How to get the file name under a folder? - php

Suppose I have a directory look like:
ABC
|_ a1.txt
|_ a2.txt
|_ a3.txt
|_ a4.txt
|_ a5.txt
How can I use PHP to get these file names to an array, limited to a specific file extension and ignoring directories?

You can use the glob() function:
Example 01:
<?php
// read all files inside the given directory
// limited to a specific file extension
$files = glob("./ABC/*.txt");
?>
Example 02:
<?php
// perform actions for each file found
foreach (glob("./ABC/*.txt") as $filename) {
echo "$filename size " . filesize($filename) . "\n";
}
?>
Example 03: Using RecursiveIteratorIterator
<?php
foreach(new RecursiveIteratorIterator( new RecursiveDirectoryIterator("../")) as $file) {
if (strtolower(substr($file, -4)) == ".txt") {
echo $file;
}
}
?>

Try this:
if ($handle = opendir('.')) {
$files=array();
while (false !== ($file = readdir($handle))) {
if(is_file($file)){
$files[]=$file;
}
}
closedir($handle);
}

scandir lists files and directories inside the specified path.

Here is the most Efficient way based on this article's benchmarks:
function getAllFiles() {
$files = array();
$dir = opendir('/ABC/');
while (($currentFile = readdir($dir)) !== false) {
if (endsWith($currentFile, '.txt'))
$files[] = $currentFile;
}
closedir($dir);
return $files;
}
function endsWith($haystack, $needle) {
return substr($haystack, -strlen($needle)) == $needle;
}
just use the getAllFiles() function, and you can even modify it to take the folder path and/or the extensions needed, it is easy.

Aside from scandir (#miku), you might also find glob interesting for wildcard matching.

If your text files is all that you have inside of the folder, the simplest way is to use scandir, like this:
<?php
$arr=scandir('ABC/');
?>
If you have other files, you should use glob as in Lawrence's answer.

$dir = "your folder url"; //give only url, it shows all folder data
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
if($file != '.' and $file != '..'){
echo $file .'<br>';
}
}
closedir($dh);
}
}
output:
xyz
abc
2017
motopress

Related

How to search file in folder by using php?

I have a folder called allfiles, and there are some files in this folder, such as
1212-how-to-sddk-thosd.html
3454-go-to-dlkkl-sdf.html
0987-sfda-asf-fdf-12331.html
4789-how-to-fdaaf-65536.html
I use scandir to list all files, and now I need to find the file by with keywords, example to-dlkkl is the keyword, and I will get the file 3454-go-to-dlkkl-sdf.html.
Glob seems not work, and opendir and readdir are not work well, any ideas?
Use loop foreach and strpos function:
$files = scandir('allfiles');
foreach ($files as $file) {
if (strpos('to-dlkkl', $file) !== false) {
//file found
}
}
I wonder why glob() function not working for it?
The below code should work I guess,
$existing_dir = getcwd();
// path to dir
chdir( '/var/www/allfiles/' );
foreach( glob( '*to-dlkkl*.html' ) as $html_file ) {
echo $html_file . '<br />';
}
chdir( $existing_dir );
you can use strstr to get actual file
$allfiles = scandir('./');
foreach ($allfiles as $file) {
if (strstr($file, 'to-dlkkl')) {
echo "file found"; //do what you want
}
}
If You want to search specific file under directory then you can use preg_match() .
<?php
if ($handle = opendir('/var/www/html/j')) { // here add your directory
$keyword = "index.php"; // your keyword
while (false !== ($entry = readdir($handle))) {
// (preg_match('/\.txt$/', $entry)) {
if (preg_match('/'.$keyword.'/i', $entry)) {
echo "$entry\n";
}
}
closedir($handle);
}
?>

