Hey I'm wanting to retrieve some data from the a database. But it seems whenever I enter my credentials into the SQL database to retrieve the data I get the following error:
Since i presume this is a similar use case as your last question
Your php file is missing the configuration of the connection:
<?php
$dbuser = "******";
$dbpass = "*******";
$db = "SSID";
$connect = OCILogon($dbuser, $dbpass, $db);
if (!$connect) {
echo "An error occurred connecting to the database";
exit;
}
So it knows which connection you are using and passing to the checkUserPass() function.
UPDATE:
For the table name you need to pass $dbtable as you can see in the function declaration
function checkUserPass($connect,$username, $password, $dbtable)
so either set a $dbtable variable before calling the function:
$dbtable="register_table";
or send it immediately as a string:
function checkUserPass($connect,$username, $password, "register_table")
Related
This question already has answers here:
Why shouldn't I use mysql_* functions in PHP?
(14 answers)
Closed 5 years ago.
I wonder if someone can help. I gave up web programming about 3 years ago. Since returning to programming about a week ago I realize I have forgotten quite a lot and so much has changed.
I signed on to a deal with php7 but my code is php5 and when I came to running my scripts nothing really works.
For example I couldn't even connect to the database. My database connection file for php5 was
<?php
$db_host = "localhost";
// Place the username for the MySQL database here
$db_username = "db_username_here";
// Place the password for the MySQL database here
$db_pass = "db_password_here";
// Place the name for the MySQL database here
$db_name = "name_of_database_here";
// Run the actual connection here
mysql_connect("$db_host","$db_username","$db_pass") or die ("could not connect to mysql");
mysql_select_db("$db_name") or die ("no database");
?>
I spoke to the server company and they told me everything has changed and to get my code compatible with php7. They then helped me get my database connected by giving me a sample file of how it should be which is this code.
<?
/* DATEBASE CONFIGURATION */
$dbHost = "ip Address";
$dbName = "name_of_database_here"; // Database name
$dbUser = "db_username_here"; // Database user
$dbPasswd = "db_password_here"; // Database password
function dbConnect(){
global $dbHost, $dbUser, $dbPasswd, $dbName;
mysql_connect( $dbHost, $dbUser, $dbPasswd ) or error( mysql_error() );
mysql_select_db( $dbName );
}
?>
I have always run my database $dbHost from localhost so I have guessed that because they haven't done the connection as localhost and done it as gobal with an ip address I have figured that the database is not on the same server as the website.
I then came to my database scripts for running from the browser to phpmyadmin and they also didnt work. Here is my database script php5.
<?php
require "connect_to_mysql.php";
$sqlCommand = "CREATE TABLE admin (
id int(11) NOT NULL auto_increment,
username varchar(24) NOT NULL,
password varchar(24) NOT NULL,
last_log_date date NOT NULL,
PRIMARY KEY (id),
UNIQUE KEY username (username)
) ";
if (mysql_query($sqlCommand)){
echo "Your admin table has been created successfully!";
} else {
echo "CRITICAL ERROR: admin table has not been created.";
}
?>
I was wondering if someone could give me some advice on why the script isn't running
Many thanks, Gary
mysql_connect is removed from php7.
instead of that you can use either mysqli or pdo
example with mysqli
<?php
$servername = "localhost";
$username = "username";
$password = "password";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
example with pdo
<?php
$servername = "localhost";
$username = "username";
$password = "password";
try {
$conn = new PDO("mysql:host=$servername;dbname=myDB", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "Connected successfully";
}
catch(PDOException $e)
{
echo "Connection failed: " . $e->getMessage();
}
For more reffer details https://www.w3schools.com/php/php_mysql_connect.asp
Just moved my site to new hosting. On the new server mysql_connect() works fine if called without using classes or inside of the method but not from the _construct. When connecting from the _construct the following error displays:
Access denied for user 'root'#'localhost' (using password: NO)...my configuration defines the user not as root but as USERNAME and does provides a password.
PHP 5.6, MySQL 5.5, Linux
Class File:
function __construct(){
error_reporting(E_ERROR);
$dbhost = 'localhost';
$dbuser = 'USERNAME';
$dbpass = 'PASSWORD';
$dbname = 'DATABASENAME';
$this->urlAppPath = "http://www.myurl.com/CD/";
// connect to the database
$this->db = mysql_connect($dbhost, $dbuser, $dbpass) or die("Connection Error: " . $SQL);
mysql_select_db($dbname);
}
function validatePerson($personID) {
$SQL = "SELECT *,COUNT(*) AS total FROM zen_customers WHERE customers_classware_id = '$personID'";
$result = mysql_query( $SQL ) or die("Could not execute query 1 . ".$SQL." ".mysql_error()." & ". $dbhost ." ".$dbuser ." ".$dbpass." ".$dbname);
}
Call Method File:
require_once('./clsCart.php');
$myclass = new clsCart();
$result2 = $myclass->validatePerson($personID);
Note
If I define and call the connection within the file that I have been trying to call the method...that is instead of calling the method it works. If I define and call the connection within the method it works...but if I define and call the connection within the construct() it does not work...error "Access denied for user 'root'#'localhost' (using password: NO)". This seems to be specific to some servers...regardless of using PHP 5.6 or lower & MySQL 5.6 or lower.
