With a big Thanks to others here i get this query now. its working fine, but i would need to get just the highest value of the post_id (how_many). it seems not possible to set a MAX(count(*)) on that. so how could i change this to get only the highest count by every id? i just need the value of every id where count == highest. how could i do this? thanks for any help.
$test = $wpdb->get_results('select
posts_id, value,count(*) as how_many
From wp_mrp_rating_item_entry_value
group by
posts_id, value
order by count(*) desc');
echo '<pre>';
print_r($test);
echo '</pre>';
i would need something like order by MAX((count(*)) or MAX((count(how_many))
i already read this but i dont know how to use this for my purpose Filtering log file using COUNT, GROUP BY, ORDER BY MAX
this is an example of the output i get now. so number 1 should not appear because number [0] has been voted 2 times. (how_many). i just need every id 1x in the output. no id shouldt appear twice or more. cause just the highest count is needed. thanks and sorry for the bad english.
Array
(
[0] => stdClass Object
(
[posts_id] => 336
[value] => 8
[how_many] => 2
)
[1] => stdClass Object
(
[posts_id] => 336
[value] => 7
[how_many] => 1
)
[2] => stdClass Object
(
[posts_id] => 380
[value] => 5
[how_many] => 1
)
[3] => stdClass Object
(
[posts_id] => 378
[value] => 7
[how_many] => 1
)
[4] => stdClass Object
(
[posts_id] => 329
[value] => 2
[how_many] => 1
)
[5] => stdClass Object
(
[posts_id] => 327
[value] => 3
[how_many] => 1
)
)
You can filter the resulting groups in a HAVING clause based on a match against a subquery for the maximal count:
SELECT posts_id, value, COUNT(*) AS how_many
FROM wp_mrp_rating_item_entry_value t1
GROUP BY posts_id, value
HAVING how_many = (
SELECT COUNT(*)
FROM wp_mrp_rating_item_entry_value t2
WHERE t2.posts_id = t1.posts_id
GROUP BY t2.value
ORDER BY COUNT(*) DESC
LIMIT 1
)
Related
I have query like this,
SELECT * FROM users ORDER BY score
So, the result is like this.
Array
(
[0] => stdClass Object
(
[userid] => 3
[user] => John Doe
[score] => 50
)
[1] => stdClass Object
(
[userid] => 1
[user] => Mae Smith
[score] => 38
)
[2] => stdClass Object
(
[userid] => 2
[user] => Mark Sam
[score] => 26
)
)
But, I want to add a rank using find_in_set query. So the result might be like this. So that the user can view their ranks when they login to their account.
Array
(
[0] => stdClass Object
(
[userid] => 3
[user] => John Doe
[score] => 50
[rank] => 1
)
[1] => stdClass Object
(
[userid] => 1
[user] => Mae Smith
[score] => 38
[rank] => 2
)
[2] => stdClass Object
(
[userid] => 2
[user] => Mark Sam
[score] => 26
[rank] => 3
)
)
I tried this one.
$listOfUser = array();
foreach($users as $user) {
$listOfUser[] = $user->userid;
}
And used another query
$userid = 2 // => id of loggedin user
SELECT *, find_in_set($userid, $listOfUser) as rank FROM users where userid=$userid ORDER BY score
So, I got this result
Array
(
[1] => stdClass Object
(
[userid] => 2
[user] => Mark Sam
[score] => 26
[rank] => 3
)
)
Which is somehow correct. But, is there another way of querying that result using only one SQL query and without using foreach loop?
Something like this.
$userid = 2 // => id of loggedin user
SELECT *, find_in_set($userid, (SELECT * FROM users ORDER BY score)) as rank FROM users where userid=$userid ORDER BY score
But I got this error Subquery returns more than 1 row
If You don't insist on using find_in_set, you can get result with simple join. You ask for list of users (p) and for each user you ask, how many users have better score than him or her (c):
SELECT p.userid, COUNT(c.userid) AS rank
FROM users AS p
LEFT JOIN users AS c ON c.score > p.score
GROUP BY p.userid
This works even if you add other conditions, like WHERE p.userid = 123.
If more users have the same score, the ranks would look like 0,1,2,2,2,5,6.
