$textone = "pate"; //$_GET
$texttwo = "tape";
$texttre = "tapp";
if ($textone ??? $texttwo) {
echo "The two strings contain the same letters";
}
if ($textone ??? $texttre) {
echo "The two strings NOT contain the same letters";
}
What if statement am I looking for?
I suppose a solution could be to, considering the two following variables :
$textone = "pate";
$texttwo = "tape";
1. First, split the strings, to get two arrays of letters :
$arr1 = preg_split('//', $textone, -1, PREG_SPLIT_NO_EMPTY);
$arr2 = preg_split('//', $texttwo, -1, PREG_SPLIT_NO_EMPTY);
Note that, as pointed out by #Mike in his comment, instead of using preg_split() like I first did, for such a situation, one would be better off using str_split() :
$arr1 = str_split($textone);
$arr2 = str_split($texttwo);
2. Then, sort those array, so the letters are in alphabetical order :
sort($arr1);
sort($arr2);
3. After that, implode the arrays, to create words where all letters are in alphabetical order :
$text1Sorted = implode('', $arr1);
$text2Sorted = implode('', $arr2);
4. And, finally, compare those two words :
if ($text1Sorted == $text2Sorted) {
echo "$text1Sorted == $text2Sorted";
}
else {
echo "$text1Sorted != $text2Sorted";
}
Turning this idea into a comparison function would give you the following portion of code :
function compare($textone, $texttwo) {
$arr1 = str_split($textone);
$arr2 = str_split($texttwo);
sort($arr1);
sort($arr2);
$text1Sorted = implode('', $arr1);
$text2Sorted = implode('', $arr2);
if ($text1Sorted == $text2Sorted) {
echo "$text1Sorted == $text2Sorted<br />";
}
else {
echo "$text1Sorted != $text2Sorted<br />";
}
}
And calling that function on your two words :
compare("pate", "tape");
compare("pate", "tapp");
Would get you the following result :
aept == aept
aept != appt
use === and !==
if ($textone === $texttwo) {
echo "The two strings contain the same letters";
}else{
echo "The two strings NOT contain the same letters";
}
or
if ($textone === $texttwo) {
echo "The two strings contain the same letters";
}
if ($textone !== $texttwo) {
echo "The two strings NOT contain the same letters";
}
Related
I have two variables such as below
$string1 = array('A','b','c');
$string2 = 'bAcdadbcliek'
need to check all the characters from string1 is presents in string2 or not in php and values are dynamic.
try This
<?php
$string1 = array('A','b','c','2');
$string2 = 'bAcdadbcliek';
foreach($string1 as $newstring)
{
$finalval=strrchr($string2,$newstring);
if($finalval!="")
{
echo $newstring." ---: Available in given String<br/>";
}
else
{
echo $newstring." ---: Not Available in given String<br/>";
}
}
?>
use str_split and array_intersect
<?php
$string1 = array('A','b','c');
$string2 = 'bAcdadbcliek';
$new = str_split($string2);
$new_2 = array_intersect($string1,$new);
if(count($new_2)==count($string1))
{
echo "all matched";
}
else
{
echo "not ";
}
?>
The following function will return a boolean true/false if all values are matched. It is case-sensitive.
Basically, split $string2 into an array and intersect it, match the count of that against the count of $string1 (which is an array, not a string by the way). If the count is equal, everything was found.
$string1 = array('A','b','c');
$string2 = 'bAcdadbcliek';
function match_string(string $string, array $match_values) {
if (count(array_intersect(str_split($string), $match_values)) == count($match_values))
return true;
return false;
}
Live demo
I googled this question I can't to find the exact solution...
I have 2 variables...
$s1 = "ABC"; //or "BC"
$s2 = "BC"; //or "Bangalore"
I have to compare $s1 and $s2 and give the output as letters which is not present in $s2
eg : "A" // or"C"
Like that
I have to compare $s2 and $s1 and give the output as letters which is not present in $s1
eg : null // or"angalore"
What I tried..
I spit the strings to array...
Using nested for loop to find the non matched letters...
I wrote code more than 35 lines..
But no result :(
Please help me ......
echo str_ireplace(str_split($s2), "", $s1); // output: A
You can use array_diff() here:
function str_compare($str1, $str2)
{
$str1chars = str_split($str1);
$str2chars = str_split($str2);
$diff = array_diff($str1chars, $str2chars)
return implode($diff);
}
By calling the function as follows:
$diffchars = str_compare('ABC', 'BC');
You will receive a string containing the characters that do not appear in both strings. In this example, it'll be A, because that character appears in $str1, but not in $str2.
