How to read and display one:many tables in PHP? - php

I am trying to combine two things which are already know how to do, but can't figure out how to combine them. Here is what I want to achieve:
I have a database with locations and events. There are several events in each location. I will be using PHP to query the database and output the code needed to display search results. I want something similar to the below:
<div id="location">
<p>Location1</p>
<div id="event">Event1</div>
<div id="event">Event2</div>
<div id="event">Event3</div>
</div>
<div id="location">
<p>Location2</p>
<div id="event">Event4</div>
<div id="event">Event5</div>
<div id="event">Event6</div>
</div>
I know that I can use select distinct to get the unique value of each location, and know that I can use a normal select statement to get all the events, however how do add all the events inside the location div?
My current PHP looks like this:
$sql ="SELECT location, event from events";
$res = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($res)){
$location = $row['location'];
$event = $row['event'];
echo "<div id="location">
<p>$location</p>
<div id="event">$event</div>
</div>";
}
My current code adds duplicates of the same location with 1 unique event in each. Even if I use select distinct I get the same results. How do I group the events have have the same location?

I think you should write something like:
$sql ="SELECT location, event from events";
$res = mysql_query($sql) or die(mysql_error());
$prevlocation = "";
while($row = mysql_fetch_assoc($res))
{
$location = $row['location'];
$event = $row['event'];
if ( $prevlocation != "" ) // Close previous div if needed
{
echo "</div>";
}
if ( $location != $prevlocation )
{
echo "<div id='location'><p>$location</p>";
$prevlocation = $location;
}
else
{
echo "<div id='event'>$event</div>";
}
}
echo "</div>"; // Close last div

If you have join of two tables, let's assume that your query looks like this:
$sql ="SELECT * FROM events
JOIN locations ON
locations.id=events.loc_id";
And then, within one loop, get events and location arrays:
$res = mysql_query($sql) or die(mysql_error());
$locations = array();
$events= array();
while($row = mysql_fetch_assoc($res))
{
$location = $row['location'];
$event = $row['event'];
$loc_id=$row['loc_id'];
$id=$row['id'];
$events[]=$loc_id.'%'.$event;
if(!in_array($id.'%'.$location,$locations)) { // avoid duplicate entries
$locations[]=$id.'%'.$location;
}
}
And, another loop (+loop inside loop):
for($i=0;$i<count($locations);$i++) {
$location=explode('%',$locations[$i]);
echo "<div class='location'>\n
<p>$location[1]</p>\n";
for($j=0;$j<count($events);$j++) {
$event=explode('%',$events[$j]);
if($event[0]==$locations[$i][0]) {
echo "<div class='event'>".$event[1]."</div>";
}
}
echo "</div>";
}
Not so elegant, but it is working, and produces valid HTML. :)
First, i wanted to make two associative arrays, and to compare keys, but i couldn't, because i couldn't convert ID keys to strings, so i made it with explode (% is separator between key and value).

Related

Handle query results properly multiple rows and columns

I want to do a a query to a mysql database that returns multiple rows and columns. I then want to assign the results to a variable and echo them out later in the page. However, the method I am using is long, tedious, and for this project impractical. here is what I am doing.
$result = mysql_query("SELECT * FROM people WHERE open_or_closed !='Closed' ORDER BY
number",$c) or die("two");
$number=mysql_num_rows($result);
if($mynumber>0){
$data= mysql_fetch_array($result,MYSQL_ASSOC);
$full_name1=mysql_result($result,0, 'full_name');
$phone_number1=mysql_result($result,0, 'phone_number');
$one=1;
}
if($mynumber>1){
$full_name2=mysql_result($result,1, 'full_name');
$phone_number2=mysql_result($result,1, 'phone_number');
$two=2;
}
Later when I want to echo it, I will not know if there is a record there or not, so I will have to
<?php if($one==1){echo '<div id="blackline"></div>';}?>
<div id="titletext"><?php echo $full_name1; ?></div><br />
<div id="datetext"><?php echo $phone_number1; ?></div>
Try this
$result = mysql_query("SELECT * FROM people WHERE open_or_closed !='Closed' ORDER BY
number",$c) or die("two");
$number=mysql_num_rows($result);
if($number>0)
{
$i=0;
while($row_result = mysql_fetch_array($result))
{
$full_name[$i][] = $row_result['full_name'];
$phone_number[$i][] = $row_result['phone_number'];
$i++;
}
}

