Related
I can get the Monday of this week with:
$monday = date_create()->modify('this Monday');
I would like to get with the same ease the 1st of this month. How can I achieve that?
Here is what I use.
First day of the month:
date('Y-m-01');
Last day of the month:
date('Y-m-t');
Requires PHP 5.3 to work ("first day of" is introduced in PHP 5.3). Otherwise the example above is the only way to do it:
<?php
// First day of this month
$d = new DateTime('first day of this month');
echo $d->format('jS, F Y');
// First day of a specific month
$d = new DateTime('2010-01-19');
$d->modify('first day of this month');
echo $d->format('jS, F Y');
// alternatively...
echo date_create('2010-01-19')
->modify('first day of this month')
->format('jS, F Y');
In PHP 5.4+ you can do this:
<?php
// First day of this month
echo (new DateTime('first day of this month'))->format('jS, F Y');
echo (new DateTime('2010-01-19'))
->modify('first day of this month')
->format('jS, F Y');
If you prefer a concise way to do this, and already have the year and month in numerical values, you can use date():
<?php
echo date('Y-m-01'); // first day of this month
echo "$year-$month-01"; // first day of a month chosen by you
This is everything you need:
$week_start = strtotime('last Sunday', time());
$week_end = strtotime('next Sunday', time());
$month_start = strtotime('first day of this month', time());
$month_end = strtotime('last day of this month', time());
$year_start = strtotime('first day of January', time());
$year_end = strtotime('last day of December', time());
echo date('D, M jS Y', $week_start).'<br/>';
echo date('D, M jS Y', $week_end).'<br/>';
echo date('D, M jS Y', $month_start).'<br/>';
echo date('D, M jS Y', $month_end).'<br/>';
echo date('D, M jS Y', $year_start).'<br/>';
echo date('D, M jS Y', $year_end).'<br/>';
Currently I'm using this solution:
$firstDay = new \DateTime('first day of this month');
$lastDay = new \DateTime('last day of this month');
The only issue I came upon is that strange time is being set. I needed correct range for our search interface and I ended up with this:
$firstDay = new \DateTime('first day of this month 00:00:00');
$lastDay = new \DateTime('first day of next month 00:00:00');
I use a crazy way to do this is using this command
$firstDay=date('Y-m-d',strtotime("first day of this month"));
$lastDay=date('Y-m-d',strtotime("last day of this month"));
Thats all
In php 5.2 you can use:
<? $d = date_create();
print date_create($d->format('Y-m-1'))->format('Y-m-d') ?>
Ugly, (and doesn't use your method call above) but works:
echo 'First day of the month: ' . date('m/d/y h:i a',(strtotime('this month',strtotime(date('m/01/y')))));
You can do it like this:
$firstday = date_create()->modify('first day January 2010');
using date method, we should be able to get the result.
ie; date('N/D/l', mktime(0, 0, 0, month, day, year));
For Example
echo date('N', mktime(0, 0, 0, 7, 1, 2017)); // will return 6
echo date('D', mktime(0, 0, 0, 7, 1, 2017)); // will return Sat
echo date('l', mktime(0, 0, 0, 7, 1, 2017)); // will return Saturday
I use this with a daily cron job to check if I should send an email on the first day of any given month to my affiliates. It's a few more lines than the other answers but solid as a rock.
//is this the first day of the month?
$date = date('Y-m-d');
$pieces = explode("-", $date);
$day = $pieces[2];
//if it's not the first day then stop
if($day != "01") {
echo "error - it's not the first of the month today";
exit;
}
Timestamp for start of this month and very last second of current month.
You can add 00:00:00 or just reference "today"
Alternative:
$startOfThisMonth = strtotime("first day of this month",strtotime("today"));
OR
$startOfThisMonth = strtotime("first day of this month 00:00:00");
$endOfThisMonth = strtotime("first day of next month",$startOfThisMonth)-1;
I am providing this answer as an alternative one liner if the DateTime object is not preferred
Basically, I get the current day number, reduce it by one then take that number of days from itself ("today" which automatically resets the clock to 00:00:00 too) and you get the start of the month.
