Is it possible to make a query that will return one time the value of the second table and set the otherones at NULL. Im stuck with this.
This is my query
return $this->db->get_results(
"
SELECT id, name, type, check_in_days, check_out_days, all_check_out_days, minimum_stay, maximum_stay, all_accom, GROUP_CONCAT( accom_id ) as accom, GROUP_CONCAT( seasons_id ) as seasons, conditional_type
FROM $this->booking_rules_table
LEFT JOIN $this->booking_rules_accom_table
ON $this->booking_rules_table.id = $this->booking_rules_accom_table.rule_id
LEFT JOIN $this->booking_rules_seasons_table
ON $this->booking_rules_table.id = $this->booking_rules_seasons_table.rule_id
GROUP BY id
"
, ARRAY_A );
This returns a array like this
[2] => Array
(
[id] => 54
[name] =>
[type] => minimum_stay
[check_in_days] => 0,1,2,3,4,5,6
[check_out_days] => 0,1,2,3,4,5,6
[all_check_out_days] => 1
[minimum_stay] => 0
[maximum_stay] => 9999
[all_accom] => 0
[accom] => 7,7,7
[seasons] => 1,3,4
[conditional_type] => compulsory
)
You see that [accom] is returning the 7 3 times because the [seasons] has 3 values.
can i fix this with my query or is there an other solution. I dont want to explode it and build the array again.
Related
I have two tables
Meetings:
m_id ProjectName
1 Test
2 Test2
Meeting_next:
id fk_m_id Meetingdate status
1 1 9-1-2018 0
1 1 10-1-2018 0
1 1 13-1-2018 1
I want to join this two tables when I left join it I will get duplicate value
Expected output
Array
(
[0] => Array
(
[m_id] => 1
[ProjectName] => test
[meetingDate] =>13-1-2018
)
[1] => Array
(
[m_id] => 2
[ProjectName] => test2
[meetingDate] =>
)
)
I tried -
select * from meetings left join meeting_next on meetings.m_id= meeting_next.fk_m_id where meeting_next.status=1 order by m_id desc
myOutput:
Array
(
[0] => Array
(
[m_id] => 1
[ProjectName] => test
[meetingDate] =>13-1-2018
) )
Bad luck I got only first Project name. I need second too. Please help me. Any help would be appreciated.
Your WHERE condition filters the number of rows to only the row of the first project.
If you want to show both projects, even if there are no meetings with status 1, you need to move the condition to the join condition:
select *
from meetings
left join meeting_next
on meetings.m_id= meeting_next.fk_m_id
and meeting_next.status=1
order by m_id desc
Now you will get all rows from meetings with only the matching entries from meeting_next.
I am using corequery of mysql in cakephp. I want the records in descending order. This is my table structure
enter code here
$coreQueryUser = $this->Message->query(
"select * from messages where messages.list_id = 3
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
order by id desc
"
);
I want last message that belongs to (sender_id and reciver_id and viceversa) that belongs to list id 3
when i run this query i get the following output
<pre>Array
(
[0] => Array
(
[messages] => Array
(
[id] => 1
[sender_id] => 21
[reciever_id] => 10
[list_id] => 3
[message] => hello
[add_date] => 2016-09-25 00:00:00
[is_check] => 0
)
)
[1] => Array
(
[messages] => Array
(
[id] => 3
[sender_id] => 22
[reciever_id] => 10
[list_id] => 3
[message] => hello s
[add_date] => 2016-09-25 16:39:41
[is_check] => 0
)
)
)
but i wnat result like that:
Array
(
[0] => Array
(
[messages] => Array
(
[id] => 2
[sender_id] => 10
[reciever_id] => 21
[list_id] => 3
[message] => hello sir
[add_date] => 2016-09-25 00:00:00
[is_check] => 0
)
)
[1] => Array
(
[messages] => Array
(
[id] => 6
[sender_id] => 22
[reciever_id] => 10
[list_id] => 3
[message] => new
[add_date] => 2016-09-25 16:39:41
[is_check] => 0
)
)
)
Can anyone help me :(
The problem is that your query is against the sql standard because you have several fields in the select list that are neither in the group by list, nor are subject of an aggregate function, such as sum(). MySQL unfortunately allows such invalid queries to run under certain sql mode settings (the default settings of the most recent versions of MySQL would prevent such queries from running).
As MySQL documentation on group by clause says (bolding is mine):
If ONLY_FULL_GROUP_BY is disabled, a MySQL extension to the standard
SQL use of GROUP BY permits the select list, HAVING condition, or
ORDER BY list to refer to nonaggregated columns even if the columns
are not functionally dependent on GROUP BY columns. This causes MySQL
to accept the preceding query. In this case, the server is free to
choose any value from each group, so unless they are the same, the
values chosen are indeterminate, which is probably not what you want.