You can use str_split and array_diff like :
<?php
$s1 = 'abcedf';
$s2 = 'xzcedf5460gf';
print_r(array_diff(str_split($s1), str_split($s2)));
Use array_diff():
function str_diff($str1, $str2) {
$arr1 = str_split($str1);
$arr2 = str_split($str2);
$diff = array_diff($arr1, $arr2);
return implode($diff);
}
Usage:
echo str_diff('BC', 'Bangalore'); // => C
echo str_diff('ABC', 'BC'); // => A
Ok to do this
$str1s = "abc";
$str2s = "BCd";
function findNot($str1, $str2, $asArray = false){
$returnValue = array_diff(array_unique(str_split(strtolower($str1))), array_unique(str_split(strtolower($str2))));
if($asArray == false){
return implode($returnValue);
}else{
return $returnValue;
}
}
echo findNot($str1s, $str2s); //gives a string
echo findNot($str1s, $str2s, true); //gives array of characters
This allows you to return as either array or string.
This question already has answers here:
String contains any items in an array (case insensitive)
(15 answers)
Closed 2 years ago.
I am trying to detect whether a string contains at least one URL that is stored in an array.
Here is my array:
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
The string is entered by the user and submitted via PHP. On the confirmation page I would like to check if the URL entered is in the array.
I have tried the following:
$string = 'my domain name is website3.com';
if (in_array($string, $owned_urls))
{
echo "Match found";
return true;
}
else
{
echo "Match not found";
return false;
}
No matter what is inputted the return is always "Match not found".
Is this the correct way of doing things?
Try this.
$string = 'my domain name is website3.com';
foreach ($owned_urls as $url) {
//if (strstr($string, $url)) { // mine version
if (strpos($string, $url) !== FALSE) { // Yoshi version
echo "Match found";
return true;
}
}
echo "Not found!";
return false;
Use stristr() or stripos() if you want to check case-insensitive.
This was a lot easier to do if all you want to do is find a string in an array.
$array = ["they has mystring in it", "some", "other", "elements"];
if (stripos(json_encode($array),'mystring') !== false) {
echo "found mystring";
}
Try this:
$owned_urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
$url_string = end(explode(' ', $string));
if (in_array($url_string,$owned_urls)){
echo "Match found";
return true;
} else {
echo "Match not found";
return false;
}
-
Thanks
Simple str_replace with count parameter would work here:
$count = 0;
str_replace($owned_urls, '', $string, $count);
// if replace is successful means the array value is present(Match Found).
if ($count > 0) {
echo "One of Array value is present in the string.";
}
More Info - https://www.techpurohit.in/extended-behaviour-explode-and-strreplace-php
I think that a faster way is to use preg_match.
$user_input = 'Something website2.com or other';
$owned_urls_array = array('website1.com', 'website2.com', 'website3.com');
if ( preg_match('('.implode('|',$owned_urls_array).')', $user_input)){
echo "Match found";
}else{
echo "Match not found";
}
$string = 'my domain name is website3.com';
$a = array('website1.com','website2.com','website3.com');
$result = count(array_filter($a, create_function('$e','return strstr("'.$string.'", $e);')))>0;
var_dump($result );
output
bool(true)
Here is a mini-function that search all values from an array in a given string.
I use this in my site to check for visitor IP is in my permitted list on certain pages.
function array_in_string($str, array $arr) {
foreach($arr as $arr_value) { //start looping the array
if (stripos($str,$arr_value) !== false) return true; //if $arr_value is found in $str return true
}
return false; //else return false
}
how to use
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
//this example should return FOUND
$string = 'my domain name is website3.com';
if (array_in_string($string, $owned_urls)) {
echo "first: Match found<br>";
}
else {
echo "first: Match not found<br>";
}
//this example should return NOT FOUND
$string = 'my domain name is website4.com';
if (array_in_string($string, $owned_urls)) {
echo "second: Match found<br>";
}
else {
echo "second: Match not found<br>";
}
DEMO: http://phpfiddle.org/lite/code/qf7j-8m09
stripos function is not very strict. it's not case sensitive or it can match a part of a word
http://php.net/manual/ro/function.stripos.php
if you want that search to be case sensitive use strpos
http://php.net/manual/ro/function.strpos.php
for exact match use regex (preg_match), check this guy answer https://stackoverflow.com/a/25633879/4481831
You can concatenate the array values with implode and a separator of |
and then use preg_match to search for the value.
Here is the solution I came up with ...