Require to display limited number of file names from directories -php

For the below code I have multiple directories and files. I can display one filename per directory(Which is good with the "BREAK").
<?php
$dir = "/images/";
$i=0;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
echo "filename:" . $file . "<br>";
break;
//---- if ($i>=5) { break; }
}
closedir($dh);
}
}
?>
With
if ($i>=5) { break; } I can still display 5 filenames but it reads only one directory.
I want to display at least 5 file names from all directories, how can I do it?
Use the scandir function.
array scandir ( string $directory [, int $sorting_order = SCANDIR_SORT_ASCENDING [, resource $context ]] )
or
If you are using unix you could also do a system call and run the following command.
ls /$dir | head -5
$dir is the directory and -5 is the number filenames in the directory.
Since you said that you have multiple directory's, I rewrote your code a bit:
(Here I first loop through all directory's with array_map() then I get all files from each directory with glob(). After this I just limit the files per directory with array_slice() and at the end I simply print all file names)
<?php
$directorys = ["images/", "xy/"];
$limit = 3;
//get all files
$files = array_map(function($v){
return glob("$v*.*");
}, $directorys);
//limit files per directory
$files = array_map(function($v)use($limit){
return array_slice($v, 0, $limit);
}, $files);
foreach($files as $directory) {
echo "<b>Directory</b><br>";
foreach($directory as $file)
echo "$file<br>";
echo "<br><br>";
}
?>
You don't have to break it, you can just skip it. And in doing so, you have to use continue instead.
$dir = "/images/";
$i=0;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
echo "filename:" . $file . "<br>";
if ($i>=5)
continue;
}
closedir($dh);
}
}
Here is also another scenario. Because you mentioned that you have many directories but you only show one main directory, I am guessing that the directories you've mentioned were inside the /images/ directory.
$dir = "images/";
$i=1;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
$j=1;
if (is_dir($file)) {
if ($internalDir = opendir($file)) {
while (($internalFile = readdir($internalDir)) !== false) {
echo $file."->filename: ".$internalFile."<br>";
if ($j>=5)
continue;
$j++;
}
closedir(opendir($file));
}
} else {
echo "filename:" . $file . "<br>";
if ($i>=5)
continue;
$i++;
}
}
closedir($dh);
}
}
Read more about continue here: http://php.net/manual/en/control-structures.continue.php

PHP auto-incude from a folder

I want to create a system which will include any .php file from a folder, similar to wordpress\plugins folder. Preferably drag and drop.
Any ideas how to do it?
Question is not clear...
read the folder files
scroll through the files found
if PHP - include it
<?php
function scandir2($dir)
{
$out = array();
if (is_dir($dir))
{
if ($dh = opendir($dir))
{
while (($file = readdir($dh)) !== false)
{
if ($file == '.' or $file == '..') continue;
if (!is_dir($dir . '/'. $file))
{
$out[] = $dir . '/' . $file;
}
}
closedir($dh);
}
}
sort($out);
return $out;
}
$i=scandir2(".");
foreach($i as $name)
{
if(strstr($name ,'.php'))
include($name);
}
?>
this code scan directory and include php files ...
Here is the code to do that:
foreach (glob("/path/*.php") as $filename) {
include $file;
}
The glob() function returns an array of all .php files on the specified path.
Here is how I would do it...
<?php
$dirPath = '/path/to/files';
if ($handle = opendir($dirPath)) {
/* loop over files in directory */
while (false !== ($entry = readdir($handle))) {
/* find extension */
$ext = substr($entry,-3);
$ext = strtolower($ext);
/* include file if extension is PHP */
if ($ext === 'php') {
include_once($dirPath .'/'. $entry);
} //if
} //if
closedir($handle);
} //if
Note that there is several security concerns and possibly performance concerns.

finding files in a dir

I have a directory with a lot of files inside:
pic_1_79879879879879879.jpg
pic_1_89798798789798789.jpg
pic_1_45646545646545646.jpg
pic_2_12345678213145646.jpg
pic_3_78974565646465645.jpg
etc...
I need to list only the pic_1_ files. Any idea how I can do?
Thanks in advance.
Use the glob() function
foreach (glob("directory/pic_1_*") as $filename) {
echo "$filename";
}
Just change directory in the glob call to the proper path.
This does it all in one shot versus grabbing the list of files and then filtering them.
The opend dir function will help you
$dir ="your path here";
$filetoread ="pic_1_";
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
if (strpos($file,$filetoread) !== false)
echo "filename: $file : filetype: " . filetype($dir . $file) . "\n";
}
closedir($dh);
}
}
good luck see php.net opendir
This is what glob() is for:
glob — Find pathnames matching a pattern
Example:
foreach (glob("pic_1*.jpg") as $file)
{
echo $file;
}
Use scandir to list all the files in a directory and then use preg_grep to get the list of files which match the pattern you are looking for.
This is one of the samples from the manual
http://nz.php.net/manual/en/function.readdir.php
<?php
if ($handle = opendir('.')) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != "..") {
echo "$file\n";
}
}
closedir($handle);
}
?>
you can modify that code to test the filename to see if it starts with pic_1_
using something like this
if (substr($file, 0, 6) == 'pic_1_')
Manual reference for substr
http://nz.php.net/manual/en/function.substr.php

