I need to loop through a .png image directory and insert the file name in a mysql database.
This is what I have so far:
mysql_connect('localhost', 'admin', '');
mysql_select_db('database');
// Each file is formated like this
$file = 'Abe+Froman+SK_HG.png';
$player_name = urldecode(str_replace("_HG.png", "", $file));
//echo $player_name;
mysql_query("INSERT IGNORE INTO signatures SET gamertag = '".$player_name."'");
Another way of doing it is with glob which allows you to select only the png images if other files are also present in the same directory.
foreach (glob("*.txt") as $filename) {
$player_name = urldecode(str_replace("_HG.png", "", $filename));
mysql_query("INSERT IGNORE INTO signatures SET gamertag = '".$player_name."'");
}
Use opendir to open a directory and readdir to loop through it:
<?php
// From the manual entry for opendir
$dir = "/etc/php5/";
// Open a known directory, and proceed to read its contents
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
//Do your sql insert - the filename is in the $file variable
}
closedir($dh);
}
}
?>
Related
I have write script to the search string in pdf files. I used script from this link: link.
I have problem, because my script not search in all files pdf, only search in first file (sorted by name)
My script:
foreach (glob("storage/cvs/*.pdf") as $file) {
// $files = 'storage/cvs/d08540965a_2017-12-06.pdf';
$this->pdf2text->setFilename($file);
$this->pdf2text->decodePDF();
$convert2Txt = $this->pdf2text->output();
if (stripos($convert2Txt, $query) !== false) {
echo $resultQuery = "tak ".$file."</br>";
} else {
echo $resultQuery = "nie znaleziono ".$file."</br>";
}
}
And I don't know how I can get name files where found string.
This is how I do it:
$dir = "/path/to/your/directory/"; // Set your directory path here
if (is_dir($dir)){ // Check its a directory
if ($dh = opendir($dir)){ // Open the directory
while (($file = readdir($dh)) !== false){ // Read the files
if (substr($file, -3)=='pdf') { // Check filename ends 'pdf'
// Your code here
$file will be set as the filename
For the below code I have multiple directories and files. I can display one filename per directory(Which is good with the "BREAK").
<?php
$dir = "/images/";
$i=0;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
echo "filename:" . $file . "<br>";
break;
//---- if ($i>=5) { break; }
}
closedir($dh);
}
}
?>
With
if ($i>=5) { break; } I can still display 5 filenames but it reads only one directory.
I want to display at least 5 file names from all directories, how can I do it?
Use the scandir function.
array scandir ( string $directory [, int $sorting_order = SCANDIR_SORT_ASCENDING [, resource $context ]] )
or
If you are using unix you could also do a system call and run the following command.
ls /$dir | head -5
$dir is the directory and -5 is the number filenames in the directory.
Since you said that you have multiple directory's, I rewrote your code a bit:
(Here I first loop through all directory's with array_map() then I get all files from each directory with glob(). After this I just limit the files per directory with array_slice() and at the end I simply print all file names)
<?php
$directorys = ["images/", "xy/"];
$limit = 3;
//get all files
$files = array_map(function($v){
return glob("$v*.*");
}, $directorys);
//limit files per directory
$files = array_map(function($v)use($limit){
return array_slice($v, 0, $limit);
}, $files);
foreach($files as $directory) {
echo "<b>Directory</b><br>";
foreach($directory as $file)
echo "$file<br>";
echo "<br><br>";
}
?>
You don't have to break it, you can just skip it. And in doing so, you have to use continue instead.
$dir = "/images/";
$i=0;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
echo "filename:" . $file . "<br>";
if ($i>=5)
continue;
}
closedir($dh);
}
}
Here is also another scenario. Because you mentioned that you have many directories but you only show one main directory, I am guessing that the directories you've mentioned were inside the /images/ directory.
$dir = "images/";
$i=1;
// Open a directory, and read its contents
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh)) !== false){
$j=1;
if (is_dir($file)) {
if ($internalDir = opendir($file)) {
while (($internalFile = readdir($internalDir)) !== false) {
echo $file."->filename: ".$internalFile."<br>";
if ($j>=5)
continue;
$j++;
}
closedir(opendir($file));
}
} else {
echo "filename:" . $file . "<br>";
if ($i>=5)
continue;
$i++;
}
}
closedir($dh);
}
}
Read more about continue here: http://php.net/manual/en/control-structures.continue.php
I have a folder 'items' in which there are 3 files item1.txt, item2.txt and item3.txt.
I want to delete item2.txt file from folder. I am using the below code but it not deleting a file from folder. Can any body help me in that.
<?php
$data="item2.txt";
$dir = "items";
$dirHandle = opendir($dir);
while ($file = readdir($dirHandle)) {
if($file==$data) {
unlink($file);
}
}
closedir($dirHandle);
?>
Initially the folder should have 777 permissions
$data = "item2.txt";
$dir = "items";
while ($file = readdir($dirHandle)) {
if ($file==$data) {
unlink($dir.'/'.$file);
}
}
or try
$path = $_SERVER['DOCUMENT_ROOT'].'items/item2.txt';
unlink($path);
No need of while loop here for just deleting a file, you have to pass path of that file to unlink() function, as shown below.
