is there a way of getting table name for each column in a postgre result in PHP?
Imagine you have a select with join, for example:
$Q = <<<E2OD
SELECT * FROM user U
LEFT JOIN department D ON U.department_id = D.id
E2OD;
In PHP/FirebirdSQL:
$R = ibase_query($Q);
$D = ibase_fetch_row($R);
$info = ibase_field_info($R, 0);
Returns
Array
(
[0] => id
[name] => id
[1] => id
[alias] => id
[2] => user
[relation] => user
[3] => 8
[length] => 8
[4] => BIGINT
[type] => BIGINT
)
While in PHP/PostgreSQL:
$select = $DB->query($Q);
$meta = $select->getColumnMeta(0);
Returns
Array
(
[pgsql:oid] => 20
[native_type] => int8
[name] => id
[len] => 8
[precision] => -1
[pdo_type] => 2
)
As you see, there's no information about the table the column is from. There's a missing key [relation] => user or similar displaying the table name.
http://php.net/manual/en/pdostatement.getcolumnmeta.php
Can PHP get this information with it's PG or PDO libraries? Does PostgreSQL provide this information to client libraries? What needs to be done to make this happen?
Thanks for any hint,
Michal
Check pg_field_table().
Related
Say, this is my php array.
postids = Array
(
[0] => 2172
[1] => 383
[2] => 2915
[3] => 677
[4] => 1289
[5] => 1654
[6] => 2252
[7] => 2366
[8] => 2998
[9] => 2442
[10] => 1246
)
Now in mysql table (t1) looks like this.
|postid|type|switch|
|1|A|0|
|2|A|1|
|3|A|0|
...
|383|A|0|
...
|1246|A|1|
...
|2172|A|1|
...
|2442|A|0|
So, I want to select postid of type 'A' where switch = 1 and order by my php array and includes post ids from my array.
so, is there any query like
select postids from t1 where type = 'A' and switch = 1 and postids = {<?php echo postids; ?>}
How do I achieve this?
You can use logical conditions in the WHERE,
SELECT * FROM table WHERE type='A' AND switch='1'
I have array below and I need to update database according to this.
It should be something like example code below but I don't know how to do it correctly:
UPDATE productPercent SET percent="$percent" WHERE
store="$store" AND
startDate>"$start_date" AND
endDate<"$end_date" AND
storeGroup="$storeGroup" AND
productGroup="$product_group" AND
productName LIKE '$search%'
I need to check for each store, store group, product (if contains word) and product group and then update productPercent table. Percent, product group, store group, product name and store are in different tables so some kind of inner join is needed.
I need some directions regarding this because I don't know how to start, thank you.
Array
(
[percent] => 3
[store] => Array
(
[0] => 36
[1] => 45
[2] => 56
)
[start_date] => 2015-02-09
[end_date] => 2015-03-31
[storeGroup] => Array
(
[0] => 2
[1] => 4
)
[product_group] => Array
(
[0] => 13
[1] => 31
[2] => 32
)
[search] => iphone
[setPercent] => Submit
)
UPDATED: data model - tableName: columns(connected tables)
store: id,name,startDate,endDate
storeGroup: id,storeGroupID(in table storeGroupName: id,name),storeID
productGroup: id,productID(in table productName: id,name),groupID(in table productGroupName: id,name)
productName: id,name
productPercent: id,productID,storeID,percent
$pdoHandle = $this->getPDOHandle();
$searchword = 'iphone';
$sql = "UPDATE
productPercent
inner join store on productPercent.storeID=store.id
inner join storeGroup on storeGroup.storeID=store.id
inner join productGroup on productGroup.id=storeGroup.groupID
inner join productName on productPercent.productID=productName.id and productGroup.productID=productName.id
SET percent=:percent
WHERE productName.name like :searchword";
$pdo->prepare($sql);
$pdo->setAttribute('percent', floatval($percent/100));
$pdo->setAttribute('searchword', $searchword . '%');
I am trying to build a website that will display the text in multiple languages.