Multiple rows from db

I'm trying to echo out multiple rows from a sql database, but I get the error Warning. Illegal string offset 'Date' In....
$channel_check = mysql_query("SELECT content, Date FROM wgo WHERE Posted_By='$user' ORDER by `id` DESC;");
$numrows_cc = mysql_num_rows($channel_check);
if ($numrows_cc == 0) {
echo '';
// They don't have any channels so they need to create one?><h4> &nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbspYou haven't posted anything yet. You can post what's going on in your life, how you're feeling, or anything else that matters to you.</h4>
<?php
}
else
{
?>
<div id="recentc">
</div>
<?php
echo"<h2 id='lp'> Latest Posts</h2>";
while($row = mysql_fetch_array($channel_check)) {
$channel_name = $row['content']['Date'];
?>
<div style="margin-top:60px;">
<hr style="margin-right:340px;width:600px; opacity:0;">
<?php echo "<div id='rpc'><h6> $channel_name</h6></div>";?>
</div>
<?php
}
}
?>
DATE is a datatype in SQL, you need to escape it with back ticks
SELECT content, `Date` FROM wgo WHERE Posted_By='$user' ORDER by `id` DESC
Also, you're accessing your row incorrectly. Rows are typically represented by a uni-dimensional array, so $row['content'] and $row['Date']
$row is 1-dimensional array with 2 fields: content and Date.
Try,
while ($row = mysql_fetch_array($channel_check)) {
print_r($row);
//$channel_name = $row['content']['Date'];

Posting values to database

I am trying to post some values from checkboxes to my database, at the moment it does post a value, but only the last selected value (I currently have 8 checkboxes). Below is what I am using the get the checkboxes:
<?
$data = mysql_query("SELECT * FROM members WHERE active='Yes' ORDER BY name") or die(mysql_error());
//And we display the results
while($result = mysql_fetch_array( $data ))
{
echo "<input type='checkbox' name='attendees[]'";
echo 'value="' . $result['name'] . '">';
echo " ";
echo $result['name'];
echo "<br>";
}
?>
So they successfully show in my form and I can tick as many as I want however when I check the database, only the last one is showing.
I have been reading around and it seems like I need to store them in an array however this is the bit I am finding hard to understand.
Could anyone help me so that all values selected are shown in the DB and not just the last one?
EDIT: Too long to fit into a comment so here is the code where it adds the values to the DB
<?php
if(isset($_POST['submit']))
{
$date = $_POST['date'];
$score = $_POST['score'];
$attendees = $_POST['attendees'];
$result = mysql_query("INSERT INTO quiz_results (date, score, attendees)
VALUES ('$date','$score','$attendees')",$connect);
echo "<div class='alert alert-info'><b>Event Added!</b> - You'll will now be taken back to the previous page.</div>";
echo "<meta http-equiv=Refresh content=4;url=add-result.php>";
}//end of if($submit).
?>
$attendees = $_POST['attendees'];
$attendees is an array. You can't simply store the PHP array in the database without first transforming it into a string. You could store it as a comma separated list:
if ( is_array($attendees) ) {
$attendees = implode(', ', $attendees);
}
But, what happens when an "attendee" has a name that contains a comma? You could serialize it:
if ( is_array($attendees) ) {
$attendees = serialize($attendees);
}
But, in either case, what happens when you want to filter your data based on attendee? Now you have more problems.
The best way to manage this data (Google: database one-to-many relationships) is to store the attendees in a separate table that looks something like:
quiz_id attendee_id
1 20
1 42
1 50
See my answer at how to select from database based on a match in category? for an example.
Looks like you need to give each checkbox a different name.
$i=0;
while($result = mysql_fetch_array( $data ))
{
echo "<input type='checkbox' name='attendees[$i]'";
$i++
...
and I hope $_POST['attendees'] is an array?
Then when you insert into quiz results, you will need to loop through the arrays and insert one row of elements at a time into the database, you cant just insert arrays directly like that and expect each element to automatically take their own row.
Hope it helps, let me know.
View
<?php
$data = mysql_query("SELECT * FROM members WHERE active='Yes' ORDER BY name");
$html = '';
//And we display the results
while($result = mysql_fetch_array( $data )) {
$html .= sprintf( '<input type="checkbox" name="attendees[]" value="%d"> %s' , $result['id'] , $result['name'] );
}
echo $html;
When you post the form...
<?php
$attendees = isset( $_REQUEST['attendees'] ) ? $_REQUEST['attendees'] : null;
if( !is_null($attendees) && is_array($attendees)){
foreach( $attendees as $attendee){
// do something.. with attendee id
}
echo 'Ids: '.implode(', ', $attendees);
}

