SELECT ac1.id, ac1.course_name, case when a.yettoapprove is not null
then 'true'
else 'false'
end OrderedAll , a.* from (SELECT ac.id, sum(case when ad.status = '2' then 1 else 0 end) as yettoapprove , sum(case when ad.status = '1' then 1 else 0 end) as approved,case when ad.status = '2' is not null
then 'true'
else 'false'
end OrderedAll FROM aw_ou_student_data ad , jos_users ju , aw_ou_lookup_courses ac,aw_ou_lookup_colleges ac1 where ac1.id=ju.college_code and ac.id in (27,28,29,30,133,32,33,34,35,36,37,38,39,40,41,42,43,44,134,135) and ac.school_id=2 and ju.id=ad.user_id and ac.id=ju.course_code GROUP BY ac.id ORDER BY ac.id ) a left join aw_ou_lookup_courses ac1 on ac1.id = a.id
In the above inner query in above one i have given 20 ac.id but i am getting only 14 out records as a result. How do i get the total 20 records as a result. i.e The id present in the in condition if it doesnt satisfy then i should a record with 0 as values for it beside that id.
How do i do it..?
A simple left join with condition should do it:
SELECT
table1.id,
table2.*
FROM
table table1
LEFT JOIN table2 ON table1.id = table2.id AND (your conditions here)
Related
I want to create an output table that is a combination of the two input tables, as shown below. Table 1 and table 2 are MySQL tables. Output is the desired table view.
Please hlep me to billd this output from table1 and table2 (mysql)
You can use conditional aggregation with UNION ALL for this:
SELECT t1.acc_no, t1.name,
SUM(CASE WHEN t2.`date` = '2016-06-01' THEN amount END) AS '2016-06-01',
SUM(CASE WHEN t2.`date` = '2016-06-02' THEN amount END) AS '2016-06-02',
SUM(CASE WHEN t2.`date` = '2016-06-03' THEN amount END) AS '2016-06-03',
SUM(amount) AS 'Total'
FROM table1 AS t1
LEFT JOIN table2 AS t2 ON t1.acc_no = t2.acc_no
UNION ALL
SELECT 'Total', null,
SUM(CASE WHEN t2.`date` = '2016-06-01' THEN amount END) AS '2016-06-01',
SUM(CASE WHEN t2.`date` = '2016-06-02' THEN amount END) AS '2016-06-02',
SUM(CASE WHEN t2.`date` = '2016-06-03' THEN amount END) AS '2016-06-03',
SUM(amount) AS 'Total'
FROM table2
I been trying different combination, but I cant seems to get this to work. I have inner join tables, I want to count the number of QA ISSUE found in the records and also output those records with only QA ISSUE, How would I do that?
SELECT d.department, m.mo_number, m.part_number, c.category,
COUNT(CASE WHEN c.category = 'QA ISSUE' THEN category END) as qa_issue,
SUM(CASE WHEN c.category = 'QA ISSUE' THEN time_spent END) as time_spent
FROM master as m
INNER JOIN category as c ON c.cat_id = m.cat_id
INNER JOIN department as d ON d.dept_id = m.dept_id
WHERE m.date_created >= DATE_SUB(now(), INTERVAL 50 DAY) AND
d.department = 'Electronics'
GROUP BY m.mo_number
ORDER BY 1
To filter results by aggregates you use the HAVING clause which occurs after the GROUP BY clause. Note this is not a substitute for the WHERE clause (which chooses the rows to be aggregated).
SELECT
d.department
, m.mo_number
, m.part_number
, c.category
, COUNT(*) AS qa_issue
, SUM(time_spent) AS time_spent
FROM master AS m
INNER JOIN category AS c ON c.cat_id = m.cat_id
INNER JOIN department AS d ON d.dept_id = m.dept_id
WHERE m.date_created >= DATE_SUB(now(), INTERVAL 50 DAY)
AND d.department = 'Electronics'
AND c.category = 'QA ISSUE'
GROUP BY
d.department
, m.mo_number
, m.part_number
, c.category
HAVING COUNT(*) = 1
ORDER BY
d.department
I have also added a condition to the where clause and added all non-aggregated columns into the GROUP BY clause - which I recommend you do always.
I have a table in my database named contacts and a table named views.
On the table contacts I have the following fields:
id
status
first_name
last_name
The status can be cold, prospect or lost.
On the table views I have the following fields:
user_id
art_views
art_title
The relation between those 2 tables is id and user_id.
