I have a php string from db it is 20/11/2017 I want to convert it milliseconds.
It's my code to doing that.
$the_date = "20/11/2017";
$mill_sec_date = strtotime($the_date);
var_dump($mill_sec_date);
But it does not print any thing rather than
bool(false);
What is the problem and how can i solve it ????
When using slashes to separate parts of the date, PHP recognizes the format as MM/DD/YYYY. Which makes your date invalid because there is no 20th month. If you want to use the format where day and month is swapped, you need to use hyphens, like DD-MM-YYYY.
$time = strtotime('10/16/2003');
$newformat = date('Y-m-d',$time);
print_r($newformat);
Use DateTime class to call function createFromFormat
$date = date_create_from_format('d/M/Y:H:i:s', $string);
$date->getTimestamp();
Most likely you got the date format wrong, see
here for a list of supported date and time formats:
This section describes all the different formats that the strtotime(), DateTime and date_create() parser understands.
You string is not accept by the strtotime, you can use createFromFormat set set the with the format type of the time string like below, you can also check the live demo. And you also can refer to this answer
var_dump(DateTime::createFromFormat('d/m/Y', "20/11/2017"));
Related
All,
I have the following string:
$dateTime = '2013-09-15T00:00:00.000Z';
Is there a function to extract Year, Month and Date from the above string, so the result looks like the following:
$yearMonthDate = '2013-09-15';
Thanks
You could convert your datetime to a timestamp using strtotime() and then convert it back into a formatted date using this kind of syntax:
date("Y-m-d", strtotime($myOriginalDate))
substr or DateTime or strtotime+date
Since the first string is actually a standard, you can just use substr:
$yearMonthDate = substr($dateTime, 0, 10);
However, that would be kind of a hack and would obviously break if the format of $dateTime were to change. So, you might want to look into the PHP DateTime class instead.
I want to convert date 24/09/2010 in format dd/mm/yyyy to 2010-09-24 in format yyyy-mm-dd.
This works:
date("Y-m-d",strtotime("09/24/2010"));
But this does not:
date("Y-m-d",strtotime("24/09/2010")); // it returns '1970-01-01'
Any idea why?
according to php, the valid php formats are stated here. So basically what you gave is invalid.
Alternatively, you can use mktime, date_parse_from_format or date_create_from_format
strtotime does its best to guess what you mean when given a string, but it can't handle all date formats. In you example, it is probably thinking that you are trying to refer to the 24th month, which isn't valid, and returns 0, which date then treats as the unix epoch (the date you got).
you can get around this using the mktime() and explode() functions, like so:
$date = "24/09/2010";
$dateArr = explode("/",$date);
$timeStamp = mktime(0,0,0,$dateArr[1],$dateArr[0],$dateArr[2]);
$newFormat = date("Y-m-d",$timeStamp);
As you say,
date("Y-m-d",strtotime("09/24/2010"))
will work,because the date format--"09/24/2010"is correct,
but "24/09/2010" is not the correct date format.
you can find something useful here
To change 2009-12-09 13:32:15 to 09/12/2009
here:
echo date("d/m/Y", strtotime('2009-12-09 13:32:15'))
You can use strtotime to get the timestamp of the first date, and date to convert it to a string using the format you want.
$timestamp = strtotime('2009-12-09 13:32:15');
echo date('d/m/Y', $timestamp);
And you'll get :
09/12/2009
[edit 2012-05-19] Note that strtotime() suffers a couple of possibly important limitations:
The format of the date must be YYYY-MM-DD; it might work in some other cases, but not always !
Also, working with UNIX Timestamps, as done with date() and strtotime() means you'll only be able to work with dates between 1970 and 2038 (possibly a wider range, depending on your system -- but not and illimited one anyway)
Working with the DateTime class is often a far better alternative:
You can use either DateTime::__construct() or DateTime::createFromFormat() to create a DateTime object -- the second one is only available with PHP >= 5.3, but allows you to specify the date's format, which can prove useful,
And you can use the DateTime::format() method to convert that object to any date format you might want to work with.
