I want to print all the folder names inside a parent folder. The current issue I am facing is, though I have 400+ folders in a folder only 257 are getting printed. Again, this is not at all issue related with permissions.
Please find my code below:
$newdir = "content/";
$dircnt = 0;
// Open a known directory, and proceed to read its contents
if (is_dir($newdir)) {
if ($dh = opendir($newdir)) {
while (($file = readdir($dh)) !== false) {
$dircnt++;
if(filetype($newdir. $file) == 'dir') {
echo "filename: $file : filetype: " . filetype($newdir. $file) . "dircnt:" .$dircnt. "<br>";
}
}
closedir($dh);
}
}
}
You can use glob() function - returns an array containing the matched files/directories, an empty array if no file matched or FALSE on error.
$filesDirectories = glob($newdir.'*', GLOB_BRACE);
foreach($filesDirectories as $key=>$file) {
echo "$file size " . filesize($file) . "\n";
}
I would use glob:
$newdir = "content/";
$dirs = glob($newdir.'*',GLOB_ONLYDIR);
foreach($dirs as $index=>$dir){
echo "filename ". $dir." filetype ".filetype($newdir.$dir)." dircnt:".($index+1)."<br/>";
}
Related
I am trying to get folder names in codeigniters' "views" folder to create a kind of template class that will fetch all folder names in "view"...
I actually want to create a default template for my site and then be able to change it just by adding another template folder like wordpress themes
how do I do that?
If you could hopefully understand what I want to say here...
?php
// declare the folder
$ourDir = "/home/public_html/folderName";
// prepare to read directory contents
$ourDirList = #opendir($ourDir);
// loop through the items
while ($ourItem = readdir($ourDirList))
{
// check if it is a directory
if (is_dir($ourItem))
{
echo "directory: $ourItem <br />";
}
// check to see if it is a file
if (is_file($ourItem))
{
echo "file: $ourItem <br />";
}
}
closedir($ourDirList);
?>
tried this but doesn't work.. :(
Well i just found my ans ...
<?php
$dir = APPPATH.'views/';
// Open a known directory, and proceed to read its contents
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
if(filetype($dir . $file) == 'dir' && $file != '..' && $file != '.') {
echo "filename: $file : filetype: " . filetype($dir . $file) . "<br>";
}
}
closedir($dh);
}
}
?>
This will echo out all the folders...
For the below code I have multiple directories and files. I can display one filename per directory(Which is good with the "BREAK").
<?php
$dir = "/images/";
$i=0;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
echo "filename:" . $file . "<br>";
break;
//---- if ($i>=5) { break; }
}
closedir($dh);
}
}
?>
With
if ($i>=5) { break; } I can still display 5 filenames but it reads only one directory.
I want to display at least 5 file names from all directories, how can I do it?
Use the scandir function.
array scandir ( string $directory [, int $sorting_order = SCANDIR_SORT_ASCENDING [, resource $context ]] )
or
If you are using unix you could also do a system call and run the following command.
ls /$dir | head -5
$dir is the directory and -5 is the number filenames in the directory.
Since you said that you have multiple directory's, I rewrote your code a bit:
(Here I first loop through all directory's with array_map() then I get all files from each directory with glob(). After this I just limit the files per directory with array_slice() and at the end I simply print all file names)
<?php
$directorys = ["images/", "xy/"];
$limit = 3;
//get all files
$files = array_map(function($v){
return glob("$v*.*");
}, $directorys);
//limit files per directory
$files = array_map(function($v)use($limit){
return array_slice($v, 0, $limit);
}, $files);
foreach($files as $directory) {
echo "<b>Directory</b><br>";
foreach($directory as $file)
echo "$file<br>";
echo "<br><br>";
}
?>
You don't have to break it, you can just skip it. And in doing so, you have to use continue instead.
$dir = "/images/";
$i=0;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
echo "filename:" . $file . "<br>";
if ($i>=5)
continue;
}
closedir($dh);
}
}
Here is also another scenario. Because you mentioned that you have many directories but you only show one main directory, I am guessing that the directories you've mentioned were inside the /images/ directory.
$dir = "images/";
$i=1;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
$j=1;
if (is_dir($file)) {
if ($internalDir = opendir($file)) {
while (($internalFile = readdir($internalDir)) !== false) {
echo $file."->filename: ".$internalFile."<br>";
if ($j>=5)
continue;
$j++;
}
closedir(opendir($file));
}
} else {
echo "filename:" . $file . "<br>";
if ($i>=5)
continue;
$i++;
}
}
closedir($dh);
}
}
Read more about continue here: http://php.net/manual/en/control-structures.continue.php
can anyone help me to get each file size individually from a local directory ?.
