I have two variables such as below
$string1 = array('A','b','c');
$string2 = 'bAcdadbcliek'
need to check all the characters from string1 is presents in string2 or not in php and values are dynamic.
try This
<?php
$string1 = array('A','b','c','2');
$string2 = 'bAcdadbcliek';
foreach($string1 as $newstring)
{
$finalval=strrchr($string2,$newstring);
if($finalval!="")
{
echo $newstring." ---: Available in given String<br/>";
}
else
{
echo $newstring." ---: Not Available in given String<br/>";
}
}
?>
use str_split and array_intersect
<?php
$string1 = array('A','b','c');
$string2 = 'bAcdadbcliek';
$new = str_split($string2);
$new_2 = array_intersect($string1,$new);
if(count($new_2)==count($string1))
{
echo "all matched";
}
else
{
echo "not ";
}
?>
The following function will return a boolean true/false if all values are matched. It is case-sensitive.
Basically, split $string2 into an array and intersect it, match the count of that against the count of $string1 (which is an array, not a string by the way). If the count is equal, everything was found.
$string1 = array('A','b','c');
$string2 = 'bAcdadbcliek';
function match_string(string $string, array $match_values) {
if (count(array_intersect(str_split($string), $match_values)) == count($match_values))
return true;
return false;
}
Live demo
Related
Hi I'm trying to check if a list of words (or any one of them) exists in a string. I tried some of the examples i found here, but i still can't get it to work correctly.
Any ideas what I'm doing wrong?
$ss3="How to make a book";
$words = array ("book","paper","page","sheet");
if (in_array($ss3, $words) )
{
echo "found it";
}
Loop over your array, check for each element if it exists in the string
$ss3="How to make a book";
$words = array ("book","paper","page","sheet");
foreach($words as $w){
if (stristr($ss3,$w)!==false)
echo "found $w \n";
}
Fiddle
You need to explode() your $ss3 string and then compare each item with your $words with loop
manual for in_array - http://php.net/manual/en/function.in-array.php
manual for explode() - http://php.net/manual/ru/function.explode.php
$matches = array();
$items = explode(" ",$ss3);
foreach($items as $item){
if(in_array($item, $words)){
$matches[] = $item; // Match found, storing in array
}
}
var_dump($matches); // To see all matches
This is how you will check for existence of a word from a string. Also remember that you must first convert the string to lowercase and then explode it.
$ss3="How to make a book";
$ss3 = strtolower($ss3);
$ss3 = explode(" ", $ss3);
$words = array ("book","paper","page","sheet");
if (in_array($ss3, $words) )
{
echo "found it";
}
Cheers!
You could use regular expressions. It would look something like this:
$ss3 = "How to make a book";
if (preg_match('/book/',$ss3))
echo 'found!!';
in_array will only check the complete string value in an array.
Now you can try this:
$string = 'How to make a book';
$words = array("book","paper","page","sheet");
foreach ($words as $val) {
if (strpos($string, $val) !== FALSE) {
echo "Match found";
return true;
}
}
echo "Not found!";
You can use str_word_count along with array_intersect like as
$ss3="How to make a book";
$words = array ("book","paper","page","sheet");
$new_str_array = str_word_count($ss3,1);
$founded_words = array_intersect($words,$new_str_array);
if(count($founded_words) > 0){
echo "Founded : ". implode(',',$founded_words);
}else{
echo "Founded Nothing";
}
Demo
This code will help you for better answer
<?php
$str="Hello World Good";
$word=array("Hello","Good");
$strArray=explode(" ",$str);
foreach($strArray as $val){
if(in_array($val,$word)){
echo $val."<br>";
}
}
?>
I looked up some reference like this question and this question but could not figure out what I need to do.
What I am trying to do is:
Say, I have two strings:
$str1 = "link/usa";
$str2 = "link/{country}";
Now I want to check if this the pattern matches. If they match, I want the value of country to be set usa.
$country = "usa";
I also want it to work in cases like:
$str1 = "link/usa/texas";
$str2 = "link/{country}/{place}";
Maybe integers as well. Like match every braces and provide the variable with value. (And, yes better performance if possible)
I cannot get a work around since I am very new to regular expresssions. Thanks in advance.
