check if a value exist in array from database query - php

Question

I am trying to build a website that will display the text in multiple languages.
I have a table 'text' with all the languages. If the text does not exist in the chosen language it has to display the default language.
query SELECT * FROM text WHERE TextId = 10
results in
Id TextId LanguageId Text
10 10 1 first name
13 10 2 名前
If I r_print this result I get something like this
Array ( [0] => Array ( [0] => 10 [Id] => 10 [1] => 10 [TextId] => 10 [2] => 1 [LanguageId] => 1 [3] => first name [Text] => first name )
[1] => Array ( [0] => 13 [Id] => 13 [1] => 10 [TextId] => 10 [2] => 2 [LanguageId] => 2 [3] => 名前 [Text] => 名前 ) )
How can I check that LanguageId 2 exist in this array ?
the problem is that it is possible that TextId 2 and Id 2 can also exist in this array.
Is this possible to do with in_array()?

Answer 1

Here is a function that can check if LanguageId equals a special value .
function isLanguageIdExists($yourArray , $LanguageId){
$exists=false;
foreach($yourArray as $array){
if(isset($array['LanguageId'])&& $array['LanguageId'] == $LanguageId){
$exists=true;break;
}
}
return $exists;
}
$exist = isLanguageIdExists($yourArray , 2);//return true or false

Answer 2

You can check by isset the key and match the value in php.
$dataArray = array(
0 => array(0 => 10 ,'Id' => 10, 1 => 10, 'TextId' => 10, 2 => 1, 'LanguageId' => 1),1 => array(0 => 10 ,'Id' => 10, 1 => 10, 'TextId' => 10, 2 => 1, 'LanguageId' => 1)
);
foreach($dataArray as $value) {
if(isset($value['LanguageId']) && $value['LanguageId'] == 2) {
echo 'language ID 2 is available';
}
}
Working Demo

Answer 3

After giving this some more thought I came up with a maybe not so elegant solution.
Instead of getting an array back I modified the SQL Query to give one row back with the default language (English) and a user selected language (Japanese).
It uses two left joins. This shows that I received (some) training in SQL but am really not at ease with multidimensional arrays.
Query
def_text = text in default language
usr_text = text in user chosen language
$table01 = "text";
$query="SELECT $table01.TextId,
text_def.Text as def_text,
text_usr.Text as usr_text
FROM $table01
LEFT JOIN $table01 as text_def ON $table01.TextId = text_def.TextId AND text_def.LanguageId = $_SESSION[default_language]
LEFT JOIN $table01 as text_usr ON $table01.TextId = text_usr.TextId AND text_usr.LanguageId = $_SESSION[language]
WHERE $table01.TextId=$mess;";
after getting back the results it is easy to check with isset() or empty() to see if the text is available in the user selected language