is_dir does not recognize folders

I am trying to make a function that scans a folder for subfolders and then returns
a numeric array with the names of those folders.
This is the code i use for testing. Once i get it to print out the folder names and not just "." and ".." for present and above folder all will be well, and I can finish the function.
<?php
function super_l_getthemes($dir="themes")
{
if ($handle = opendir($dir)) {
echo "Handle: {$handle}\n";
echo "Files:\n";
while (false !== ($file = readdir($handle))) {
echo "{$file}<br>";
}
closedir($handle);
}
?>
The above code works fine, and prints out all the contents of the folder: files, subfolders and the "." and ".."
but if i replace:
while (false !== ($file = readdir($handle))) {
echo "{$file}<br>";
}
with:
while (false !== ($file = readdir($handle))) {
if(file_exists($file) && is_dir($file)){echo "{$file}";}
}
The function only prints "." and ".." , not the two folder names that I'd like it to print.
Any help is appreciated.
You must provide the absolute path to file_exists, otherwise it will look for it in the current execution path.
while (false !== ($file = readdir($handle))) {
$file_path = $dir . DIRECTORY_SEPARATOR . $file;
if (file_exists($file_path) && is_dir($file_path)) {
echo "{$file}";
}
}
The problem with readdir is that it only reads the strings of the named entries inside of the directory.
For instance, if you had file "foo" inside of directory "/path/to/files/", when using readdir on "/path/to/files/", you would eventually come to the string "foo".
Normally this wouldn't be a problem if it were in the same directory as the current working directory of the script, but, since you are reading from an arbitrary director, when you are attempting to inspect the entry (file, directory, whatever), you are calling is_dir on the bare string "foo".
I would try prefixing the name you pull out using readdir with the path to the file.
if ($handle = opendir($dir)) {
echo "Handle: {$handle}\n";
echo "Files:\n";
while ($file = readdir($handle)) {
/*** make $file into an absolute path ***/
$absolute_path = $dir . '/' . $file;
/*** NOW try stat'ing it ***/
if (is_dir($absolute_path)) {
/* it's a directory; do stuff */
}
}
closedir($handle);
}
You need to use:
while (false !== ($file = readdir($handle))) {
if(file_exists($dir.'/'.$file) && is_dir($dir.'/'.$file)){echo "{$file}";}
}
See http://php.net/readdir
If you only want the directories of the starting folder, you can simply do:
glob('/some/path/to/search/in/*', GLOB_ONLYDIR);
which would given you only those foldernames in an array. If you want all directories below a given path, try SPL's RecursiveDirectoryIterator
$fileSystemIterator = new RecursiveIteratorIterator(
new RecursiveDirectoryIterator('/some/path/to/look/in'),
RecursiveIteratorIterator::SELF_FIRST);
Iterators can be used with foreach:
$directories = array();
foreach($fileSystemIterator as $path => $fileSystemObject) {
if($fileSystemObject->isDir()) {
$directories[] = $path;
}
}
You will then have an array $directories with all directories under the given path.
$files = array();
foreach(new DirectoryIteraror('/path') as $file){
if($file->isDir() /* && !$file->isDot()*/) $files[] = $file->getFilename();
}
[edit: though you wanted to skip the dot, commented it out)
I don't think you need both file_exists and is_dir,
You just need the is_dir function. From the manual:
is_dir Returns TRUE if the filename exists and is a directory, FALSE otherwise.
Use this:
while (false !== ($file = readdir($handle))) {
if(is_dir($file)){echo "{$file}";}
}
is_dir will also check whether it's a relative path or an absolute path.
$directory = scandir($path);
foreach($directory as $a){
if(is_dir($path.$a.'/') && $a != '.' && $a != '..'){
echo $a.'<br/>';
}
}
With the path given as shown, it displays the folders present in the path.
I agree with nuqqsa's solution, however, I'd like to add something to it.
Instead of specifying the path, you can change the current directory instead.
For example,
// open directory handle
// ....
chdir($dir);
while (false !== ($file = readdir($handle)))
if(is_dir($file))
echo $file;
// close directory handle

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