I'm trying to find the best way to grab the dynamic substring, but replace all of the content after.
This is what I'm trying to achieve:
{table_telecommunications}
The substring {table_ is always the same, the only that varies is telecommunications}.
I want to grab the word telecommunications so I can do a search on a MySQL table and then replace {table_telecommunications} with the content returned.
I thought of making a strpos and then explode and so on.
But I guess it would be easier with regex, but I have no skills on creating regex.
Could you possibly give me the best way to do this?
Edit: I'm saying possibly regex is the best way because I need to find strings that are in this format, but the second part is variable, just like {table_*}
Use Regex.
<?php
$string = "{table_telecommunications} blabla blabla {table_block}";
preg_match_all("/\{table_(.+?)\}/is", $string, $matches);
$substrings = $matches[1];
print_r($substrings);
?>
if (preg_match('#table_([^}]+)}#', '{table_telecommunications}', $matches)){
echo $matches[1];
}
That's a regex solution. You can do the same with explode:
$parts = explode('table_', '{table_telecommunications}');
echo substr($parts[1], 0, -1);
$input = '{table_telecommunications}';
$table_name = trim(implode('_', array_shift(explode($input, '_'))), '}');
Should be fast, no regex required.
Related
I have a server application which looks up where the stress is in Russian words. The end user writes a word жажда. The server downloads a page from another server which contains the stresses indicated with apostrophes for each case/declension like this жа'жда. I need to find that word in the downloaded page.
In Russian the stress is always written after a vowel. I've been using so far a regex that is a grouping of all possible combinations (жа'жда|жажда'). Is there a more elegant solution using just a regex pattern instead of making a PHP script which creates all these combinations?
EDIT:
I have a word жажда
The downloaded page contains the string жа'жда. (notice the
apostrophe, I do not before-hand know where the apostrophe in the
word is)
I want to match the word with apostrophe (жа'жда).
P.S.: So far I have a PHP script creating the string (жа'жда|жажда') used in regex (apostrophe is only after vowels) which matches it. My goal is to get rid of this script and use just regex in case it's possible.
If I understand your question,
have these options (d'isorder|di'sorder|dis'order|diso'rder|disor'der|disord'er|disorde'r|disorder') and one of these is in the downloaded page and I need to find out which one it is
this may suit your needs:
<pre>
<?php
$s = "d'isorder|di'sorder|dis'order|diso'rder|disor'der|disord'er|disorde'r|disorder'|disorde'";
$s = explode("|",$s);
print_r($s);
$matches = preg_grep("#[aeiou]'#", $s);
print_r($matches);
running example: https://eval.in/207282
Uhm... Is this ok with you?
<?php
function find_stresses($word, $haystack) {
$pattern = preg_replace('/[aeiou]/', '\0\'?', $word);
$pattern = "/\b$pattern\b/";
// word = 'disorder', pattern = "diso'?rde'?r"
preg_match_all($pattern, $haystack, $matches);
return $matches[0];
}
$hay = "something diso'rder somethingelse";
find_stresses('disorder', $hay);
// => array(diso'rder)
You didn't specify if there can be more than one match, but if not, you could use preg_match instead of preg_match_all (faster). For example, in Italian language we have àncora and ancòra :P
Obviously if you use preg_match, the result would be a string instead of an array.
Based, on your code, and the requirements that no function is called and disorder is excluded. I think this is what you want. I have added a test vector.
<pre>
<?php
// test code
$downloadedPage = "
there is some disorde'r
there is some disord'er in the example
there is some di'sorder in the example
there also' is some order in the example
there is some disorder in the example
there is some dso'rder in the example
";
$word = 'disorder';
preg_match_all("#".preg_replace("#[aeiou]#", "$0'?", $word)."#iu"
, $downloadedPage
, $result
);
print_r($result);
$result = preg_grep("#'#"
, $result[0]
);
print_r($result);
// the code you need
$word = 'also';
preg_match("#".preg_replace("#[aeiou]#", "$0'?", $word)."#iu"
, $downloadedPage
, $result
);
print_r($result);
$result = preg_grep("#'#"
, $result
);
print_r($result);
Working demo: https://eval.in/207312
I know it may sound as a common question but I have difficulty understanding this process.
So I have this string:
http://domain.com/campaign/tgadv?redirect
And I need to get only the word "tgadv". But I don't know that the word is "tgadv", it could be whatever.
Also the url itself may change and become:
http://domain.com/campaign/tgadv
or
http://domain.com/campaign/tgadv/
So what I need is to create a function that will get whatever word is after campaign and before any other particular character. That's the logic..
The only certain thing is that the word will come after the word campaign/ and that any other character that will be after the word we are searching is a special one ( i.e. / or ? )
I tried understanding preg_match but really cannot get any good result from it..
Any help would be highly appreciated!
I would not use a regex for that. I would use parse_url and basename:
$bits = parse_url('http://domain.com/campaign/tgadv?redirect');
$filename = basename($bits['path']);
echo $filename;
However, if want a regex solution, use something like this:
$pattern = '~(.*)/(.*)(\?.*)~';
preg_match($pattern, 'http://domain.com/campaign/tgadv?redirect', $matches);
$filename = $matches[2];
echo $filename;
Actually, preg_match sounds like the perfect solution to this problem. I assume you are having problems with the regex?
Try something like this:
<?php
$url = "http://domain.com/campaign/tgadv/";
$pattern = "#campaign/([^/\?]+)#";
preg_match($pattern, $url, $matches);
// $matches[1] will contain tgadv.