Furthermore, the selection of values from each group cannot be
influenced by adding an ORDER BY clause. Result set sorting occurs
after values have been chosen, and ORDER BY does not affect which
value within each group the server chooses.
You apparently want the latest record (with max(id) for each group. The proper way is to have a subquery that returns the max(id) per group and in the outer query join back to your main table using the ids to get the value of the other fields:
select m.*
from
messages m
inner join (
select max(id) as maxid
from messages
where messages.list_id = 3
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
) t1 on m.id=t1.maxid
This code working:
SELECT * FROM generate_invoice
WHERE id IN
(
SELECT max(id) as id
FROM generate_invoice
GROUP by pay_id
ORDER by id DESC
)
How to group by DESC order
Try
SELECT * FROM ( SELECT * FROM generate_invoice ORDER BY id DESC ) AS g GROUP BY g.pay_id
OR
Use this code
SELECT m1.*,m2.* FROM generate_invoice m1 LEFT JOIN generate_invoice m2 ON (m1.pay_id = m2.pay_id AND m1.id < m2.id ) order by m1.id desc
I have 3 tables: tco_articles, tco_module_eostext and tco_articles_modules. My tco_articles has unique id key. One for each article. My tco_module_eostext has unique instance_id that belongs to each article.
My tco_articles_modules contains all article_ids, but have 9 times as much instance_ids that are used in other tables.
So I can have article_id with instance_id that when you query in the tco_module_eostext will return empty.
I'd like to make a query that will return correct body text for the correct article.
So far I have:
global $wpdb;
$posts = array();
$ids = $wpdb->get_results('SELECT DISTINCT instance_id, article_id FROM tco_articles_modules', ARRAY_A);
This returns array with all the instances and ids like:
Array
(
[0] => Array
(
[instance_id] => 928615
[article_id] => 129396
)
[1] => Array
(
[instance_id] => 928616
[article_id] => 129396
)
[2] => Array
(
[instance_id] => 928617
[article_id] => 129396
)
[3] => Array
(
[instance_id] => 928618
[article_id] => 129396
)
You can see that the article_ids are the same but instance_id. When you put
$wpdb->get_results('SELECT body FROM tco_module_eostext WHERE instance_id=928617 ', ARRAY_A);
You may get empty, but for
$wpdb->get_results('SELECT body FROM tco_module_eostext WHERE instance_id=928618 ', ARRAY_A);
You could have some body text.
This is my problem. I need to go through all of them and filter out the not empty ones and assign them correct article. I managed to output the articles
foreach ($ids as $key => $value) {
$instance_ID = $value['instance_id'];
$article_ID = $value['article_id'];
$article_out = $wpdb->get_results('SELECT * FROM tco_articles WHERE id='.$article_ID.' ', ARRAY_A);
$posts[$article_ID] = $article_out[0];
}
Which returns something like:
Array
(
[129396] => Array
(
[id] => 129396
[headline] => Bla bla bla title
[intro] => This is cool article intro
[needs_review] => 0
[published] => 2014-12-16 09:17:00
[unpublished] =>
[hidden] => 0
[no_single_page] => 0
[permalink] => link-perma-link-here
[internal_slug] =>
[type_id] => 3
[thread_id] => 0
[news_id] => 0
[header_game_id] => 0
[puff_hh_id] => 0
[puff_title] =>
[hdrcol_id] => 900
[review_queued] =>
[lock_timeout] => 0
[created] => 2014-12-16 09:17:00
[updated] => 2015-01-16 13:51:30
[created_by] => 84142
[updated_by] => 84142
)
...
Now I'd like to append the body text from the tco_module_eostext table.
Is there a query I can use to do this automatically or to do this one at the time and then append to the $posts array?
The foreach method of querying is kinda slow when you have 180000+ posts.
Any help is appreciated.
If you are sure that there is always only one row in tco_module_eostext against each article_id, you can use JOIN (inner join), which will only show one row for each article_id.
SELECT a.*, t.body
FROM tco_articles a
JOIN tco_articles_modules m ON m.article_id = a.id
JOIN tco_module_eostext t ON m.instance_id = t.instance_id
//WHERE .....
But, this will not show any row of some articles if there is no entry in other two tables for that article_id. But there is still way to solve this. We can use LEFT OUTER JOIN and then make sure we only make the join if there is any row in tco_module_eostext for any instace_id. This will make sure you get at least the article info from tco_articles table when there is no data in other tables.