$startOfMonth = strtotime("today - ".(date("j")-1)." days");
If you're using composer, you can install carbon:
composer require nesbot/carbon
This is then as simple as:
use Carbon/Carbon;
$startOfMonth = Carbon::now()->startOfMonth()->toDateTime();
Is it possible to update a date every week automatically with php?
For instance, I have a weekly forecast that is updated every Monday. The title would read something like "Forecast for Friday June 28th."
<h1>- Forecast for Friday June 28th -</h1>
Then on the following monday, I would like to automatically update the date in the title to the next occurring Friday.
is this possible with php?
This is what you're looking for:
switch (date('N'))
{
case 5:
$time = time();
break;
case 6:
case 7:
$time = strtotime('last Friday');
break;
default:
$time = strtotime('next Friday');
}
echo date('l F jS', $time);
Check the date function for different formatting options.
Although are you sure you want to wait until Monday until showing the forecast for the next Friday? Surely it should update to the following week on the Saturday (otherwise you'll be forecasting a past date)? If so, just remove the case 6/case 7 section.
Yes. Take a look at date() for formatting and strtotime() to quickly create relative timestamps:
The following should get you started:
echo date('l F jS', strtotime('monday'));
Note: If you're using PHP > 5.3 you should look at the DateTime class.
It's very simple coded to explain as much simple as possible. The script calculates how many days left until next Friday, if $today is not Friday.
Hope that helps you!
<?php
$now = time(); // current timestamp
$today = date("w", $now); // "w" returns the weekday (number)
$friday = 5; // 5th day of the week (sunday = 0)
if ($today == $friday) {
$ts = $now; // today is friday, don't change the timestamp
$daysLeft = 0; // no days left!
} else {
if ($today == 6) {
$daysLeft = 6; // saturday is bigger then friday
} else {
$daysLeft = $friday-$today; // get the left days
}
$ts = $now + 84600 * $daysLeft; // now + seconds of one day * days left
}
?>
<h1>
- Forecast for <?php echo date("D M d", $ts) ?>-
</h1>
$currDay = date('w');
$delta = $currDay==6 ? 6 : 5-$currDay;
$date = new DateTime();
$date->add(new DateInterval('P'.$delta.'D'));
echo $date->format('D M jS');
Here's a summary of the issue: On Sundays, strtotime('this week') returns the start of next week.
In PHP, the week seems to start on Monday. But, on any day except Sunday, this code
echo date('Y-m-d', strtotime('monday this week', strtotime('last sunday')));
Outputs the date of this week's Monday, when it seems like it should be outputting last weeks Monday. It seems like, in this case, PHP is treating both Sunday and Monday as the the start of the week. It's now Monday, Dec 10, 2012, or 2012-12-10. date('Y-m-d', strtotime('sunday last week')) returns 2012-12-09 - yesterday.
Is this a bug, or am I missing something? It seems like a bug this obvious should be fairly well known, but I can't find anything about it. Is the only way to get the start of the week to use some special handling for Sundays?
$week_offset = (int) 'sunday' == date('l');
$week_start = strtotime("-$week_offset monday"); // 1 or 0 Mondays ago
As far as I can tell, this is a bug. I see no logical reason why strtotime('this week'); should return a future date. This is a pretty major bug. In my particular case, I had a leaderboard that showed the users with the most points since the beginning of the week. But on Sundays, it was empty because strtotime returned a timestamp for a future date. I was doubtful, because just I don't know how this could have gone unnoticed, but I couldn't find any other reports of this bug.
Thanks for all your time and help, folks.
This answer is late, but it's something that I've been struggling with. Every solution I've tried so far has malfunctioned for one reason or another. This is what I ended up with that worked for me. (though it may be look pretty, it at least works).
$thisMonday = strtotime('next Monday -1 week', strtotime('this sunday'));
Here is how you can get Monday of current week:
echo date("Y-m-d", strtotime(date('o-\\WW')));
It's not ideal but this is what I resorted to using:
if(date('N') == 7) {
$date = date('Y-m-d',strtotime('monday last week'));
} else {
$date = date('Y-m-d',strtotime('monday this week'));
}
I think the only problem with your coding is TimeZone.
