sql search using like not working - php

i have an search box on website but whenever we search, it doesn't give any output.
I want to search for page title from database. But don't know what is wrong.
<div id="siteSearch">
<h3>Site Search</h3>
<?php
if (isset($_POST['search'])) {
$search = $_POST['search'];
$query = "SELECT * FROM pages WHERE ptitle LIKE '%$search%'";
$result = mysql_query($query) or die(mysql_error());
$count = mysql_num_rows($result);
if ($count > 0) {
while ($fetch = mysql_fetch_array($result)) {
echo $fetch['ptitle'];
}
}
} else {
echo "No result found!";
}
?>
</div>

You are using the semicolon after the while loop:
while($fetch = mysql_fetch_array($result));
Please remove the semicolon in this line.

You have a misplaced closing bracket. The one above else should be 5 lines below. As it currently stands, the else clause relates to if (isset($_POST['search'])).

Related

Need assistance with MySQL query into array and output into an echo

I need some PHP coding assistance in building an echo to display the results of a database query...(list friends of the logged-in user?) I have the majority of it built, but I don't know how to echo the results data and link it to his/her profile? Any help would be greatly appreciated...maybe a code snippet of how to write it out?
Here is my code:
$query = mysqli_query($db_conx, $sql);
$numrows = mysqli_num_rows($query);
if ($numrows > 0){
while($row = mysqli_fetch_array($query, MYSQLI_ASSOC)){
array_push($my_friends, $row["user2"]);
array_push($my_friends, $row["user1"]);
}
//remove your id from array
$my_friends = array_diff($my_friends, array($u));
//reset the key values
$my_friends = array_values($my_friends);
mysqli_free_result($query);
} else {
echo "You have no friends.";
}
// Build My friends From Results
****this is where I need help with*****
if (array_key_exists('0', $my_friends)){
$sql = "SELECT user1, user2
FROM friends
WHERE (user1='$u' OR user2='$u')
AND accepted='1'";
$result = mysqli_query($db_conx, $sql);
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
$my_friends = "<a href='user.php?u=".$result."'>". $row['avatar']. '&nbsp'. $row['firstname']. '&nbsp' .$row['lastname'] ."</a>"; }
}
?>
Here is my html code:
<?php
echo "<li>$my_friends</li>";
?>
You are using the $result variable in the html link. Replace it with $row['id'] or the row attribute you use as GET parameter to see a user's detailed page

Search works properly, only first result not shown

Title should make the problem clear. The search function works as intended, but what should be the first hit will not show at all and i don't know why. Here's the code:
<form action="admin_orders_search.php" method="GET">
<input type="text" name="query" value="Search"/>
</form>
<?php
$query = $_GET['query'];
$query = htmlspecialchars($query);
$query = mysql_real_escape_string($query);
$sql = "SELECT * FROM orders WHERE 1";
$matches = preg_split('/\s+/',$query);
foreach($matches as $match){
$sql .= " AND `ship_eta` LIKE '%".$match."%'";
}
$raw_results = mysql_query($sql) or die(mysql_error());
if(mysql_num_rows($raw_results) > 0){
while($results = mysql_fetch_array($raw_results))
{
// ---- RESULTS START ---->
$res=mysql_query("select * from orders ".$qry." order by id desc ");
while($row=mysql_fetch_array($raw_results))
{ ?>
// here are the hits shown
}
// ---- RESULT END ---->
}
}
else{
echo "No hits";
}
?>
In the code:
$res=mysql_query("select * from orders ".$qry." order by id desc ");
while($row=mysql_fetch_array($raw_results))
{
//results here
}
You still use the variable $raw_results. I think you want to use the variable $res since you already have a while with the $raw_results
Ive found some unused lines in the code and after removing them it works! The affected lines are these:
...
if(mysql_num_rows($raw_results) > 0){
// ---- RESULTS START ---->
while($row=mysql_fetch_array($raw_results))
{ ?>
// here are the hits
}
// ---- RESULT END ---->
}
else{
echo "No hits";
}
}
else{
echo "error: ".$min_length." needed minimum!";
}
?>
// ---- SEARCH END ---->
<?php
}
}
?>