Using the date() method.
print date("d/m/Y", strtotime("2009-12-09 13:32:15"));
$long_date = '2009-12-09 13:32:15';
$epoch_date = strtotime($long_date);
$short_date = date('m/d/Y', $epoch_date);
The above is not the shortest way of doing it, but having the long date as an epoch timestamp ensures that you can reuse the original long date to get other date format outputs, like if you wanted to go back and have just the time somewhere else.
Duplicate
Managing date formats differences between PHP and MySQL
PHP/MySQL: Convert from YYYY-MM-DD to DD Month, YYYY?
Format DATETIME column using PHP after printing
date formatting in php
Dear All,
I have a PHP page where i wil be displaying some data from Mysql db.
I have 2 dates to display on this page.In my db table, Date 1 is in the format d/m/Y (ex: 11/11/2002) and Date 2 is in the format d-m-Y (ex : 11-11-2002)
I need to display both of this in the same format .The format i have stored in a variable $dateFormat='m/d/Y'
Can any one guide me
Thanks in advance
Use strtotime to convert the strings into a Unix timestamp, then use the date function to generate the correct output format.
Since you're using the UK date format "d/m/Y", and strtotime expects a US format, you need to convert it slighly differently:
$date1 = "28/04/2009";
$date2 = "28-04-2009";
function ukStrToTime($str) {
return strtotime(preg_replace("/^([0-9]{1,2})[\/\. -]+([0-9]{1,2})[\/\. -]+([0-9]{1,4})/", "\\2/\\1/\\3", $str));
}
$date1 = date($dateFormat, ukStrToTime($date1));
$date2 = date($dateFormat, ukStrToTime($date2));
You should be all set with this:
echo date($dateFormat, strtotime($date1));
echo date($dateFormat, strtotime($date2));
You may want to look into the strptime function. This can convert any date from a string back into numeric values. Unlike strtotime, it can be adapted to different formats, including those from different locales, and its output is not a UNIX timestamp, so it's capable of parsing dates before 1970 and after 2037. It may be a little bit more work though because it returns an associative array though.
Unfortunately it's not available on Windows systems either so it's not portable.
If for some reason strtotime will not work for you, could always just replace the offending punctuation with str_replace.
function dateFormat($date) {
$newDate = str_replace(/, -, $date);
echo $newDate;
}
echo dateFormat($date1);
echo dateFormat($date2);
I know this will make most folks cringe, but it may help you with formatting non-date strings in the future.
rookie i am. so came up with the method that just do that. what mysql needs.. shish i used param 2... hope it helps. regards
public function dateConvert($date,$param){
if($param==1){
list($day,$month,$year)=split('[/.-]',$date);
$date="$year-$month-$day"; //changed this line
return $date;
}
if ($param == 2){ //output conversion
list($day,$month,$year) = split('[/.]', $date);
$date = "$year-$day-$month";
return $date;
}
}
I have a string as mentioned below:
$ts = "3/11/09 11:18:59 AM";
which I got using the date() function.
Now I need to convert this to a readable format like below
11-Mar-2009
I have tried everything using date(). How can I achieve this?
You need to convert it to something you can use for further formatting. strtotime() is a good start, which yields a unix timestamp. You can format that one using strftime() then.
strftime("%d-%b-%G", strtotime($ts));
Actually I tried doing this and it worked.
echo date("d-M-Y", strtotime($ts));
If you initially get the string from the date() function, then pass on formatting arguments to the date-function instead:
date('Y-m-d')
instead of converting the string once again.
EDIT: If you need to keep track of the actual timestamp, then store it as a timestamp:
// Store the timestamp in a variable. This is just an integer, unix timestamp (seconds since epoch)
$time = time();
// output ISO8601 (maybe insert to database? whatever)
echo date('Y-m-d H:i', $time);
// output your readable format
echo date('j-M-Y', $time);
Using strtotime() is convinient but unessecary parsing and storage of a timerepresentation is a stupid idea.
You can use the date() function to generate the required format directly, like so:
date("j-M-Y");
See www.php.net/date for all the possible formats of the output of the date() function.