$emails = array('#gmail', '#hotmail', '#outlook', '#live', '#msn', '#yahoo', '#ymail', '#aol');
$emails = implode('|', $emails);
if(!preg_match("/$emails/i", $email)){
// do something
}
If your $string is always consistent (ie. the domain name is always at the end of the string), you can use explode() with end(), and then use in_array() to check for a match (as pointed out by #Anand Solanki in their answer).
If not, you'd be better off using a regular expression to extract the domain from the string, and then use in_array() to check for a match.
$string = 'There is a url mysite3.com in this string';
preg_match('/(?:http:\/\/)?(?:www.)?([a-z0-9-_]+\.[a-z0-9.]{2,5})/i', $string, $matches);
if (empty($matches[1])) {
// no domain name was found in $string
} else {
if (in_array($matches[1], $owned_urls)) {
// exact match found
} else {
// exact match not found
}
}
The expression above could probably be improved (I'm not particularly knowledgeable in this area)
Here's a demo
You are checking whole string to the array values. So output is always false.
I use both array_filter and strpos in this case.
<?php
$urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
$check = array_filter($urls, function($url){
global $string;
if(strpos($string, $url))
return true;
});
echo $check?"found":"not found";
$owned_urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
for($i=0; $i < count($owned_urls); $i++)
{
if(strpos($string,$owned_urls[$i]) != false)
echo 'Found';
}
$message = "This is test message that contain filter world test3";
$filterWords = array('test1', 'test2', 'test3');
$messageAfterFilter = str_replace($filterWords, '',$message);
if( strlen($messageAfterFilter) != strlen($message) )
echo 'message is filtered';
else
echo 'not filtered';
I find this fast and simple without running loop.
$array = array("this", "that", "there", "here", "where");
$string = "Here comes my string";
$string2 = "I like to Move it! Move it";
$newStr = str_replace($array, "", $string);
if(strcmp($string, $newStr) == 0) {
echo 'No Word Exists - Nothing got replaced in $newStr';
} else {
echo 'Word Exists - Some Word from array got replaced!';
}
$newStr = str_replace($array, "", $string2);
if(strcmp($string2, $newStr) == 0) {
echo 'No Word Exists - Nothing got replaced in $newStr';
} else {
echo 'Word Exists - Some Word from array got replaced!';
}
Little explanation!
Create new variable with $newStr replacing value in array of original string.
Do string comparison - If value is 0, that means, strings are equal and nothing was replaced, hence no value in array exists in string.
if it is vice versa of 2, i.e, while doing string comparison, both original and new string was not matched, that means, something got replaced, hence value in array exists in string.
$search = "web"
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
foreach ($owned_urls as $key => $value) {
if (stristr($value, $search) == '') {
//not fount
}else{
//found
}
this is the best approach search for any substring , case-insensitive and fast
just like like im mysql
ex:
select * from table where name = "%web%"
I came up with this function which works for me, hope this will help somebody
$word_list = 'word1, word2, word3, word4';
$str = 'This string contains word1 in it';
function checkStringAgainstList($str, $word_list)
{
$word_list = explode(', ', $word_list);
$str = explode(' ', $str);
foreach ($str as $word):
if (in_array(strtolower($word), $word_list)) {
return TRUE;
}
endforeach;
return false;
}
Also, note that answers with strpos() will return true if the matching word is a part of other word. For example if word list contains 'st' and if your string contains 'street', strpos() will return true
This question already has answers here:
String contains any items in an array (case insensitive)
(15 answers)
Closed 2 years ago.
This is for a chat page. I have a $string = "This dude is a mothertrucker". I have an array of badwords: $bads = array('truck', 'shot', etc). How could I check to see if $string contains any of the words in $bad?
So far I have:
foreach ($bads as $bad) {
if (strpos($string,$bad) !== false) {
//say NO!
}
else {
// YES! }
}
Except when I do this, when a user types in a word in the $bads list, the output is NO! followed by YES! so for some reason the code is running it twice through.
function contains($str, array $arr)
{
foreach($arr as $a) {
if (stripos($str,$a) !== false) return true;
}
return false;
}
1) The simplest way:
if ( in_array( 'three', ['one', 'three', 'seven'] ))
...