$path = "http://domain.com/campaign/tgadv?redirect";
$url_parts = parse_url($path);
$tgadv = strrchr($url_parts['path'], '/');
You don't really need a regex to accomplish this. You can do it using stripos() and substr().
For example:
$str = '....Your string...';
$offset = stripos($str, 'campaign/');
if ( $offset === false ){
//error, end of h4 tag wasn't found
}
$offset += strlen('campaign/');
$newStr = substr($str, $offset);
At this point $newStr will have all the text after 'campaign/'.
You then just need to use a similar process to find the special character position and use substr() to strip the string you want out.
You can also just use the good old string functions in this case, no need to involve regexps.
First find the string /campaign/, then take the substring with everything after it (tgadv/asd/whatever/?redirect), then find the next / or ? after the start of the string, and everything in between will be what you need (tgadv).
I am going to parse a log file and I wonder how I can convert such a string:
[5189192e][game]: kill killer='0:Tee' victim='1:nameless tee' weapon=5 special=0
into some kind of array:
$log['5189192e']['game']['killer'] = '0:Tee';
$log['5189192e']['game']['victim'] = '1:nameless tee';
$log['5189192e']['game']['weapon'] = '5';
$log['5189192e']['game']['special'] = '0';
The best way is to use function preg_match_all() and regular expressions.
For example to get 5189192e you need to use expression
/[0-9]{7}e/
This says that the first 7 characters are digits last character is e you can change it to fits any letter
/[0-9]{7}[a-z]+/
it is almost the same but fits every letter in the end
more advanced example with subpatterns and whole details
<?php
$matches = array();
preg_match_all('\[[0-9]{7}e\]\[game]: kill killer=\'([0-9]+):([a-zA-z]+)\' victim=\'([0-9]+):([a-zA-Z ]+)\' weapon=([0-9]+) special=([0-9])+\', $str, $matches);
print_r($matches);
?>
$str is string to be parsed
$matches contains the whole data you needed to be pared like killer id, weapon, name etc.
Using the function preg_match_all() and a regex you will be able to generate an array, which you then just have to organize into your multi-dimensional array:
here's the code:
$log_string = "[5189192e][game]: kill killer='0:Tee' victim='1:nameless tee' weapon=5 special=0";
preg_match_all("/^\[([0-9a-z]*)\]\[([a-z]*)\]: kill (.*)='(.*)' (.*)='(.*)' (.*)=([0-9]*) (.*)=([0-9]*)$/", $log_string, $result);
$log[$result[1][0]][$result[2][0]][$result[3][0]] = $result[4][0];
$log[$result[1][0]][$result[2][0]][$result[5][0]] = $result[6][0];
$log[$result[1][0]][$result[2][0]][$result[7][0]] = $result[8][0];
$log[$result[1][0]][$result[2][0]][$result[9][0]] = $result[10][0];
// $log is your formatted array
You definitely need a regex. Here is the pertaining PHP function and here is a regex syntax reference.
Basically from a database I am getting data that is formatted like this nameofproject101 Now this could continue to increase so eventually it could be nameofproject1001 my question is how can I trim off the number and just get the name of the project. I thought about using substr but since I dont know the length always I cant really do that. Since the numbers differ I dont think I can use str_replace is there any way to accomplish this?
It sounds like something is way off about your database scheme. You should probably try to do refactor/normalize your scheme.
But in the meantime, you can use rtrim() to trim all numbers off of the right side.
$val = rtrim($val, '0123456789');
Examples
Input Output
nameofproject1001 nameofproject
nameofproject nameofproject
n4me0fproj3ct1001 n4me0fproj3ct
for string like, project12V123, It is better to do this
$text = `project12V123`;
$text = preg_replace('/([\w]+)([^0-9])([0-9])+$/', '$1$2', $text);
Will return:
Project12V
or use rtrim:
$text = rtrim($text,'0123456789');
You should definitely use regular expressions:
$fullname = "nameofproject101";
preg_match("/([a-z]+)([0-9]+)/i", $fullname, $matches);
$name = $matches[1];
$number = $matches[2];
echo "'$fullname' is '$name' followed by '$number'";
preg_replace('/[^a-z]/i', '', $string);
I have some testcases/strings in this format:
o201_01_01a_Testing_to_see_If_this_testcases_passes:without_data
o201_01_01b_Testing_to_see_If_this_testcases_passes:data
rx01_01_03d_Testing_the_reconfiguration/Retest:
Actually this testcase name consists of the actual name and the description.
So, I want to split them like this :
o201_01_01a Testing_to_see_If_this_testcases_passes:without_data
o201_01_01b Testing_to_see_If_this_testcases_passes:data
rx01_01_03d Testing_the_reconfiguration/Retest:
I am unable to figure out the exact way to do this in explode in php
Can anyone help please?
Thanks.
If the first part has always the same length, why don't you use substr, e.g.
$string = "o201_01_01a_Testing_to_see_If_this_testcases_passes:without_data";
$first_part = substr($string, 0, 11); // o201_01_01a
$second_part = substr($string, 12); // Testing_to_see_If_this_testcases_passes:without_data
$results = preg_split("/([a-z0-9]+_[0-9]+_[0-9]+[a-z])(.*)/", $input);
That should give you an array of results, provided I got the regular expression correct.
http://www.php.net/manual/en/function.preg-split.php
Looking at the pattern, it appears that you need to use regular expressions. If this is how they all are, you can cut off the beginning by looking for an upper case character. The code might look like this:
$matches = array()
preg_match('/^[^A-Z]*?/', $string, $matches);
$matches = substr($matches[0], 0, count($matches[0])-1);
Would put the first little part into $matches. Working on second part...