I have a table in my database named contacts and a table named views.
On the table contacts I have the following fields:
id
status
first_name
last_name
The status can be cold, prospect or lost.
On the table views I have the following fields:
user_id
art_views
art_title
The relation between those 2 tables is id and user_id.
I need a query to make a new html table with the following columns:
art_title
cold
prospect
lost
Now I have the following query (UPDATED):
SELECT
v.art_title,
SUM(CASE c.status WHEN 'cold' THEN v.art_views ELSE 0 END) cold,
SUM(CASE c.status WHEN 'prospect' THEN v.art_views ELSE 0 END) prospect,
SUM(CASE c.status WHEN 'lost' THEN v.art_views ELSE 0 END) lost
FROM views v
JOIN contacts c ON v.user_id = c.id
GROUP BY v.art_title
This query is working now (thanks to Gerv) but i still have users who don't have a status. So i leave the field user_id in the table 'views' empty. How can i change the query for those users so i can count them also?
I tried to: SUM(CASE v.user_id WHEN ' ' THEN v.art_views ELSE 0 END) test,
but with no result here.
You can switch the logic by selecting from the views table and joining de contacts table.
Below query will pivot the status with a CASE clause
SELECT
v.art_title,
SUM(CASE c.status WHEN 'cold' THEN v.art_views ELSE 0 END) cold,
SUM(CASE c.status WHEN 'prospect' THEN v.art_views ELSE 0 END) prospect,
SUM(CASE c.status WHEN 'lost' THEN v.art_views ELSE 0 END) lost,
SUM(CASE c.status WHEN NULL THEN v.art_views ELSE 0 END) no_user
FROM views v
LEFT JOIN contacts c ON v.user_id = c.id
GROUP BY v.art_title
ORDER BY (cold+lost+prospect+no_user) DESC
LIMIT 10
Try
SELECT art_title, SUM(art_views), status FROM contacts AS c INNER JOIN views AS v ON v.user_id = c.id GROUP BY v.art_title, c.status
Related
I want to create an output table that is a combination of the two input tables, as shown below. Table 1 and table 2 are MySQL tables. Output is the desired table view.
Please hlep me to billd this output from table1 and table2 (mysql)
You can use conditional aggregation with UNION ALL for this:
SELECT t1.acc_no, t1.name,
SUM(CASE WHEN t2.`date` = '2016-06-01' THEN amount END) AS '2016-06-01',
SUM(CASE WHEN t2.`date` = '2016-06-02' THEN amount END) AS '2016-06-02',
SUM(CASE WHEN t2.`date` = '2016-06-03' THEN amount END) AS '2016-06-03',
SUM(amount) AS 'Total'
FROM table1 AS t1
LEFT JOIN table2 AS t2 ON t1.acc_no = t2.acc_no
UNION ALL
SELECT 'Total', null,
SUM(CASE WHEN t2.`date` = '2016-06-01' THEN amount END) AS '2016-06-01',
SUM(CASE WHEN t2.`date` = '2016-06-02' THEN amount END) AS '2016-06-02',
SUM(CASE WHEN t2.`date` = '2016-06-03' THEN amount END) AS '2016-06-03',
SUM(amount) AS 'Total'
FROM table2
I am using this code to get the data of a team
SELECT `in_standings`.*, `in_teams`.`name` as team_name, `in_teams`.`logo` as team_logo, `in_teams`.`shortcode` as team_shortcode, lr.*, in_teams.id as team_id
FROM `in_standings` daa
LEFT JOIN `in_teams` ON `in_standings`.`team_id`= `in_teams`.`id`
left join
(SELECT team1_id,daa.team_id as teamID,
MAX(CASE WHEN rn = 1 THEN winning_team END) AS result1,
MAX(CASE WHEN rn = 2 THEN winning_team END) AS result2,
MAX(CASE WHEN rn = 3 THEN winning_team END) AS result3,
MAX(CASE WHEN rn = 4 THEN winning_team END) AS result4,
MAX(CASE WHEN rn = 5 THEN winning_team END) AS result5
FROM (
SELECT team1_id, winning_team,
#row_number := #row_number + 1 AS rn
FROM in_games
CROSS JOIN (SELECT #row_number := 0) AS vars
WHERE team1_id = teamID <!-- here is problem -->
) AS t) as lr on lr.team1_id=in_standings.team_id
WHERE `in_standings`.`division_id` = '21'
ORDER BY `in_standings`.`points` DESC
My sub query where i comment is not getting the team_id by which i want to set the result of last 5 matchs in a same row.
Could anyone solve where is the problem?
I have this tbl_religion with fieldname creldesc
and tbl_member with these fields
and I have this query to count all existing religion in tbl_member and count also the no. of male and female with that religion so i made this query :
SELECT m.creldesc as type,
COUNT(m.creldesc) as total,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m, tbl_barangay as b, tbl_household as h
WHERE m.chholdnumber = h.chholdnumber and h.cbrgycode=b.cbrgycode and b.cbrgyname = 'AGAO'
and m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC;
and get this output :
what I want to achieve is also display the remaining religion from tbl_religion with 0 as value. I made a left join but get an error. Can someone help me how can I achive that ?
type total male female
Roman Catholic 7 4 3
Baptist 3 1 2
Islam 3 3 0
Iglesia ni Cristo 1 1 0
Free Methodist 1 1 0
Ang Dating Daan 1 0 1
Aglipay/Filipinsta 0 0 0
All the Gospel 0 0 0
Alpha Omega 0 0 0
and so on.............................