$files = scandir('soft');
foreach($files as $file) {
echo $file . "<br />";
}
From here
$files = scandir('soft');
foreach($files as $file) {
if (!in_array($file,array(".","..")))
{
echo $file . "<br />";
echo filesize('soft/'.$file) . ' bytes';
}
}
Just need to keep in mind that scandir gets only the filenames in that dir, and not the relative path to it. that's why you need to use 'soft/'.$file and not $file
<?
$files = scandir('.');
foreach($files as $file) {
echo filesize($file) . " bytes<br>";
}
?>
use filesize($filename) php function, it will give size in bytes
myFolderi have thousands of image files that have keyword text for the name. i am trying to read from the list of images and upload the text into a dB field. the problem is that some of the text has utf8 characters like l’Été that show up like this ��t�
how can i read foreign characters so that the accents will insert into the dB field?
this is how im handling it now
function ListFiles($dir) {
if($dh = opendir($dir)) {
$files = Array();
$inner_files = Array();
while($file = readdir($dh)) {
if($file != "." && $file != ".." && $file[0] != '.') {
if(is_dir($dir . "/" . $file)) {
$inner_files = ListFiles($dir . "/" . $file);
if(is_array($inner_files)) $files = array_merge($files, $inner_files);
} else {
array_push($files, $dir . "/" . $file);//$dir = directory name
//array_push($files, $dir);
}
}
}
closedir($dh);
return $files;
}
}
foreach (ListFiles('../../myDirectory') as $key=>$file){
//$file = preg_replace( '#[^\0-\x80]#u',"", $file );
echo $file ."<br />";
}
this is producing the same result
$str = "l’Été";
utf8_decode($str);
echo $str;
This solution may work for you, it will loop through all files in a directoy and then recursivly through any directories found until it ends up with a massive array of files.
Ive added some points you may wish to change, eg either mutli or single dimension arrays ( all depend on if you may want to maintain the folder structure.
and also if you want the file extention to be saved when you save the file name to db.
Code
function recursive_search_dir($dir) {
if ($handle = opendir($dir)) {
while (false !== ($file = readdir($handle))) {
if (in_array($file,array(".","..")))
continue; // We dont want to do anything with parent / current directory.
if (is_dir($file)) {
$result[] = recursive_search_dir($file); // Multi-dimension
# OR
array_merge($result,recursive_search_dir($file));// Single-dimension if you dont care about folder structure.
} else {
$result[] = utf8_decode($file); // full file name ( includes extention )
# OR
$result[] = utf8_decode(filename($file,PATHINFO_FILENAME)); // if you only want to capture the name and not the extention.
}
}
closedir($handle);
}
return $result;
}
$files = recursive_search_dir("."); // recursively searcht the current directory.
I want to print the folder names in a particular folder. For example Folder 1,2,3 are in a folder named 'New' I want to print the folder names 1 2 3 using php. Is it possible ? is there any function in php to do that ? any kind of solutions or ideas are very much appreciated.
<?php
$dir = "/etc/php5/";
// Open a known directory, and proceed to read its contents
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
echo "filename: $file : filetype: " . filetype($dir . $file) . "\n";
}
closedir($dh);
}
}
?>
credit to php.net
Extending this logic,
<?php
$dir = "/etc/php5/";
// Open a known directory, and proceed to read its contents
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
if(filetype($dir . $file) == 'dir') {
echo "filename: $file : filetype: " . filetype($dir . $file) . "\n";
}
}
closedir($dh);
}
}
?>
should echo all directories
The output on my local server is:
filename: . : filetype: dir
filename: .. : filetype: dir
filename: apache : filetype: dir
filename: etc : filetype: dir
filename: pranav : filetype: dir
Here is some example code from php.net on the readdir() function:
<?php
if ($handle = opendir('.')) {
while (false !== ($entry = readdir($handle))) {
if ($entry != "." && $entry != "..") {
echo "$entry\n";
}
}
closedir($handle);
}
?>
If you modify this code to check $entry with the is_dir() function, you can easily find your directories.
<?php
// declare the folder
$ourDir = "/home/public_html/folderName";
// prepare to read directory contents
$ourDirList = #opendir($ourDir);
// loop through the items
while ($ourItem = readdir($ourDirList))
{
// check if it is a directory
if (is_dir($ourItem))
{
echo "directory: $ourItem <br />";
}
// check to see if it is a file
if (is_file($ourItem))
{
echo "file: $ourItem <br />";
}
}
closedir($ourDirList);
?>
This is to echo both folders and files in a Directory.
glob function can be used to fetch directories too.
<?php
$folders = glob('/',GLOB_ONLYDIR);
print_r($folders);
?>