I am using this code to get the data of a team
SELECT `in_standings`.*, `in_teams`.`name` as team_name, `in_teams`.`logo` as team_logo, `in_teams`.`shortcode` as team_shortcode, lr.*, in_teams.id as team_id
FROM `in_standings` daa
LEFT JOIN `in_teams` ON `in_standings`.`team_id`= `in_teams`.`id`
left join
(SELECT team1_id,daa.team_id as teamID,
MAX(CASE WHEN rn = 1 THEN winning_team END) AS result1,
MAX(CASE WHEN rn = 2 THEN winning_team END) AS result2,
MAX(CASE WHEN rn = 3 THEN winning_team END) AS result3,
MAX(CASE WHEN rn = 4 THEN winning_team END) AS result4,
MAX(CASE WHEN rn = 5 THEN winning_team END) AS result5
FROM (
SELECT team1_id, winning_team,
#row_number := #row_number + 1 AS rn
FROM in_games
CROSS JOIN (SELECT #row_number := 0) AS vars
WHERE team1_id = teamID <!-- here is problem -->
) AS t) as lr on lr.team1_id=in_standings.team_id
WHERE `in_standings`.`division_id` = '21'
ORDER BY `in_standings`.`points` DESC
My sub query where i comment is not getting the team_id by which i want to set the result of last 5 matchs in a same row.
Could anyone solve where is the problem?
Related
Why DISTINCT UID doesn't work in my code below?
$q = mysql_fetch_array(mysql_query("SELECT COUNT(DISTINCT UID) AS TOTAL,
SUM(CASE WHEN SYSTEM = 'Android' THEN 1 ELSE 0 END) AS A,
SUM(CASE WHEN SYSTEM = 'IOS' THEN 1 ELSE 0 END) AS I,
SUM(CASE WHEN SYSTEM = 'Windows' THEN 1 ELSE 0 END) AS W FROM user_visits"));
The query returns all items from the database selected even I put DISTINCT UID or *. Same result.
The distinct keyword is supposed to be outside like below,
SELECT DISTINCT column1, column2, ...
FROM table_name;
?
Also, you are trying to sum few things, It should be something like below,
SELECT UID, COUNT(UID) AS TOTAL,
SUM(CASE WHEN SYSTEM = 'Android' THEN 1 ELSE 0 END) AS A,
SUM(CASE WHEN SYSTEM = 'IOS' THEN 1 ELSE 0 END) AS I,
SUM(CASE WHEN SYSTEM = 'Windows' THEN 1 ELSE 0 END) AS W FROM user_visits
GROUP BY UID
with aggregate (group by)
I have a problem with my queries. I have now 2 queries and that works fine. But when I want to add another query with a PIVOT, it doesn't work. I have tried a lot of things but nothing works..
This is my first two queries
$query = "SET SQL_BIG_SELECTS = 1;";
$query .= "SELECT * FROM datakram, datakram2, datakram3 WHERE datakram.NAME = datakram2.NAME AND datakram2.NAME = datakram3.NAME"
And I want to add a PIVOT for table "datakram4". But I want only the rows where the NAME is equal to the NAME in the others tables. Without the PIVOT it works..
My PIVOT code.
SELECT `name` ,
MAX( CASE WHEN `year` =2017 THEN `income` ELSE 0 END ) AS INCOME_2017,
MAX( CASE WHEN `year` =2017 THEN `expense` ELSE 0 END ) AS EXPENSE_2017,
MAX( CASE WHEN `year` =2016 THEN `income` ELSE 0 END ) AS INCOME_2016,
MAX( CASE WHEN `year` =2016 THEN `expense` ELSE 0 END ) AS EXPENSE_2016
FROM `test_data` GROUP BY `name`
I use multi_query for my php script.