Solution:
Set your own time Zone. Here is the example of my own time zone:
Example
date_default_timezone_set('Asia/Kolkata');
Set the above line before calling any time function.
Have a nice day.
I think instead of trying
echo date('Y-m-d', strtotime('monday this week', strtotime('last sunday')));
you should try
echo date('Y-m-d', strtotime('monday last week'));
Try this code
// set current date
$date = date("m/d/Y");
$ts = strtotime($date); // also $ts = time();
// find the year and the current week
$year = date('o', $ts);
$week = date('W', $ts);
// print week for the current date
$i = 1; // 1 denotes the first day of week
$ts = strtotime($year.'W'.$week.$i);
echo $day = date("l", $ts); // generate the name of day
echo "<br>";
echo $day = date("Y-m-d", $ts); // generate the date
You will get the the date of current week, whether you are on monday you will get the date of that monday.
If you want the most recent monday:
function mostRecentMonday(){
if(date("w") == 1){
return strtotime("midnight today");
} else {
return strtotime("last monday");
}
}
Easy to modify to use DateTime, or, to even specify a different date to use as the base.
Based on Bryant answer :
$first_week_date = date('d F Y', strtotime('next Monday -1 week', strtotime('this sunday')));
$last_week_date = date('d F Y', strtotime('next Monday -1 week + 6 days', strtotime('this sunday')));
This is for thos looking for a friendly solution that works with any day.
function getWeekStart($week_start_day = "Monday") {
$week_days = array("Sunday"=>0,"Monday"=>1,"Tuesday"=>2,"Wednesday"=>3,"Thursday"=>4,"Friday"=>5,"Saturday"=>6,);
if(!isset($week_days[$week_start_day])) {
return false;
} else {
$start_day = $week_days[$week_start_day];
$today = date("w");
$one_day = (60 * 60 * 24);
if($today < $start_day) {
$days_difference = 7 - ($start_day - $today);
} else {
$days_difference = ($today - $start_day);
}
$week_starts = strtotime(date("Y-m-d 00:00:00")) - ($one_day * $days_difference);
return $week_starts;
}
}
//Test: If today is Monday, it will return today's date
echo date("Y-m-d H:i:s", getWeekStart("Monday"));
I can get the Monday of this week with:
$monday = date_create()->modify('this Monday');
I would like to get with the same ease the 1st of this month. How can I achieve that?
Here is what I use.
First day of the month:
date('Y-m-01');
Last day of the month:
date('Y-m-t');
Requires PHP 5.3 to work ("first day of" is introduced in PHP 5.3). Otherwise the example above is the only way to do it:
<?php
// First day of this month
$d = new DateTime('first day of this month');
echo $d->format('jS, F Y');
// First day of a specific month
$d = new DateTime('2010-01-19');
$d->modify('first day of this month');
echo $d->format('jS, F Y');
// alternatively...
echo date_create('2010-01-19')
->modify('first day of this month')
->format('jS, F Y');
In PHP 5.4+ you can do this:
<?php
// First day of this month
echo (new DateTime('first day of this month'))->format('jS, F Y');
echo (new DateTime('2010-01-19'))
->modify('first day of this month')
->format('jS, F Y');
If you prefer a concise way to do this, and already have the year and month in numerical values, you can use date():
<?php
echo date('Y-m-01'); // first day of this month
echo "$year-$month-01"; // first day of a month chosen by you
This is everything you need:
$week_start = strtotime('last Sunday', time());
$week_end = strtotime('next Sunday', time());
$month_start = strtotime('first day of this month', time());
$month_end = strtotime('last day of this month', time());
$year_start = strtotime('first day of January', time());
$year_end = strtotime('last day of December', time());
echo date('D, M jS Y', $week_start).'<br/>';
echo date('D, M jS Y', $week_end).'<br/>';
echo date('D, M jS Y', $month_start).'<br/>';
echo date('D, M jS Y', $month_end).'<br/>';
echo date('D, M jS Y', $year_start).'<br/>';
echo date('D, M jS Y', $year_end).'<br/>';
Currently I'm using this solution:
$firstDay = new \DateTime('first day of this month');
$lastDay = new \DateTime('last day of this month');
The only issue I came upon is that strange time is being set. I needed correct range for our search interface and I ended up with this:
$firstDay = new \DateTime('first day of this month 00:00:00');
$lastDay = new \DateTime('first day of next month 00:00:00');
I use a crazy way to do this is using this command
$firstDay=date('Y-m-d',strtotime("first day of this month"));
$lastDay=date('Y-m-d',strtotime("last day of this month"));
Thats all
In php 5.2 you can use:
<? $d = date_create();
print date_create($d->format('Y-m-1'))->format('Y-m-d') ?>
Ugly, (and doesn't use your method call above) but works:
echo 'First day of the month: ' . date('m/d/y h:i a',(strtotime('this month',strtotime(date('m/01/y')))));
You can do it like this:
$firstday = date_create()->modify('first day January 2010');
using date method, we should be able to get the result.