In your query, you can add counter, like this:
set #n:=0;
SELECT #i := #i + 1 AS rank, * FROM users ORDER BY score
The rank here is relative to the score distribution across all users. I believe you should try something originally proposed in this answer:
SELECT users.*,
#rownum := #rownum + 1 as rank
FROM users
CROSS JOIN (select #rownum := 0) r
ORDER BY score DESC
What it does is basically order all users by score, and assign each of them an incremental value "rank". So the top scorer would have a rank of 1, the second scorer would have a rank of 2 etc.
Keep in mind that this solution is not "fair" - each user will have a different rank, even if all users have the same score. If you try to rank users as they do in sports (if two top competitors have the same score, they both take 1st place, and the next best competitor takes 3rd place, not second), you should think of a different solution.
I link my last question to explain that i need
obtain results of two different tables mysql
This is the result of my mysql query.
date | rate | percent
2017-01-06 500 0
2017-01-07 500 0.10
2017-01-07 500 0.15
How can i make this array, i am tring with php but i can´t do this, i can do it with one dimension array, but no a multidimensional array like this
Array
(
[1] => Array
(
[0] => Array
(
[date] => 2017-01-06
[rate]=>500
[percent] => 0.00
)
[1] => Array
(
[date] => 2017-01-07
[rate]=>500
[percent] => 0.10
)
[2] => Array
(
[0] => Array
(
[date] => 2017-01-06
[rate]=>500
[percent] => 0.00
)
[1] => Array
(
[date] => 2017-01-07
[rate]=>500
[percent] => 0.15
)
)
)
It is a matter of (if I understand the problem) plucking the MAX() and MIN() percent values for each date. For this, you must use GROUP BY.
SELECT s.date, s.rate, MAX(p.percent) AS maxperc, MIN(p.percent) AS minperc
FROM stock s
LEFT JOIN promotions p ON s.date = p.date
WHERE s.date BETWEEN '2017-01-29' AND '2017-01-31'
GROUP BY s.date,s.rate;
...I haven't test that, so it may need some fiddling with.
Then as you loop through your result set, you can declare the two separate subarrays and build your complete array.
$array=[];
$i=0;
while($row=mysqli_fetch_assoc($result)){
$array[0][$i]["date"]=$row["date"];
$array[0][$i]["rate"]=$row["rate"];
$array[0][$i]["perc"]=$row["minperc"];
$array[1][$i]["date"]=$row["date"];
$array[1][$i]["rate"]=$row["rate"];
$array[1][$i]["perc"]=$row["maxperc"];
++$i;
}
By this point, I've made too many assumptions about your purpose/usage.
Basically, set zero as the percent default, query for highest and lowest percent for each date-rate pair (if zero, then zero will appear as highest and lowest value). Do whatever you wish with the result set.
I am using corequery of mysql in cakephp. I want the records in descending order. This is my table structure
enter code here
$coreQueryUser = $this->Message->query(
"select * from messages where messages.list_id = 3
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
order by id desc
"
);
I want last message that belongs to (sender_id and reciver_id and viceversa) that belongs to list id 3
when i run this query i get the following output
<pre>Array
(
[0] => Array
(
[messages] => Array
(
[id] => 1
[sender_id] => 21
[reciever_id] => 10
[list_id] => 3
[message] => hello
[add_date] => 2016-09-25 00:00:00
[is_check] => 0
)
)
[1] => Array
(
[messages] => Array
(
[id] => 3
[sender_id] => 22
[reciever_id] => 10
[list_id] => 3
[message] => hello s
[add_date] => 2016-09-25 16:39:41
[is_check] => 0
)
)
)
but i wnat result like that:
Array
(
[0] => Array
(
[messages] => Array
(
[id] => 2
[sender_id] => 10
[reciever_id] => 21
[list_id] => 3
[message] => hello sir
[add_date] => 2016-09-25 00:00:00
[is_check] => 0
)
)
[1] => Array
(
[messages] => Array
(
[id] => 6
[sender_id] => 22
[reciever_id] => 10
[list_id] => 3
[message] => new
[add_date] => 2016-09-25 16:39:41
[is_check] => 0
)
)
)
Can anyone help me :(
The problem is that your query is against the sql standard because you have several fields in the select list that are neither in the group by list, nor are subject of an aggregate function, such as sum(). MySQL unfortunately allows such invalid queries to run under certain sql mode settings (the default settings of the most recent versions of MySQL would prevent such queries from running).