While-loop inside else-statement not printing all answers

I got this code, which is linked to a search field on my index page:
<?php
ini_set('display_errors', 2);
$search = $_GET ['q'];
$conn = mysqli_connect("localhost", "root", "","release");
$query = mysqli_query($conn,"SELECT * FROM game WHERE game_name LIKE '%". $search ."%'");
$foundnum = mysqli_fetch_assoc($query);
$count = count($foundnum['game_name']);
if ($foundnum == 0) {
echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
}
else {
while($foundnum= mysqli_fetch_assoc($query))
{
echo "$count result(s) found!<p>";
echo"<pre/>";print_r($foundnum['game_name']);
echo"<pre/>";print_r($foundnum['game_release']);
}
}
?>
Everything's working fine without the while-loop, but because some search terms ('car' for example), should print both Project CARS and Rise of Incarnates, I need a while-loop.
I tried putting the while-loop before the if-statement as well, but that doesnt work either. What am I doing wrong?
I have made some correction in your code.. please re-veirfy using below code
I have tried the code using my db tables and it is showing correct values...
<?php
ini_set('display_errors', 1);
$search = $_GET['q'];
$conn = mysqli_connect("localhost", "root", "", "release");
$query = mysqli_query($conn, "SELECT * FROM game WHERE game_name LIKE '%" . $search . "%'");
$count = mysqli_num_rows($query); // right way to find row count
if ($count == 0)
{
echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
}
else
{
while ($foundnum = mysqli_fetch_assoc($query))
{
echo "$count result(s) found!<p>";
echo"<pre>";
print_r($foundnum['game_name']);
echo"</pre><pre>";
print_r($foundnum['game_code']);
echo"</pre>";
}
}
?>
if you want to search insensitively (i.e ignoring capital and small letters) than do let me know.. I will update the code

Echo message based on row number in php

I have a table which displays information from a database. I added a column where I want to display a message according to row number displayed.
<form name="afisare1" method="POST" >
<input type="submit" name="opt1" value="OK"/>
<?php
if (isset($_POST['opt1'])) {
$loc=mysql_query("SELECT loc FROM program WHERE den='Option'");
//$loc result is a number
$sql=mysql_query("SELECT Col1, Col2
FROM date WHERE Opt_1='Option' OR Opt_2='Option'
ORDER BY Col2 DESC");
?>
<table>
<thead>
<tr>
<th>Col1</th> <th>Col2</th> <th>OK/NOT OK</th>
</tr>
</thead>
<?php
$num_rows = 0;
while ($row = mysql_fetch_assoc($sql)) {
$num_rows++;
if ($num_rows <= $loc) {
echo"<tr>
<td>".$row['Col1']."</td><td >".$row['Col2']."</td><td>OK</td>
</tr>";
break;
}
if ($num_rows > $locuri_buget) {
//here i have a problem because i don't know how to display something like this :
//echo"<tr><td>".$row['Col1']."</td><td >".$row['Col2']."</td><td>NOT OK</td></tr>";
}
}
} ?>
</table>
</form>
For example if the result of $loc=2 i want to echo for the first 2 rows OK and for extra rows i want to echo NOT OK
To retrieve loc from MySQL, your original code does it like this:
$loc = mysql_query("SELECT loc FROM program WHERE den='Option'");
But you might want to change it like this:
$loc = 0; # default value in case of error in a query
$result = mysql_query("SELECT loc FROM program WHERE den='Option'");
while($row = mysql_fetch_assoc($result)){
$loc = $row['loc'];
}
Or if you want retrieve only one record from your databse, you can also write a SQL with LIMIT like this:
$loc = 0; # default value in case of error in a query
$result = mysql_query("SELECT loc FROM program WHERE den='Option' LIMIT 1");
if($row = mysql_fetch_assoc($result)){
$loc = $row['loc'];
}
Hope this helps.
You can try with following inside while loop
if($num_rows<=$loc){
echo"<tr><td>".$row['Col1']."</td><td >".$row['Col2']."</td><td>OK</td></tr>";
}else{
echo"<tr><td>".$row['Col1']."</td><td >".$row['Col2']."</td><td>NOT OK</td></tr>";
}
$num_rows = 0;
while($row = mysql_fetch_assoc($sql)){
$num_rows++;
if($num_rows<=$loc){
echo"<tr><td>".$row['Col1']."</td><td >".$row['Col2']."</td><td>OK</td></tr>";
}else {
echo"<tr><td>".$row['Col1']."</td><td >".$row['Col2']."</td><td>OK</td></tr>";
}
}
I think your problem is with break,
break ends execution of the current for, foreach, while, do-while or switch structure.
Break