SELECT a.*, t.body
FROM tco_articles a
LEFT OUTER JOIN tco_articles_modules m ON m.article_id = a.id AND EXISTS ( SELECT NULL FROM tco_module_eostext WHERE instance_id = m.instance_id )
LEFT OUTER JOIN tco_module_eostext t ON m.instance_id = t.instance_id
//WHERE .....
Why not use a query with join?
Not tested!:
SELECT
article.*,
text.body as bodytext
FROM
tco_articles_modules AS modules LEFT OUTER JOIN
tco_module_eostext AS text ON
modules.instance_id = text.instance_id LEFT OUTER JOIN
tco_articles AS article ON
article.id = modules.article_id
it should get all articles with the assigned article_id from tco_articles_modules
Have a look at OUTER Join - you may want to replace this with an INNER JOIN for faster Queries. Also you ma want an WHERE condition for filtering in the query. Watch also out for the right indexing in mysql table - each joining column should be indexed - this will get much more faster results.
I have array below and I need to update database according to this.
It should be something like example code below but I don't know how to do it correctly:
UPDATE productPercent SET percent="$percent" WHERE
store="$store" AND
startDate>"$start_date" AND
endDate<"$end_date" AND
storeGroup="$storeGroup" AND
productGroup="$product_group" AND
productName LIKE '$search%'
I need to check for each store, store group, product (if contains word) and product group and then update productPercent table. Percent, product group, store group, product name and store are in different tables so some kind of inner join is needed.
I need some directions regarding this because I don't know how to start, thank you.
Array
(
[percent] => 3
[store] => Array
(
[0] => 36
[1] => 45
[2] => 56
)
[start_date] => 2015-02-09
[end_date] => 2015-03-31
[storeGroup] => Array
(
[0] => 2
[1] => 4
)
[product_group] => Array
(
[0] => 13
[1] => 31
[2] => 32
)
[search] => iphone
[setPercent] => Submit
)
UPDATED: data model - tableName: columns(connected tables)
store: id,name,startDate,endDate
storeGroup: id,storeGroupID(in table storeGroupName: id,name),storeID
productGroup: id,productID(in table productName: id,name),groupID(in table productGroupName: id,name)
productName: id,name
productPercent: id,productID,storeID,percent
$pdoHandle = $this->getPDOHandle();
$searchword = 'iphone';
$sql = "UPDATE
productPercent
inner join store on productPercent.storeID=store.id
inner join storeGroup on storeGroup.storeID=store.id
inner join productGroup on productGroup.id=storeGroup.groupID
inner join productName on productPercent.productID=productName.id and productGroup.productID=productName.id
SET percent=:percent
WHERE productName.name like :searchword";
$pdo->prepare($sql);
$pdo->setAttribute('percent', floatval($percent/100));
$pdo->setAttribute('searchword', $searchword . '%');
With a big Thanks to others here i get this query now. its working fine, but i would need to get just the highest value of the post_id (how_many). it seems not possible to set a MAX(count(*)) on that. so how could i change this to get only the highest count by every id? i just need the value of every id where count == highest. how could i do this? thanks for any help.
$test = $wpdb->get_results('select
posts_id, value,count(*) as how_many
From wp_mrp_rating_item_entry_value
group by
posts_id, value
order by count(*) desc');
echo '<pre>';
print_r($test);
echo '</pre>';
i would need something like order by MAX((count(*)) or MAX((count(how_many))
i already read this but i dont know how to use this for my purpose Filtering log file using COUNT, GROUP BY, ORDER BY MAX
this is an example of the output i get now. so number 1 should not appear because number [0] has been voted 2 times. (how_many). i just need every id 1x in the output. no id shouldt appear twice or more. cause just the highest count is needed. thanks and sorry for the bad english.
Array
(
[0] => stdClass Object
(
[posts_id] => 336
[value] => 8
[how_many] => 2
)
[1] => stdClass Object
(
[posts_id] => 336
[value] => 7
[how_many] => 1
)
[2] => stdClass Object
(
[posts_id] => 380
[value] => 5
[how_many] => 1
)
[3] => stdClass Object
(
[posts_id] => 378
[value] => 7
[how_many] => 1
)
[4] => stdClass Object
(
[posts_id] => 329
[value] => 2
[how_many] => 1
)
[5] => stdClass Object
(
[posts_id] => 327
[value] => 3
[how_many] => 1
)
)
You can filter the resulting groups in a HAVING clause based on a match against a subquery for the maximal count:
SELECT posts_id, value, COUNT(*) AS how_many
FROM wp_mrp_rating_item_entry_value t1
GROUP BY posts_id, value
HAVING how_many = (
SELECT COUNT(*)
FROM wp_mrp_rating_item_entry_value t2
WHERE t2.posts_id = t1.posts_id
GROUP BY t2.value
ORDER BY COUNT(*) DESC
LIMIT 1
)