I have a table 'text' with all the languages. If the text does not exist in the chosen language it has to display the default language.
query SELECT * FROM text WHERE TextId = 10
results in
Id TextId LanguageId Text
10 10 1 first name
13 10 2 名前
If I r_print this result I get something like this
Array ( [0] => Array ( [0] => 10 [Id] => 10 [1] => 10 [TextId] => 10 [2] => 1 [LanguageId] => 1 [3] => first name [Text] => first name )
[1] => Array ( [0] => 13 [Id] => 13 [1] => 10 [TextId] => 10 [2] => 2 [LanguageId] => 2 [3] => 名前 [Text] => 名前 ) )
How can I check that LanguageId 2 exist in this array ?
the problem is that it is possible that TextId 2 and Id 2 can also exist in this array.
Is this possible to do with in_array()?
Here is a function that can check if LanguageId equals a special value .
function isLanguageIdExists($yourArray , $LanguageId){
$exists=false;
foreach($yourArray as $array){
if(isset($array['LanguageId'])&& $array['LanguageId'] == $LanguageId){
$exists=true;break;
}
}
return $exists;
}
$exist = isLanguageIdExists($yourArray , 2);//return true or false
You can check by isset the key and match the value in php.
$dataArray = array(
0 => array(0 => 10 ,'Id' => 10, 1 => 10, 'TextId' => 10, 2 => 1, 'LanguageId' => 1),1 => array(0 => 10 ,'Id' => 10, 1 => 10, 'TextId' => 10, 2 => 1, 'LanguageId' => 1)
);
foreach($dataArray as $value) {
if(isset($value['LanguageId']) && $value['LanguageId'] == 2) {
echo 'language ID 2 is available';
}
}
Working Demo
After giving this some more thought I came up with a maybe not so elegant solution.
Instead of getting an array back I modified the SQL Query to give one row back with the default language (English) and a user selected language (Japanese).
It uses two left joins. This shows that I received (some) training in SQL but am really not at ease with multidimensional arrays.
Query
def_text = text in default language
usr_text = text in user chosen language
$table01 = "text";
$query="SELECT $table01.TextId,
text_def.Text as def_text,
text_usr.Text as usr_text
FROM $table01
LEFT JOIN $table01 as text_def ON $table01.TextId = text_def.TextId AND text_def.LanguageId = $_SESSION[default_language]
LEFT JOIN $table01 as text_usr ON $table01.TextId = text_usr.TextId AND text_usr.LanguageId = $_SESSION[language]
WHERE $table01.TextId=$mess;";
after getting back the results it is easy to check with isset() or empty() to see if the text is available in the user selected language
I know how to retrieve the comments for each posts, but now I'm trying to do my own system 'reply to'. When someone replying, I store the comment id as reply_id in new comment.
$sql = 'SELECT cid, cname, user_uid, reply_id,
published, content, avatar
FROM comments, users
WHERE report < 3 AND (uid = user_uid AND post_pid='.$id.')
OR ( user_uid ="_'.$id.'" AND post_pid='.$id.')';
this request return me this list of comments:
Array
(
[0] => stdClass Object
(
[cid] => 101
[cname] => ramzan
[user_uid] => 1
[reply_id] => 100
[published] => 2013-12-08 01:44:56
[content] => why?
[avatar] => users/anonyme.png
)
[1] => stdClass Object
...
but I want to get something like this :
Array
(
[0] => stdClass Object
(
[cid] => 101
[cname] => ramzan
[user_uid] => 1
[reply_id] => array() // the reply if exist
[published] => 2013-12-08 01:44:56
[content] => why?
[avatar] => users/anonyme.png
)
maybe this is a bad idea to do like this, but I don't know how to do otherwise!!!
maybe someone can help this, I resolved my problem like this :
lvl1, lvl2 have to be declare as null, only set the value of field when someone reply to a comment
...SELECT field FROM table where ...