It will give you results as expected
$str1 = "link/usa";
$str2 = "link/{country}";
if(preg_match('~link/([a-z]+)~i', $str1, $matches1) && preg_match('~link/{([a-z]+)}~i', $str2, $matches2)){
$$matches2[1] = $matches1[1];
echo $country;
}
Note: Above code will just parse alphabets, you can extend characters in range as per need.
UPDATE:
You can also do it using explode, see example below:
$val1 = explode('/', $str1);
$val2 = explode('/', $str2);
${rtrim(ltrim($val2[1],'{'), '}')} = $val1[1];
echo $country;
UPDATE 2
$str1 = "link/usa/texas/2/";
$str2 = "/link/{country}/{city}/{page}";
if(preg_match_all('~/([a-z0-9]+)~i', $str1, $matches1) && preg_match_all('~{([a-z]+)}~i', $str2, $matches2)){
foreach($matches2[1] as $key => $matches){
$$matches = $matches1[1][$key];
}
echo $country;
echo '<br>';
echo $city;
echo '<br>';
echo $page;
}
I don't see the point to use the key as variable name when you can built an associative array that will be probably more handy to use later and that avoids to write ugly dynamic variable names ${the_name_of_the_var_${of_my_var_${of_your_var}}}:
$str1 = "link/usa/texas";
$str2 = "link/{country}/{place}";
function combine($pattern, $values) {
$keys = array_map(function ($i) { return trim($i, '{}'); },
explode('/', $pattern));
$values = explode('/', $values);
if (array_shift($keys) == array_shift($values) && count($keys) &&
count($keys) == count($values))
return array_combine($keys, $values);
else throw new Exception ("invalid format");
}
print_r(combine($str2, $str1));
I googled this question I can't to find the exact solution...
I have 2 variables...
$s1 = "ABC"; //or "BC"
$s2 = "BC"; //or "Bangalore"
I have to compare $s1 and $s2 and give the output as letters which is not present in $s2
eg : "A" // or"C"
Like that
I have to compare $s2 and $s1 and give the output as letters which is not present in $s1
eg : null // or"angalore"
What I tried..
I spit the strings to array...
Using nested for loop to find the non matched letters...
I wrote code more than 35 lines..
But no result :(
Please help me ......
echo str_ireplace(str_split($s2), "", $s1); // output: A
You can use array_diff() here:
function str_compare($str1, $str2)
{
$str1chars = str_split($str1);
$str2chars = str_split($str2);
$diff = array_diff($str1chars, $str2chars)
return implode($diff);
}
By calling the function as follows:
$diffchars = str_compare('ABC', 'BC');
You will receive a string containing the characters that do not appear in both strings. In this example, it'll be A, because that character appears in $str1, but not in $str2.
You can use str_split and array_diff like :
<?php
$s1 = 'abcedf';
$s2 = 'xzcedf5460gf';
print_r(array_diff(str_split($s1), str_split($s2)));
Use array_diff():
function str_diff($str1, $str2) {
$arr1 = str_split($str1);
$arr2 = str_split($str2);
$diff = array_diff($arr1, $arr2);
return implode($diff);
}
Usage:
echo str_diff('BC', 'Bangalore'); // => C
echo str_diff('ABC', 'BC'); // => A
Ok to do this
$str1s = "abc";
$str2s = "BCd";
function findNot($str1, $str2, $asArray = false){
$returnValue = array_diff(array_unique(str_split(strtolower($str1))), array_unique(str_split(strtolower($str2))));
if($asArray == false){
return implode($returnValue);
}else{
return $returnValue;
}
}
echo findNot($str1s, $str2s); //gives a string
echo findNot($str1s, $str2s, true); //gives array of characters
This allows you to return as either array or string.
This question already has answers here:
String contains any items in an array (case insensitive)
(15 answers)
Closed 2 years ago.
I am trying to detect whether a string contains at least one URL that is stored in an array.
Here is my array:
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
The string is entered by the user and submitted via PHP. On the confirmation page I would like to check if the URL entered is in the array.
I have tried the following:
$string = 'my domain name is website3.com';
if (in_array($string, $owned_urls))
{
echo "Match found";
return true;
}
else
{
echo "Match not found";
return false;
}
No matter what is inputted the return is always "Match not found".
