLink=1
ShowViewPropertiesAgentLink=1
ThumbsInAccordion=5
WidthThumbsAccordion=100
HeightThumbsAccordion=75
ShowFeaturesInList=1
ShowAllParentCategory=0
AmountPanel=
AmountForRegistered=5
RegisteredAutoPublish=1
AmountForAuthor=5
AmountForEditor=5
AmountForPublisher=5
AmountForManager=5
AmountForAdministrator=5
AutoPublish=1
MailAdminPublish=1
DetailLayout=0
ActivarTabs=0
ActivarDescripcion=1
ActivarDetails=1
ActivarVideo=1
ActivarPanoramica=1
ActivarContactar=1
ContactMailFormat=1
ActivarReservas=1
ActivarMapa=1
ShowImagesSystemDetail=1
WidthThumbsDetail=120
HeightThumbsDetail=90
idCountryDefault=1
idStateDefault=1
ms_country=1
ms_state=1
ms_locality=1
ms_category=1
ms_Subcategory=1
ms_type=1
ms_price=1
ms_bedrooms=1
ms_bathrooms=1
ms_parking=1
ShowTextSearch=1
minprice=
maxprice=
ms_catradius=1
idcatradius1=
idcatradius2=
ShowTotalResult=1
md_country=1
md_state=1
md_locality=1
md_category=1
md_type=1
showComments=0
useComment2=0
useComment3=0
useComment4=0
useComment5=0
AmountMonthsCalendar=3
StartYearCalendar=2009
StartMonthCalendar=1
PeriodOnlyWeeks=0
PeriodAmount=3
PeriodStartDay=1
apikey=ABQIAAAAJ879Hg7OSEKVrRKc2YHjixSmyv5A3ewe40XW2YiIN-ybtu7KLRQiVUIEW3WsL8vOtIeTFIVUXDOAcQ
";
in that string only i want "api==ABQIAAAAJ879Hg7OSEKVrRKc2YHjixSmyv5A3ewe40XW2YiIN-ybtu7KLRQiVUIEW3WsL8vOtIeTFIVUXDOAcQ";
plz guide me correctly;
EDIT
As shamittomar pointed out, the parse_str will not work for this situation, posted the proper regex below.
Given this seems to be a QUERY STRING, use the parse_str() function PHP provides.
UPDATE
If you want to do it with regex using preg_match() as powertieke pointed out:
preg_match('/apikey=(.*)/', $var, $matches);
echo $matches[1];
Should do the trick.
preg_match(); should be right up your alley
people are so fast to jump to preg match when this can be done with regular string functions thats faster.
$string = '
expireDays=5
apikey=ABQIAAAAFHktBEXrHnX108wOdzd3aBTupK1kJuoJNBHuh0laPBvYXhjzZxR0qkeXcGC_0Dxf4UMhkR7ZNb04dQ
distancia=15
AutoCoord=1';
//test to see what type of line break it is and explode by that.
$parts = (strstr($string,"\r\n") ? explode("\r\n",$string) : explode("\n",$string));
$data = array();
foreach($parts as $part)
{
$sub = explode("=",trim($part));
if(!empty($sub[0]) || !empty($sub[1]))
{
$data[$sub[0]] = $sub[1];
}
}
and use $data['apikey'] for your api key, i would also advise you to wrpa in function.
I can bet this is a better way to parse the string and much faster.
function ParsemyString($string)
{
$parts = (strstr($string,"\r\n") ? explode("\r\n",$string) : explode("\n",$string));
$data = array();
foreach($parts as $part)
{
$sub = explode("=",trim($part));
if(!empty($sub[0]) || !empty($sub[1]))
{
$data[$sub[0]] = $sub[1];
}
}
return $data;
}
$data = ParsemyString($string);
First of all, you are not looking for
api==ABQIAAAAJ879Hg7OSEKVrRKc2YHjixSmyv5A3ewe40XW2YiIN-ybtu7KLRQiVUIEW3WsL8vOtIeTFIVUXDOAcQ
but you are looking for
apikey=ABQIAAAAJ879Hg7OSEKVrRKc2YHjixSmyv5A3ewe40XW2YiIN-ybtu7KLRQiVUIEW3WsL8vOtIeTFIVUXDOAcQ
It is important to know if the api-key property always occurs at the end and if the length of the api-key value is always the same. I this is the case you could use the PHP substr() function which would be easiest.
If not you would most probably need a regular expression which you can feed to PHPs preg_match() function. Something along the lines of apikey==[a-zA-Z0-9\-] Which matches an api-key containing a-z in both lowercase and uppercase and also allows for dashes in the key. If you are using the preg_match() function you can retrieve the matches (and thus your api-key value).
I have fooled around with regex but can't seem to get it to work. I have a file called includes/header.php I am converting the file into one big string so that I can pull out a certain portion of the code to paste in the html of my document.
$str = file_get_contents('includes/header.php');
From here I am trying to get return only the string that starts with <ul class="home"> and ends with </ul>
try as I may to figure out an expression I am still confused.
Once I trim down the string I can just print that on my page but I can't figure out the trimming part
If you need something really hardcore, http://www.php.net/manual/en/book.xmlreader.php.
If you just want to rip out the text that fits that pattern try something like this.
$string = "stuff<ul class=\"home\">alsdkjflaskdvlsakmdf<another></another></ul>stuff";
if( preg_match( '/<ul class="home">(.*)<\/ul>/', $string, $match ) ) {
//do stuff with $match[0]
}
I'm assuming that the difficulty you're having has to do with escaping the regex special characters in the string(s) you're using as a delimiter. If so, try using the preg_quote() function:
$start = preg_quote('<ul class="home">');
$end = preg_quote('</ul>', '/');
preg_match("/" . $start. '.*' . $end . "/", $str, $matching_html_snippets);
The html you want should be in $matching_html_snippets[0]
You probably want an XML parser such as the built in one. Here is an example you might want to take a look at.
http://www.php.net/manual/en/function.xml-parse.php#90733
If you want to use regex then something along the lines of
$str = file_get_contents('includes/header.php');
$matchedstr = preg_match("<place your pattern here>", $str, $matches);
You probably want the pattern
'/<ul class="home">.*?<\/ul>/s'
Where $matches will contain an array of the matches it found so you can grab whatever element you want from the array with
$matchedstr[0];
which will return the first element. And then output that.
But I'd be a bit wary, regular expressions do tend to match to surprising edge cases and you need to feed them actual data to get reliable results as to when they are failing. However if you are just passing templates it should be ok, just do some tests and see if it all works. If not I'd still recommend using the PHP XML Parser.
Hope that helps.
If you feel like not using regexes you could use string finding, which I think the PHP manual implies is quicker:
function substrstr($orig, $startText, $endText) {
//get first occurrence of the start string
$start = strpos($orig, $startText);
//get last occurrence of the end string
$end = strrpos($orig, $endText);
if($start === FALSE || $end === FALSE)
return $orig;
$start++;
$length = $end - $start;
return substr($orig, $start, $length);
}
$substr = substrstr($string, '<ul class="home">', '</ul>');
You'll need to make some adjustments if you want to include the terminating strings in the output, but that should get you started!
Here's a novel way to do it; I make no guarantees about this technique's robustness or performance, other than it does work for the example given:
$prefix = '<ul class="home">';
$suffix = '</ul>';
$result = $prefix . array_shift(explode($suffix, array_pop(explode($prefix, $str)))) . $suffix;