I have array below and I need to update database according to this.
It should be something like example code below but I don't know how to do it correctly:
UPDATE productPercent SET percent="$percent" WHERE
store="$store" AND
startDate>"$start_date" AND
endDate<"$end_date" AND
storeGroup="$storeGroup" AND
productGroup="$product_group" AND
productName LIKE '$search%'
I need to check for each store, store group, product (if contains word) and product group and then update productPercent table. Percent, product group, store group, product name and store are in different tables so some kind of inner join is needed.
I need some directions regarding this because I don't know how to start, thank you.
Array
(
[percent] => 3
[store] => Array
(
[0] => 36
[1] => 45
[2] => 56
)
[start_date] => 2015-02-09
[end_date] => 2015-03-31
[storeGroup] => Array
(
[0] => 2
[1] => 4
)
[product_group] => Array
(
[0] => 13
[1] => 31
[2] => 32
)
[search] => iphone
[setPercent] => Submit
)
UPDATED: data model - tableName: columns(connected tables)
store: id,name,startDate,endDate
storeGroup: id,storeGroupID(in table storeGroupName: id,name),storeID
productGroup: id,productID(in table productName: id,name),groupID(in table productGroupName: id,name)
productName: id,name
productPercent: id,productID,storeID,percent
$pdoHandle = $this->getPDOHandle();
$searchword = 'iphone';
$sql = "UPDATE
productPercent
inner join store on productPercent.storeID=store.id
inner join storeGroup on storeGroup.storeID=store.id
inner join productGroup on productGroup.id=storeGroup.groupID
inner join productName on productPercent.productID=productName.id and productGroup.productID=productName.id
SET percent=:percent
WHERE productName.name like :searchword";
$pdo->prepare($sql);
$pdo->setAttribute('percent', floatval($percent/100));
$pdo->setAttribute('searchword', $searchword . '%');
Related
I have query like this,
SELECT * FROM users ORDER BY score
So, the result is like this.
Array
(
[0] => stdClass Object
(
[userid] => 3
[user] => John Doe
[score] => 50
)
[1] => stdClass Object
(
[userid] => 1
[user] => Mae Smith
[score] => 38
)
[2] => stdClass Object
(
[userid] => 2
[user] => Mark Sam
[score] => 26
)
)
But, I want to add a rank using find_in_set query. So the result might be like this. So that the user can view their ranks when they login to their account.
Array
(
[0] => stdClass Object
(
[userid] => 3
[user] => John Doe
[score] => 50
[rank] => 1
)
[1] => stdClass Object
(
[userid] => 1
[user] => Mae Smith
[score] => 38
[rank] => 2
)
[2] => stdClass Object
(
[userid] => 2
[user] => Mark Sam
[score] => 26
[rank] => 3
)
)
I tried this one.
$listOfUser = array();
foreach($users as $user) {
$listOfUser[] = $user->userid;
}
And used another query
$userid = 2 // => id of loggedin user
SELECT *, find_in_set($userid, $listOfUser) as rank FROM users where userid=$userid ORDER BY score
So, I got this result
Array
(
[1] => stdClass Object
(
[userid] => 2
[user] => Mark Sam
[score] => 26
[rank] => 3
)
)
Which is somehow correct. But, is there another way of querying that result using only one SQL query and without using foreach loop?
Something like this.
$userid = 2 // => id of loggedin user
SELECT *, find_in_set($userid, (SELECT * FROM users ORDER BY score)) as rank FROM users where userid=$userid ORDER BY score
But I got this error Subquery returns more than 1 row
If You don't insist on using find_in_set, you can get result with simple join. You ask for list of users (p) and for each user you ask, how many users have better score than him or her (c):
SELECT p.userid, COUNT(c.userid) AS rank
FROM users AS p
LEFT JOIN users AS c ON c.score > p.score
GROUP BY p.userid
This works even if you add other conditions, like WHERE p.userid = 123.
If more users have the same score, the ranks would look like 0,1,2,2,2,5,6.
In your query, you can add counter, like this:
set #n:=0;
SELECT #i := #i + 1 AS rank, * FROM users ORDER BY score
The rank here is relative to the score distribution across all users. I believe you should try something originally proposed in this answer:
SELECT users.*,
#rownum := #rownum + 1 as rank
FROM users
CROSS JOIN (select #rownum := 0) r
ORDER BY score DESC
What it does is basically order all users by score, and assign each of them an incremental value "rank". So the top scorer would have a rank of 1, the second scorer would have a rank of 2 etc.