As MySQL documentation on group by clause says (bolding is mine):
If ONLY_FULL_GROUP_BY is disabled, a MySQL extension to the standard
SQL use of GROUP BY permits the select list, HAVING condition, or
ORDER BY list to refer to nonaggregated columns even if the columns
are not functionally dependent on GROUP BY columns. This causes MySQL
to accept the preceding query. In this case, the server is free to
choose any value from each group, so unless they are the same, the
values chosen are indeterminate, which is probably not what you want.
Furthermore, the selection of values from each group cannot be
influenced by adding an ORDER BY clause. Result set sorting occurs
after values have been chosen, and ORDER BY does not affect which
value within each group the server chooses.
You apparently want the latest record (with max(id) for each group. The proper way is to have a subquery that returns the max(id) per group and in the outer query join back to your main table using the ids to get the value of the other fields:
select m.*
from
messages m
inner join (
select max(id) as maxid
from messages
where messages.list_id = 3
group By (if(sender_id > reciever_id, sender_id, reciever_id)),
(if(sender_id > reciever_id, reciever_id, sender_id))
) t1 on m.id=t1.maxid
This code working:
SELECT * FROM generate_invoice
WHERE id IN
(
SELECT max(id) as id
FROM generate_invoice
GROUP by pay_id
ORDER by id DESC
)
How to group by DESC order
Try
SELECT * FROM ( SELECT * FROM generate_invoice ORDER BY id DESC ) AS g GROUP BY g.pay_id
OR
Use this code
SELECT m1.*,m2.* FROM generate_invoice m1 LEFT JOIN generate_invoice m2 ON (m1.pay_id = m2.pay_id AND m1.id < m2.id ) order by m1.id desc
Is it possible to make a query that will return one time the value of the second table and set the otherones at NULL. Im stuck with this.
This is my query
return $this->db->get_results(
"
SELECT id, name, type, check_in_days, check_out_days, all_check_out_days, minimum_stay, maximum_stay, all_accom, GROUP_CONCAT( accom_id ) as accom, GROUP_CONCAT( seasons_id ) as seasons, conditional_type
FROM $this->booking_rules_table
LEFT JOIN $this->booking_rules_accom_table
ON $this->booking_rules_table.id = $this->booking_rules_accom_table.rule_id
LEFT JOIN $this->booking_rules_seasons_table
ON $this->booking_rules_table.id = $this->booking_rules_seasons_table.rule_id
GROUP BY id
"
, ARRAY_A );
This returns a array like this
[2] => Array
(
[id] => 54
[name] =>
[type] => minimum_stay
[check_in_days] => 0,1,2,3,4,5,6
[check_out_days] => 0,1,2,3,4,5,6
[all_check_out_days] => 1
[minimum_stay] => 0
[maximum_stay] => 9999
[all_accom] => 0
[accom] => 7,7,7
[seasons] => 1,3,4
[conditional_type] => compulsory
)
You see that [accom] is returning the 7 3 times because the [seasons] has 3 values.
can i fix this with my query or is there an other solution. I dont want to explode it and build the array again.
I have the following query:
$count = (SELECT COUNT(*) FROM post GROUP BY ID
HAVING ID NOT IN (SELECT taxiID FROM taxi WHERE userID = '.$userID.' AND value IS NOT NULL)
ORDER BY postID), OBJECT);
Count contains this:
count = Array ( [0] => stdClass Object ( [COUNT(*)] => 1 ) [1] => stdClass Object ( [COUNT(*)] => 1 ) [2] => stdClass Object ( [COUNT(*)] => 1 ) [3] => stdClass Object ( [COUNT(*)] => 1 ) [4] => stdClass Object ( [COUNT(*)] => 1 ) [5] => stdClass Object ( [COUNT(*)] => 1 ) [6] => stdClass Object ( [COUNT(*)] => 1 ) [7] => stdClass Object ( [COUNT(*)] => 1 ) [8] => stdClass Object ( [COUNT(*)] => 1 ) [9] => stdClass Object ( [COUNT(*)] => 1 ) [10] => stdClass Object ( [COUNT(*)] => 1 ) [11] => stdClass Object ( [COUNT(*)] => 1 ) [12] => stdClass Object ( [COUNT(*)] => 1 ) [13] => stdClass Object ( [COUNT(*)] => 1 ) [14] => stdClass Object ( [COUNT(*)] => 1 ) [15] => stdClass Object ( [COUNT(*)] => 1 ) [16] => stdClass Object ( [COUNT(*)] => 1 ) [17] => stdClass Object ( [COUNT(*)] => 1 ) [18] => stdClass Object ( [COUNT(*)] => 1 ) [19] => stdClass Object ( [COUNT(*)] => 1 )
I need to count the number of results delivered by the above. Thing is, I have no idea how to use the result!