Simply join the queries:
SELECT d4.*
FROM datakram d1
INNER JOIN datakram2 d2
ON d1.`NAME` = d2.`NAME`
INNER JOIN datakram3 d3
ON d2.`NAME` = d3.`NAME`
INNER JOIN
(SELECT `name` ,
MAX(CASE WHEN `year`=2017 THEN `income` ELSE 0 END) AS INCOME_2017,
MAX(CASE WHEN `year`=2017 THEN `expense` ELSE 0 END) AS EXPENSE_2017,
MAX(CASE WHEN `year`=2016 THEN `income` ELSE 0 END) AS INCOME_2016,
MAX(CASE WHEN `year`=2016 THEN `expense` ELSE 0 END) AS EXPENSE_2016
FROM `test_data`
GROUP BY `name`
) d4
ON d3.`NAME` = d4.`name`
A simple way is to filter in the WHERE clause:
SELECT `name` ,
MAX(CASE WHEN `year` = 2017 THEN `income` ELSE 0 END) AS INCOME_2017,
MAX(CASE WHEN `year` = 2017 THEN `expense` ELSE 0 END) AS EXPENSE_2017,
MAX(CASE WHEN `year` = 2016 THEN `income` ELSE 0 END) AS INCOME_2016,
MAX(CASE WHEN `year` = 2016 THEN `expense` ELSE 0 END) AS EXPENSE_2016
FROM `test_data` td
WHERE EXISTS (SELECT 1 FROM FROM datakram d WHERE d.name = td.NAME) AND
EXISTS (SELECT 1 FROM FROM datakram2 d WHERE d.name = td.NAME) AND
EXISTS (SELECT 1 FROM FROM datakram3 d WHERE d.name = td.NAME)
GROUP BY `name` ;
I want to create an output table that is a combination of the two input tables, as shown below. Table 1 and table 2 are MySQL tables. Output is the desired table view.
Please hlep me to billd this output from table1 and table2 (mysql)
You can use conditional aggregation with UNION ALL for this:
SELECT t1.acc_no, t1.name,
SUM(CASE WHEN t2.`date` = '2016-06-01' THEN amount END) AS '2016-06-01',
SUM(CASE WHEN t2.`date` = '2016-06-02' THEN amount END) AS '2016-06-02',
SUM(CASE WHEN t2.`date` = '2016-06-03' THEN amount END) AS '2016-06-03',
SUM(amount) AS 'Total'
FROM table1 AS t1
LEFT JOIN table2 AS t2 ON t1.acc_no = t2.acc_no
UNION ALL
SELECT 'Total', null,
SUM(CASE WHEN t2.`date` = '2016-06-01' THEN amount END) AS '2016-06-01',
SUM(CASE WHEN t2.`date` = '2016-06-02' THEN amount END) AS '2016-06-02',
SUM(CASE WHEN t2.`date` = '2016-06-03' THEN amount END) AS '2016-06-03',
SUM(amount) AS 'Total'
FROM table2
I have a table in my database named contacts and a table named views.
On the table contacts I have the following fields:
id
status
first_name
last_name
The status can be cold, prospect or lost.
On the table views I have the following fields:
user_id
art_views
art_title
The relation between those 2 tables is id and user_id.
I need a query to make a new html table with the following columns:
art_title
cold
prospect
lost
Now I have the following query (UPDATED):
SELECT
v.art_title,
SUM(CASE c.status WHEN 'cold' THEN v.art_views ELSE 0 END) cold,
SUM(CASE c.status WHEN 'prospect' THEN v.art_views ELSE 0 END) prospect,
SUM(CASE c.status WHEN 'lost' THEN v.art_views ELSE 0 END) lost
FROM views v
JOIN contacts c ON v.user_id = c.id
GROUP BY v.art_title
This query is working now (thanks to Gerv) but i still have users who don't have a status. So i leave the field user_id in the table 'views' empty. How can i change the query for those users so i can count them also?
I tried to: SUM(CASE v.user_id WHEN ' ' THEN v.art_views ELSE 0 END) test,
but with no result here.
You can switch the logic by selecting from the views table and joining de contacts table.
