else statement content wont show? - php

Question

Currently, my problem continues to persist as I want to display errors for existing accounts or a success message if the user creates a non-already existing account. For some odd reason, even if the sign-up is successful, it still display the errors? Is there something that I am doing wrong? The two if statements still run even if they are false??? I am not understanding...
if ($db_found) {
$uSQL = "SELECT * FROM login WHERE username = '$username'";
$uresult = mysql_query($uSQL);
$unum_rows = mysql_num_rows($uresult);
$eSQL = "SELECT * FROM login WHERE email = '$email'";
$eresult = mysql_query($eSQL);
$enum_rows = mysql_num_rows($eresult);
if ($unum_rows > 0) {
echo '<div class="error-message"><li>Username Already Exists</li></div>';
}
if ($enum_rows > 0) {
echo '<div class="error-message"><li>Email Already Exists</li></div>';
}
else {
echo '<div class="success-message">successfully</div>';
}
}

Answer 1

Personally I would combine the queries - and simplify the logic ( and escape your input )
if ($db_found) {
$sql = "SELECT * FROM login WHERE username = '{mysql_real_escape_string($username)}' OR email = '{mysql_real_escape_string($email)}'";
$result = mysql_query($sql);
if( mysql_num_rows($result) ){
while(false !== ($row = mysql_fetch_assoc($result))) {
if($row['username'] == $username ){
echo '<div class="error-message"><li>Username Already Exists</li></div>';
}
if($row['email'] == $email) {
echo '<div class="error-message"><li>Email Already Exists</li></div>';
}
}
}else{
echo '<div class="success-message">successfully</div>';
}
}

Answer 2

This might help you
$enum_rows = mysql_num_rows($eresult);
if($unum_rows < 1)
{
echo "Username is available";
}
else
{
echo '<div class="error-message"><li>Username Already Exists</li></div>';
}
if($enum_rows < 1)
{
echo '<div class="success-message">successfully</div>';
}
else
{
echo '<div class="error-message"><li>Email Already Exists</li></div>';
}