2) Another way (while checking arrays towards another arrays):
$keywords=array('one','two','three');
$targets=array('eleven','six','two');
foreach ( $targets as $string )
{
foreach ( $keywords as $keyword )
{
if ( strpos( $string, $keyword ) !== FALSE )
{ echo "The word appeared !!" }
}
}
can you please try this instead of your code
$string = "This dude is a mothertrucker";
$bads = array('truck', 'shot');
foreach($bads as $bad) {
$place = strpos($string, $bad);
if (!empty($place)) {
echo 'Bad word';
exit;
} else {
echo "Good";
}
}
There is a very short php script that you can use to identify bad words in a string which uses str_ireplace as follows:
$string = "This dude is a mean mothertrucker";
$badwords = array('truck', 'shot', 'ass');
$banstring = ($string != str_ireplace($badwords,"XX",$string))? true: false;
if ($banstring) {
echo 'Bad words found';
} else {
echo 'No bad words in the string';
}
The single line:
$banstring = ($string != str_ireplace($badwords,"XX",$string))? true: false;
does all the work.
You can flip your bad word array and do the same checking much faster. Define each bad word as a key of the array. For example,
//define global variable that is available to too part of php script
//you don't want to redefine the array each time you call the function
//as a work around you may write a class if you don't want global variable
$GLOBALS['bad_words']= array('truck' => true, 'shot' => true);
function containsBadWord($str){
//get rid of extra white spaces at the end and beginning of the string
$str= trim($str);
//replace multiple white spaces next to each other with single space.
//So we don't have problem when we use explode on the string(we dont want empty elements in the array)
$str= preg_replace('/\s+/', ' ', $str);
$word_list= explode(" ", $str);
foreach($word_list as $word){
if( isset($GLOBALS['bad_words'][$word]) ){
return true;
}
}
return false;
}
$string = "This dude is a mothertrucker";
if ( !containsBadWord($string) ){
//doesn't contain bad word
}
else{
//contains bad word
}
In this code we are just checking if an index exist rather than comparing bad word with all the words in the bad word list.
isset is much faster than in_array and marginally faster than array_key_exists.
Make sure none of the values in bad word array are set to null.
isset will return false if the array index is set to null.
Put and exit or die once it find any bad words, like this
foreach ($bads as $bad) {
if (strpos($string,$bad) !== false) {
//say NO!
}
else {
echo YES;
die(); or exit;
}
}
You can do the filter this way also
$string = "This dude is a mothertrucker";
if (preg_match_all('#\b(truck|shot|etc)\b#', $string )) //add all bad words here.
{
echo "There is a bad word in the string";
}
else {
echo "There is no bad word in the string";
}
Wanted this?
$string = "This dude is a mothertrucker";
$bads = array('truck', 'shot', 'mothertrucker');
foreach ($bads as $bad) {
if (strstr($string,$bad) !== false) {
echo 'NO<br>';
}
else {
echo 'YES<br>';
}
}
If you want to do with array_intersect(), then use below code :
function checkString(array $arr, $str) {
$str = preg_replace( array('/[^ \w]+/', '/\s+/'), ' ', strtolower($str) ); // Remove Special Characters and extra spaces -or- convert to LowerCase
$matchedString = array_intersect( explode(' ', $str), $arr);
if ( count($matchedString) > 0 ) {
return true;
}
return false;
}
I would go that way if chat string is not that long.
$badwords = array('mothertrucker', 'ash', 'whole');
$chatstr = 'This dude is a mothertrucker';
$chatstrArr = explode(' ',$chatstr);
$badwordfound = false;
foreach ($chatstrArr as $k => $v) {
if (in_array($v,$badwords)) {$badwordfound = true; break;}
foreach($badwords as $kb => $vb) {
if (strstr($v, $kb)) $badwordfound = true;
break;
}
}
if ($badwordfound) { echo 'You\'re nasty!';}
else echo 'GoodGuy!';
$string = "This dude is a good man";
$bad = array('truck','shot','etc');
$flag='0';
foreach($bad as $word){
if(in_array($word,$string))
{
$flag=1;
}
}
if($flag==1)
echo "Exist";
else
echo "Not Exist";
How can I use two or more strings?
This is what I'm using to do just one string.
if ($input == "test")
{
echo "$imput is equal to test.";
}
If I understand you correctly, something like this might work best if you have many strings to compare with.
$string = array("foo", "bar", "hello", "world");
foreach ($string as $s) {
if ($input == $s) {
echo "$input is equal to $s";
break;
}
}
I think this is what you're looking for:
if ($input == "test" && $input2 == "hello")
{
echo "$input is equal to test and input2 is equal to hello.";
}
Do you mean how can you check if two strings contain a certain value?
If so, just use &&:
if($input == "test" && $input2 == "test") {
Then you can use
foreach ($dataarray as $string) {
if ($input == $string) {
echo "Match Found";
break;
}
}
Then it results Match Found if it founds the string in the array $dataarray();