strtotime() in PHP works great if you can provide it with a date format it understands and can convert, but for example you give it a UK date it fails to give the correct unix timestamp.
Is there any PHP function, official or unofficial, that can accept a format variable that tells the function in which format the date and time is being passed?
The closest I have come to doing this is a mixture of date_parse_from_format() and mktime()
// Example usage of the function I'm after
//Like the date() function but in reverse
$timestamp = strtotimeformat("03/05/2011 16:33:00", "d/m/Y H:i:s");
If you have PHP 5.3:
$date = DateTime::createFromFormat('d/m/Y H:i:s', '03/05/2011 16:33:00');
echo $date->getTimestamp();
You are looking for strptime, I think. you can use it to parse the date and then use mktime if you need a UNIX timestamp.
function strotimeformat($date, $format) {
$d = strptime($date, $format);
return mktime($d['tm_hour'], $d['tm_min'], $d['tm_sec'],
$d['tm_mon'], $d['tm_mday'], $d['tm_year']);
}
This will work with PHP 5.1 and onwards.
strtotime assumes it's a US date/time when using / as the separator. To get it to think it's a Euro date/time, use - or . as the date separator. You can change the /s to -s or .s with a simple str_replace()
Related
I have a php string from db it is 20/11/2017 I want to convert it milliseconds.
It's my code to doing that.
$the_date = "20/11/2017";
$mill_sec_date = strtotime($the_date);
var_dump($mill_sec_date);
But it does not print any thing rather than
bool(false);
What is the problem and how can i solve it ????
When using slashes to separate parts of the date, PHP recognizes the format as MM/DD/YYYY. Which makes your date invalid because there is no 20th month. If you want to use the format where day and month is swapped, you need to use hyphens, like DD-MM-YYYY.
$time = strtotime('10/16/2003');
$newformat = date('Y-m-d',$time);
print_r($newformat);
Use DateTime class to call function createFromFormat
$date = date_create_from_format('d/M/Y:H:i:s', $string);
$date->getTimestamp();
Most likely you got the date format wrong, see
here for a list of supported date and time formats:
This section describes all the different formats that the strtotime(), DateTime and date_create() parser understands.
You string is not accept by the strtotime, you can use createFromFormat set set the with the format type of the time string like below, you can also check the live demo. And you also can refer to this answer
var_dump(DateTime::createFromFormat('d/m/Y', "20/11/2017"));
How to convert this (in ISO8601 format): 2014-03-13T09:05:50.240Z
To this (in MySQL DATE format): 2014-03-13
in php?
try this
$date = '2014-03-13T09:05:50.240Z';
$fixed = date('Y-m-d', strtotime($date));
The complete date function documentation can be found here: http://php.net/manual/en/function.date.php
The PHP function "strtotime" does nothing else then converting your timestring into an unix timestamp.
Hope I could help :)
P.s.:
Just in case strtotime will return 0 try using this:
$date = '2014-03-13T09:05:50.240Z';
$fixed = date('Y-m-d', strtotime(substr($date,0,10)));
Since PHP 5.2.0 you can do it using OOP and DateTime() as well (of course if you prefer OOP):
$now = new DateTime("2014-03-13T09:05:50.240Z");
echo $now->format('Y-m-d'); // MySQL datetime format
There is no reason to use the inefficient time functions. The most efficient way is to simply extract the first 10 characters:
substr($date,0,10)
People, that are really coding for year ≥10000, can use:
substr($date,0,strpos($date,"T"))
Simply convert datetime description into a Unix timestamp using with strtotime and then five format using Date Formats
Try it will surely work for you.
$date = '2014-03-13T09:05:50.240Z';
$fixed = date('Y-m-d', strtotime($date));
For those using Carbon (php library), the parse() works quite well:
Carbon::parse($date)
https://carbon.nesbot.com/docs/
Today I have published an interitty/utils package that deals with, among other things, the ISO-8601 format and perhaps all permutations of this standard.
I hope it will help you too.
$dateTimeFactory = new Interitty\Utils\DateTimeFactory();
$dateTime = $dateTimeFactory->createFromIso8601('1989-12-17T12:00:00Z');
This should be simple, but I'm having trouble... so turn to StackOverflow...
I'm in the UK and am getting a date from the jQuery DatePicker in a dd/mm/yy format.
I want to store this date as a serial (yyyymmdd) so run a Date_To_Serial function that just does:
return date("Ymd", strtotime($strDate_In));
where $strDate_In is the date string in dd/mm/yy format.
So, passing in 01/12/2013, I expect 20131201 to be returned.
But, when 01/12/2013 is passed in, it returns 20130112 - PHP obviously assumes the date format is mm/dd/yyyy.
How can I fix this please?
If you know the format, try using the static createFromFormat method on the DateTime class:
$date = DateTime::createFromFormat('d/m/Y', '01/12/2013');
return $date->format('Ymd');
If the separator is a / then strtotime assumes a US-format. To have it recognise a UK format the separator must be - or .:
echo date('Ymd', strtotime('01/12/2014')); // 20140112
echo date('Ymd', strtotime('01-12-2014')); // 20141201
So for this to work in your example you would do:
return date("Ymd", strtotime(str_replace('/', '-', $strDate_In)));
Use a DateTime object's createFromFormat method. It allows you to specify the format of the input.
Afterwards, use the format method to export the date in the desired format.
Check out DateTime::createFromFormat for correct handling of non-standard date formats.
return DateTime::createFromFormat("d/m/Y", $strDate_In)->format("Ymd");
I need to get the date/time format produced from a date / picker which currently outputs in this format 06-15-2011 09:35:32
The format I require is the same as what get produced from the function time() = 1308126939
I have look everywhere for this answer and cannot find.
use the strtotime function
echo strtotime('06-15-2011 09:35:32');
Good luck!
Try using strtotime() function which converts text datetime notation into Unix timestamp.
The timestamp from time() is a unix format representing the number of seconds since 1st January 1970. It can be replicated in date() as $timestamp = date("U");
You should be able to convert it using the strtotime() command.
$myDate = "06-15-2011 0-9:35:32"
$timestamp = strtotime($myDate)
You can then go on to format that in other ways using the date() function.
I have a string as mentioned below:
$ts = "3/11/09 11:18:59 AM";
which I got using the date() function.
Now I need to convert this to a readable format like below
11-Mar-2009
I have tried everything using date(). How can I achieve this?
You need to convert it to something you can use for further formatting. strtotime() is a good start, which yields a unix timestamp. You can format that one using strftime() then.
strftime("%d-%b-%G", strtotime($ts));
Actually I tried doing this and it worked.
echo date("d-M-Y", strtotime($ts));
If you initially get the string from the date() function, then pass on formatting arguments to the date-function instead:
date('Y-m-d')
instead of converting the string once again.
EDIT: If you need to keep track of the actual timestamp, then store it as a timestamp:
// Store the timestamp in a variable. This is just an integer, unix timestamp (seconds since epoch)
$time = time();
// output ISO8601 (maybe insert to database? whatever)
echo date('Y-m-d H:i', $time);
// output your readable format
echo date('j-M-Y', $time);
Using strtotime() is convinient but unessecary parsing and storage of a timerepresentation is a stupid idea.
You can use the date() function to generate the required format directly, like so:
date("j-M-Y");
See www.php.net/date for all the possible formats of the output of the date() function.