$file_to_delete = 'items/item2.txt';
unlink($file_to_delete);
Please read details of unlink() function
http://php.net/manual/en/function.unlink.php
There is one bug in your code, you haven't given the correct path
<?php
$data="item2.txt";
$dir = "items";
$dirHandle = opendir($dir);
while ($file = readdir($dirHandle)) {
if($file==$data) {
unlink($dir."/".$file);//give correct path,
}
}
closedir($dirHandle);
?>
unlink
if($file==$data) {
unlink( $dir .'/'. $file);
}
It's very simple:
$file='a.txt';
if(unlink($file))
{
echo "file named $file has been deleted successfully";
}
else
{
echo "file is not deleted";
}
//if file is in other folder then do as follows
unlink("foldername/".$file);
try renaming it to the trash or a temp folder that the server have access **UNLESS IT'S sensitive data.
rename($old, $new) or die("Unable to rename $old to $new.");
I need to read only pdf files in a directory and then read the filename of every files then I will use the filename to rename some txt files. I have tried using only eregi function. but it seems cannot read all I need. how to read them well?
here's my code :
$savePath ='D:/dir/';
$dir = opendir($savePath);
$filename = array();
while ($filename = readdir($dir)) {
if (eregi("\.pdf",$filename)){
$read = strtok ($filename,"."); //get the filenames
//to rename some txt files using the filenames that I get before
//$testfile is text files that I've read before
$testfile = "$read.txt";
$file = fopen($testfile,"r") or die ('cannot open file');
if (filesize($testfile)==0){}
else{
$text = fread($file,55024);
fclose($file);
echo "</br>"; echo "</br>";
}
}
More elegant:
foreach (glob("D:/dir/*.pdf") as $filename) {
// do something with $filename
}
To get the filename only:
foreach (glob("D:/dir/*.pdf") as $filename) {
$filename = basename($filename);
// do something with $filename
}
You can do this by filter file type.. following is sample code.
<?php
// directory path can be either absolute or relative
$dirPath = '.';
// open the specified directory and check if it's opened successfully
if ($handle = opendir($dirPath)) {
// keep reading the directory entries 'til the end
$i=0;
while (false !== ($file = readdir($handle))) {
$i++;
// just skip the reference to current and parent directory
if (eregi("\.jpg",$file) || eregi("\.gif",$file) || eregi("\.png",$file)){
if (is_dir("$dirPath/$file")) {
// found a directory, do something with it?
echo " [$file]<br>";
} else {
// found an ordinary file
echo $i."- $file<br>";
}
}
}
// ALWAYS remember to close what you opened
closedir($handle);
}
?>
Above is demonstrating for file type related to images you can do the same for .PDF files.
Better explained here
I have a number of text files held in directory
/results/...
All the text files are named with unixtime stamps, inside each of the following files there is:
#text¬test¬test1¬test2¬test3¬test4¬1262384177
Each piece of text is seperated by '¬'.
I'd then like to feed the contents of the text file into an array and output it, in for example a table, but for each of the files (Perhaps loop-like?)
If have this but it only works for one file and fixed file name:
$filename = "results/unixtime.txt";
$handle = fopen($filename, "r");
$contents = fread($handle, filesize($filename));
fclose($handle);
$array01 = explode("¬",$contents);
$count = count($array01);
echo "<table width = 500 border=1 cellpadding=4>";
$i=0;
for ($i=0;$i<$count;$i++) {
echo "<tr><td>";
echo $array01[$i];
echo "</td></tr>";
}
echo "</table>";
I suggest the fairly-unknown glob function to detect all your files. Then with all the filenames in a handy array, just iterate through and open up/read each one. Sort of like this:
$files = glob('*.txt');
while(list($i, $filename) = each($files)){
//what you have now
}
A couple of things:
Unless you're dealing with really large files just use file_get_contents() to load files. It's a one-liner versus three lines of code that you just don't need;
Loop over arrays using foreach unless you explicitly need a loop counter. The loop condnition/counter is just another area where you can make simple errors;
Use opendir(), readdir() and closedir() for reading directory contents; and
Directories will contain entries like "." and "..". Use filetype() and/or a check on the name and/or extension to limit it to the files you're interested in.
Example:
$directory = "results/";
$dir = opendir($directory);
while (($file = readdir($dir)) !== false) {
$filename = $directory . $file;
$type = filetype($filename);
if ($type == 'file') {
$contents = file_get_contents($filename);
$items = explode('¬', $contents);
echo '<table width="500" border="1" cellpadding="4">';
foreach ($items as $item) {
echo "<tr><td>$item</td></tr>\n";
}
echo '</table>';
}
}
closedir($dir);
You can get all the files located in "result" via opendir.
There is also an example ...
<?php
$dir = "/etc/php5/";
// Open a known directory, and proceed to read its contents
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
echo "filename: $file : filetype: " . filetype($dir . $file) . "\n";
}
closedir($dh);
}
}
?>
Grab the files in the directory and read each filename.
<?php
if ($handle = opendir('.')) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != "..") {
$filename = $file;
//your code
}
}
closedir($handle);
}
?>
source: http://php.net/manual/en/function.readdir.php
Here is a more elegant way of writing brianreavis solution, also use file_get_contents instead of fopen, fread and fclose, it's faster and less verbose.
foreach (glob('*.txt') as $filename)
{
$contents = file_get_contents($filename);
}
Use this code, replace DOCROOT with directory you want to scan.
foreach (scandir(DOCROOT.'css') as $dir) {
echo $dir . "<br>";
echo file_get_contents(DOCROOT . 'css/' . $dir ) . "<hr />";
}