PHP MySQL omit result if contains phrase

I need some help with some PHP and MySQL code. At the moment I have a php file which displays the contents of a table in my database. I would like it to omit results that match "Not Booked". So the file only shows me slots which are booked. Here is my code:
<link href="../css/pagestyle.css" rel="stylesheet" type="text/css" />
<?php
include("../config.php");
include("functions.php");
if($logged["level"] == "HDJ" OR $logged["level"] == "SA") {
echo "<div class=\"head\">View Booked Slots</div>
<img src=\"../images/spacer.png\" width=\"5\" height=\"5\">
<div class=\"board\">Here you can view booked slots.</div>
<img src=\"../images/spacer.png\" width=\"5\" height=\"5\">
<table width=\"580px\" class=\"board\" border=\>";
$order = "SELECT * FROM timetable";
$result = mysql_query($order);
while ($row=mysql_fetch_array($result)){
echo ("<tr><td>$row[username]</td>");
</tr>");
}
echo "
</table>
";
} else {
echo ("<div class=\"caution\">Access is denied.</div>");
}
?>
Modify the query not to pull them in the first place.
$order = "SELECT * FROM timetable WHERE <the column> <> 'Not Booked';
Replace <the column> with the correct column name in your table where Not Booked appears.
It is often not advisable to intermix database logic and display logic as you have done here. Instead, you ought to do the query before outputting your table, and store its results in an array. Then loop over the array to display your table.
$order = "SELECT * FROM timetable WHERE somecolumn <> 'Not Booked'";
$result = mysql_query($order);
// Error checking
if (!$result) {
// output error, take other action
}
else {
while ($row=mysql_fetch_array($result)){
// Append all results onto an array
$rowset[] = $row;
}
}
Later, loop over the array to output your values. Dont' forget to escape it for HTML output with htmlspecialchars().
foreach ($rowset as $row) {
echo "<tr><td>" . htmlspecialchars($row['username']) . "</td></tr>";
}
In your mySQL code:
SELECT * FROM timetable WHERE myvariable <> 'Not Booked'
Michael's answer will only pull out results that MATCH 'Not Booked' rather than omit them. Tweak the code to:
$order = "SELECT * FROM timetable WHERE <the column> <> 'Not Booked';
And you'll get all the booked ones (assuming there are only two states)

How to select certain fields from table in mySQL using PHP

I'm trying out my hand at php at the moment - I'm very new to it!
I was wondering how you would go about selecting all items from a mySQL table (Using a SELECT * FROM .... query) to put all data into an array but then not displaying the data in a table form. Instead, using the extracted data in different areas of a web page.
For example:
I would like the name, DOB and favorite fruit to appear in one area where there is already say 'SAINSBURYS' section hardcoded into the page. Then further down the next row that is applicable to 'ASDA' to appear below that.
I searched both here and google and cant seem to find an answer to my strange questions! Would this involve running the query multiple times filtering out the sainsburies data and the asda data where ever I wanted to place the relevant
echo $row['name']." ";
echo $row['DOB']." "; etc etc
next to where it should go?
I have got php to include data into an array (I think?!)
$query = "SELECT * FROM people";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result) or die(mysql_error());
while($row = mysql_fetch_assoc($result))
{
echo $row['name']." ";
echo $row['DOB']." ";
echo $row['Fruit']." ";
}
?>
Just place this (or whatever your trying to display):
echo $row['name']." ";
Anywhere you want the info to appear. You can place it within HTML if you want, just open new php tags.
<h1>This is a the name <?php echo $row['name']." ";?></h1>
If you want to access your data later outside the while-loop, you have to store it elsewhere.
You could for example create a class + array and store the data in there.
class User {
public $name, $DOB, $Fruit;
}
$users = new array();
$query = "SELECT * FROM people";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
$user = new User;
$user->name = $row["name"];
$user->DOB = $row["DOB"];
$user->Fruit = $row["Fruit"];
$users[$row["name"]] = $user;
}
Now you can access the user-data this way:
$users["USERNAME"]->name
$users["USERNAME"]->DOB
$users["USERNAME"]->Fruit

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