Display values not present in another table - php

Question

I have this tbl_religion with fieldname creldesc
and tbl_member with these fields
and I have this query to count all existing religion in tbl_member and count also the no. of male and female with that religion so i made this query :
SELECT m.creldesc as type,
COUNT(m.creldesc) as total,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m, tbl_barangay as b, tbl_household as h
WHERE m.chholdnumber = h.chholdnumber and h.cbrgycode=b.cbrgycode and b.cbrgyname = 'AGAO'
and m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC;
and get this output :
what I want to achieve is also display the remaining religion from tbl_religion with 0 as value. I made a left join but get an error. Can someone help me how can I achive that ?
type total male female
Roman Catholic 7 4 3
Baptist 3 1 2
Islam 3 3 0
Iglesia ni Cristo 1 1 0
Free Methodist 1 1 0
Ang Dating Daan 1 0 1
Aglipay/Filipinsta 0 0 0
All the Gospel 0 0 0
Alpha Omega 0 0 0
and so on.............................

Answer 1

Use same joining approach for all tables, like this:
SELECT m.creldesc as type, COUNT(m.creldesc) as tot,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_religion
LEFT JOIN tbl_member as m
ON tbl_religion.creldesc=m.creldesc
LEFT JOIN tbl_household as h
ON m.chholdnumber = h.chholdnumber
LEFT JOIN tbl_barangay as b
ON h.cbrgycode=b.cbrgycode
WHERE b.cbrgyname = 'AGAO' AND m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC
Your current query approach of ... FROM tbl_member, tbl_barangay, tbl_household LEFT JOIN tbl_religion ... is wrong and will produce syntax error.

Answer 2

You can not make this:
FROM #TABLE1, #TABLE2, #TABLE3 LEFT JOIN #TABLE0 ON ...
You can select items only from a table at once... same for join.
SELECT m.creldesc as type,
COUNT(m.creldesc) as tot,
SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m
LEFT JOIN tbl_religion z ON z.creldesc = m.creldesc
LEFT JOIN tbl_barangay h ON h.cbrgycode=b.cbrgycode
SO ON.... WITH JOINS
GROUP BY m.creldesc
UPDATE WOKING CODE:
SELECT m.creldesc as type, COUNT(m.creldesc) as tot, SUM(CASE WHEN m.cgender='Male' THEN 1 ELSE 0 END) as male,
SUM(CASE WHEN m.cgender='Female' THEN 1 ELSE 0 END) as female
FROM tbl_member as m
LEFT JOIN tbl_religion r ON r.creldesc = m.creldesc
LEFT JOIN tbl_barangay as b ON m.chholdnumber = b.cbrgycode
LEFT JOIN tbl_household as h ON h.cbrgycode = b.cbrgycode
WHERE b.cbrgyname = 'AGAO' and m.crelationdesc !='Brgy. Captain'
GROUP BY m.creldesc
ORDER BY tot DESC

Answer 3

Here's what I did:
SELECT tbl_member.creldesc AS type,
COUNT(tbl_member.creldesc) AS total,
SUM(CASE WHEN tbl_member.cgender::text = 'Male'::text THEN 1 ELSE 0 END) AS male,
SUM(CASE WHEN tbl_member.cgender::text = 'Female'::text THEN 1 ELSE 0 END) AS female
FROM tbl_member
GROUP BY tbl_member.creldesc
UNION
SELECT b.creldesc AS type, 0 AS total, 0 AS male, 0 AS female
FROM tbl_religion b
WHERE NOT (b.creldesc::text IN
( SELECT DISTINCT tbl_member.creldesc FROM tbl_member))
GROUP BY b.creldesc;
and here is it's output :
that's all :) I used UNION instead of LEFT JOIN.