Keep in mind that this solution is not "fair" - each user will have a different rank, even if all users have the same score. If you try to rank users as they do in sports (if two top competitors have the same score, they both take 1st place, and the next best competitor takes 3rd place, not second), you should think of a different solution.
I have a two table 1. grocery_product and 2. grocery_attribute where i can get all data from grocery_product my array look like as below.
Array
(
[0] => Array
(
[id] => 1
[pname] => Royal Moong Dal/Moong Dal
[categoryid] => 4
[subcatid] => 3
[added_date] => 2016-08-16
)
[1] => Array
(
[id] => 2
[pname] => Royal Toor Dal/Arhar Dal/Tuver Dal
[categoryid] => 4
[subcatid] => 3
[added_date] => 2016-08-16
)
)
What i want to do that in my grocerry_attribute table i am passing grocery_product_id and fetch all data from grocery_attribute where product is only one and attributes are multiple.
My grocery atrtribute table look like .
id 1
product_id 2
price 1500
discount 15
product_qty 20
id 2
product_id 2
price 1000
discount 10
product_qty 50
i want to fetch one grocery_product(id=1) and its attribute data.
Query ??
You can use LEFT JOIN like,
SELECT p.id,p.pname,g.price,g.discount,g.product_qty FROM
grocery_product as p
LEFT JOIN grocery_attribute as g
ON p.id = g.product_id
WHERE p.id=2
Now you can loop for attributes and show different price, discount, and product_qty for a single product.
// Let $products is multidimensional array
if(!empty($products) && isset($products[0]['pname'])){
echo '<h1>'.$products[0]['pname'].'</h1>';
foreach($products as $product){
echo 'Price:'.$product['price']."\n";
echo 'Discount:'.$product['discount']."\n";
echo 'Product Quantity:'.$product['product_qty']."\n";
}
}
Is it possible to make a query that will return one time the value of the second table and set the otherones at NULL. Im stuck with this.
This is my query
return $this->db->get_results(
"
SELECT id, name, type, check_in_days, check_out_days, all_check_out_days, minimum_stay, maximum_stay, all_accom, GROUP_CONCAT( accom_id ) as accom, GROUP_CONCAT( seasons_id ) as seasons, conditional_type
FROM $this->booking_rules_table
LEFT JOIN $this->booking_rules_accom_table
ON $this->booking_rules_table.id = $this->booking_rules_accom_table.rule_id
LEFT JOIN $this->booking_rules_seasons_table
ON $this->booking_rules_table.id = $this->booking_rules_seasons_table.rule_id
GROUP BY id
"
, ARRAY_A );
This returns a array like this
[2] => Array
(
[id] => 54
[name] =>
[type] => minimum_stay
[check_in_days] => 0,1,2,3,4,5,6
[check_out_days] => 0,1,2,3,4,5,6
[all_check_out_days] => 1
[minimum_stay] => 0
[maximum_stay] => 9999
[all_accom] => 0
[accom] => 7,7,7
[seasons] => 1,3,4
[conditional_type] => compulsory
)
You see that [accom] is returning the 7 3 times because the [seasons] has 3 values.
can i fix this with my query or is there an other solution. I dont want to explode it and build the array again.
Assuming the following array:
$users = array(
// User ID => Username
'72' => 'jack192',
'23' => 'robert1984',
'253' => 'mary111',
'4' => 'jason92'
);
and the following table:
Table myTable:
username | colFoo | colBar
I would like run a query like the following, however I would like the output to additionally include a column not in the table (The user's ID from the array):
$user_string = implode("','", array_values($users));
$query = "SELECT username, colFoo, colBar FROM myTable WHERE username IN ('$user_string')";
This would normally output something like this:
Array
(
[0] => Array
(
[username] => jack192
[colFoo] => 98
[colBar] => 7
)
[1] => Array
(
[username] => robert1984
[colFoo] =>
[colBar] => 2
)
[2] => Array
(
[username] => mary111
[colFoo] => 41
[colBar] => 9
)
[3] => Array
(
[username] => jason92
[colFoo] => 46
[colBar] => 13
)
)
However, I would like the output to look like this, with user_id corresponding to the key in the original array:
Array
(
[0] => Array
(
[username] => jack192
[colFoo] => 98
[colBar] => 7
[user_id] => 72
)
[1] => Array
(
[username] => robert1984
[colFoo] =>
[colBar] => 2
[user_id] => 23
)
[2] => Array
(
[username] => mary111
[colFoo] => 41
[colBar] => 9
[user_id] => 253
)
[3] => Array
(
[username] => jason92
[colFoo] => 46
[colBar] => 13
[user_id] => 4
)
)
I suppose I basically want to just feed the user's ID into the query and get it back out as output, without MySQL doing anything further with it. Is this possible to do purely in SQL without any additional PHP code?
