having successfully stored my arrays by serializing them, I am having trouble unserialising amd outputting it back into arrayed data.
while( $row= $stmt->fetch(PDO::FETCH_ASSOC))
var_dump($row);
{
$rss=unserialize($row);
echo $rss;
}
var_dump($rss);
I have vardumped to try and get a better picture of what is and isnt working and unserialize not working lol..
once the data is unserialised(problem1), I can then send it through a foreach to.output it(problem 2)...?
try this:
$i=0;
while( $row= $stmt->fetch(PDO::FETCH_ASSOC))
{
foreach($row as $key=>$value)
{
$rss[$i][$key]=unserialize($value);
}
$i++;
}
var_dump($rss);
Related
I'm trying to save into file a mysql SELECT query as follows:
$result = mysqli_query($db,$sql);
$out = fopen('tmp/csv.csv', 'w');
while ($row = $result -> fetch_row()) {
fputcsv($out,$row);
}
fclose($out);
after save I need to publish on a page as follows :
while ($row = mysqli_fetch_assoc($result)) {
//embed html code
}
The problem is that anytime I run $result->fetch_row(), a record of data is lost. I need to be able to run fetch_object at least 2 times within my code and preserve the data. I thought cloning would be a good solution for this, but it isn't.
Any hints, other that doing 2 query on the sql database ?
I believe another solution that could work is to use mysqli_data_seek.
The mysqli_result object is a pointer that moves through the data with each call of fetch_row(), but you can move the pointer back to the beginning by calling
mysqli_data_seek($result, 0);
And now the result is "reset", as it were, and you can use it again.
Learn more here:
https://www.php.net/manual/en/mysqli-result.data-seek.php
If you need to re-use the data, load it into an array - or do all the logic in the same loop.
So for example,
$data = []:
$result = $mysqli->query("...");
while ($row = mysqli_fetch_assoc($result)) {
$data[] = $row;
}
$out = fopen('tmp/csv.csv', 'w');
foreach ($data as $row) {
fputcsv($out, $row);
}
fclose($out);
// ...
foreach ($data as $row) {
//embed html code
}
Or do it all in the same loop (this may not always be possible, so if it isn't, go with the option above).
$result = mysqli_query($db, $sql);
$out = fopen('tmp/csv.csv', 'w');
while ($row = $result->fetch_row()) {
fputcsv($out,$row);
// embed HTML
}
fclose($out);
If you have mysqlind installed as part of your PHP MySQL infrastructure, Use a fetch_all() to get all the results into an array. You can then use that array as many times as you like.
$result = mysqli_query($db,$sql);
$all_results = $result->fetch_all();
$out = fopen('tmp/csv.csv', 'w');
foreach ( $all_results as $row){
fputcsv($out,$row);
}
fclose($out);
// now to reuse the array for your HTML output
foreach ($all_results as $row) {
//embed html code
}
Then you can reuse $all_results
If you dont have mysqlind then write a simple loop to load an array manually with all the results from the resultset
$result = mysqli_query($db,$sql);
$all_results = [];
while ($row = $result -> fetch_assoc()) {
$all_results[] = $row;
}
$out = fopen('tmp/csv.csv', 'w');
foreach ( $all_results as $row){
fputcsv($out,$row);
}
fclose($out);
// now to reuse the array for your HTML output
foreach ($all_results as $row) {
//embed html code
}
This code when run on our localhost works:
if($result){
if($tmp=$result->num_rows){
while($row = $result->fetch_assoc()) {
$myArray[] = $row;
}
echo json_encode($myArray[0]);
}
}
But, when it is run on the server (Godaddy Hosting) it reutrns a null value.
Check if you have any results in your database. If yes, then check if you have any non-ASCII caracters which makes your json_encode returning false, or encode them with utf8_encode :
while($row = $result->fetch_assoc()) {
$myArray[] = array_map('utf8_encode', $row);
}
You can also use json_last_error to help you debbuging.
I have database connection. I want to make an array but something is problem i think. Here is my array code:
$var = "SELECT SUBSTRING(KayitTarihi,1,4) AS year,SUBSTRING(KayitTarihi,6,2) AS month,SUBSTRING(KayitTarihi,9,2) AS day,SUBSTRING(KayitTarihi,12,2) AS saat,SUBSTRING(KayitTarihi,15,2) AS dakika,Guc FROM Urun WHERE Date(KayitTarihi)=\"".$link_m."\"";
$result = $mysqli->query($var);
$data = array();
foreach ($result as $row) {$data[] = $row;}
print_r($data);
$no=1;$total_deger=count($data);
echo $total_deger;
for($i=0;$i<$total_deger);$i++){
$xxx[i]="[Date.UTC(".$data[i]['year'].",".$data[i]['month'].",".$data[i]['day'].",".$data[i]['saat'].",".$data[i]['dakika'].",00),".$data[i]['Guc']."]";if($no < $total_deger){echo ",";}
echo $xxx[i];
}
When I run this code, nothing happens in page. When I write to for example 0 for i. I can see my array value. Where do I mistake?
