Trying to connect database MySQL from PHP (Not Successful) - php

I'm following a tutorial on the net on PHP and MySQL.
I'm using Linux. I'm trying to establish a connection to a database but it is not working.
I have my database:
create database test;
create table user(name text, pass text);
insert into user values('john', '123');
and then my php:
<?php
$_host = "localhost";
$_dbuser = "root"
$_dbpass = "";
$_dbname = "test";
#mysql_connect("$_host", "$_dbuser", "$_dbpass") or die("could not connect");
#mysql_select_db("$_dbname") or die("no database");
echo "connection stablished";
?>
And the output of my file is just a blank tab on the browser.
What should I do to solve this? What am I doing wrong?
Thank you in advance. I'm very new to web programming.

$_host = "localhost";
$_dbuser = "root"
$_dbpass = "";
$_dbname = "test";
$link = mysqli_connect($_host, $_dbuser, $_dbpass, $_dbname);
if (!$link) {
die('Connect Error (' . mysqli_connect_errno() . ') '
. mysqli_connect_error());
}
echo "connection stablished";
Now...
Use mysqli_* functions as mysql_* are deprecated.
You will need $link variable later for queries.
As you're newbie read this: How can I prevent SQL injection in PHP?
Prepared statements FTW! Remember!

Related

MySQL error message, mysql_connect(), any way to fix it?

So this is the error message:
PHP Deprecated: mysql_connect(): The mysql extension is deprecated and will be removed in the future: use mysqli or PDO instead
This is the affected piece of code:
class wdClient {
var $dbLink; // The database link
var $prefix; // Table prefix
var $script; // The script running
/**
* Construct a new directory object.
*/
function wdClient() {
error_reporting(E_ALL ^ E_NOTICE);
$this->prefix = WDDBPREFIX;
// Connect to the database
$this->dbLink = mysql_connect(WDDBHOST, WDDBUSER, WDDBPASSWD);
// Select the database
mysql_select_db(WDDBNAME, $this->dbLink) or die('Sorry, The site is currently unavailable!');
}
where WDDBPREFIX, WDDBHOST, WDDBUSER, WDDBPASSWD, WDDBNAME are already defined in a config file.
I have tried simply using mysqli_connect instead of mysql_connect but it's not working.
Note: Never use MySQL, use this method!
//MySQLi information
$db_host = "localhost";
$db_username = "username";
$db_password = "password";
//connect to mysqli database (Host/Username/Password)
$connection = mysqli_connect($db_host, $db_username, $db_password) or die("Error " . mysqli_error());
//select MySQLi dabatase table
$db = mysqli_select_db($connection, "table") or die("Error " . mysqli_error());
Good luck!
well, as pointed in here http://php.net/manual/en/function.mysqli-connect.php , you should make something like this:
$link = mysqli_connect("127.0.0.1", "my_user", "my_password", "my_db");
Apparently, in your case it will look like this:
$link = mysqli_connect(WDDBHOST, WDDBUSER, WDDBPASSWD, WDDBNAME);
And then you can continue with your code...
if (!link){
die('Sorry, The site is currently unavailable!');
} else{
// write your SQL here and fetch it
}

Cannot add values to table using mysql and php

I have a problem with my code. I'm trying to add new post to the table events. I'm confused because I have used this code in other place on the same website (but it was using mysqli_query to register new user). mysqql_error returns "No database selected"
This is the code:
<?php
$add_title = $_POST['add_title'];
$add_happen = $_POST['add_happen'];
$add_created = date('Y-m-d');
$add_content = $_POST['add_content'];
$add_author = $_POST['add_author'];
//connect to
//localhost
$db_host = "localhost";
$db_username = "root";
$db_password = "";
$db_dbname = "zhp2";
$db_con = mysql_connect($db_host, $db_username, $db_password, $db_dbname);
$query = "
INSERT INTO events ( title, happen, created, content, author )
VALUES ( '$add_title', '$add_happen', '$add_created', '$add_content', '$add_author') )
";
$retval = mysql_query($query, $db_con);
if(! $retval ){
die('Could not enter data: ' . mysql_error());
}
else{
echo "Entered data successfully\n";
}
mysql_close($db_con);
//header('Location: ../../index.php?link=events');?>
I've tried to fix it using trial and error method playing with different combinations both mysql_query and mysqli_query
You are confusing mysql_connect and mysqli_connect functions in the way you pass those parameters. In your example:
$db_con = mysql_connect($db_host, $db_username, $db_password, $db_dbname);
you are passing a fourth parameter which is the database name but that wont work as you should only pass the three first (host,username,password) and then call mysql_select_db():
$db_con = mysql_connect($db_host, $db_username, $db_password);
mysql_select_db( $db_dbname, $db_con );
In mysqli which is the BETTER way of doing it since mysql_ functions are very vulnerable and being deprecated from php you could pass four elements like here:
$db_con = mysqli_connect($db_host,$db_username, $db_password, $db_dbname) or die("Error " . mysqli_error($link));
which is close to what you are trying to do, but in a correct mysqli_ way.
Well then, you need to select the database! ;) The fourth parameter of mysql_connect() is not the database name. You need to do this separate of connecting to the MySQL server.
Using mysql_select_db() function:
$db_host = "localhost";
$db_username = "root";
$db_password = "";
$db_dbname = "zhp2";
$db_con = mysql_connect($db_host, $db_username, $db_password );
mysql_select_db( $db_dbname, $db_con );
And of course all the obligatory warnings about SQL injection, sanitizing your data, deprecation of mysql_* functions.
You need to select which database to connect to using the mysql_select_db function:
// make $db_dbname the current db
$db_selected = mysql_select_db($db_dbname, $db_con);
if (!$db_selected) {
die ("Can't use $db_dbname : " . mysql_error());
}
See the PHP manual for more info: http://php.net/manual/en/function.mysql-select-db.php

