Display contents of multiple text files - php

Question

I have a number of text files held in directory
/results/...
All the text files are named with unixtime stamps, inside each of the following files there is:
#text¬test¬test1¬test2¬test3¬test4¬1262384177
Each piece of text is seperated by '¬'.
I'd then like to feed the contents of the text file into an array and output it, in for example a table, but for each of the files (Perhaps loop-like?)
If have this but it only works for one file and fixed file name:
$filename = "results/unixtime.txt";
$handle = fopen($filename, "r");
$contents = fread($handle, filesize($filename));
fclose($handle);
$array01 = explode("¬",$contents);
$count = count($array01);
echo "<table width = 500 border=1 cellpadding=4>";
$i=0;
for ($i=0;$i<$count;$i++) {
echo "<tr><td>";
echo $array01[$i];
echo "</td></tr>";
}
echo "</table>";

Answer 1

I suggest the fairly-unknown glob function to detect all your files. Then with all the filenames in a handy array, just iterate through and open up/read each one. Sort of like this:
$files = glob('*.txt');
while(list($i, $filename) = each($files)){
//what you have now
}

Answer 2

A couple of things:
Unless you're dealing with really large files just use file_get_contents() to load files. It's a one-liner versus three lines of code that you just don't need;
Loop over arrays using foreach unless you explicitly need a loop counter. The loop condnition/counter is just another area where you can make simple errors;
Use opendir(), readdir() and closedir() for reading directory contents; and
Directories will contain entries like "." and "..". Use filetype() and/or a check on the name and/or extension to limit it to the files you're interested in.
Example:
$directory = "results/";
$dir = opendir($directory);
while (($file = readdir($dir)) !== false) {
$filename = $directory . $file;
$type = filetype($filename);
if ($type == 'file') {
$contents = file_get_contents($filename);
$items = explode('¬', $contents);
echo '<table width="500" border="1" cellpadding="4">';
foreach ($items as $item) {
echo "<tr><td>$item</td></tr>\n";
}
echo '</table>';
}
}
closedir($dir);

Answer 3

You can get all the files located in "result" via opendir.
There is also an example ...
<?php
$dir = "/etc/php5/";
// Open a known directory, and proceed to read its contents
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
echo "filename: $file : filetype: " . filetype($dir . $file) . "\n";
}
closedir($dh);
}
}
?>

Answer 4

Grab the files in the directory and read each filename.
<?php
if ($handle = opendir('.')) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != "..") {
$filename = $file;
//your code
}
}
closedir($handle);
}
?>
source: http://php.net/manual/en/function.readdir.php

Answer 5

Here is a more elegant way of writing brianreavis solution, also use file_get_contents instead of fopen, fread and fclose, it's faster and less verbose.
foreach (glob('*.txt') as $filename)
{
$contents = file_get_contents($filename);
}

Answer 6

Use this code, replace DOCROOT with directory you want to scan.
foreach (scandir(DOCROOT.'css') as $dir) {
echo $dir . "<br>";
echo file_get_contents(DOCROOT . 'css/' . $dir ) . "<hr />";
}