While-loop inside else-statement not printing all answers - php

Question

I got this code, which is linked to a search field on my index page:
<?php
ini_set('display_errors', 2);
$search = $_GET ['q'];
$conn = mysqli_connect("localhost", "root", "","release");
$query = mysqli_query($conn,"SELECT * FROM game WHERE game_name LIKE '%". $search ."%'");
$foundnum = mysqli_fetch_assoc($query);
$count = count($foundnum['game_name']);
if ($foundnum == 0) {
echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
}
else {
while($foundnum= mysqli_fetch_assoc($query))
{
echo "$count result(s) found!<p>";
echo"<pre/>";print_r($foundnum['game_name']);
echo"<pre/>";print_r($foundnum['game_release']);
}
}
?>
Everything's working fine without the while-loop, but because some search terms ('car' for example), should print both Project CARS and Rise of Incarnates, I need a while-loop.
I tried putting the while-loop before the if-statement as well, but that doesnt work either. What am I doing wrong?

Answer 1

I have made some correction in your code.. please re-veirfy using below code
I have tried the code using my db tables and it is showing correct values...
<?php
ini_set('display_errors', 1);
$search = $_GET['q'];
$conn = mysqli_connect("localhost", "root", "", "release");
$query = mysqli_query($conn, "SELECT * FROM game WHERE game_name LIKE '%" . $search . "%'");
$count = mysqli_num_rows($query); // right way to find row count
if ($count == 0)
{
echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
}
else
{
while ($foundnum = mysqli_fetch_assoc($query))
{
echo "$count result(s) found!<p>";
echo"<pre>";
print_r($foundnum['game_name']);
echo"</pre><pre>";
print_r($foundnum['game_code']);
echo"</pre>";
}
}
?>
if you want to search insensitively (i.e ignoring capital and small letters) than do let me know.. I will update the code