How to read and display one:many tables in PHP?

I am trying to combine two things which are already know how to do, but can't figure out how to combine them. Here is what I want to achieve:
I have a database with locations and events. There are several events in each location. I will be using PHP to query the database and output the code needed to display search results. I want something similar to the below:
<div id="location">
<p>Location1</p>
<div id="event">Event1</div>
<div id="event">Event2</div>
<div id="event">Event3</div>
</div>
<div id="location">
<p>Location2</p>
<div id="event">Event4</div>
<div id="event">Event5</div>
<div id="event">Event6</div>
</div>
I know that I can use select distinct to get the unique value of each location, and know that I can use a normal select statement to get all the events, however how do add all the events inside the location div?
My current PHP looks like this:
$sql ="SELECT location, event from events";
$res = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($res)){
$location = $row['location'];
$event = $row['event'];
echo "<div id="location">
<p>$location</p>
<div id="event">$event</div>
</div>";
}
My current code adds duplicates of the same location with 1 unique event in each. Even if I use select distinct I get the same results. How do I group the events have have the same location?
I think you should write something like:
$sql ="SELECT location, event from events";
$res = mysql_query($sql) or die(mysql_error());
$prevlocation = "";
while($row = mysql_fetch_assoc($res))
{
$location = $row['location'];
$event = $row['event'];
if ( $prevlocation != "" ) // Close previous div if needed
{
echo "</div>";
}
if ( $location != $prevlocation )
{
echo "<div id='location'><p>$location</p>";
$prevlocation = $location;
}
else
{
echo "<div id='event'>$event</div>";
}
}
echo "</div>"; // Close last div
If you have join of two tables, let's assume that your query looks like this:
$sql ="SELECT * FROM events
JOIN locations ON
locations.id=events.loc_id";
And then, within one loop, get events and location arrays:
$res = mysql_query($sql) or die(mysql_error());
$locations = array();
$events= array();
while($row = mysql_fetch_assoc($res))
{
$location = $row['location'];
$event = $row['event'];
$loc_id=$row['loc_id'];
$id=$row['id'];
$events[]=$loc_id.'%'.$event;
if(!in_array($id.'%'.$location,$locations)) { // avoid duplicate entries
$locations[]=$id.'%'.$location;
}
}
And, another loop (+loop inside loop):
for($i=0;$i<count($locations);$i++) {
$location=explode('%',$locations[$i]);
echo "<div class='location'>\n
<p>$location[1]</p>\n";
for($j=0;$j<count($events);$j++) {
$event=explode('%',$events[$j]);
if($event[0]==$locations[$i][0]) {
echo "<div class='event'>".$event[1]."</div>";
}
}
echo "</div>";
}
Not so elegant, but it is working, and produces valid HTML. :)
First, i wanted to make two associative arrays, and to compare keys, but i couldn't, because i couldn't convert ID keys to strings, so i made it with explode (% is separator between key and value).

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