Use same joining approach for all tables, like this:
SELECT m.creldesc as type, COUNT(m.creldesc) as tot,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_religion
LEFT JOIN tbl_member as m
ON tbl_religion.creldesc=m.creldesc
LEFT JOIN tbl_household as h
ON m.chholdnumber = h.chholdnumber
LEFT JOIN tbl_barangay as b
ON h.cbrgycode=b.cbrgycode
WHERE b.cbrgyname = 'AGAO' AND m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC
Your current query approach of ... FROM tbl_member, tbl_barangay, tbl_household LEFT JOIN tbl_religion ... is wrong and will produce syntax error.
You can not make this:
FROM #TABLE1, #TABLE2, #TABLE3 LEFT JOIN #TABLE0 ON ...
You can select items only from a table at once... same for join.
SELECT m.creldesc as type,
COUNT(m.creldesc) as tot,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m
LEFT JOIN tbl_religion z ON z.creldesc = m.creldesc
LEFT JOIN tbl_barangay h ON h.cbrgycode=b.cbrgycode
SO ON.... WITH JOINS
GROUP BY m.creldesc
UPDATE WOKING CODE:
SELECT m.creldesc as type, COUNT(m.creldesc) as tot, SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m
LEFT JOIN tbl_religion r ON r.creldesc = m.creldesc
LEFT JOIN tbl_barangay as b ON m.chholdnumber = b.cbrgycode
LEFT JOIN tbl_household as h ON h.cbrgycode = b.cbrgycode
WHERE b.cbrgyname = 'AGAO' and m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC
Here's what I did:
SELECT tbl_member.creldesc AS type,
COUNT(tbl_member.creldesc) AS total,
SUM(CASE WHEN tbl_member.cgender::text = 'Male'::text THEN 1 ELSE 0 END) AS male,
SUM(CASE WHEN tbl_member.cgender::text = 'Female'::text THEN 1 ELSE 0 END) AS female
FROM tbl_member
GROUP BY tbl_member.creldesc
UNION
SELECT b.creldesc AS type, 0 AS total, 0 AS male, 0 AS female
FROM tbl_religion b
WHERE NOT (b.creldesc::text IN
( SELECT DISTINCT tbl_member.creldesc FROM tbl_member))
GROUP BY b.creldesc;
and here is it's output :
that's all :) I used UNION instead of LEFT JOIN.
SELECT ac1.id, ac1.course_name, case when a.yettoapprove is not null
then 'true'
else 'false'
end OrderedAll , a.* from (SELECT ac.id, sum(case when ad.status = '2' then 1 else 0 end) as yettoapprove , sum(case when ad.status = '1' then 1 else 0 end) as approved,case when ad.status = '2' is not null
then 'true'
else 'false'
end OrderedAll FROM aw_ou_student_data ad , jos_users ju , aw_ou_lookup_courses ac,aw_ou_lookup_colleges ac1 where ac1.id=ju.college_code and ac.id in (27,28,29,30,133,32,33,34,35,36,37,38,39,40,41,42,43,44,134,135) and ac.school_id=2 and ju.id=ad.user_id and ac.id=ju.course_code GROUP BY ac.id ORDER BY ac.id ) a left join aw_ou_lookup_courses ac1 on ac1.id = a.id
In the above inner query in above one i have given 20 ac.id but i am getting only 14 out records as a result. How do i get the total 20 records as a result. i.e The id present in the in condition if it doesnt satisfy then i should a record with 0 as values for it beside that id.
How do i do it..?
A simple left join with condition should do it:
SELECT
table1.id,
table2.*
FROM
table table1
LEFT JOIN table2 ON table1.id = table2.id AND (your conditions here)
I am building a polling system and I have a query right now that is supposed to select all of the polls and count all of the votes for each of the polls (which lie in a separate table). So my tables look like:
Polls:
ID
Title
Body
Votes:
ID
PollID
Vote (This value is either 0 or 1)
Well the totaling of the votes looks like it is working, the issue is that it is currently only displaying one record.
Currently my query looks like this:
SELECT POLLS.ID,
POLLS.TITLE,
POLLS.BODY,
Sum(CASE
WHEN VOTES.VOTE = 1
AND VOTES.POLLID = POLLS.ID THEN 1
ELSE 0
END) AS yay,
Sum(CASE
WHEN VOTES.VOTE = 0
AND VOTES.POLLID = POLLS.ID THEN 1
ELSE 0
END) AS nay,
FROM polls,
VOTES
ORDER BY POLLS.ID
Also I am using PHP with Codeigniter.
SELECT polls.ID,polls.title,polls.body,
SUM(case when votes.vote = 1 then 1 else 0 end) AS yay,
SUM(case when votes.vote = 0 then 1 else 0 end) AS nay,
FROM polls
JOIN votes ON polls.ID = votes.pollID
GROUP BY poll.ID, polls.title, polls.body
ORDER BY polls.ID
You need to GROUP BY pollID the values in the votes table:
SELECT p.ID, p.title, p.body, v.yay, v.nay
FROM
(
SELECT PollID,
SUM(CASE WHEN vote = 1 THEN 1 ELSE 0 END) AS yay,
SUM(CASE WHEN vote = 0 THEN 1 ELSE 0 END) AS nay,
FROM votes
GROUP BY PollID
) v
INNER JOIN Polls p ON v.PollID = p.Id
ORDER BY p.ID
I'd go with:
SELECT polls.ID, polls.title, polls.body,
SUM(IF(votes.vote = 1, 1, 0)) AS yay,
SUM(IF(votes.vote = 0, 1, 0)) AS nay
FROM polls
JOIN votes ON (votes.pollID = polls.ID)
GROUP BY ID, title, body
What you are missing is "GROUP BY". Use GROUP BY PollID while taking sum.