Below query will pivot the status with a CASE clause
SELECT
v.art_title,
SUM(CASE c.status WHEN 'cold' THEN v.art_views ELSE 0 END) cold,
SUM(CASE c.status WHEN 'prospect' THEN v.art_views ELSE 0 END) prospect,
SUM(CASE c.status WHEN 'lost' THEN v.art_views ELSE 0 END) lost,
SUM(CASE c.status WHEN NULL THEN v.art_views ELSE 0 END) no_user
FROM views v
LEFT JOIN contacts c ON v.user_id = c.id
GROUP BY v.art_title
ORDER BY (cold+lost+prospect+no_user) DESC
LIMIT 10
Try
SELECT art_title, SUM(art_views), status FROM contacts AS c INNER JOIN views AS v ON v.user_id = c.id GROUP BY v.art_title, c.status
I have this tbl_religion with fieldname creldesc
and tbl_member with these fields
and I have this query to count all existing religion in tbl_member and count also the no. of male and female with that religion so i made this query :
SELECT m.creldesc as type,
COUNT(m.creldesc) as total,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m, tbl_barangay as b, tbl_household as h
WHERE m.chholdnumber = h.chholdnumber and h.cbrgycode=b.cbrgycode and b.cbrgyname = 'AGAO'
and m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC;
and get this output :
what I want to achieve is also display the remaining religion from tbl_religion with 0 as value. I made a left join but get an error. Can someone help me how can I achive that ?
type total male female
Roman Catholic 7 4 3
Baptist 3 1 2
Islam 3 3 0
Iglesia ni Cristo 1 1 0
Free Methodist 1 1 0
Ang Dating Daan 1 0 1
Aglipay/Filipinsta 0 0 0
All the Gospel 0 0 0
Alpha Omega 0 0 0
and so on.............................
Use same joining approach for all tables, like this:
SELECT m.creldesc as type, COUNT(m.creldesc) as tot,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_religion
LEFT JOIN tbl_member as m
ON tbl_religion.creldesc=m.creldesc
LEFT JOIN tbl_household as h
ON m.chholdnumber = h.chholdnumber
LEFT JOIN tbl_barangay as b
ON h.cbrgycode=b.cbrgycode
WHERE b.cbrgyname = 'AGAO' AND m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC
Your current query approach of ... FROM tbl_member, tbl_barangay, tbl_household LEFT JOIN tbl_religion ... is wrong and will produce syntax error.
You can not make this:
FROM #TABLE1, #TABLE2, #TABLE3 LEFT JOIN #TABLE0 ON ...
You can select items only from a table at once... same for join.
SELECT m.creldesc as type,
COUNT(m.creldesc) as tot,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m
LEFT JOIN tbl_religion z ON z.creldesc = m.creldesc
LEFT JOIN tbl_barangay h ON h.cbrgycode=b.cbrgycode
SO ON.... WITH JOINS
GROUP BY m.creldesc
UPDATE WOKING CODE:
SELECT m.creldesc as type, COUNT(m.creldesc) as tot, SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m
LEFT JOIN tbl_religion r ON r.creldesc = m.creldesc
LEFT JOIN tbl_barangay as b ON m.chholdnumber = b.cbrgycode
LEFT JOIN tbl_household as h ON h.cbrgycode = b.cbrgycode
WHERE b.cbrgyname = 'AGAO' and m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC
Here's what I did:
SELECT tbl_member.creldesc AS type,
COUNT(tbl_member.creldesc) AS total,
SUM(CASE WHEN tbl_member.cgender::text = 'Male'::text THEN 1 ELSE 0 END) AS male,
SUM(CASE WHEN tbl_member.cgender::text = 'Female'::text THEN 1 ELSE 0 END) AS female
FROM tbl_member
GROUP BY tbl_member.creldesc
UNION
SELECT b.creldesc AS type, 0 AS total, 0 AS male, 0 AS female
FROM tbl_religion b
WHERE NOT (b.creldesc::text IN
( SELECT DISTINCT tbl_member.creldesc FROM tbl_member))
GROUP BY b.creldesc;
and here is it's output :
that's all :) I used UNION instead of LEFT JOIN.