ie; date('N/D/l', mktime(0, 0, 0, month, day, year));
For Example
echo date('N', mktime(0, 0, 0, 7, 1, 2017)); // will return 6
echo date('D', mktime(0, 0, 0, 7, 1, 2017)); // will return Sat
echo date('l', mktime(0, 0, 0, 7, 1, 2017)); // will return Saturday
I use this with a daily cron job to check if I should send an email on the first day of any given month to my affiliates. It's a few more lines than the other answers but solid as a rock.
//is this the first day of the month?
$date = date('Y-m-d');
$pieces = explode("-", $date);
$day = $pieces[2];
//if it's not the first day then stop
if($day != "01") {
echo "error - it's not the first of the month today";
exit;
}
Timestamp for start of this month and very last second of current month.
You can add 00:00:00 or just reference "today"
Alternative:
$startOfThisMonth = strtotime("first day of this month",strtotime("today"));
OR
$startOfThisMonth = strtotime("first day of this month 00:00:00");
$endOfThisMonth = strtotime("first day of next month",$startOfThisMonth)-1;
I am providing this answer as an alternative one liner if the DateTime object is not preferred
Basically, I get the current day number, reduce it by one then take that number of days from itself ("today" which automatically resets the clock to 00:00:00 too) and you get the start of the month.
$startOfMonth = strtotime("today - ".(date("j")-1)." days");
If you're using composer, you can install carbon:
composer require nesbot/carbon
This is then as simple as:
use Carbon/Carbon;
$startOfMonth = Carbon::now()->startOfMonth()->toDateTime();
Given a date MM-dd-yyyy format, can someone help me get the first day of the week?
Here is what I am using...
$day = date('w');
$week_start = date('m-d-Y', strtotime('-'.$day.' days'));
$week_end = date('m-d-Y', strtotime('+'.(6-$day).' days'));
$day contains a number from 0 to 6 representing the day of the week (Sunday = 0, Monday = 1, etc.).
$week_start contains the date for Sunday of the current week as mm-dd-yyyy.
$week_end contains the date for the Saturday of the current week as mm-dd-yyyy.
Very simple to use strtotime function:
echo date("Y-m-d", strtotime('monday this week')), "\n";
echo date("Y-m-d", strtotime('sunday this week')), "\n";
It differs a bit across PHP versions:
Output for 5.3.0 - 5.6.6, php7#20140507 - 20150301, hhvm-3.3.1 - 3.5.1
2015-03-16
2015-03-22
Output for 4.3.5 - 5.2.17
2015-03-23
2015-03-22
Output for 4.3.0 - 4.3.4
2015-03-30
2015-03-29
Comparing at Edge-Cases
Relative descriptions like this week have their own context. The following shows the output for this week monday and sunday when it's a monday or a sunday:
$date = '2015-03-16'; // monday
echo date("Y-m-d", strtotime('monday this week', strtotime($date))), "\n";
echo date("Y-m-d", strtotime('sunday this week', strtotime($date))), "\n";
$date = '2015-03-22'; // sunday
echo date("Y-m-d", strtotime('monday this week', strtotime($date))), "\n";
echo date("Y-m-d", strtotime('sunday this week', strtotime($date))), "\n";
Againt it differs a bit across PHP versions:
Output for 5.3.0 - 5.6.6, php7#20140507 - 20150301, hhvm-3.3.1 - 3.5.1
2015-03-16
2015-03-22
2015-03-23
2015-03-29
Output for 4.3.5 - 5.0.5, 5.2.0 - 5.2.17
2015-03-16
2015-03-22
2015-03-23
2015-03-22
Output for 5.1.0 - 5.1.6
2015-03-23
2015-03-22
2015-03-23
2015-03-29
Output for 4.3.0 - 4.3.4
2015-03-23
2015-03-29
2015-03-30
2015-03-29
strtotime('this week', time());
Replace time(). Next sunday/last monday methods won't work when the current day is sunday/monday.
