match two strings and compare each letter in php - php

Question

I googled this question I can't to find the exact solution...
I have 2 variables...
$s1 = "ABC"; //or "BC"
$s2 = "BC"; //or "Bangalore"
I have to compare $s1 and $s2 and give the output as letters which is not present in $s2
eg : "A" // or"C"
Like that
I have to compare $s2 and $s1 and give the output as letters which is not present in $s1
eg : null // or"angalore"
What I tried..
I spit the strings to array...
Using nested for loop to find the non matched letters...
I wrote code more than 35 lines..
But no result :(
Please help me ......

Answer 1

echo str_ireplace(str_split($s2), "", $s1); // output: A

Answer 2

You can use array_diff() here:
function str_compare($str1, $str2)
{
$str1chars = str_split($str1);
$str2chars = str_split($str2);
$diff = array_diff($str1chars, $str2chars)
return implode($diff);
}
By calling the function as follows:
$diffchars = str_compare('ABC', 'BC');
You will receive a string containing the characters that do not appear in both strings. In this example, it'll be A, because that character appears in $str1, but not in $str2.

Answer 3

You can use str_split and array_diff like :
<?php
$s1 = 'abcedf';
$s2 = 'xzcedf5460gf';
print_r(array_diff(str_split($s1), str_split($s2)));

Answer 4

Use array_diff():
function str_diff($str1, $str2) {
$arr1 = str_split($str1);
$arr2 = str_split($str2);
$diff = array_diff($arr1, $arr2);
return implode($diff);
}
Usage:
echo str_diff('BC', 'Bangalore'); // => C
echo str_diff('ABC', 'BC'); // => A

Answer 5

Ok to do this
$str1s = "abc";
$str2s = "BCd";
function findNot($str1, $str2, $asArray = false){
$returnValue = array_diff(array_unique(str_split(strtolower($str1))), array_unique(str_split(strtolower($str2))));
if($asArray == false){
return implode($returnValue);
}else{
return $returnValue;
}
}
echo findNot($str1s, $str2s); //gives a string
echo findNot($str1s, $str2s, true); //gives array of characters
This allows you to return as either array or string.