Is this the correct way of doing things?
Try this.
$string = 'my domain name is website3.com';
foreach ($owned_urls as $url) {
//if (strstr($string, $url)) { // mine version
if (strpos($string, $url) !== FALSE) { // Yoshi version
echo "Match found";
return true;
}
}
echo "Not found!";
return false;
Use stristr() or stripos() if you want to check case-insensitive.
This was a lot easier to do if all you want to do is find a string in an array.
$array = ["they has mystring in it", "some", "other", "elements"];
if (stripos(json_encode($array),'mystring') !== false) {
echo "found mystring";
}
Try this:
$owned_urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
$url_string = end(explode(' ', $string));
if (in_array($url_string,$owned_urls)){
echo "Match found";
return true;
} else {
echo "Match not found";
return false;
}
-
Thanks
Simple str_replace with count parameter would work here:
$count = 0;
str_replace($owned_urls, '', $string, $count);
// if replace is successful means the array value is present(Match Found).
if ($count > 0) {
echo "One of Array value is present in the string.";
}
More Info - https://www.techpurohit.in/extended-behaviour-explode-and-strreplace-php
I think that a faster way is to use preg_match.
$user_input = 'Something website2.com or other';
$owned_urls_array = array('website1.com', 'website2.com', 'website3.com');
if ( preg_match('('.implode('|',$owned_urls_array).')', $user_input)){
echo "Match found";
}else{
echo "Match not found";
}
$string = 'my domain name is website3.com';
$a = array('website1.com','website2.com','website3.com');
$result = count(array_filter($a, create_function('$e','return strstr("'.$string.'", $e);')))>0;
var_dump($result );
output
bool(true)
Here is a mini-function that search all values from an array in a given string.
I use this in my site to check for visitor IP is in my permitted list on certain pages.
function array_in_string($str, array $arr) {
foreach($arr as $arr_value) { //start looping the array
if (stripos($str,$arr_value) !== false) return true; //if $arr_value is found in $str return true
}
return false; //else return false
}
how to use
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
//this example should return FOUND
$string = 'my domain name is website3.com';
if (array_in_string($string, $owned_urls)) {
echo "first: Match found<br>";
}
else {
echo "first: Match not found<br>";
}
//this example should return NOT FOUND
$string = 'my domain name is website4.com';
if (array_in_string($string, $owned_urls)) {
echo "second: Match found<br>";
}
else {
echo "second: Match not found<br>";
}
DEMO: http://phpfiddle.org/lite/code/qf7j-8m09
stripos function is not very strict. it's not case sensitive or it can match a part of a word
http://php.net/manual/ro/function.stripos.php
if you want that search to be case sensitive use strpos
http://php.net/manual/ro/function.strpos.php
for exact match use regex (preg_match), check this guy answer https://stackoverflow.com/a/25633879/4481831
You can concatenate the array values with implode and a separator of |
and then use preg_match to search for the value.
Here is the solution I came up with ...
$emails = array('#gmail', '#hotmail', '#outlook', '#live', '#msn', '#yahoo', '#ymail', '#aol');
$emails = implode('|', $emails);
if(!preg_match("/$emails/i", $email)){
// do something
}
If your $string is always consistent (ie. the domain name is always at the end of the string), you can use explode() with end(), and then use in_array() to check for a match (as pointed out by #Anand Solanki in their answer).
If not, you'd be better off using a regular expression to extract the domain from the string, and then use in_array() to check for a match.
$string = 'There is a url mysite3.com in this string';
preg_match('/(?:http:\/\/)?(?:www.)?([a-z0-9-_]+\.[a-z0-9.]{2,5})/i', $string, $matches);
if (empty($matches[1])) {
// no domain name was found in $string
} else {
if (in_array($matches[1], $owned_urls)) {
// exact match found
} else {
// exact match not found
}
}
The expression above could probably be improved (I'm not particularly knowledgeable in this area)
Here's a demo
You are checking whole string to the array values. So output is always false.
I use both array_filter and strpos in this case.