Keep it simple :
<?php
$dateTime = new \DateTime('2020-04-01');
$monday = clone $dateTime->modify(('Sunday' == $dateTime->format('l')) ? 'Monday last week' : 'Monday this week');
$sunday = clone $dateTime->modify('Sunday this week');
?>
Source : PHP manual
NB: as some user commented the $dateTime value will be modified.
$givenday = date("w", mktime(0, 0, 0, MM, dd, yyyy));
This gives you the day of the week of the given date itself where 0 = Sunday and 6 = Saturday. From there you can simply calculate backwards to the day you want.
This question needs a good DateTime answer:-
function firstDayOfWeek($date)
{
$day = DateTime::createFromFormat('m-d-Y', $date);
$day->setISODate((int)$day->format('o'), (int)$day->format('W'), 1);
return $day->format('m-d-Y');
}
var_dump(firstDayOfWeek('06-13-2013'));
Output:-
string '06-10-2013' (length=10)
This will deal with year boundaries and leap years.
EDIT: the below link is no longer running on the version of PHP stated. It is running on PHP 5.6 which improves the reliability of strtotime, but isn't perfect! The results in the table are live results from PHP 5.6.
For what it's worth, here is a breakdown of the wonky behavior of strtotime when determining a consistent frame of reference:
http://gamereplays.org/reference/strtotime.php
Basically only these strings will reliably give you the same date, no matter what day of the week you're currently on when you call them:
strtotime("next monday");
strtotime("this sunday");
strtotime("last sunday");
Assuming Monday as the first day of the week, this works:
echo date("M-d-y", strtotime('last monday', strtotime('next week', time())));
The following code should work with any custom date, just uses the desired date format.
$custom_date = strtotime( date('d-m-Y', strtotime('31-07-2012')) );
$week_start = date('d-m-Y', strtotime('this week last monday', $custom_date));
$week_end = date('d-m-Y', strtotime('this week next sunday', $custom_date));
echo '<br>Start: '. $week_start;
echo '<br>End: '. $week_end;
I tested the code with PHP 5.2.17 Results:
Start: 30-07-2012
End: 05-08-2012
How about this?
$first_day_of_week = date('m-d-Y', strtotime('Last Monday', time()));
$last_day_of_week = date('m-d-Y', strtotime('Next Sunday', time()));
This is what I am using to get the first and last day of the week from any date.
In this case, monday is the first day of the week...
$date = date('Y-m-d') // you can put any date you want
$nbDay = date('N', strtotime($date));
$monday = new DateTime($date);
$sunday = new DateTime($date);
$monday->modify('-'.($nbDay-1).' days');
$sunday->modify('+'.(7-$nbDay).' days');
Here I am considering Sunday as first & Saturday as last day of the week.
$m = strtotime('06-08-2012');
$today = date('l', $m);
$custom_date = strtotime( date('d-m-Y', $m) );
if ($today == 'Sunday') {
$week_start = date("d-m-Y", $m);
} else {
$week_start = date('d-m-Y', strtotime('this week last sunday', $custom_date));
}
if ($today == 'Saturday') {
$week_end = date("d-m-Y", $m);
} else {
$week_end = date('d-m-Y', strtotime('this week next saturday', $custom_date));
}
echo '<br>Start: '. $week_start;
echo '<br>End: '. $week_end;
Output :
Start: 05-08-2012
End: 11-08-2012
How about this?
