Require to display limited number of file names from directories -php - php

Question

For the below code I have multiple directories and files. I can display one filename per directory(Which is good with the "BREAK").
<?php
$dir = "/images/";
$i=0;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
echo "filename:" . $file . "<br>";
break;
//---- if ($i>=5) { break; }
}
closedir($dh);
}
}
?>
With
if ($i>=5) { break; } I can still display 5 filenames but it reads only one directory.
I want to display at least 5 file names from all directories, how can I do it?

Answer 1

Use the scandir function.
array scandir ( string $directory [, int $sorting_order = SCANDIR_SORT_ASCENDING [, resource $context ]] )
or
If you are using unix you could also do a system call and run the following command.
ls /$dir | head -5
$dir is the directory and -5 is the number filenames in the directory.

Answer 2

Since you said that you have multiple directory's, I rewrote your code a bit:
(Here I first loop through all directory's with array_map() then I get all files from each directory with glob(). After this I just limit the files per directory with array_slice() and at the end I simply print all file names)
<?php
$directorys = ["images/", "xy/"];
$limit = 3;
//get all files
$files = array_map(function($v){
return glob("$v*.*");
}, $directorys);
//limit files per directory
$files = array_map(function($v)use($limit){
return array_slice($v, 0, $limit);
}, $files);
foreach($files as $directory) {
echo "<b>Directory</b><br>";
foreach($directory as $file)
echo "$file<br>";
echo "<br><br>";
}
?>

Answer 3

You don't have to break it, you can just skip it. And in doing so, you have to use continue instead.
$dir = "/images/";
$i=0;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
echo "filename:" . $file . "<br>";
if ($i>=5)
continue;
}
closedir($dh);
}
}
Here is also another scenario. Because you mentioned that you have many directories but you only show one main directory, I am guessing that the directories you've mentioned were inside the /images/ directory.
$dir = "images/";
$i=1;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
$j=1;
if (is_dir($file)) {
if ($internalDir = opendir($file)) {
while (($internalFile = readdir($internalDir)) !== false) {
echo $file."->filename: ".$internalFile."<br>";
if ($j>=5)
continue;
$j++;
}
closedir(opendir($file));
}
} else {
echo "filename:" . $file . "<br>";
if ($i>=5)
continue;
$i++;
}
}
closedir($dh);
}
}
Read more about continue here: http://php.net/manual/en/control-structures.continue.php