How to wrap words of string every 1000 characters in php - php

Question

i have some big string, and some array of words that must be replaced with some changes, like wrapping in link. First issue is wrap whole words or combinations words. And the second issue is do previous step minimum every 1000 characters.
$string="lalala word lalala blah, blah lalala combination of words lalala lalala...";
$patterns=array('word','combination of words');
$replacements=array('word','combination of words');
For an example, what i must to do with snippet before?

Answer 1

It sounds to me like you're looking for wordwrap(). You can then use preg_replace_callback() to apply it to your search patterns and make the replacements:
foreach ($patterns as $pattern) {
$regex = '/' . preg_quote($pattern, '/') . '/';
$string = preg_replace_callback($regex, function($match) {
return '<a href="#">'
. wordwrap(htmlspecialchars($match), 1000, '<br />')
. '</a>';
}, $string);
}

Answer 2

SOLUTION:
<?php
function set_keys_by_words($content, $key, $words,$before,$after) {
$positions = array();
$string = '';
for ($i = 0; $i < count($words); $i++) {
$string = preg_replace('/\b' . $words[$i] . '\b/ui', $key . $words[$i], $content);
$position = mb_strpos($string, $key);
if ($position != '') {
$positions[(int) $position] = $words[$i];
}
}
ksort($positions);
$word = '';
$number = '';
$i = 0;
foreach ($positions as $k => $v) {
$i++;
if ($i == 1) {
$number = $k;
$word = $v;
}
}
if ((int) $number) {
$word_len = strlen($word);
$part_after = preg_replace('/\b' . $word . '\b/ui', $before . $word . $after, mb_substr($content, 0, $number + $word_len));
echo $part_after . mb_substr($content, $number + $word_len, 1000);
$content = mb_substr($content, $number + $word_len + 1000);
if ($content != '') {
set_keys_by_words($content, $key, $words);
}
} else if ($number == '' && $content != '') {
echo $content;
}
}
?>