<?php
$urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
$check = array_filter($urls, function($url){
global $string;
if(strpos($string, $url))
return true;
});
echo $check?"found":"not found";
$owned_urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
for($i=0; $i < count($owned_urls); $i++)
{
if(strpos($string,$owned_urls[$i]) != false)
echo 'Found';
}
$message = "This is test message that contain filter world test3";
$filterWords = array('test1', 'test2', 'test3');
$messageAfterFilter = str_replace($filterWords, '',$message);
if( strlen($messageAfterFilter) != strlen($message) )
echo 'message is filtered';
else
echo 'not filtered';
I find this fast and simple without running loop.
$array = array("this", "that", "there", "here", "where");
$string = "Here comes my string";
$string2 = "I like to Move it! Move it";
$newStr = str_replace($array, "", $string);
if(strcmp($string, $newStr) == 0) {
echo 'No Word Exists - Nothing got replaced in $newStr';
} else {
echo 'Word Exists - Some Word from array got replaced!';
}
$newStr = str_replace($array, "", $string2);
if(strcmp($string2, $newStr) == 0) {
echo 'No Word Exists - Nothing got replaced in $newStr';
} else {
echo 'Word Exists - Some Word from array got replaced!';
}
Little explanation!
Create new variable with $newStr replacing value in array of original string.
Do string comparison - If value is 0, that means, strings are equal and nothing was replaced, hence no value in array exists in string.
if it is vice versa of 2, i.e, while doing string comparison, both original and new string was not matched, that means, something got replaced, hence value in array exists in string.
$search = "web"
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
foreach ($owned_urls as $key => $value) {
if (stristr($value, $search) == '') {
//not fount
}else{
//found
}
this is the best approach search for any substring , case-insensitive and fast
just like like im mysql
ex:
select * from table where name = "%web%"
I came up with this function which works for me, hope this will help somebody
$word_list = 'word1, word2, word3, word4';
$str = 'This string contains word1 in it';
function checkStringAgainstList($str, $word_list)
{
$word_list = explode(', ', $word_list);
$str = explode(' ', $str);
foreach ($str as $word):
if (in_array(strtolower($word), $word_list)) {
return TRUE;
}
endforeach;
return false;
}
Also, note that answers with strpos() will return true if the matching word is a part of other word. For example if word list contains 'st' and if your string contains 'street', strpos() will return true
Is there a built in function in PHP that would combine 2 strings into 1?
Example:
$string1 = 'abcde';
$string2 = 'cdefg';
Combine to get: abcdefg.
If the exact overlapping sequence and the position are known, then it is possible to write a code to merge them.
TIA
I found the substr_replace method to return funny results.
Especially when working with url strings. I just wrote this function.
It seems to be working perfectly for my needs.
The function will return the longest possible match by default.
function findOverlap($str1, $str2){
$return = array();
$sl1 = strlen($str1);
$sl2 = strlen($str2);
$max = $sl1>$sl2?$sl2:$sl1;
$i=1;
while($i<=$max){
$s1 = substr($str1, -$i);
$s2 = substr($str2, 0, $i);
if($s1 == $s2){
$return[] = $s1;
}
$i++;
}
if(!empty($return)){
return $return;
}
return false;
}
function replaceOverlap($str1, $str2, $length = "long"){
if($overlap = findOverlap($str1, $str2)){
switch($length){
case "short":
$overlap = $overlap[0];
break;
case "long":
default:
$overlap = $overlap[count($overlap)-1];
break;
}
$str1 = substr($str1, 0, -strlen($overlap));
$str2 = substr($str2, strlen($overlap));
return $str1.$overlap.$str2;
}
return false;
}
Usage to get the maximum length match:
echo replaceOverlap("abxcdex", "xcdexfg"); //Result: abxcdexfg
To get the first match instead of the last match call the function like this:
echo replaceOverlap("abxcdex", "xcdexfg", “short”); //Result: abxcdexcdexfg
To get the overlapping string just call:
echo findOverlap("abxcdex", "xcdexfg"); //Result: array( 0 => "x", 1 => "xcdex" )
It's possible using substr_replace() and strcspn():
$string1 = 'abcde';
$string2 = 'cdefgh';
echo substr_replace($string1, $string2, strcspn($string1, $string2)); // abcdefgh
No, there is no builtin function, but you can easily write one yourself by using substr and a loop to see how much of the strings that overlap.