Search works properly, only first result not shown - php

Question

Title should make the problem clear. The search function works as intended, but what should be the first hit will not show at all and i don't know why. Here's the code:
<form action="admin_orders_search.php" method="GET">
<input type="text" name="query" value="Search"/>
</form>
<?php
$query = $_GET['query'];
$query = htmlspecialchars($query);
$query = mysql_real_escape_string($query);
$sql = "SELECT * FROM orders WHERE 1";
$matches = preg_split('/\s+/',$query);
foreach($matches as $match){
$sql .= " AND `ship_eta` LIKE '%".$match."%'";
}
$raw_results = mysql_query($sql) or die(mysql_error());
if(mysql_num_rows($raw_results) > 0){
while($results = mysql_fetch_array($raw_results))
{
// ---- RESULTS START ---->
$res=mysql_query("select * from orders ".$qry." order by id desc ");
while($row=mysql_fetch_array($raw_results))
{ ?>
// here are the hits shown
}
// ---- RESULT END ---->
}
}
else{
echo "No hits";
}
?>

Answer 1

In the code:
$res=mysql_query("select * from orders ".$qry." order by id desc ");
while($row=mysql_fetch_array($raw_results))
{
//results here
}
You still use the variable $raw_results. I think you want to use the variable $res since you already have a while with the $raw_results

Answer 2

Ive found some unused lines in the code and after removing them it works! The affected lines are these:
...
if(mysql_num_rows($raw_results) > 0){
// ---- RESULTS START ---->
while($row=mysql_fetch_array($raw_results))
{ ?>
// here are the hits
}
// ---- RESULT END ---->
}
else{
echo "No hits";
}
}
else{
echo "error: ".$min_length." needed minimum!";
}
?>
// ---- SEARCH END ---->
<?php
}
}
?>