Note: I do not have write access to the DB I'm pulling this data from, and I did not create the schema, so I can't add a user_id field to it or anything.
Here is another way to do it, almost a mashup of the other 2 answers. You can build a 'fake' table and JOIN it to myTable.
SELECT t.username, t.colFoo, t.colBar, s.user_id
FROM myTable t
LEFT JOIN
(
SELECT 72 as user_id, 'jack192' as username
UNION SELECT 23 as user_id, 'robert1984' as username
UNION SELECT 253 as user_id, 'mary111' as username
UNION SELECT 4 as user_id, 'jason92' as username
) s
ON t.username = s.username;
SQLFiddle example - sqlfiddle.com/#!2/64650/2
The fake table structure can be created by a php foreach loop.
$select = '';
foreach ($users as $k => $v){
$select .= "UNION SELECT $k as user_id, '$v' as username\n";
}
echo ltrim($select, "UNION ");
Still a tedious, and not ideal solution, but another option.
You might try CASE
SELECT username, colFoo, colBar,
CASE `username`
WHEN 'jack192' THEN SELECT 72;
WHEN 'robert1984' THEN SELECT 23;
ELSE SELECT NULL;
...
END CASE userid
FROM myTable ...
It will get a bit cumbersome if there are a lot of values in the array.
http://dev.mysql.com/doc/refman/5.0/en/case.html
You can't do this with SQL alone because the id is not defined in the table (not withstanding the cumbersome case statement proposed by Hulka).
Less directly answer the question but providing an alternate solution:
However, you can make a 'small' modification to your php which will accomplish the desired result:
$user_string = implode("','", array_values($users));
foreach ($users as $k => $v){
$query[$k] = "SELECT \"$v\"
,username
,colFoo
,colBar
FROM myTable WHERE username IN ('$user_string')";
}
the query is is basically the same as 'SELECT "6" as user_id, field from TABLE;' for each user, this which would return
6 field
----------
6 value1
6 value2
...
depending on your interface you may be able to prepare and execute, but you did not give enough details to produce specific code.
You would have to run the query multiple times, but you could push or array_merge. Although, I personally think you should use the user_ids as the indexes for this new array. That would require a modest rewrite of above.
Let's say I have one table: "cars" with 3 fields: id, brand, cost.
There's a second table: "models" with 3 fields: id, brand, model_name.
Each "cars" row can have multiple related "models" rows.
Is it possible to do an sql-select whose output looks like this?
edit: I use PHP for the database querys
array(
[0] => array(
[id] => 1
[brand] => mercedes
[cost] => 1000
[models] => array(
[0] => array(
[id] => 1
[brand] => mercedes
[model_name] => slk
)
[1] => array(
[id] => 2
[brand] => mercedes
[model_name] => clk
)
[2] => array(
[id] => 3
[brand] => mercedes
[model_name] => whatever
)
)
)
)
You need to add a foreign key relation to the models table, say car_id. Then:
SELECT * FROM cars JOIN models ON car_id = models.id;
This will output something similar to what you are looking for.
Assuming you are using PHP, using the output:
$query= "SELECT * FROM cars JOIN models ON car_id = models.id";
$r= #mysqli_query($dbc, $query);
while ($row= mysqli_fetch_array($r, MYSQLI_ASSOC)) {
$carstuff['id']=$row[id];
$carstuff['brand']=$row[brand];
$carstuff['cost']=$row[cost];
$carstuff[$row['models']][]=$row['model_name'];
}
var_dump($carstuff);
Note, that the id, brand and cost are repeatedly overwritten, but that is okay because they are overwritten with the same information. I'm not too sure about the cleanliness of the code, but that is the basic idea.
Try this:
Query:
SELECT c.ID, c.brand,c.cost, GROUP_CONCAT(model_name SEPARATOR '","') as models
, GROUP_CONCAT(m.ID SEPARATOR ',') as MID
, GROUP_CONCAT(m.brand SEPARATOR '","') as mbrand
FROM cars c
LEFT OUTER JOIN model m
ON m.brand = c.brand
GROUP BY brand;
Output:
ID BRAND COST MODELS MID MBRAND
1 audi 1000 m11","m22 4,5 audi","audi
1 mercedes 1200 m1","m2","m3 1,2,3 mercedes","mercedes","mercedes
Now in your php code you can process the MODEL,MID and MBrand
(By using explode)
$modelArray = explode(" ,", $row["MODELS");
SQLFIDDLE