ORDER BY COALESCE (lvl1, lvl2, id ), lvl1, lvl2, id
...
Thank you,
Best regards
Assuming the following array:
$users = array(
// User ID => Username
'72' => 'jack192',
'23' => 'robert1984',
'253' => 'mary111',
'4' => 'jason92'
);
and the following table:
Table myTable:
username | colFoo | colBar
I would like run a query like the following, however I would like the output to additionally include a column not in the table (The user's ID from the array):
$user_string = implode("','", array_values($users));
$query = "SELECT username, colFoo, colBar FROM myTable WHERE username IN ('$user_string')";
This would normally output something like this:
Array
(
[0] => Array
(
[username] => jack192
[colFoo] => 98
[colBar] => 7
)
[1] => Array
(
[username] => robert1984
[colFoo] =>
[colBar] => 2
)
[2] => Array
(
[username] => mary111
[colFoo] => 41
[colBar] => 9
)
[3] => Array
(
[username] => jason92
[colFoo] => 46
[colBar] => 13
)
)
However, I would like the output to look like this, with user_id corresponding to the key in the original array:
Array
(
[0] => Array
(
[username] => jack192
[colFoo] => 98
[colBar] => 7
[user_id] => 72
)
[1] => Array
(
[username] => robert1984
[colFoo] =>
[colBar] => 2
[user_id] => 23
)
[2] => Array
(
[username] => mary111
[colFoo] => 41
[colBar] => 9
[user_id] => 253
)
[3] => Array
(
[username] => jason92
[colFoo] => 46
[colBar] => 13
[user_id] => 4
)
)
I suppose I basically want to just feed the user's ID into the query and get it back out as output, without MySQL doing anything further with it. Is this possible to do purely in SQL without any additional PHP code?
Note: I do not have write access to the DB I'm pulling this data from, and I did not create the schema, so I can't add a user_id field to it or anything.
Here is another way to do it, almost a mashup of the other 2 answers. You can build a 'fake' table and JOIN it to myTable.
SELECT t.username, t.colFoo, t.colBar, s.user_id
FROM myTable t
LEFT JOIN
(
SELECT 72 as user_id, 'jack192' as username
UNION SELECT 23 as user_id, 'robert1984' as username
UNION SELECT 253 as user_id, 'mary111' as username
UNION SELECT 4 as user_id, 'jason92' as username
) s
ON t.username = s.username;
SQLFiddle example - sqlfiddle.com/#!2/64650/2
The fake table structure can be created by a php foreach loop.
$select = '';
foreach ($users as $k => $v){
$select .= "UNION SELECT $k as user_id, '$v' as username\n";
}
echo ltrim($select, "UNION ");
Still a tedious, and not ideal solution, but another option.
You might try CASE
SELECT username, colFoo, colBar,
CASE `username`
WHEN 'jack192' THEN SELECT 72;
WHEN 'robert1984' THEN SELECT 23;
ELSE SELECT NULL;
...
END CASE userid
FROM myTable ...
It will get a bit cumbersome if there are a lot of values in the array.
http://dev.mysql.com/doc/refman/5.0/en/case.html
You can't do this with SQL alone because the id is not defined in the table (not withstanding the cumbersome case statement proposed by Hulka).
Less directly answer the question but providing an alternate solution:
However, you can make a 'small' modification to your php which will accomplish the desired result:
$user_string = implode("','", array_values($users));
foreach ($users as $k => $v){
$query[$k] = "SELECT \"$v\"
,username
,colFoo
,colBar
FROM myTable WHERE username IN ('$user_string')";
}
the query is is basically the same as 'SELECT "6" as user_id, field from TABLE;' for each user, this which would return
6 field
----------
6 value1
6 value2
...
depending on your interface you may be able to prepare and execute, but you did not give enough details to produce specific code.
You would have to run the query multiple times, but you could push or array_merge. Although, I personally think you should use the user_ids as the indexes for this new array. That would require a modest rewrite of above.