I need a query to make a new html table with the following columns:
art_title
cold
prospect
lost
Now I have the following query (UPDATED):
SELECT
v.art_title,
SUM(CASE c.status WHEN 'cold' THEN v.art_views ELSE 0 END) cold,
SUM(CASE c.status WHEN 'prospect' THEN v.art_views ELSE 0 END) prospect,
SUM(CASE c.status WHEN 'lost' THEN v.art_views ELSE 0 END) lost
FROM views v
JOIN contacts c ON v.user_id = c.id
GROUP BY v.art_title
This query is working now (thanks to Gerv) but i still have users who don't have a status. So i leave the field user_id in the table 'views' empty. How can i change the query for those users so i can count them also?
I tried to: SUM(CASE v.user_id WHEN ' ' THEN v.art_views ELSE 0 END) test,
but with no result here.
You can switch the logic by selecting from the views table and joining de contacts table.
Below query will pivot the status with a CASE clause
SELECT
v.art_title,
SUM(CASE c.status WHEN 'cold' THEN v.art_views ELSE 0 END) cold,
SUM(CASE c.status WHEN 'prospect' THEN v.art_views ELSE 0 END) prospect,
SUM(CASE c.status WHEN 'lost' THEN v.art_views ELSE 0 END) lost,
SUM(CASE c.status WHEN NULL THEN v.art_views ELSE 0 END) no_user
FROM views v
LEFT JOIN contacts c ON v.user_id = c.id
GROUP BY v.art_title
ORDER BY (cold+lost+prospect+no_user) DESC
LIMIT 10
Try
SELECT art_title, SUM(art_views), status FROM contacts AS c INNER JOIN views AS v ON v.user_id = c.id GROUP BY v.art_title, c.status
I need to count record year wise, I did some query but i am not getting correct result. Below is my query. But that is not working for me. Can anyone please look in this and give me right query ? Any help will be appreciated.
SELECT
(SELECT count(DISTINCT id) FROM call_response WHERE disposition=0 AND user_id=pu.id ) AS `trueAlarm`,
(SELECT count(DISTINCT id) FROM call_response WHERE disposition=1 AND user_id=pu.id ) AS `falseAlarm`,
(SELECT count(DISTINCT id) FROM call_response WHERE disposition=2 AND user_id=pu.id ) AS `disregarded`,
YEAR(cr.created_date) AS `callYear`
FROM `call_response` AS `cr`
INNER JOIN `permit_users` AS `pu`
ON cr.user_id=pu.id
WHERE ( pu.is_deleted=0 AND pu.is_trashed=0 AND cr.is_deleted=0)
GROUP BY `callYear`
The query that you want uses either conditional aggregation or subqueries, but not both. In other words, either use the subqueries but do not have an outer join to call_response. Or, have the outer join but not the subqueries.
I would write the query like this:
SELECT count(distinct case when disposition = 0 AND user_id = pu.id then id end) as trueAlarm,
count(distinct case when disposition = 1 AND user_id = pu.id then id end) as falseAlarm,
count(distinct case when disposition = 2 AND user_id = pu.id then id end) as disregarded,
YEAR(cr.created_date) AS `callYear`
FROM `call_response` `cr` INNER JOIN
`permit_users` `pu`
ON cr.user_id = pu.id
WHERE pu.is_deleted = 0 AND pu.is_trashed = 0 AND cr.is_deleted = 0
GROUP BY `callYear`;
I need to combine 2 queries into one. Both query the same table and same column name. I need the results in one query so that I can repeat region the results. I have tried UNION but this doesn't run the second half correctly. Query 1 is as follows:
SELECT o.value AS sdate
FROM order_option o
INNER JOIN order_product p ON o.order_product_id = p.order_product_id
WHERE
p.product_id = '$_GET[u]'
AND o.name = 'Start Date'
And query 2 is as follows...
SELECT o2.value AS sday
FROM order_option o2
INNER JOIN order_product p ON o2.order_product_id = p.order_product_id
WHERE
p.product_id = '$_GET[u]'
AND o2.name = 'Number of Days'
UNION should be correct. Does the second query run correctly as shown? if so, it should run the same way in a UNION. You may try UNION ALL and see if that 'corrects' the query.
You can use a combination of MAX and CASE like this
SELECT
MAX(CASE WHEN o.name = 'Start Date' THEN o.value END) AS sdate,
MAX(CASE WHEN o.name = 'Number of Days' THEN o.value END) AS sday
FROM order_option o
INNER JOIN order_product p USING (order_product_id)
WHERE
p.product_id = '$_GET[u]'
;