$day_of_week = date('N', strtotime($string_date));
$week_first_day = date('Y-m-d', strtotime($string_date . " - " . ($day_of_week - 1) . " days"));
$week_last_day = date('Y-m-d', strtotime($string_date . " + " . (7 - $day_of_week) . " days"));
Just use date($format, strtotime($date,' LAST SUNDAY + 1 DAY'));
Try this:
function week_start_date($wk_num, $yr, $first = 1, $format = 'F d, Y')
{
$wk_ts = strtotime('+' . $wk_num . ' weeks', strtotime($yr . '0101'));
$mon_ts = strtotime('-' . date('w', $wk_ts) + $first . ' days', $wk_ts);
return date($format, $mon_ts);
}
$sStartDate = week_start_date($week_number, $year);
$sEndDate = date('F d, Y', strtotime('+6 days', strtotime($sStartDate)));
(from this forum thread)
This is the shortest and most readable solution I found:
<?php
$weekstart = strtotime('monday this week');
$weekstop = strtotime('sunday this week 23:59:59');
//echo date('d.m.Y H:i:s', $weekstart) .' - '. date('d.m.Y H:i:s', $weekstop);
?>
strtotime is faster than new DateTime()->getTimestamp().
$monday = date('d-m-Y',strtotime('last monday',strtotime('next monday',strtotime($date))));
You have to get next monday first then get the 'last monday' of next monday. So if the given date is monday it will return the same date not last week monday.
$string_date = '2019-07-31';
echo $day_of_week = date('N', strtotime($string_date));
echo $week_first_day = date('Y-m-d', strtotime($string_date . " - " . ($day_of_week - 1) . " days"));
echo $week_last_day = date('Y-m-d', strtotime($string_date . " + " . (7 - $day_of_week) . " days"));
Given PHP version pre 5.3 following function gives you a first day of the week of given date (in this case - Sunday, 2013-02-03):
<?php
function startOfWeek($aDate){
$d=strtotime($aDate);
return strtotime(date('Y-m-d',$d).' - '.date("w",$d).' days');
}
echo(date('Y-m-d',startOfWeek("2013-02-07")).'
');
?>
$today_day = date('D'); //Or add your own date
$start_of_week = date('Ymd');
$end_of_week = date('Ymd');
if($today_day != "Mon")
$start_of_week = date('Ymd', strtotime("last monday"));
if($today_day != "Sun")
$end_of_week = date('Ymd', strtotime("next sunday"));
If you want Monday as the start of your week, do this:
$date = '2015-10-12';
$day = date('N', strtotime($date));
$week_start = date('Y-m-d', strtotime('-'.($day-1).' days', strtotime($date)));
$week_end = date('Y-m-d', strtotime('+'.(7-$day).' days', strtotime($date)));
A smart way of doing this is to let PHP handle timezone differences and Daylight Savings Time (DST). Let me show you how to do this.
This function will generate all days from Monday until Friday, inclusive (handy for generating work week days):
class DateTimeUtilities {
public static function getPeriodFromMondayUntilFriday($offset = 'now') {
$now = new \DateTimeImmutable($offset, new \DateTimeZone('UTC'));
$today = $now->setTime(0, 0, 1);
$daysFromMonday = $today->format('N') - 1;
$monday = $today->sub(new \DateInterval(sprintf('P%dD', $daysFromMonday)));
$saturday = $monday->add(new \DateInterval('P5D'));
return new \DatePeriod($monday, new \DateInterval('P1D'), $saturday);
}
}
foreach (DateTimeUtilities::getPeriodFromMondayUntilFriday() as $day) {
print $day->format('c');
print PHP_EOL;
}
This will return datetimes Monday-Friday for current week. To do the same for an arbitrary date, pass a date as a parameter to DateTimeUtilities ::getPeriodFromMondayUntilFriday, thus:
foreach (DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21+00:00') as $day) {
print $day->format('c');
print PHP_EOL;
}
//prints
//2017-01-02T00:00:01+00:00
//2017-01-03T00:00:01+00:00
//2017-01-04T00:00:01+00:00
//2017-01-05T00:00:01+00:00
//2017-01-06T00:00:01+00:00
Only interested in Monday, as the OP asked?
