ignore url in PHP regex - php

Question

I've got a utility where I'm trying to enforce brand standards in an application where the function will wrap brand words in a span with a class.
public function filterBrandWords($text)
{
// look up the brand words from the config settings
$filter_terms = ['brandword1', 'brandword2', 'brandword3'];
$filtered_text = $text;
foreach ($filter_terms as $word) {
$match_count = preg_match_all('/' . $word . '/i', $text, $matches);
for ($i = 0; $i < $match_count; $i++) {
$brand_string = trim($matches[0][$i]);
$lower = strtolower($brand_string);
$new = '<span class="font-semibold">' . substr($lower, 0, 3) . '</span>' . substr($lower, 3);
$filtered_text = preg_replace('/\b' . $brand_string . '\b/', $new, $filtered_text);
}
}
return $filtered_text;
}
This works but noticed that it's also filtering text that contains the brand URL when applied.
I tried amending $match_count = preg_match_all('/' . $word . '/i', $text, $matches); to $match_count = preg_match_all('/' . $word . 'com$' . '/i', $text, $matches); in the hope it would ignore matches with com in them.
What have I gotten wrong here the regex?
If I do
echo filterBrandWords('brandword1');
the output is
<span class="font-semibold">bra</span>ndword1
with a URL, the output is
<span class="font-semibold">bra</span>ndword1.com
In those instances, I want to ignore the filter and just give it straight.

Answer 1

If you want to ignore anything like a URL you can use something like this as your regex:
(?|.*\.(com|net|org))
which is a Negative Lookahead assertion that matches URL's (broadly). Insert that into your function as I have done here:
function filterBrandWords($text)
{
// look up the brand words from the config settings
$filter_terms = ['brandword1', 'brandword2', 'brandword3'];
$filtered_text = $text;
if(!preg_match('/(?|.*\.(com|net|org))/', $filtered_text)) { // if it resembles a URL, skip it
foreach ($filter_terms as $word) {
$match_count = preg_match_all('/' . $word . '/i', $text, $matches);
for ($i = 0; $i < $match_count; $i++) {
$brand_string = trim($matches[0][$i]);
$lower = strtolower($brand_string);
$new = '<span class="font-semibold">' . substr($lower, 0, 3) . '</span>' . substr($lower, 3);
$filtered_text = preg_replace('/\b' . $brand_string . '\b/', $new, $filtered_text);
}
}
}
return $filtered_text;
}
Now call the function with something resembling a URL:
echo filterBrandWords('brandword1.com');
And the entire URL is just returned:
brandword1.com
EXAMPLE