<?php
// MySQL database connection file
$SERVER = "127.0.0.1"; // MySQL SERVER
$USER = "root"; // MySQL USER
$PASSWORD = "admin"; // MySQL PASSWORD
$link = #mysql_connect($SERVER,$USER,$PASSWORD);
$db = mysql_select_db("website");
?>
This is a database connecting code for chat program but it not connecting,Can any one pls help me to correct this code?
Drop the # infront of mysql_connect, it's used to suppress error which you don't want.
Also you need to check the return value of mysql_connect which is there in $link and make sure that it is not false before you proceed and to a DB select. Calling the function mysql_error when an error occurs gives you the reason for the error.
$link = mysql_connect($SERVER,$USER,$PASSWORD);
if (!$link) {
die('Could not connect: ' . mysql_error());
}
Related
I've looked through StackOverflow for an answer to this and have so far come up empty handed. I know some have had a similar issue, but so far none of the responses to the issues have worked.
So I work on two sites, both of which are on the same host with the same PHP Admin set up (different accounts and domains, sites are not affiliated). One of them uses MySqli perfectly, without issues, while the other either gives a database selection failure, localhost access denied with password as "NO" or a blank page when I attempt to replace the MySql with MySqli.
The deprecated code:
$host = "LOCALHOST";
$usr = "USER";
$pwd = "PASSWORD";
$dbname = "DATABASE";
$connection = #mysql_connect($host,$usr,$pwd);
if(!$connection){
die("No connection.");
}
mysql_select_db($dbname,$connection);
The MySqli I am attempting (identical to the site that MySqli works perfectly on):
$host = "LOCALHOST";
$usr = "USER";
$pwd = "PASSWORD";
$dbname = "DATABASE";
$connection = mysqli_connect($host,$usr,$pwd);
if (!$connection) {
die("No connection.");
}
$db_select = mysqli_select_db($connection, $dbname);
if (!$db_select) {
die("Database selection failed: " . mysqli_error($connection));
}
So the PHP error codes did not work at all and it had nothing to do with the local host or port, so I first checked to make sure mysqli_connect was on. Next, I ran a simple test where I echoed a random word before each mysqli command.
echo 'Passed.';
global $c_mysqli;
$conn = new mysqli($host, $usr, $pwd, $dbname);
echo '<br>Passed global mysqli.';
I found that my second pass was not working, and then proceeded to do an error message. An error showed up then. However, nothing I did fixed the issue... then I realized that one of my files, the header file, is the meat and potatoes and if it were to fail then everything else would fail too.
Sure enough, one of my lines of code contained a mysql connection and not mysqli. Long story short, double check and triple check to make sure that all
$statement = mysql_query("STATEMENT");
$query = mysql_fetch_array($statement);
Appear as
$statement = $conn->query("STATEMENT");
$query = mysqli_fetch_array($statement);
I am a student.
I'm trying to deliberately induce an error in
$db_connect->select_db($db_name);
to check the error handling, but it won't give out an error?
The actual database name is 'cart', but i am using 'cartxx' to try and induce an error, but nothing happens, it runs as if there is no error. I don't have a database named 'cartxx'.
<?php
session_start();
$host = 'localhost'; // connects to the host server
$db_name = 'cartxx'; // name of the database we are connecting to
$db_username = 'root'; // username for database
$db_password = ''; // password for database
$db_connect = new mysqli($host, $db_username, $db_password); // connect to mysql
// If error
if (mysqli_connect_errno()) {
echo('Connection to database failed: ' . mysqli_connect_error());
exit();
}
// Select database
$db_connect->select_db($db_name);
// If error
if (mysqli_connect_errno()) {
echo 'Connection to database {$db_name} has failed: ' . mysqli_connect_error();
exit();
}
Thanks.
you need to pass default db name in connection string directly. if you need connect to one more database you can use select statment
$db_connect = new mysqli($host, $db_username, $db_password, $db_name);
for more :- http://php.net/manual/en/function.mysqli-connect.php
mysqli::selectdb will NOT return false if you give him an incorrect database name.
This function suits better a "i want to switch from database X to database Y" scenario, and will stay connected to database X if database Y is not found.
You can check the manual for this function.
A better way to select the database at connection is to use the mysqli constructor.
Hey I'm wanting to retrieve some data from the a database. But it seems whenever I enter my credentials into the SQL database to retrieve the data I get the following error:
Since i presume this is a similar use case as your last question
Your php file is missing the configuration of the connection:
<?php
$dbuser = "******";
$dbpass = "*******";
$db = "SSID";
$connect = OCILogon($dbuser, $dbpass, $db);
if (!$connect) {
echo "An error occurred connecting to the database";
exit;
}
So it knows which connection you are using and passing to the checkUserPass() function.
UPDATE:
For the table name you need to pass $dbtable as you can see in the function declaration
function checkUserPass($connect,$username, $password, $dbtable)
so either set a $dbtable variable before calling the function:
$dbtable="register_table";
or send it immediately as a string:
function checkUserPass($connect,$username, $password, "register_table")
I'm following a tutorial on the net on PHP and MySQL.
I'm using Linux. I'm trying to establish a connection to a database but it is not working.
I have my database:
create database test;
create table user(name text, pass text);
insert into user values('john', '123');
and then my php:
<?php
$_host = "localhost";
$_dbuser = "root"
$_dbpass = "";
$_dbname = "test";
#mysql_connect("$_host", "$_dbuser", "$_dbpass") or die("could not connect");
#mysql_select_db("$_dbname") or die("no database");
echo "connection stablished";
?>
And the output of my file is just a blank tab on the browser.
What should I do to solve this? What am I doing wrong?
Thank you in advance. I'm very new to web programming.
$_host = "localhost";
$_dbuser = "root"
$_dbpass = "";
$_dbname = "test";
$link = mysqli_connect($_host, $_dbuser, $_dbpass, $_dbname);
if (!$link) {
die('Connect Error (' . mysqli_connect_errno() . ') '
. mysqli_connect_error());
}
echo "connection stablished";
Now...
Use mysqli_* functions as mysql_* are deprecated.
You will need $link variable later for queries.
As you're newbie read this: How can I prevent SQL injection in PHP?
Prepared statements FTW! Remember!
I am just using a basic code to connect to my Mysql database. I am able to connect to my server but not database. using sqlyog:
<?php
$username = "root";
$hostname = "localhost";
$dbhandle = mysql_connect($hostname, $username) or die("Unable to connect to MySQL");
$selected = mysql_select_db("project",$dbhandle) or die("Could not select project");
$sql = "SELECT image_small FROM images";
mysql_query($sql,$selected);
while($row=extract_row($sql))
{
echo $row['image_small'];
}
?>
where is password of database? mysql_connect should be used as:
mysql_connect("localhost", "mysql_user", "mysql_password");
otherwise it will be the default password that will be used
There are so many things wrong here.
1. Your have a blank password for the root user in your database.
2. You're using mysql_* which everybody know is subject to many hasck.
3. You're trying to "extract" a row from your SQL query.
Use PDO:
$DB = new PDO("mysql:host=localhost;dbname=project","root","root_password");
$sql = "SELECT image_small FROM images";
foreach($DB->query($sql, PDO::FETCH_ASSOC) as $row) {
echo $row['image_small'];
}
try to connect using the following statement
$selected = mysql_select_db("project");
// i think you have to provide password in here mysql_connect($hostname, $username,$password);
since it is localhost and user is root you could use like this
mysql_connect($hostname, $username,"");