I have a string as mentioned below:
$ts = "3/11/09 11:18:59 AM";
which I got using the date() function.
Now I need to convert this to a readable format like below
11-Mar-2009
I have tried everything using date(). How can I achieve this?
You need to convert it to something you can use for further formatting. strtotime() is a good start, which yields a unix timestamp. You can format that one using strftime() then.
strftime("%d-%b-%G", strtotime($ts));
Actually I tried doing this and it worked.
echo date("d-M-Y", strtotime($ts));
If you initially get the string from the date() function, then pass on formatting arguments to the date-function instead:
date('Y-m-d')
instead of converting the string once again.
EDIT: If you need to keep track of the actual timestamp, then store it as a timestamp:
// Store the timestamp in a variable. This is just an integer, unix timestamp (seconds since epoch)
$time = time();
// output ISO8601 (maybe insert to database? whatever)
echo date('Y-m-d H:i', $time);
// output your readable format
echo date('j-M-Y', $time);
Using strtotime() is convinient but unessecary parsing and storage of a timerepresentation is a stupid idea.
You can use the date() function to generate the required format directly, like so:
date("j-M-Y");
See www.php.net/date for all the possible formats of the output of the date() function.
Related
I have a php string from db it is 20/11/2017 I want to convert it milliseconds.
It's my code to doing that.
$the_date = "20/11/2017";
$mill_sec_date = strtotime($the_date);
var_dump($mill_sec_date);
But it does not print any thing rather than
bool(false);
What is the problem and how can i solve it ????
When using slashes to separate parts of the date, PHP recognizes the format as MM/DD/YYYY. Which makes your date invalid because there is no 20th month. If you want to use the format where day and month is swapped, you need to use hyphens, like DD-MM-YYYY.
$time = strtotime('10/16/2003');
$newformat = date('Y-m-d',$time);
print_r($newformat);
Use DateTime class to call function createFromFormat
$date = date_create_from_format('d/M/Y:H:i:s', $string);
$date->getTimestamp();
Most likely you got the date format wrong, see
here for a list of supported date and time formats:
This section describes all the different formats that the strtotime(), DateTime and date_create() parser understands.
You string is not accept by the strtotime, you can use createFromFormat set set the with the format type of the time string like below, you can also check the live demo. And you also can refer to this answer
var_dump(DateTime::createFromFormat('d/m/Y', "20/11/2017"));
Paypal returns a timestamp of the following format:
yyyy-MM-ddTHH:mm:ssZ
And I don't quite know what to do with it...
How can I convert it to yyyy-MM-dd HH:mm:ss using my local timezone in php?
I'm tempted to preg_replace the mysterious letters, but something tells me there must a better way. There also appears to be 8 hours difference to my zone which I'm not sure how to substract.
Use DateTime class to do your magic.
$date = new DateTime('2012-09-09T21:24:34Z');
$date->format('Y-m-d'); # read format from date() function
You can use strtotime() to get a UNIX timestamp. From there you can do whatever you need: DateTime object, date(), etc.
Example with date():
echo date('r', strtotime('2012-09-10T10:00:00Z'));
strtotime() in PHP works great if you can provide it with a date format it understands and can convert, but for example you give it a UK date it fails to give the correct unix timestamp.
Is there any PHP function, official or unofficial, that can accept a format variable that tells the function in which format the date and time is being passed?
The closest I have come to doing this is a mixture of date_parse_from_format() and mktime()
// Example usage of the function I'm after
//Like the date() function but in reverse
$timestamp = strtotimeformat("03/05/2011 16:33:00", "d/m/Y H:i:s");
If you have PHP 5.3:
$date = DateTime::createFromFormat('d/m/Y H:i:s', '03/05/2011 16:33:00');
echo $date->getTimestamp();
You are looking for strptime, I think. you can use it to parse the date and then use mktime if you need a UNIX timestamp.
function strotimeformat($date, $format) {
$d = strptime($date, $format);
return mktime($d['tm_hour'], $d['tm_min'], $d['tm_sec'],
$d['tm_mon'], $d['tm_mday'], $d['tm_year']);
}
This will work with PHP 5.1 and onwards.
strtotime assumes it's a US date/time when using / as the separator. To get it to think it's a Euro date/time, use - or . as the date separator. You can change the /s to -s or .s with a simple str_replace()
I need to get the date/time format produced from a date / picker which currently outputs in this format 06-15-2011 09:35:32
The format I require is the same as what get produced from the function time() = 1308126939
I have look everywhere for this answer and cannot find.
use the strtotime function
echo strtotime('06-15-2011 09:35:32');
Good luck!
Try using strtotime() function which converts text datetime notation into Unix timestamp.
The timestamp from time() is a unix format representing the number of seconds since 1st January 1970. It can be replicated in date() as $timestamp = date("U");
You should be able to convert it using the strtotime() command.
$myDate = "06-15-2011 0-9:35:32"
$timestamp = strtotime($myDate)
You can then go on to format that in other ways using the date() function.
I want to convert date 24/09/2010 in format dd/mm/yyyy to 2010-09-24 in format yyyy-mm-dd.
This works:
date("Y-m-d",strtotime("09/24/2010"));
But this does not:
date("Y-m-d",strtotime("24/09/2010")); // it returns '1970-01-01'
Any idea why?
according to php, the valid php formats are stated here. So basically what you gave is invalid.
Alternatively, you can use mktime, date_parse_from_format or date_create_from_format
strtotime does its best to guess what you mean when given a string, but it can't handle all date formats. In you example, it is probably thinking that you are trying to refer to the 24th month, which isn't valid, and returns 0, which date then treats as the unix epoch (the date you got).
you can get around this using the mktime() and explode() functions, like so:
$date = "24/09/2010";
$dateArr = explode("/",$date);
$timeStamp = mktime(0,0,0,$dateArr[1],$dateArr[0],$dateArr[2]);
$newFormat = date("Y-m-d",$timeStamp);
As you say,
date("Y-m-d",strtotime("09/24/2010"))
will work,because the date format--"09/24/2010"is correct,
but "24/09/2010" is not the correct date format.
you can find something useful here