Code with correction and suggestion (both are commented):-
<?php
error_reporting(E_ALL); // check all errors
ini_set('display_errors',1);// display those errors
$var = "SELECT SUBSTRING(KayitTarihi,1,4) AS year,SUBSTRING(KayitTarihi,6,2) AS month,SUBSTRING(KayitTarihi,9,2) AS day,SUBSTRING(KayitTarihi,12,2) AS saat,SUBSTRING(KayitTarihi,15,2) AS dakika,Guc FROM Urun WHERE Date(KayitTarihi)=\"".$link_m."\"";
$result = $mysqli->query($var);
$data = array();
if ($result->num_rows > 0) { // check you got results or not
while($row = $result->fetch_assoc()) {
$data[] = $row; // assign them
}
}
//foreach ($result as $row) {$data[] = $row;} // not needed
print_r($data);
$no=1;
$total_deger= count($data);
echo $total_deger;
for($i=0;$i<$total_deger;$i++){ // remove )
$xxx[$i]="[Date.UTC(".$data[$i]['year'].",".$data[$i]['month'].",".$data[$i]['day'].",".$data[$i]['saat'].",".$data[$i]['dakika'].",00),".$data[$i]['Guc']."]"; // use $i instead of i
if($no < $total_deger)
{
echo ",";
}
echo $xxx[$i];
}
Note:- Always add some error reporting code. So that all errors will populated and you can rectify those
Also better would be to use foreach() instead of for loop (as it will take care of indexes itself):-
//use foreach
foreach ($data as $dat){
echo "[Date.UTC(".$data['year'].",".$data['month'].",".$data['day'].",".$data['saat'].",".$data['dakika'].",00),".$data['Guc']."]";
}
Firstly you want to check your SQL query returns rows. Then I think you need to modify your foreach to a while as below. Also checking that rows are returned before looping.
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$data[] = $row;
}
}
As per example given here: http://www.w3schools.com/php/php_mysql_select.asp
I want to echo the values of all arrays that has been returned from a search function. Each array contains one $category, that have been gathered from my DB. The code that I've written so far to echo these as their original value (e.g. in the same form they lay in my DB.) is:
$rows = search($rows);
if (count($rows) > 0) {
foreach($rows as $row => $texts) {
foreach ($texts as $idea) {
echo $idea;
}
}
}
However, the only thing this code echoes is a long string of all the info that exists in my DB.
The function, which result I'm calling looks like this:
function search($query) {
$query = mysql_real_escape_string(preg_replace("[^A-Za-zÅÄÖåäö0-9 -_.]", "", $query));
$sql = "SELECT * FROM `text` WHERE categories LIKE '%$query%'";
$result = mysql_query($sql);
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows['text'] = $row;
}
mysql_free_result($result);
return $rows;
}
How can I make it echo the actual text that should be the value of the array?
This line: echo $rows['categories'] = $row; in your search function is problematic. For every pass in your while loop, you are storing all rows with the same key. The effect is only successfully storing the last row from your returned query.
You should change this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
echo $rows['categories'] = $row;
}
mysql_free_result($result);
return $rows;
to this...
$rows = array();
while ($row = mysql_fetch_assoc($result)) {
$rows[] = $row;
}
return $rows;
Then when you are accessing the returned value, you could handle it like the following...
foreach ($rows as $key => $array) {
echo $array['columnName'];
// or
foreach ($array as $column => $value) {
echo $column; // column name
echo $value; // stored value
}
}
The problem is that you have a multi-dimensional array, that is each element of your array is another array.
Instead of
echo $row['categories'];
try print_r:
print_r($row['categories']);
This will technically do what you ask, but more importantly, it will help you understand the structure of your sub-arrays, so you can print the specific indices you want instead of dumping the entire array to the screen.
What does a var_dump($rows) look like? Sounds like it's a multidimensional array. You may need to have two (or more) loops:
foreach($rows as $row => $categories) {
foreach($categories as $category) {
echo $category;
}
}
I think this should work:
foreach ($rows as $row => $categories) {
echo $categories;
}
If this will output a sequence of Array's again, try to see what in it:
foreach ($rows as $row => $categories) {
print_r($categories);
}
I am trying to build a function that extracts information from a database and inserts it into an associative array in PHP using mysql_fetch_assoc, and return the array so another function can display it. I need a way to display the returned assoc array. This should be a different function from the first one
print_r($array) will give nicely formatted (textually, not html) output.
If you just want information about what is in the array (for debugging purposes), you can use print_r($array) or var_dump($array), or var_export($array) to print it in PHP's array format.
If you want nicely formatted output, you might want to do something like:
<table border="1">
<?php
foreach($array as $name => $value) {
echo "<tr><th>".htmlspecialchars($name).
"</th><td>".htmlspecialchars($value)."</th></tr>";
}
?>
</table>
This will, as you might already see, print a nicely formatted table with the names in the left column and the values in the right column.
while ($row = mysql_fetch_assoc($result)) {
foreach ($row as $column => $value) {
//Column name is in $column, value in $value
//do displaying here
}
}
If this is a new program, consider using the mysqli extension instead.
Assuming you've made the call, and got $result back:
$array = new array();
while($row = mysql_fetch_assoc($result)){
$array[] = $row;
}
return $array;
This should get you going:
$rows = mysql_query("select * from whatever");
if ($rows) {
while ($record = mysql_fetch_array($rows)) {
echo $record["column1"];
echo $record["column2"];
// or you could just var_dump($record); to see what came back...
}
}
The following should work:
$rows = mysql_query("select * from whatever");
if ($rows) {
$header = true;
while ($record = mysql_fetch_assoc($rows)) {
if ($header) {
echo '<tr>';
foreach (array_keys($record) AS $col) {
echo '<td>'.htmlspecialchars($col).'</td>';
}
echo '</tr>';
$header = false;
}
echo '<tr>';
foreach (array_values($record) AS $col) {
echo '<td>'.htmlspecialchars($col).'</td>';
}
echo '</tr>';
}
}
(Yes, blatant mod of Fosco's code)
This should print the column headers once, then the contents after that. This would print just whatever columns were retrieved from the DB, regardless of the query.