not returning sufficient rows - php

Question

What I'm trying to figure out here is how to access the different array values that I need. I have the following query and it returns this for an array when the print_r() is applied. For some reason it only does the first row from the db table. It should return a whole another row.
<?php
session_start();
// Include the database page
require ('../inc/dbconfig.php');
require ('../inc/global_functions.php');
//Login submitted
if (isset($_POST['submit'])) {
// Errors defined as not being any
$errors = "no";
if((empty($_POST['answer1'])) || (trim($_POST['answer1'])=="") || ($_POST['answer1'] == NULL) || (!isset($_POST['answer1']))){$errors = "yes";}
if((empty($_POST['answer2'])) || (trim($_POST['answer2'])=="") || ($_POST['answer2'] == NULL) || (!isset($_POST['answer2']))){$errors = "yes";}
// Error checking, make sure all form fields have input
if ($errors == "yes") {
// Not all fields were entered error
$message = "You must enter values to all of the form fields!";
$output = array('errorsExist' => true, 'message' => $message);
} else {
$userID = mysqli_real_escape_string($dbc,$_POST['userID']);
$answer1Post = mysqli_real_escape_string($dbc,$_POST['answer1']);
$answer2Post = mysqli_real_escape_string($dbc,$_POST['answer2']);
$question1 = mysqli_real_escape_string($dbc,$_POST['question1']);
$question2 = mysqli_real_escape_string($dbc,$_POST['question2']);
$query = "SELECT * FROM manager_users_secretAnswers WHERE userID = '".$userID."'";
$result = mysqli_query($dbc,$query);
// Count number of returned results from query
if (mysqli_num_rows($result) > 0) {
while ($row = mysqli_fetch_array($result)) {
$answer = $row['answer'];
// Comparing the database password with the posted password
if ($answer == $answerPost) {
} else {
$errors = "yes";
$message = "Your answers did not match the answers inside the database!";
$output = array('errorsExist' => true, 'message' => $message);
}
}
} else {
$errors = "yes";
$message = "We did not find any answers for your questions! Please consult the site administrator!";
$output = array('errorsExist' => true, 'message' => $message);
}
}
}
//Output the result
$output = json_encode($output);
echo $output;
?>

Answer 1

Because you just fetch the first one, where you should loop on the result set instead:
$query = "SELECT * FROM manager_users_secretAnswers WHERE userID = '$userID'";
$result = mysqli_query($dbc,$query);
if (mysqli_num_rows($result) > 0) {
while ($row = mysqli_fetch_array($result)) {
print_r($row);
}
}
By the way, you should be using prepared statements to avoid SQL injection.

Answer 2

You need to wrap your fetch in a loop. e.g.
if (mysqli_num_rows($result) > 0)
{
while (($row = mysqli_fetch_array($result)) !== false)
{
if ($row['answer'] == $answerPost)
{
// $row matches what we're looking for
}
else
{
$errors = "yes";
$message = "Your answers did not match the answers inside the database!";
$output = array('errorsExist' => true, 'message' => $message);
}
print_r($row);
}
}