$monday = DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21+00:00')->getStartDate()->format('c');
print $monday;
// prints
//2017-01-02T00:00:01+00:00
You parse the date using strptime() and use date() on the result:
date('N', strptime('%m-%d-%g', $dateString));
<?php
/* PHP 5.3.0 */
date_default_timezone_set('America/Denver'); //Set apprpriate timezone
$start_date = strtotime('2009-12-15'); //Set start date
//Today's date if $start_date is a Sunday, otherwise date of previous Sunday
$today_or_previous_sunday = mktime(0, 0, 0, date('m', $start_date), date('d', $start_date), date('Y', $start_date)) - ((date("w", $start_date) ==0) ? 0 : (86400 * date("w", $start_date)));
//prints 12-13-2009 (month-day-year)
echo date('m-d-Y', $today_or_previous_sunday);
?>
(Note: MM, dd and yyyy in the Question are not standard php date format syntax - I can't be sure what is meant, so I set the $start_date with ISO year-month-day)
I've come against this question a few times and always surprised the date functions don't make this easier or clearer. Here's my solution for PHP5 that uses the DateTime class:
/**
* #param DateTime $date A given date
* #param int $firstDay 0-6, Sun-Sat respectively
* #return DateTime
*/
function getFirstDayOfWeek(DateTime $date, $firstDay = 0) {
$offset = 7 - $firstDay;
$ret = clone $date;
$ret->modify(-(($date->format('w') + $offset) % 7) . 'days');
return $ret;
}
Necessary to clone to avoid altering the original date.
Another way to do it....
$year = '2014';
$month = '02';
$day = '26';
$date = DateTime::createFromFormat('Y-m-d H:i:s', $year . '-' . $month . '-' . $day . '00:00:00');
$day = date('w', $date->getTimestamp());
// 0=Sunday 6=Saturday
if($day!=0){
$newdate = $date->getTimestamp() - $day * 86400; //86400 seconds in a day
// Look for DST change
if($old = date('I', $date->getTimestamp()) != $new = date('I', $newdate)){
if($old == 0){
$newdate -= 3600; //3600 seconds in an hour
} else {
$newdate += 3600;
}
}
$date->setTimestamp($newdate);
}
echo $date->format('D Y-m-d H:i:s');
The easiest way to get first day(Monday) of current week is:
strtotime("next Monday") - 604800;
where 604800 - is count of seconds in 1 week(60*60*24*7).
This code get next Monday and decrease it for 1 week. This code will work well in any day of week. Even if today is Monday.
I found this quite frustrating given that my timezone is Australian and that strtotime() hates UK dates.
If the current day is a Sunday, then strtotime("monday this week") will return the day after.
To overcome this:
Caution: This is only valid for Australian/UK dates
$startOfWeek = (date('l') == 'Monday') ? date('d/m/Y 00:00') : date('d/m/Y', strtotime("last monday 00:00"));
$endOfWeek = (date('l') == 'Sunday') ? date('d/m/Y 23:59:59') : date('d/m/Y', strtotime("sunday 23:59:59"));
Here's a one liner for the first day of last week, and the last day of last week as a DateTime object.
$firstDay = (new \DateTime())->modify(sprintf('-%d day', date('w') + 7))
->setTime(0, 0, 0);
$lastDay = (new \DateTime())->modify(sprintf('-%d day', date('w') + 1))
->setTime(23, 59, 59);
Just to note that timestamp math can also be a solution. If you have in mind that 01.jan 1970 was a Thursday, then start of a week for any given date can be calculated with:
function weekStart($dts)
{ $res = $dts - ($dts+date('Z',$dts)+259200)%604800;
return $res + 3600*(date('I',$dts)-date('I',$res));
}
It is predictable for any timestamp and php version, using date-func ('Z', 'I') only for timezone and daylight-saving offsets. And it produces same results as:
strtotime(date('Y-m-d', $dts).' - '.(date('N', $dts)-1.' days');
and with (the best and the most elegant) mentioned:
strtotime('monday this week', $dts);