Posting values to database - php

Question

I am trying to post some values from checkboxes to my database, at the moment it does post a value, but only the last selected value (I currently have 8 checkboxes). Below is what I am using the get the checkboxes:
<?
$data = mysql_query("SELECT * FROM members WHERE active='Yes' ORDER BY name") or die(mysql_error());
//And we display the results
while($result = mysql_fetch_array( $data ))
{
echo "<input type='checkbox' name='attendees[]'";
echo 'value="' . $result['name'] . '">';
echo " ";
echo $result['name'];
echo "<br>";
}
?>
So they successfully show in my form and I can tick as many as I want however when I check the database, only the last one is showing.
I have been reading around and it seems like I need to store them in an array however this is the bit I am finding hard to understand.
Could anyone help me so that all values selected are shown in the DB and not just the last one?
EDIT: Too long to fit into a comment so here is the code where it adds the values to the DB
<?php
if(isset($_POST['submit']))
{
$date = $_POST['date'];
$score = $_POST['score'];
$attendees = $_POST['attendees'];
$result = mysql_query("INSERT INTO quiz_results (date, score, attendees)
VALUES ('$date','$score','$attendees')",$connect);
echo "<div class='alert alert-info'><b>Event Added!</b> - You'll will now be taken back to the previous page.</div>";
echo "<meta http-equiv=Refresh content=4;url=add-result.php>";
}//end of if($submit).
?>

Answer 1

$attendees = $_POST['attendees'];
$attendees is an array. You can't simply store the PHP array in the database without first transforming it into a string. You could store it as a comma separated list:
if ( is_array($attendees) ) {
$attendees = implode(', ', $attendees);
}
But, what happens when an "attendee" has a name that contains a comma? You could serialize it:
if ( is_array($attendees) ) {
$attendees = serialize($attendees);
}
But, in either case, what happens when you want to filter your data based on attendee? Now you have more problems.
The best way to manage this data (Google: database one-to-many relationships) is to store the attendees in a separate table that looks something like:
quiz_id attendee_id
1 20
1 42
1 50
See my answer at how to select from database based on a match in category? for an example.

Answer 2

Looks like you need to give each checkbox a different name.
$i=0;
while($result = mysql_fetch_array( $data ))
{
echo "<input type='checkbox' name='attendees[$i]'";
$i++
...
and I hope $_POST['attendees'] is an array?
Then when you insert into quiz results, you will need to loop through the arrays and insert one row of elements at a time into the database, you cant just insert arrays directly like that and expect each element to automatically take their own row.
Hope it helps, let me know.

Answer 3

View
<?php
$data = mysql_query("SELECT * FROM members WHERE active='Yes' ORDER BY name");
$html = '';
//And we display the results
while($result = mysql_fetch_array( $data )) {
$html .= sprintf( '<input type="checkbox" name="attendees[]" value="%d"> %s' , $result['id'] , $result['name'] );
}
echo $html;
When you post the form...
<?php
$attendees = isset( $_REQUEST['attendees'] ) ? $_REQUEST['attendees'] : null;
if( !is_null($attendees) && is_array($attendees)){
foreach( $attendees as $attendee){
// do something.. with attendee id
}
echo 'Ids: '.implode(', ', $attendees);
}