I had this code but now it won't work:
<?php if($count[0]->{'COUNT(*)'} > 10){ ?
echo "Load More";
}else {
echo "Nothing to load";
} ?>
$count should be more than 10 and my php should echo Load More but it is echoing Nothing to load.
The taxi table looks like this:
ID taxiID userID value
1 1 1 1
2 1 6 1
3 1 4 0
4 2 1 0
5 2 6 1
6 2 4 0
7 3 6 1
8 3 4 0
The post table looks like this:
ID postID randomNum
1 1 564
2 2 789
3 3 234
4 4 845
5 5 089
Assuming $userID is 1, the query returns postID 1,3,4,5 (1 is liked, 3 is not liked and not disliked by user 1, 4 and 5 are not liked and not disliked by any user). Therefore $count should contain 4 (4 results are found).
If my query is inefficient, how do I adapt it to be efficient?
Ultimately, the question is how do I do something like:
if ($count > 10) {}
Your problem is, your query isn't returning what you think it returns (it always helps to run you query standalone, to see if the result set is what you expect).
Right, let's break this down.
It is counting all posts that the user has not liked or disliked. likes and dislikes are stored in the taxi table. taxi.taxiID matches post.ID. Hence if the userID with any value that isn't null is found, ignore that post.ID. I am counting those post.ID which are not ignored
You're trying count all posts that don't have a matching record in the taxi table, for that userID. What you want here is to JOIN the tables and get those rows in post that would normally be excluded by the join. This is achieved by an left outer join
(edited)
SELECT p.ID, t.taxiID
FROM post p LEFT OUTER JOIN taxi t ON p.ID = t.taxiID AND t.userID = '.$user.'
HAVING t.taxiID IS NULL
That HAVING clause is saying: only those rows in the resultset that didn't have a corresponding t.taxiID.
If you run this query and get the expected set of rows (posts that do not have likes or dislikes by that user) THEN you can add an outer query to count the number of returned rows:
SELECT COUNT(*) as count FROM (
SELECT p.ID, t.taxiID
FROM post p LEFT OUTER JOIN taxi t ON p.ID = t.taxiID AND t.userID = '.$user.'
HAVING t.taxiID IS NULL
) a
This should return a single scalar named count. In this case you'll be able to say:
if ($count[0]->count > 10) { blah blah blah }
(2nd edit) This inner query will get you those posts that have either value = 1 in the taxi table, or no value at all, which results in 4 being returned for your example:
SELECT p.ID, t.taxiID, t.value
FROM post p LEFT OUTER JOIN taxi t ON p.ID = t.taxiID AND t.userID = '.$user.'
HAVING t.taxiID IS NULL OR t.value = 1
In case you want to know how many results would have been returned WITHOUT the LIMIT clause, according to the MySQL documentation:
A SELECT statement may include a LIMIT clause to restrict the number
of rows the server returns to the client. In some cases, it is
desirable to know how many rows the statement would have returned
without the LIMIT, but without running the statement again. To obtain
this row count, include a SQL_CALC_FOUND_ROWS option in the SELECT
statement, and then invoke FOUND_ROWS() afterward:
mysql> SELECT SQL_CALC_FOUND_ROWS * FROM tbl_name
-> WHERE id > 100 LIMIT 10;
mysql> SELECT FOUND_ROWS();
http://dev.mysql.com/doc/refman/5.0/en/information-functions.html#function_found-rows
SELECT COUNT(*) FROM post
WHERE postID NOT IN
( SELECT taxiID
FROM taxi
WHERE userID = '.$userID.'
AND value = 0
)
ORDER BY postID;
SELECT COUNT(*) FROM post
WHERE postID NOT IN
( SELECT taxiID
FROM taxi
WHERE userID = '.$userID.'
AND value = 0
)
Can you also provide us with the error message if this does not work?
Why not this?
SELECT COUNT(*) FROM post
WHERE postID NOT IN (
SELECT taxiID FROM taxi
WHERE userID = '.$userID.' AND value = 0
)
LIMIT 10
Note there is no need to perform an order by if you are only looking for the count. Also note you have a limit there so the result won't have more than 10 records. Not sure if that is the idea.
I found the answer and it was dead simple:
if (count($count) > 10) {}