Connecting and inserting data into mysql table using php

I am a PHP newbie and have been trying for sometime now to connect to MySQL database using PHP so I can insert data into a table I have created but I am unable to do this.
I suspect the problem is coming from my PHP .ini file,but that's just me.
Would be grateful if anyone can help me configure my PHP .ini file so I can connect to MySQL and insert data into my table. Here is my PHP script in case you are wondering.
Any help will be gratefully appreciated.
<?php
$host ="localhost";
$username = "username";
$password = "password";
$database = "database1";
$table ="users";
$con = mysql_connect("localhost","username","password");
if (!$con)
{
die('Could not connect:'.mysql_error());
}
mysql_select_db("database1",$con);
$mysql = "INSERT INTO $table(name,email,password)
VALUES('$_POST[name]','$_POST[email]','$_POST[password]";
if(mysql_query($mysql)) die(mysql_error());
echo"Data inserted";
mysql_close();
?>
I revised some of your code this should work. You had a bunch of little errors. I suggest you read a couple tutorials on just connecting and the syntax of php.
Here is some really basic examples of connecting to a database:
http://www.w3schools.com/php/php_mysql_connect.asp
Also once you get the hang of it here is a really good tutorial to teach you the OOP way of creating a class for a database:
http://net.tutsplus.com/tutorials/php/real-world-oop-with-php-and-mysql/
As far as I see this is not an ini issue. I hope this helps.
<?php
//Set your variables
$host = "127.0.0.1";
$username = "username";
$password = "password";
$database = "database1";
$table = "users";
//Make your connection to database
$con = mysql_connect($host,$username,$password);
//Check your connection
if (!$con) {
die("Could not connect: " . mysql_error());
}
//Select your database
$db_selected = mysql_select_db($database, $con);
//Check to make sure the database is there
if (!$db_selected) {
die ('Can\'t use the db : ' . mysql_error());
}
//Run query
$result = mysql_query("INSERT INTO $table(name,email,password) VALUES('$_POST[name]','$_POST[email]','$_POST[password]'");
//Check Query
if (!$result) {
die("lid query: " . mysql_error());
}
echo "Data inserted";
mysql_close($con);
?>
First, why do you have <br/> in your PHP statements? Remove all those.
Also, you have to use PDO or mysqli_ instead of the mysql_ library, mysql_ is deprecated.

WebMatrix PHP mySQL

I am using WebMatrix Beta 3 which has support for php 5.2 and 5.3 I am able to run php pages but when I am trying to connect to mySql DB its not working.
Can anyone please suggest me the right way of doing it.
The connection code is written in a file called dbinfo.php which resides under config folder
<?php
$hostname = '127.0.0.1';
$username = 'root';
$password = 'password';
$database = 'test';
$link = mysql_connect($hostname, $username, $password)
or die("Could not connect : " . mysql_error());
mysql_select_db($database) or die("Could not select database");
//Below function added to allow customized unescaping.
function mysql_unescape($sRet_VAL=""){
$sRet_VAL = str_replace('\"','"',$sRet_VAL);
$sRet_VAL = str_replace("\'","'",$sRet_VAL);
return $sRet_VAL;
}
?>
and I am using this file as follows
<?php
require_once( $_SERVER['DOCUMENT_ROOT'] . '/config/dbinfo.php');
?>
<?php
$query = "SELECT * from temp";
$result = mysql_query($query)
or die("Error: " . mysql_error());
?>
it worked seems like webmatrix do not recognize I replaced it wilt <>php echo $varData ?> and it worked.

Database code is not connecting in chat program using php

<?php
// MySQL database connection file
$SERVER = "127.0.0.1"; // MySQL SERVER
$USER = "root"; // MySQL USER
$PASSWORD = "admin"; // MySQL PASSWORD
$link = #mysql_connect($SERVER,$USER,$PASSWORD);
$db = mysql_select_db("website");
?>
This is a database connecting code for chat program but it not connecting,Can any one pls help me to correct this code?
Drop the # infront of mysql_connect, it's used to suppress error which you don't want.
Also you need to check the return value of mysql_connect which is there in $link and make sure that it is not false before you proceed and to a DB select. Calling the function mysql_error when an error occurs gives you the reason for the error.
$link = mysql_connect($SERVER,$USER,$PASSWORD);
if (!$link) {
die('Could not connect: ' . mysql_error());
}

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