So, if I use :
$dbhost = 'localhost';
$dbuser = 'USERNAME';
$dbpass = 'PASSWORD';
$dbname = 'DATABASENAME';
// connect to the database
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die("Connection Error: " . $SQL);
mysql_select_db($dbname);
Outside of the class or within the method then it works...but, I should (as I have in the past) be able to connect within the construct().
This seems to be related to a server issue. From the __contruct() only the Database default user information is being recognized. Everywhere else in the applications uses the User created for the database, but the construct will only connect when using the default database user on this server. Other servers are not having this issue, such that any database user with all privileges work.
You have to use mysqli_connect. Please never use mysql_connect it deprecated in PHP 5.5.0 and onwards. If still you face issue please let us know.
Following code for mysqli_connect :
<?php
$con = mysqli_connect("localhost","my_user","my_password","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
Definition and Usage
The mysqli_connect() function opens a new connection to the MySQL server.
Syntax
mysqli_connect(host,username,password,dbname,port,socket);
Parameter Description
port Optional. Specifies the port number to attempt to connect to the MySQL server.
socket Optional. Specifies the socket or named pipe to be used.
I've been having a bit of trouble with my PHP code.
I'm trying to insert a new row in table gebruikers.
I'm using a JSON API to post the data from my C# Android app to the server.
running the code returns an invalid request error.
PHP:
function registerUser($api_data)
{
// connection
$servername = "xxx";
$username = "xxx";
$password = "xxx";
$database = "test";
$mysqli = new mysqli($servername, $username, $password, $database);
//check connection
if(mysqli_connect_errno())
{
API_Response(true, 'connection error');
}
$register_data = json_decode($api_data);
$leerlingnummer = intval($register_data->leerlingnummer); //passed as string, int in database
$wachtwoord = $register_data->wachtwoord; //string
$email = $register_data->email; //string
$result = $mysqli->query("INSERT INTO `gebruikers` (`Leerlingnummer`, `Wachtwoord`, `Email`) VALUES ({$leerlingnummer}, {$wachtwoord}, {$email})");
if ($result == false)
{
API_Response(true, "{$mysqli->error}");
}
else
{
API_Response(false, 'SUCCESS');
}
$mysqli->close();
}
database is looking as follows:
database layout
I've never felt this stupid before, but the error came from the fact that I was still referencing to an older .php file. I was so focussed on the PHP script that I didn't notice this error in my app before.
the quotes advised by Sean and fuso were needed later on though so thanks for that.
Problem solved, sorry for wasting some of your time :/
You should quote your data in the insert query.
... VALUES ('{$email}','{$other}')
I am creating a form that will take a person's name and email and see if the email exists in the database already but I can't get the database to be selected. The mysql_error() won't display the error either. Is there something wrong with my code for selecting the database? All it shows is the hardcoded text "Could not select database because" then nothing. I replaced all the variables associated with the database with random fillers so as not to give away my info but everything I have is correct regarding that.
$host = "host";
$user = "user";
$password = "pass";
$database = "db";
$port = xxxx;
$table = "table";
// Create connection
$conn = mysqli_connect($host, $user, $password, $database, $port);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connection Successful";
mysqli_select_db($database)
or die("Could not select database because".mysqli_error());
// check if the username is taken
$check = "select email from $table where email = '".$_POST['email']."';";
$qry = mysqli_query($check)
or die ("Could not match data because ".mysqli_error());
$num_rows = mysqli_num_rows($qry);
if ($num_rows != 0) {
echo "Sorry, there the username $username is already taken.";
}
Don't call mysqli_select_db. You've already selected your database with the fourth parameter to mysqli_connect.
You only need to call mysqli_select_db if you want to access a different database after the connection has been established.
Also, Raptor is correct that if you call procedural mysqli_error() you must pass it a connection handle.
For Procedural style mysqli_error(), you must supply the MySQLi DB link as parameter:
mysqli_select_db($database)
or die("Could not select database because" . mysqli_error($conn));
But it's useless to call mysqli_select_db() as you already specified the DB schema in mysqli_connect().
Additionally, your SQL is vulnerable to SQL Injection attack. Always escape the parameter before putting into SQL statement, or use prepared statements.
try this code
<?php
$username = "your_name";
$password = "your_password";
$hostname = "localhost";
//connection to the database
$dbhandle = mysqli_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
echo "Connected to MySQL<br>";
?>
<?php
// MySQL database connection file
$SERVER = "127.0.0.1"; // MySQL SERVER
$USER = "root"; // MySQL USER
$PASSWORD = "admin"; // MySQL PASSWORD
$link = #mysql_connect($SERVER,$USER,$PASSWORD);
$db = mysql_select_db("website");
?>
This is a database connecting code for chat program but it not connecting,Can any one pls help me to correct this code?
Drop the # infront of mysql_connect, it's used to suppress error which you don't want.
Also you need to check the return value of mysql_connect which is there in $link and make sure that it is not false before you proceed and to a DB select. Calling the function mysql_error when an error occurs gives you the reason for the error.
$link = mysql_connect($SERVER,$USER,$PASSWORD);
if (!$link) {
die('Could not connect: ' . mysql_error());
}